Determine the MI of the beam's cross-sectional area about its centroidal axes. 12.7 mm 165 mm 165 mm 165 mm 12.7 mm 12.7 mm ​

Answer:

Gasoline is injected directly into the cylinder.

Explanation:

In a direct injection system, the air and gasoline are not pre-mixed. Rather, air comes in using the intake manifold, while the gasoline is injected directly into the cylinder.

Answer:

the answer c or e or do wha t the first guy do

The process of die forming that uses a die and a press to form parts from the given processes is called; C: Hydroforming

There are different types of die forming in sheet metal operations. Now, Hydroforming is a specialized type of die forming that uses a high pressure hydraulic fluid to press room temperature working material into a die.

Tailor Welding is a process of making welded blanks made from individual sheets of steel of different thickness, strength and even coating that are joined together by the use of laser welding.

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Based on the calculations, the average temperature of the water leaving this core is equal to 531.11 Btu/lb.

Since the core is cooled by water, which enters at the bottom at 496°F, the heat input ([tex]h_{in}[/tex]) would be equal to 483.02 Btu/lb based on the steam table.

Given the following data:

Substituting the given parameters into the formula, we have;

[tex]h_{out}= \frac{q}{w} + h_{in}\\\\h_{out}= \frac{1.635 \times 10^9}{34 \times 10^6} + 483.02\\\\h_{out}= 48.09 + 483.02\\\\h_{out}= 531.11\;Btu/lb[/tex]

First of all, we would determine the area of this core by using this formula:

Area = πd²/2

Area = 3.142 × (0.298/2)²

Area = 0.0698 in².

Mathematically, the average power density is given by:

[tex]q_{av}=\frac{q}{W} =\frac{q}{\pi A^2H \times 23142} \\\\q_{av}=\frac{485 \times 10^3}{3.142 \times 0.0698^2 \times 91.9 \times 0.01639 \times 23142} \\\\q_{av}=199.5\;kW/liter.[/tex]

In this scenario, we would assume the reactor core is bare. Thus, the heat is given by:

[tex]q(0) = \frac{2.32PE_1}{HE_R} \\\\q(0) =\frac{2.32 \times 485 \times 180}{23142 \times 200} \\\\q(0) =0.044 \;MW = 1.5 \times 10^8 \;Btu/hr^2[/tex]

For the maximum heat production rate, we have:

[tex]q_{max}=\frac{q(0)}{2HA^2} \\\\q_{max}=\frac{1.5 \times 10^8}{2 \times (\frac{75.4}{2} \times \frac{1}{12}) \times (\frac{0.298}{2} \times \frac{1}{12})} \\\\q_{max}=\frac{1.5 \times 10^8}{2 \times 3.1417 \times 0.00124} \\\\q_{max}=\frac{1.5 \times 10^5}{0.007791416}\\\\q_{max}=1.55 \times 10^8 \;Btu/hr.ft^3[/tex]

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Answer:

C++ and Python

Explanation:

C++ and Python

Answer:

  5

Explanation:

The sum of the digits of the number is ...

  (4+1+3)+(4+6+5)+(7+8+9) = 8+15+24 = 47

The sum of those digits is 4+7=11, and those digits sum to 1+1 = 2.

That is, the value of the number mod 9 (or 3) is 2.

The ones digit is odd, so the value of the number mod 2 is 1.

This combination of modulo values tells you the mod 6 result is 5.

_____

Additional comment

We can look at the (mod2, mod3) values of the numbers 0 to 5:

  0 ⇒ (0, 0)

  1 ⇒ (1, 1)

  2 ⇒ (0, 2)

  3 ⇒ (1, 0)

  4 ⇒ (0, 1)

  5 ⇒ (1, 2) . . . . the mod {2, 3} results we have for the number of interest.

This process of adding up the digits repeatedly is referred to as "casting out 9s." The result of it is the modulo 9 value of the number (with 0 mapped to 9). Checking the mod 9 result of arithmetic operations is one quick way to spot certain kinds of errors. It can also be used as part of a divisibility test for 3 or 9.

Answer:

11.5-10/10= 0.15x100 =15%

Explanation:

The moisture content of the board is 13.04% as per the given data.

Simply said, a product's moisture content is its water content. It affects a substance's weight, density, viscosity, conductivity, and other physical characteristics.

The original weight of the test sample was 11.5 oz, and the weight of the sample after oven-drying was 10 oz.

The amount of moisture lost during the oven-drying process is equal to the original weight of the sample minus the weight of the sample after drying, or:

11.5 oz - 10 oz = 1.5 oz

To calculate the moisture content, you then divide the amount of moisture lost by the original weight of the sample and multiply by 100 to express the result as a percentage:

(1.5 oz / 11.5 oz) x 100% = 13.04%

Thus, the moisture content of the board is 13.04%.

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Answer:

2/6 cause there is 2 ways to get 6, 6 × 1 and 3×2 and 6 and 3 are multiples of 3

Answer:

The p-value of the hypothsis 0.00135

Explanation:

Answer:

  83.6%

Explanation:

On its current schedule, the plant can theoretically produce ...

  (30 pc/h/machine)(10 machine)(8 h/shift)(2 shift/day)(5 day/wk)(50 wk/yr)

  = (30)(10)(8)(2)(5)(50) pc/yr = 1,200,000 pc/yr

__

On the proposed schedule, this production becomes ...

  (30 pc/mach)(10 mach)(8 h/sh)(3 sh/da)(6 da/wk)(51 wk/yr)

  = (30)(10)(8)(3)(6)(51) pc/yr = 2,203,200 pc/yr

The increase in capacity is ...

  (2,203,200/1,200,000 -1) × 100% = 83.6% . . . capacity increase

_____

Additional comment

The number of parts per shift did not change. Only the number of shifts per year changed. It went up by a factor of (3/2)(6/5)(51/50) = 1.836. Hence the 83.6% increase in capacity.

We have to assume that maintenance and repair are done as effectvely as before in the reduced down time that each machine has.

Renewable resources are those energy resources which will never end. Germany aims to be completely dependent on renewable energy resources by 2035.

Renewable resources are those energy resources which will never end. A few examples of such energy resources are Solar Energy, Wind Energy, etc.

Germany is a European country, therefore, it is a cold country and is highly dependent on the natural resources of Russia. As the war is going on between Russia and Ukraine, it is hard for countries like Germany to put sanctions on Russia because of its dependency on its resources.

Thus, Germany wants to be a self-dependent country in terms of electricity and wants to completely stop the use of non-renewable resources for the production of electricity.

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Answer:

fibrocartilage

The theoretical density of diamond given that the C-C distance and bond angle are 0.154 nm and 109.5° respectively is; 3.54 g/cm³

The first thing we will do is to get the unit cell edge length from the given C - C distance.

From the structure of diamond;

Φ = ¹/₂ * bond angle

Φ = ¹/₂ * 109.5°

Φ = 54.75°

Thus;

θ = 90° - 54.75°

θ = 35.25°

Let the height from a point to the base of the cube of the structure be x. Thus;

x = a/4 = y sin θ

where a is unit cell edge length and y is C -C length. Thus;

a = 4y sin θ

a = 4 * (0.154 * 10⁻⁹) * sin 35.25°

a = 3.56 * 10⁻⁸ cm

The unit cell volume is;

V_c = a³

Thus; V_c = (3.56 * 10⁻⁸)³

V_c = 4.51 * 10⁻²³ cm³

Now, there are 8 equivalent atoms per unit cell and as such density is calculated from;

ρ = (n * A_c)/(V_c * N_a)

A_c is atomic weight of diamond = 12.01 g/mol

N_a is avogadro's number = 6.022 * 10²² atoms/g

Thus;

ρ = (8 * 12.01)/(4.51 * 10⁻²³ * 6.022 * 10²²)

ρ = 3.54 g/cm³

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6.8÷1.5 = 4.53...

So, it's 4 pipe with some left over.

Hope this helps!

Explanation:

Kirchhoffs Voltage Law or KVL, states that “in any closed loop network, the total voltage around the loop is equal to the sum of all the voltage drops within the same loop” which is also equal to zero. In other words the algebraic sum of all voltages within the loop must be equal to zero.

Answer:

"The Diamond Sutra was printed in China in 868 AD." (paragraph 4)

Explanation:

I took the test

Answer:

busway

Explanation:

Answer:

Tech B

Explanation:

Advantages:

- allowed steel to be produced without fuel

- using the impurities of the iron to create the necessary heat

- reduced the costs of steel production

Disadvantages:

- could convert only a pig iron low in phosphorus and sulfur

- these elements could have been removed by adding a basic flux such as lime, but the basic sl*g produced would have degraded the acidic refractory lining of Bessemer's converter.

au revoir mon amour <3

Answer:

Yes it is possible. Grain size is often determined by the rate so Firstly reduce the average grain diameter of an undeformed alloy specimen form 0.040 mm to 0.10mm