**DUE TOMORROW NEED ANSWER ASAP**
If the entire mass of the Milky Way was due to gas and stars, how would you expect the rotational speed of a star near the edge of the galaxy to compare to the rotational speed of a star near the center?

Answer:

9mol N

Explanation:

The balanced chemical equation is:

N₂ + 3H₂ → 2NH₃

According to the stoichiometry of this reaction, 1 mole of N₂ reacts with 3 moles of H₂ to produce 2 moles of NH₃.

So, to produce 2 moles of NH₃, we need 1 mole of N₂.

Therefore, to produce 18 moles of NH₃, we would need:

18 mol NH₃ × (1 mol N₂ / 2 mol NH₃) = 9 mol N₂

Thus, 9 moles of nitrogen are required to produce 18 mol of NH₃.

Without more information about the specific experiment, it is difficult to provide a definitive answer to this question. However, based on the limited information provided, it seems that the experiment involves placing water samples from Detroit and Flint into separate beakers, stirring them, and then introducing a metal coil into each beaker.

What is Metal?

Metal is a type of element characterized by its shiny appearance, malleability, ductility, and ability to conduct heat and electricity. Metals are typically solid at room temperature (except for mercury, which is a liquid) and have a high melting and boiling point.

If the metal coil is made of a reactive metal such as iron, zinc, or aluminum, and the water contains dissolved oxygen and other ions, then the metal coil may undergo a chemical reaction with the water. This could result in the formation of metal ions and the release of hydrogen gas. The metal ions and other reaction products could then combine with other compounds in the water to form insoluble precipitates, which could appear as a cloudy or turbid solution.

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The molarity of the sodium hydroxide solution is 0.09111 M.

What is Molarity?

Molarity is a measure of the concentration of a solution. It is defined as the number of moles of solute dissolved in one liter of solution.

Molarity is an important concept in chemistry because it allows us to quantify the amount of solute in a solution and to make predictions about the behavior of the solution in various chemical reactions.

First, we can calculate the number of moles of potassium hydrogen phthalate using its molecular weight:

moles of KHP = mass / molecular weight

moles of KHP = 0.600 g / 204.22 g/mol

moles of KHP = 0.002938 mol

Since one mole of KHP reacts with one mole of NaOH, we know that there are also 0.002938 moles of NaOH in the titrated solution. We can calculate the molarity of the NaOH solution using the formula:

molarity = moles of solute / volume of solution (in liters)

First, we need to convert the volume of the NaOH solution from milliliters to liters:

volume of NaOH solution = 32.21 mL = 0.03221 L

Now we can calculate the molarity of the NaOH solution:

molarity = 0.002938 mol / 0.03221 L

molarity = 0.09111 M

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The molecular formula of the compound is [tex]C_6H_{12}O_6[/tex] whose molar mass is 180.16g/mol with mass percent composition: C 40.00%, H 6.72%, O 53.28%.

Given the mass percent compositions as:

the mass percent composition of carbon (C) = 40.00%

the mass percent composition of hydrogen (H) = 6.72%

the mass percent composition of oxygen (O) = 53.28%

The molar mass of the compound is  = 180.16 g/mol.

Let us assume we have 100g of compound then,

we have 40g of carbon, 6.72g of hydrogen and 53.28g of oxygen.

The atomic masses of carbon, hydrogen, and oxygen, respectively, are 12.01 g/mol, 1.01 g/mol, and 16.00 g/mol.

We need to calculate the number of moles of each element present in the compound.

Number of moles of carbon = 40.00/12.01 g/mol = 3.33 moles

Number of moles of hydrogen = 6.72/1.01 g/mol = 6.65 moles

Number of moles of oxygen = 53.28/16.00 g/mol = 3.33 moles

Total number of moles = 3.33 + 6.65 + 3.33 = 13.31 moles

Mole ratio of carbon, hydrogen and carbon = 3.33 : 6.65 : 3.33

Mole ratio of carbon, hydrogen and carbon = 1 : 2 : 1

The empirical formula is = [tex]CH_2O[/tex]

The empirical formula mass of [tex]CH_2O[/tex] is = 30.03

n = 180.18/30.03 = 6

The molecular formula is = [tex]C_6H_{12}O_6[/tex]

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Explanation:

a)Take percentages and divide by mole wt ( from periodic table) of the corresponding element

          C     14.25 / 12            = 1.1875

          O     56.93 / 15.99     = 3.56

          Mg   28.83/24.3        = 1.186        Divide by the smallest number

                        C 1.1875/1.186      = 1

                         O 3.56 / 1.186     = 3

                         Mg  1.186 / 1.186 =  1

C O3  Mg         commonly written as Mg CO3   ( magnesium carbonate)

The number of moles of CO contained in the 20.0 L tank at 93 °C and 4.52 atm is 3.01 moles (3rd option)

First, we shall list out the given parameters from the question. Details below:

We can obtain the number of mole in the tank as follow:

PV = nRT

4.52 × 20 = n × 0.0821 × 366

90.4 = n × 30.0486

Divide both sides by 30.0486

n = 90.4 / 30.0486

n = 3.01 moles

Thus, we can conclude that the number of mole of the gas is 3.01 moles (3rd option)

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Answer:

the pressure of the gas is 1.67 atm when the volume increased to 4.5 L.

Explanation:

Assuming the temperature and the amount of gas remain constant (i.e., the process is isobaric):

Using Boyle's law, we can relate the initial pressure (P1) and volume (V1) to the final pressure (P2) and volume (V2):

P1V1 = P2V2

Plugging in the given values:

P1 = 1.50 atm

V1 = 5.00 L

V2 = 4.5 L

Solving for P2:

P2 = (P1V1)/V2 = (1.50 atm x 5.00 L)/4.5 L = 1.67 atm

Answer:

Disproportionation reactions involve a molecule being both oxidized and reduced simultaneously, while comproportionation reactions involve two different species reacting to form a single product with an intermediate oxidation state.

For example, the reaction of hydrogen peroxide (H2O2) with potassium permanganate (KMnO4) is a disproportionation reaction, which can be represented as:

For example, the reaction of sodium thiosulfate (Na2S2O3) with iodine (I2) is a comproportionation reaction, which can be represented as:

Answer:

the rate constant of the reaction is approximately 0.0021 s^-1.

Explanation:

To calculate the rate constant of a first-order reaction, we can use the following equation:

ln([A]t/[A]0) = -kt

Where [A]t is the concentration of reactant at time t, [A]0 is the initial concentration of reactant, k is the rate constant, and t is time.

Given that the reaction is 45% complete after 400 s, we can assume that [A]t/[A]0 = 0.55 (since 100% - 45% = 55%). Plugging this value into the equation above, we get:

ln(0.55) = -k(400)

Solving for k, we get:

k = -ln(0.55)/400

k ≈ 0.0021 s^-1

A first-order reaction is 45% complete after 400 s. Therefore, 0.0021 s⁻¹ is the rate constant of the reaction.

The chemical kinetics rate law, which connects the molecular concentration of reacting substances to reaction rate, uses the rate constant as a proportionality factor. The letter k in an equation designates it, which is also referred to as either the resultant rate constant and reaction rate coefficient.

The link among the molecular concentration of reactants with the rate for a chemical reaction is shown by the proportionality constant k. Utilising the molecular weights of each of the reactants with the sequence of the reaction, the rate constant can be calculated experimentally. As an alternative, the Arrhenius equation can be used to compute it.

ln([A]t/[A]0) = -kt

[A]t/[A]0 = 0.55

ln(0.55) = -k(400)

k = -ln(0.55)/400

k ≈ 0.0021 s⁻¹

Therefore, 0.0021 s⁻¹ is the rate constant.

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For a 1-gram piece of magnesium, the amount of MgO produced by Mg is less than the amount produced by O2. Therefore, Mg is the limiting reactant and O2 is in excess.

For a 1000-gram piece of magnesium, the amount of MgO produced by Mg is still less than the amount produced by O2, even though there is a lot more Mg present. Therefore, Mg is still the limiting reactant and O2 is in excess.

To determine which reactant is limiting and which is in excess, we need to calculate the amount of product that each reactant can produce and compare them.

For a 1-gram piece of magnesium:

Moles of Mg = mass/Molar mass = 1 g/24.31 g/mol = 0.041 moles

Moles of O2 = volume x pressure/RT = (22.4 L at STP x 1 atm)/(0.0821 L·atm/mol·K x 273 K) = 1.0 moles

According to the balanced equation, 2 moles of Mg reacts with 1 mole of O2 to produce 2 moles of MgO

Therefore, the amount of MgO produced by 0.041 moles of Mg would be (2/2) x 0.041 moles = 0.041 moles

The amount of MgO produced by 1 mole of O2 would be (2/1) x 0.041 moles = 0.082 moles

We can see that the amount of MgO produced by Mg is less than the amount produced by O2. Therefore, Mg is the limiting reactant and O2 is in excess.

For a 1000-gram piece of magnesium:

Moles of Mg = mass/Molar mass = 1000 g/24.31 g/mol = 41.1 moles

Moles of O2 = volume x pressure/RT = (22.4 L at STP x 1 atm)/(0.0821 L·atm/mol·K x 273 K) = 1.0 moles

According to the balanced equation, 2 moles of Mg reacts with 1 mole of O2 to produce 2 moles of MgO

Therefore, the amount of MgO produced by 41.1 moles of Mg would be (2/2) x 41.1 moles = 41.1 moles

The amount of MgO produced by 1 mole of O2 would be (2/1) x 41.1 moles = 82.2 moles

We can see that the amount of MgO produced by Mg is still less than the amount produced by O2, even though there is a lot more Mg present. Therefore, Mg is still the limiting reactant and O2 is in excess.

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The percentage of iron in ferric oxide is 70%.

Molecular formula of ferric oxide is [tex]Fe_{2} O_{3}[/tex].

First, we will calculate the total mass of ferric oxide.

Molecular weight of oxygen = 16

Molecular weight of iron = 56

Therefore, total mass of oxygen=3 × 16 =48 g

and total mass of iron=2 × 56 =112 g

Percentage of metal in the chemical = total mass of the metal/ total mass of the compound× 100

Now, total mass of ferric oxide = 48+ 112 =160 g

Percentage of iron in the chemical = total mass of the iron/ total mass of ferric oxide × 100= 112160 × 100=70 %

Therefore, the percentage of iron in ferric oxide is 70%.

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Based on public policy, the most recent scientific findings, and efficient management, we give leadership on matters relating to food, agriculture, energy wealth, rural development, nutrition, & related topics.

A few examples of how biotechnology is influencing medicine are synthetic growth hormone and insulin as well as diagnostic procedures to find various ailments. The improvement of industrial procedures, environmental remediation, and agricultural production have all benefited from the use of biotechnology.

The demand for biotechnology is growing in industries including pharmaceutical, animal husbandry, agricultural, healthcare, medicine, genetic engineering, etc. In addition, biotechnologists are well compensated for their work. Thus, it is undoubtedly a smart professional choice.

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Answer:

Great question! Here are four body systems that are used when taking a test and how each helps: 1. Nervous system: The nervous system is responsible for processing information and responding to stimuli. It plays a crucial role in test-taking by allowing students to process and understand the questions being asked, recall the relevant information, and formulate responses. 2. Cardiovascular system: The cardiovascular system circulates blood throughout the body, providing oxygen and nutrients to the brain and other organs. During a test, the cardiovascular system helps to maintain focus and mental clarity by providing the brain with the energy it needs to function optimally. 3. Respiratory system: The respiratory system is responsible for taking in oxygen and expelling carbon dioxide. Proper breathing is essential during test-taking because it helps to reduce stress and anxiety, and provides oxygen to the brain, which is necessary for clear thinking. 4. Muscular system

Four key body systems that are used when taking a test are Nervous System, Circulatory System, Respiratory System, Musculoskeletal System

Nervous System: The nervous system is crucial for cognitive processes, including memory, attention, and problem-solving.

Circulatory System: The circulatory system, consisting of the heart, blood vessels, and blood, plays a vital role in delivering oxygen and nutrients to the brain.

Respiratory System: The respiratory system is responsible for supplying oxygen to the body and eliminating carbon dioxide.

Musculoskeletal System: The musculoskeletal system, consisting of bones, muscles, and joints, supports posture and physical stability during the test.

Hence, four body systems are explained above.

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Answer:

Explanation:

need points :>

Answer:

the molarity of the HCl is 1.17 M.

Explanation:

The balanced chemical equation for the reaction between HCl and NaOH is:

HCl + NaOH -> NaCl + H2O

From the equation, we can see that one mole of HCl reacts with one mole of NaOH to produce one mole of NaCl and one mole of water.

First, let's calculate the number of moles of NaOH used:

moles of NaOH = Molarity x Volume in liters

moles of NaOH = 0.650 M x 0.0900 L

moles of NaOH = 0.0585 mol

Since the reaction between HCl and NaOH is a 1:1 stoichiometry, the number of moles of HCl is also equal to 0.0585 mol.

Now, we can use the number of moles of HCl and the volume of HCl to calculate the molarity:

Molarity of HCl = moles of HCl / Volume in liters

Molarity of HCl = 0.0585 mol / 0.0500 L

Molarity of HCl = 1.17 M

Therefore, the molarity of the HCl is 1.17 M.

The amount of potassium permanganate (KMnO4) in the volumetric pipette and the 100 ml solution is the same.

When a volumetric pipette is used to take 10 ml of the stock solution, it is designed to deliver an accurate volume of liquid, ensuring that the amount of solute (KMnO4) is accurately transferred to the flask. By adding water to the volumetric flask to make a more dilute solution, the total amount of solute (KMnO4) remains the same, but it is now distributed throughout the larger volume of the flask.

Therefore, there is no more or less KMnO4 in the volumetric pipette or the 100 ml solution. Both contain the same amount of KMnO4, which was accurately transferred using the volumetric pipette. It is important to note that accuracy in transferring the correct volume is critical in ensuring that the concentration of the diluted solution is correct.

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The balanced equation is:

2[tex]Fe^{3+}[/tex]+ 4[tex]H^{+}[/tex] + 2[tex]No_{2} ^{-}[/tex] → 2[tex]Fe^{2+}[/tex] + 2H2O + 2[tex]No_{3} ^{-}[/tex]

What is balanced equation?

To balance this redox reaction, we first need to identify which elements are being oxidized and reduced. In this case, the iron (Fe) is being reduced from a +3 oxidation state to a +2 oxidation state, while the nitrogen (N) in the nitrite ion (NO2-) is being oxidized from a +3 oxidation state to a +5 oxidation state in the nitrate ion (NO3-).

To balance the equation, we can follow these steps:

Write out the unbalanced equation:

[tex]Fe^{3+}[/tex] + [tex]No_{2} ^{-}[/tex] + H₂O → [tex]Fe^{2+}[/tex] +[tex]H^{+}[/tex] + [tex]No_{3} ^{-}[/tex]

Separate the equation into two half-reactions, one for the oxidation and one for the reduction:

Oxidation: [tex]No_{2} ^{-}[/tex] → [tex]No_{3} ^{-}[/tex]

Reduction: [tex]Fe^{3+}[/tex] → [tex]Fe^{2+}[/tex]

Balance the elements in each half-reaction by adding the appropriate number of electrons (e-):

Oxidation: 4[tex]H^{+}[/tex] + [tex]No_{2} ^{-}[/tex] + e- → [tex]No_{3} ^{-}[/tex] + 2H2O

Reduction: Fe³+ [tex]e^{-}[/tex] → [tex]Fe^{2+}[/tex]

Balance the number of electrons transferred in the two half-reactions by multiplying one or both of the half-reactions by a suitable coefficient:

Oxidation: 4[tex]H^{+}[/tex] + [tex]No_{2} ^{-}[/tex] + 2[tex]e^{-}[/tex] → [tex]No_{3} ^{-}[/tex] + 2H2O

Reduction: 2[tex]Fe^{3+}[/tex] + 2[tex]e^{-}[/tex] → 2[tex]Fe^{2+}[/tex]

Add the two half-reactions together and cancel out any common species on both sides of the equation:

2[tex]Fe^{3+}[/tex]+ 4[tex]H^{+}[/tex] + 2[tex]No_{2} ^{-}[/tex] → 2[tex]Fe^{2+}[/tex] + 2H2O + 2[tex]No_{3} ^{-}[/tex]

The balanced equation is:

2[tex]Fe^{3+}[/tex]+ 4[tex]H^{+}[/tex] + 2[tex]No_{2} ^{-}[/tex] → 2[tex]Fe^{2+}[/tex] + 2H2O + 2[tex]No_{3} ^{-}[/tex]

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The percentage yield of the reaction is 99.5%.

Percentage yield is the ratio of the actual yield of a reaction to the theoretical yield, expressed as a percentage. It is a measure of the efficiency of a reaction and indicates how much of the desired product was obtained relative to the amount that could have been produced under ideal conditions.

The yield of a chemical reaction can be affected by a variety of factors, including the purity and amount of the reactants, the conditions under which the reaction occurs (e.g. temperature, pressure, and reaction time), and the efficiency of the reaction process (e.g. whether the product is recovered efficiently).

Other factors that can affect yield include the presence of impurities or side reactions, the stability of the reactants and products, and the skill and experience of the person carrying out the reaction.

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Answer:

2) 110 g P2O3

Explanation:

If the green box is in the denominator of a fraction and represents the molar mass of P2O3, then the correct answer choice would be 2) 110 g P2O3. Here’s how you can use this value to solve the problem:

The balanced chemical equation for the reaction between P2O3 and H2O to produce H3PO3 is: P2O3 + 3H2O → 2H3PO3.

From this equation, we can see that 1 mole of P2O3 reacts with 3 moles of H2O to produce 2 moles of H3PO3. So the number of moles of H3PO3 produced is twice the number of moles of P2O3 that reacted.

The molar mass of P2O3 is approximately 110 g/mol. So 93.2 g of P2O3 is equivalent to (93.2 g) / (110 g/mol) = 0.848 mol of P2O3.

Since the number of moles of H3PO3 produced is twice the number of moles of P2O3 that reacted, the number of moles of H3PO3 produced is 0.848 mol × 2 = 1.696 mol.

The molar mass of H3PO3 is (3 × 1.01 g/mol) + (1 × 30.97 g/mol) + (3 × 16.00 g/mol) = 81.99 g/mol. So 1.696 mol of H3PO3 is equivalent to (1.696 mol) × (81.99 g/mol) = 139 g of H3PO3.

So the complete reaction of 93.2 g P2O3 would produce approximately 139 g of H3PO3.

Layer 1 because it is closest to the surface

The final balanced chemical equation is:

C₉H₂₀(l) + 14O₂(g) → 9CO₂(g) + 10H₂O(l)

A balanced chemical equation is a representation of a chemical reaction using chemical formulas and coefficients to show the reactants and products involved in the reaction.

To balance a chemical equation, coefficients are placed in front of the chemical formulas to ensure that the number of atoms of each element is equal on both sides of the equation. This results in a balanced equation that accurately represents the reactants and products involved in the reaction, and their relative amounts.

To balance the chemical equation, we need to make sure that the number of atoms of each element is the same on both sides of the equation.

Let's start by counting the number of atoms of each element in the reactants and products:

Reactants:

C₉H₂₀(l) → 9 carbon atoms (C), 20 hydrogen atoms (H)

O₂(g) → 2 oxygen atoms (O) per molecule, so 14 O₂ molecules give 28 oxygen atoms (O)

Products:

9CO₂(g) → 9 carbon atoms (C), 18 oxygen atoms (O)

10H₂O(l) → 20 hydrogen atoms (H), 10 oxygen atoms (O)

Now, we can see that the number of carbon and hydrogen atoms are already balanced, but we need to balance the oxygen atoms.

To do so, we can see that 14 O₂ molecules give us 28 oxygen atoms, which means we need 28/2 = 14 molecules of CO₂ and 14 molecules of H₂O to balance the equation.

The final balanced equation is:

C₉H₂₀(l) + 14O₂(g) → 9CO₂(g) + 10H₂O(l)

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In both fusion and fission, stability decreases as a result of the reaction. In fusion, two smaller nuclei combine to form a larger nucleus, releasing energy in the process.

The resulting nucleus may be unstable and undergo radioactive decay, which can further release energy. In fission, a larger nucleus is split into smaller nuclei, also releasing energy. The resulting nuclei may also be unstable and undergo radioactive decay. In both cases, the process of splitting or combining nuclei releases energy, but it also reduces the overall stability of the resulting nuclei.

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Fe²⁺ is the reducing agent since in the given redox reaction it loses electrons which are transferred to another species.

A reducing agent, also known as a reductant, is a substance that causes a reduction in another substance by donating electrons or by removing oxygen from the substance being reduced. In other words, it is a substance that facilitates a chemical reaction by undergoing oxidation itself.

A reducing agent is typically an electron donor and is oxidized during the reaction. Examples of reducing agents include metals like zinc, hydrogen gas, and organic compounds like alcohols and sugars.

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The buffer capacity for OH- is equal to the concentration of OH- added, which is [tex]1.87 × 10^-9[/tex] M.

The buffer capacity for OH- is given by the Henderson-Hasselbalch equation:

pH = pKa + log([A-]/[HA])

where pH is the desired pH change, pKa is the dissociation constant of the acid, [A-] is the concentration of the conjugate base, and [HA] is the concentration of the acid.

Rearranging the equation, we get:

[A-]/[HA] = [tex]10^(pH - pKa)[/tex]

In this case, CH3COOH is the acid, and NaCH3COO is its conjugate base. The dissociation constant of acetic acid (CH₃COOH) is 4.76. We can calculate the concentrations of CH₃COOH and NaCH₃COO as follows:

[CH₃COOH] = 1.0 M

[NaCH₃COO] = 0.575 M

To calculate the buffer capacity for OH-, we first need to find the pH of the buffer before adding OH-. We can use the Henderson-Hasselbalch equation to do this:

pH = pKa + log([A-]/[HA])

pH = 4.76 + log(0.575/1.0)

pH = 4.19

Now, if we add OH- to the buffer, it will react with CH₃COOH to form CH₃COO-, according to the following balanced equation:

CH₃COOH + OH- → CH₃COO- + H₂O

The concentration of OH- added to the buffer can be calculated using the pH change:

pH = 4.19 + 4.52 = 8.71

[OH-] = 10^-(pH) = 1.87 × [tex]10^-9[/tex]M

The change in concentration of CH3COOH and CH3COO- due to the addition of OH- can be calculated using stoichiometry:

Δ[CH₃COOH] = -[OH-]

Δ[CH₃COO-] = [OH-]

Therefore, the new concentrations of CH₃COOH and CH₃COO- after adding OH- are:

[CH₃COOH] = 1.0 - [OH-] = 1.0 - 1.87 ×[tex]10^-9[/tex] = 1.0 M

[CH₃COO-] = [NaCH₃COO] + [OH-] = 0.575 + 1.87 × [tex]10^-9[/tex] = 0.575 M

Using the Henderson-Hasselbalch equation, we can calculate the new pH of the buffer:

pH = pKa + log([A-]/[HA])

pH = 4.76 + log(0.575/1.0)

pH = 4.19

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The probability that two heterozygous individuals will have a child together with the short earlobes phenotype is 15%.

The likelihood of the genotype and phenotype of the progeny can be calculated using a Punnett square. Let's refer to the long earlobe gene as "L" and the short earlobe allele as "l."

The probability of each genotype is:

LL = 1/4

Ll = 1/2

ll = 1/4

Now we need to take into account the 60% penetrance of the short earlobes genotype. This means that even if an individual has the genotype for short earlobes (ll), they may not actually exhibit the phenotype.

So the probability of having the short earlobes phenotype is:

P(short earlobes phenotype) = P(ll) x 0.6

P(ll) = 1/4

Substituting in:

P(short earlobes phenotype) = (1/4) x 0.6

P(short earlobes phenotype) = 0.15 or 15%

The probability that two heterozygous individuals will have a child together with the short earlobes phenotype is 15%.

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There are approximately [tex]1.2*10^17[/tex] molecules of food dye in the last solution.

Assuming that one drop of 100% solution is approximately 0.1 mL, then 10 drops of the 100% solution would be equivalent to 1 mL. If this 1 mL of the 100% solution was diluted to a final volume of 50 mL, then the dilution factor is 50.

Using the given approximation of 1 gram of food dye having approximately [tex]1.2*10^22[/tex] molecules, we can calculate the number of molecules in the original 1 mL of the 100% solution to be:

1 g * ([tex]1.210^22[/tex]molecules/g) = [tex]1.210^22[/tex]molecules

For the first dilution, the number of molecules would be 1/10th of this value, or:

(1/10) * [tex]1.210^221.210^22[/tex] = [tex]1.210^21[/tex]molecule

For the second dilution, the number of molecules would be 1/10th of this value, or:

[tex](1/10) * 1.210^21 = 1.210^20[/tex] molecules

If this process was repeated for a total of 5 dilutions, the number of molecules in the final solution would be:

[tex](1/10)^5 * 1.210^22 = 1.210^17[/tex]molecules

Therefore, there are approximately [tex]1.2*10^17[/tex] molecules of food dye in the last solution.

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Answer:

the sodium hydroxide solution was 0.4 M.

Explanation:

To solve this problem, we can use the dilution formula:

M1V1 = M2V2

where M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume.

We are given that 45.0 mL of a sodium hydroxide solution was diluted and the resulting volume is 180 mL with a concentration of 0.100 M. Let's use M1 for the initial concentration, V1 for the initial volume, M2 for the final concentration, and V2 for the final volume.

M2 = 0.100 M

V1 = 45.0 mL

V2 = 180 mL

We can rearrange the dilution formula to solve for M1:

M1 = (M2V2) / V1

Substituting the given values, we get:

M1 = (0.100 M x 180 mL) / 45.0 mL

M1 = 0.400 M

Therefore, the initial molarity of the sodium hydroxide solution was 0.4 M.

The molarity of the sodium hydroxide solution is 0.0911 M.

we need to calculate the number of moles of potassium hydrogen phthalate:

moles of KHP = mass / molar mass = 0.600 g / 204.22 g/mol = 0.00294 mol

Since one mole of KHP reacts with one mole of NaOH, we know that there are 0.00294 moles of NaOH used in the titration. We can use this information to calculate the molarity of the NaOH solution:

molarity of NaOH = moles of NaOH / volume of NaOH used in liters

We need to convert the volume of NaOH from milliliters to liters:

volume of NaOH = 32.21 mL = 0.03221 L

Now we can calculate the molarity of NaOH:

molarity of NaOH = 0.00294 mol / 0.03221 L = 0.0911 M

The molarity of the sodium hydroxide solution is 0.0911 M.

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Answer:

Ethane(C2H6) reacts with oxygen gas to produce carbon dioxide and water.