Answer:
Exponential decay since the base (0.765) of the exponential is greater than 0 but less than 1.
What is the value of x?
sin49°=cosx
BC is the diameter of the semicircle. The area of rectangle ABCD is 20 and the length of line AB is 5.What is the area of the semicircle?
Answer:
2[tex]\pi[/tex] [tex]units^{2}[/tex]
Step-by-step explanation:
BC is equal to 4 because 5*4=20.
The radius is 2. The equation for the area of a circle is [tex]\pi r^2[/tex].
Therefore, if we plug in 2 we will get [tex]4\pi[/tex].
But then we divide by 2 to get 2[tex]\pi[/tex] [tex]units^{2}[/tex] as our answer.
Hope this helped! :)
y to the -3 power
pls help!!!!!!!!!
Answer:
any number goes down 3 places
Step-by-step explanation:
EX:10 to the power of -3 = 0.001
Lisette wrote the following algebraic expression to represent “4 times as large as the product of w and 11.”
The translation of the sentence "4 times as large as the product of w and 11" to an expression is 44w
How to translate the algebraic sentence to an expressionFrom the question, we have the following parameters that can be used in our computation:
“4 times as large as the product of w and 11.”
The number is represented with w
So, the statement remains unchanged as follows
“4 times as large as the product of w and 11.”
4 times as large means 4 *
So, we have the following representation
4 times as large as the product of w and 11 ⇒ 4 * the product of w and 11.
the product of means that we multiply
4 times as large as the product of w and 11 ⇒ 4 * w * 11
Evaluate the products
This gives
4 times as large as the product of w and 11 ⇒ 44w
Hence, the expression is 44w
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If m = 2, n = 3 and p = 0; then what is the value of 4mp + 3n
Answer: The answer is 9.
Answer:
9
Step-by-step explanation:
4mp + 3n
Given:
m = 2
n = 3
p = 0
Work:
4mp + 3n
4(2)(0) + 3(3)
0 + 9
9
A pizza shop sold 18 medium pizzas. The number of large pizzas sold was 3 times as many as the number of medium pizzas sold. How many pizzas did the pizza shop sell altogether?
Answer:
18 × 3 = 54
18 + 54 = 72
Therefore, the answer is 72.
Random samples of students at four-year colleges were interviewed several times since . Of the students who reported , the percentage who reported bingeing at least three times within the past two weeks was % of students in and of students in a. Estimate the difference between the proportions in and , and interpret. b. Find the standard error for this difference. Interpret it. c. Define the two relevant population parameters to compare in the context of this exercise. d. Construct and interpret a % confidence interval to estimate the true difference. e. State the assumptions for the confidence interval in part d to be valid.
Answer:
Step-by-step explanation:
Of The Students Who Repo Drinking Alcohol, The Percentage Who Reported Random samples of students at 112 four-year colleges were interviewed who reported bingeing at least three times within the past two weeks was 42.5% of Estimate the difference between the proportions in 2007 and 1998, and interpret.
Factor the expression y^2+8x+12
Answer: y^2+8x+12
Step-by-step explanation:
Can someone help me with my last question for my hw plz
answer:
-4
explanation:
when reflected the a will be at -2 in the third quadrant, when moved 2 units to the left you get the y coordinate of -4
hope this helped!
Please help I was sick and missed out on class thank you.
Answer: slope=-5 and y-intercept=1
Step-by-step explanation:
The equation given is in slope-intercept form. Slope-intercept for is y=mx+b, where m is slope and b is y-intercept.
This gives m=-5 and b=1.
Solve this inequality for x.
Answer:
A. x ≥ 21[tex]\frac{2}{3}[/tex]
Step-by-step explanation:
81 - 1[tex]\frac{1}{5}[/tex] x ≤ 55
-1[tex]\frac{1}{5}[/tex] x ≤ 55-81
-[tex]\frac{6}{5 }[/tex] x ≤ -26
x ≥ -26(-[tex]\frac{5}{6}[/tex]) **flip the inequality when you divide by a negative number
x ≥ 21[tex]\frac{2}{3}[/tex]
Hydrocodone bitartrate is used as a cough suppressant. After the drug is fully absorbed, the quantity of drug in the body decreases at a rate proportional to the amount left in the body, with constant of proportionality k. Suppose that the half-life of hydrocodone bitartrate in the body is 3.9 hours, and that the oral dose taken is 9 mg.
a) Write a differential equation for the quantity Q of hydrocodone bitartrate in the body at time t, in hours, since the drug was fully absorbed.
b) Solve your differential equation, assuming that at the patient has just absorbed the full 9 mg dose of the drug.
c) Use the half-life to find the constant of proportionality k.
d) How much of the 9 mg dose is still in the body after 12 hours?
Answer:
a. dQ/dt = -kQ
b. [tex]Q = 9e^{-kt}[/tex]
c. k = 0.178
d. Q = 1.063 mg
Step-by-step explanation:
a) Write a differential equation for the quantity Q of hydrocodone bitartrate in the body at time t, in hours, since the drug was fully absorbed.
Let Q be the quantity of drug left in the body.
Since the rate of decrease of the quantity of drug -dQ/dt is directly proportional to the quantity of drug left, Q then
-dQ/dt ∝ Q
-dQ/dt = kQ
dQ/dt = -kQ
This is the required differential equation.
b) Solve your differential equation, assuming that at the patient has just absorbed the full 9 mg dose of the drug.
with t = 0, Q(0) = 9 mg
dQ/dt = -kQ
separating the variables, we have
dQ/Q = -kdt
Integrating we have
∫dQ/Q = ∫-kdt
㏑Q = -kt + c
[tex]Q = e^{-kt + c}\\Q = e^{-kt}e^{c}\\Q = Ae^{-kt} (A = e^{c})[/tex]
when t = 0, Q = 9
[tex]Q = Ae^{-kt} \\9 = Ae^{-k0}\\9 = Ae^{0}\\9 = A\\A = 9[/tex]
So, [tex]Q = 9e^{-kt}[/tex]
c) Use the half-life to find the constant of proportionality k.
At half-life, Q = 9/2 = 4.5 mg and t = 3.9 hours
So,
[tex]Q = 9e^{-kt}\\4.5 = 9e^{-kX3.9}\\\frac{4.5}{9} = e^{-kX3.9}\\\frac{1}{2} = e^{-3.9k}\\[/tex]
taking natural logarithm of both sides, we have
[tex]ln\frac{1}{2} = ln(e^{-3.9k})\\\\-ln2 = -3.9k\\k = -ln2/-3,9 \\k = -0.693/-3.9\\k = 0.178[/tex]
d) How much of the 9 mg dose is still in the body after 12 hours?
Since k = 0.178,
[tex]Q = 9e^{-0.178t}[/tex]
when t = 12 hours,
[tex]Q = 9e^{-0.178t}\\Q = 9e^{-0.178X12}\\Q = 9e^{-2.136}\\Q = 9 X 0.1181\\Q = 1.063 mg[/tex]
PLEASE someone help
7????
Step-by-step explanation:
what is the trigonometric ratio for cos n
Answer: 12/13, i think
Step-by-step explanation:
By which number 4704 must be divided so as to obtain a perfect square
Answer:
6 the last one
Step-by-step explanation:
4704/6=784
784 squared is 28
making it a perfect square unlike the rest which have excess numbers after the decimal
Answer:
6
Step-by-step explanation:
WHEN YOU DIVIDE 4704 BY 6 YOU GET 784
IN ORDER TO GE THE PERFECT SQUARE YOU HAVE TO FIND THE LCM O 4704
brainliest
eeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee
Ignore the blue dots they are wrong
Answer:
1. true
2. false
3. false
4. true
Restrictions must be indicated for rational functions involving a denominator because__________
is not defined
Answer:
rational expressions
hope I helped! :)
Evaluate -3x³-4x for x = -1.
A)-1
B)7
C)1
Answer:
B) 7
Step-by-step explanation:
-3x³-4x =
-3(-1)³-4(-1) =
-3(-1)+4=
3+4 =7
-3x-6+(-1)
i will give brainliest !
Answer:
-3x-7
Step-by-step explanation:
Let's simplify step-by-step.
−3x−6−1
=−3x+−6+−1
Combine Like Terms:
=−3x+−6+−1
=(−3x)+(−6+−1)
=−3x+−7
Answer:
=−3x−7
If f(x)=2x^3−x^2−16x+15 and f(−3)=0, list all of the zeros from least to greatest
x=
x=
x=
The roots from smallest to greatest are -3, 1, and 5/2 or (2 1/2).
Help please look at picture no links!!
Answer:
66
Step-by-step explanation:
[tex]1)\ \frac{28.9}{3.14} = 9.2[/tex]
[tex]2)\ \frac{9.2}{2} = 4.6[/tex]
[tex]3)\ 4.6^2 * 3.14 = 21.16 * 3.14 = 66.4[/tex]
factorise y^6 - 64 as possible
Answer:
Step-by-step explanation:
Observe that [tex]y^6-64=y^6-2^6.[/tex]
And you factor out using this expression:
[tex](a^6-b^6)=(a-b)(a^5+a^4b+a^3b^2+a^2b^3+ab^4+b^5)[/tex]
Take a=y and b=2.
Answer:
(y - 2)(y + 2)([tex]y^{4}[/tex] + 4y + 16)
Step-by-step explanation:
[tex]y^{6}[/tex] - 64 ← is a difference of cubes and factors in general as
a³ - b³ = (a - b)(a² + ab + b²) , then
[tex]y^{6}[/tex] - 64
= (y² )³ - 4³
= (y² - 4)([tex]y^{4}[/tex] + 4y + 16) ← note y² - 4 is a difference of squares
= (y - 2)(y + 2)([tex]y^{4}[/tex] + 4y + 16)
Does anyone know how to solve this?
Answer:
The right answer is C ( π/2)
To find the next number in the sequence: 7, 10, 13, 16, ____ you would need to do which of the following?
Answer:
19. Add
Step-by-step explanation:
10 - 7 =
13 - 10 =
16 - 13 =
16 + 3 =
Use the graph of the function,
f(x)=x-1/x^2+5x+6
to identify the function's
vertical asymptotes.
a. x=-1, x= 6
b. x=1, x=-6
c. x=-2, x=-3
d. X= 2, x= 3
Answer:
c. x = -2 or x = -3
Step-by-step explanation:
The vertical asymptotes occur where the denominator = 0. That happens when the f(x) is undefined. So,
x^2 + 5x + 6 = 0
(x + 2)(x + 3) = 0
x = -2 or x = -3
Which expression is equivalent to -51 - (-60)−51−(−60)minus, 51, minus, left parenthesis, minus, 60, right parenthesis?
Choose 1 answer:
Choose 1 answer:
(Choice A)
A
-60+(-51)−60+(−51)minus, 60, plus, left parenthesis, minus, 51, right parenthesis
(Choice B)
B
60+5160+5160, plus, 51
(Choice C)
C
51-6051−6051, minus, 60
(Choice D)
D
-51+60−51+60minus, 51, plus, 60
Answer:
it's B.
Step-by-step explanation:
Answer:
its c
Step-by-step explanation:
Equations of Exponential Functions
Given the following equations of an exponential function
R = 10.5(0.535)t
determine the decay rate.
a. 0.535%
b. 10.5%
c. 50%
d. 46.5%
Please select the best answer from the choices provided
Answer:
D. 46.5%
Step-by-step explanation:
I calculated it logically
Explain the cyclin-dependent regulation
cell cycle
Cyclins drive the events of the cell cycle by partnering with a family of enzymes called the cyclin-dependent kinases (Cdks). A lone Cdk is inactive, but the binding of a cyclin activates it, making it a functional enzyme and allowing it to modify target proteins.
hope this helps!
Answer:
Cyclins drive the events of the cell cycle by partnering with a family of enzymes called the cyclin-dependent kinases (Cdks). A lone Cdk is inactive, but the binding of a cyclin activates it, making it a functional enzyme and allowing it to modify target proteins.
Step-by-step explanation:
I need to know the first and last one
The lines FE and GH are parallel to each orther.
What is congruent of the triangle?
The shapes maintain their equality regardless of how they are turned, flipped, or rotated before being cut out and stacked. We'll see that they'll be placed entirely on top of one another and will superimpose one another. Due to their identical radius and ability to be positioned directly on top of one another, the following circles are considered to be congruent.
Any two figures can be perfectly positioned over one another to demonstrate their congruence. The relationship between two figures that are said to be congruent is described using the word "congruence."
Given that
ΔPEI = ΔGHI
here ∠pie = ∠gih
PI =HI
GI=EI
So both triangles are congruent
So the FE║GH.
Hence the lines FE and GH are parallel to each orther.
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