Determine the zeros for x2 + 7x − 20 = 6x.

Answer:

= 176,945,596

Step-by-step explanation:

100,000,000 + 70,000,000 + 6,000,000 + 900,000 + 40,000 + 5,000 + 500 + 90 + 6 = 176,945,596

= 176,945,596

(Hope this helps can I pls have brainlist (crown)☺️)

Answer:

i don't knoe if we can do it without the graph

Answer:

7868

Step-by-step explanation:

Answer:

I believe the answer is D

Step-by-step explanation:

ang mga gan yan Hindi ko alam Kase may mudule din ako bb

He spent on transport = 20%

spent on breakfast = 60/-

spent on lunch = 15%

remaining amount = 340

rs he spent on transport = 20/100 × 340 =68

rs he spent on lunch = 15/100 × 340 = 51

Therefore, total of his pocket money = 68 + 51 + 60 + 340

= ₹519

Answer:

on a 6-sided dice, 1/6

Step-by-step explanation:

Answer:

6x^3yz^4

Step-by-step explanation:

(2x3)x^2xyz^4

6x^2+1yz^4

6x^3yz^4

Answer:

-4/3x-7=1

Step-by-step explanation:

just combine like terms

Answer:

9600400000000000 is in standard form

Answer:

(13 + or - (sign) square root(37)) / 6

Step-by-step explanation:

First search up the quadratic formula which is

x = (- b + or - square root(b^2 - 4ac)) / 2a

and to find a, b, and c you need this formula

ax^2 + bx + c = 0 (btw this is the safest solution to finding your answer with a number in-front of a quadratic equation.)

Math:

a = 3, b = -13, c = 11

b = -13, because of the x on the other end of the equation as the equation above "ax^2 + bx + c = 0" you need the zero to proceed to this next step.

Side Note: You only take the number and not the variable, variables are x, y, w, z, or etc.

(- (- 13) + or - square root((-13)^2 - 4(3)(11) ) ) / 2 * 3

13 + or - square root(37) / 6

Answer:

e

Step-by-step explanation:

Answer:

Step-by-step explanation:

The motorist drove at a distance of 90km at a constant speed for the first 40km, and then 20 km/hr faster for the rest of the journey.

The whole journey took him 1hr.

Let S denotes the average speed (in km/hr) for the first 40 km.

Hence we get the following relation,

40/S + (90 - 40)/(S + 20) = 1

or 50/(S + 20) = 1 - 40/S = (S - 40)/S

or (S + 20)(S - 40) = 50S or S^2 - 70S - 800 = 0 or (S - 80)(S + 10) = 0

or S = 80 (km/hr) [Ans]

[S cannot be negative value]

Answer:

y=9, x=7

Step-by-step explanation:

2x-y=5 --> equation 1

2x-5y=-31 --> equation 2

change signs of equation 1

-2x+y=-5

solving method

-2x+y=-5                   (cut -2x and 2x because -2x+2x =0)

2x-5y=-31                       (likewise +y-5y and -5-31)

-4y= -36            (since -4 is multiplying on right side it will divide)

y= -36/-4             (cut negative with negative and simplify equation)

y= 9                  

put value of y in equation 1

2x-y=5

2x-9=5

2x= 14

x=14/2

x=7

Answer:

d

took the test

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

khan academy

Hi there!

a. A stratified sample can be used by dividing the tenants into two groups: those who have children and those who do not have children. Then, a Sample Random Sample FROM EACH stratum can be conducted for a total of 16 tenants surveyed.

b. Using a cluster sample in this situation could introduce undercoverage or selection bias if there is a distinction between those on some floors and those on others. For example, tenants on lower floors might be more opposed to a playground  (ex: noise, crowd, etc.) in comparison to those on higher floors.

[tex]\frac { 2 + 3 i } { 3 + 4 i }[/tex]

[tex]=\frac{\left(2+3i\right)\left(3-4i\right)}{\left(3+4i\right)\left(3-4i\right)} [/tex]

[tex]=\frac{\left(2+3i\right)\left(3-4i\right)}{3^{2}-4^{2}i^{2}} [/tex]

[tex]=\frac{\left(2+3i\right)\left(3-4i\right)}{25} [/tex]

[tex]=\frac{2\times 3+2\times \left(-4i\right)+3i\times 3+3\left(-4\right)i^{2}}{25}[/tex]

[tex]=\frac{2\times 3+2\times \left(-4i\right)+3i\times 3+3\left(-4\right)\left(-1\right)}{25} [/tex]

[tex]=\frac{6-8i+9i+12}{25} [/tex]

[tex]=\frac{6+12+\left(-8+9\right)i}{25} [/tex]

[tex]=\frac{18+i}{25} [/tex]

[tex]=\boxed{\frac{18}{25}+\frac{1}{25}i=0.72+0.04i}[/tex]

_______

Hope it helps :) ⚜

The rate of change is in Y over the change in X.

Y is the dollar amount at 4 is 78 at 1 it is 54, the change is 78 - 54 = 24.

X is the time the change from 4 to 1 is 3 ( 4 - 1 = 3)

The rate of change is 24 / 3 = 8.

The answer is 8 dollars per hour.

An ice cream truck sells ice cream between 2 p.m. and 10 p.m. each night in the summer. the average rate of change from the 1st hour to the 4th hour is 8.

The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.

An ice cream truck sells ice cream between 2 p.m. and 10 p.m. each night in the summer.

At the end of the night, the driver calculates his profits and makes a graph to analyze the data.

The rate of change is in Y over the change in X.

Y is the dollar amount at 4 = 78 ,

at 1 = 54

the change is 78 - 54 = 24.                                        

X is the time the change from 4 to 1 = 3

The change is ( 4 - 1 = 3)

The rate of change = 24 / 3 = 8.

Therefore, The answer is 8 dollars per hour.

Learn more about the unitary method;

https://brainly.com/question/23423168

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Answer:

a is 0.085 b is 19.6%

Step-by-step explanation:

1% = 0.01 so 8.5 = 0.085

0.20 = 20% so 0.196 = 19.6%

Now we proceed to present the graphs of the polygon and its image with the help of a graphing tool. The original polygon is highlighted in red and the image is highlighted in blue.

DIlations are defined by the follwing operation:

[tex]P'(x,y) = O(x,y) + k\cdot [P(x,y)-O(x,y)][/tex] (1)

Where:

If we know that [tex]O(x,y) = (1,1)[/tex], [tex]k = 0.5[/tex], [tex]J(x,y) = (3,1)[/tex], [tex]K(x,y) = (5, -3)[/tex], [tex]L(x,y) = (5,5)[/tex] and [tex]M(x,y) = (3,7)[/tex], then the coordinates of the new polygon are:

[tex]J'(x,y) = (1,1) + 0.5\cdot [(3,1)-(1,1)][/tex]

[tex]J'(x,y) = (1,1)+0.5\cdot (2,0)[/tex]

[tex]J'(x,y) = (1,1) +(1,0)[/tex]

[tex]J'(x,y) = (2,1)[/tex]

[tex]K'(x,y) = (1,1) + 0.5\cdot [(5,-3)-(1,1)][/tex]

[tex]K'(x,y) = (1,1) +0.5\cdot (4,-4)[/tex]

[tex]K'(x,y) = (1,1) +(2,-2)[/tex]

[tex]K'(x,y) = (3,-1)[/tex]

[tex]L'(x,y) = (1,1) + 0.5\cdot [(5,5)-(1,1)][/tex]

[tex]L'(x,y) = (1,1) + 0.5\cdot (4,4)[/tex]

[tex]L'(x,y) = (1,1) + (2,2)[/tex]

[tex]L'(x,y) = (3,3)[/tex]

[tex]M'(x,y) = (1,1) + 0.5\cdot [(3,7)-(1,1)][/tex]

[tex]M'(x,y) = (1,1) +0.5\cdot (2,6)[/tex]

[tex]M'(x,y) = (1,1) +(1,3)[/tex]

[tex]M'(x,y) = (2,4)[/tex]

Now we proceed to present the graphs of the polygon and its image with the help of a graphing tool. The original polygon is highlighted in red and the image is highlighted in blue.

We kindly invite to check this question on dilations: https://brainly.com/question/13176891

Answer:

I don't believe your wrong mate

Answer:

D.

Step-by-step explanation:

Pretend the y-axis is a wall, on the left side it is decreasing and on the right it is increasing, so A. and B. aren't correct. C. and D. are left, x<0 means on the left side of the y-axis because x (any number) is less than 0 and on the left side it is decreasing so C. isn't correct so D. is your answer because x>0 means x is greater than 0 so it's on the left side of the y-axis.

I hope this helps!

Answer:

[tex]a_{14} = 10496[/tex]

Step-by-step explanation:

A geometric sequence is of the form:

[tex]ar^0, ar^1, ar^2, ar^3, \cdot \cdot \cdot[/tex]

So the given values can be represent as:

[tex]1. \quad ar^5 = \frac{41}{256}\\2. \quad ar^{10} = -164[/tex]

So you have a system of equations with two unknows [tex]a[/tex] and [tex]r[/tex]. Then you can find one unknow in terms of the other.

[tex]a = \frac{-164}{r^{10}}[/tex]

Now replace [tex]a[/tex] in the first equation

[tex]\frac{-164}{r^{10}}r^5 = \frac{41}{256}\\\frac{-164}{r^{5}} = \frac{41}{256}\\r^5 = \frac{256 \cdot -164}{41} = -\frac{41984}{41}\\r = \sqrt[5]{-\frac{41984}{41}}\\[/tex]

You don't have to worry about the negative number inside the root, because is a odd root then you can find odd negative numbers that give me the desire result.

[tex]r = -\frac{4\sqrt[5]{41} }{\sqrt[5]{41}} \\r = -4[/tex]

For find [tex]a[/tex] only replace [tex]r[/tex] in whatever of the two equations.

[tex]-a4^5 = \frac{41}{256}\\-a1024 = \frac{41}{256}\\a = -\frac{41}{262144}[/tex]

After find [tex]a[/tex] and [tex]r[/tex] use the next formula for find the [tex]14^{th}[/tex] term.

[tex]ar^{13} = x\\-\frac{41}{262144} \cdot -4^{13} = x\\\\10496 = x[/tex]

Answer:

Step-by-step explanation:

m is only raised to the 3rd power. The 8 effects only the n

Numerator

m^3

(n^8 )^3 = n ^24

denominator

(n^9)^3 = n^27

Answer: m^3 * n^24 / n^27 = m^3 / n^(27 - 24) = (m/n )3

Hi!

Given:

[tex](\cfrac{mn^8}{n^9} )^3[/tex]

First, let's do what is inside the parenthesis. Since we're dividing, we subtract unlike exponents, and if there are any negatives, we switch them to make them positive:

[tex]8-9=-1[/tex]

Switch since it's negative:

[tex]\frac{m}{n} ^3[/tex]

Answer:

m = 2/5

Step-by-step explanation:

2x - 5y = 52

-5y = -2x + 52

y = 2/5x - 52/5

The slope of the line with equation 2x−5y=52 is 2/5.

The given equation of line is 2x−5y=52.

The slope formula is used to calculate the inclination or steepness of a line. It finds application in determining the slope of any line by finding the ratio of the change in the y-axis to the change in the x-axis.

The given equation 2x−5y=52 can be rewritten as

2x-52=5y

⇒ y = 2x/5-52/5

Now, compare y = 2x/5-52/5 with the standard form of an equation y=mx+c

So, m=2/5

Therefore, the slope of the line with equation 2x−5y=52 is 2/5.

To learn more about the slope of an equation visit:

https://brainly.com/question/13496015.

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Answer:

if you're doing the scale factor of small to big it would be 1/4, but if you're doing from big to small it would be 4

Answer:

90 degree

Step-by-step explanation:

Answer: 3 pounds

Step-by-step explanation:

brainliest me

Answer:

3

Step-by-step explanation:

14.04 divided by 4.68 is 3