Answer:
1. The balanced equation is 2KCIO3 → 2KCI + 3O2. According to the law of conservation of mass, the mass of the reactants must equal the mass of the products. Therefore, the mass of oxygen produced is:
Mass of oxygen = Mass of KCIO3 - Mass of KCI
Mass of oxygen = 500 g - 303 g
Mass of oxygen = 197 g
Therefore, 197 g of O2 are produced.
2. The balanced equation is N2 + 3H2 → 2NH3. We need to find out how much H2 is needed to react with 100 g of N2 to produce 121 g of NH3. First, we need to calculate the number of moles of N2 and NH3:
Moles of N2 = Mass of N2 / Molar mass of N2
Moles of N2 = 100 g / 28 g/mol
Moles of N2 = 3.57 mol
Moles of NH3 = Mass of NH3 / Molar mass of NH3
Moles of NH3 = 121 g / 17 g/mol
Moles of NH3 = 7.12 mol
According to the balanced equation, 1 mole of N2 reacts with 3 moles of H2 to produce 2 moles of NH3. Therefore, the number of moles of H2 needed is:
Moles of H2 = Moles of N2 x (3/1)
Moles of H2 = 3.57 mol x 3
Moles of H2 = 10.71 mol
Finally, we can calculate the mass of H2 needed:
Mass of H2 = Moles of H2 x Molar mass of H2
Mass of H2 = 10.71 mol x 2 g/mol
Mass of H2 = 21.42 g
Therefore, 21.42 g of H2 are needed.
3. The balanced equation is 4Fe + 3O2 → 2Fe2O3. We need to find out how much oxygen is needed to react with 350 g of Fe to produce 500 g of Fe2O3. First, we need to calculate the number of moles of Fe and Fe2O3:
Moles of Fe = Mass of Fe / Molar mass of Fe
Moles of Fe = 350 g / 55.85 g/mol
Moles of Fe = 6.26 mol
Moles of Fe2O3 = Mass of Fe2O3 / Molar mass of Fe2O3
Moles of Fe2O3 = 500 g / 159.69 g/mol
Moles of Fe2O3 = 3.13 mol
According to the balanced equation, 4 moles of Fe react with 3 moles of O2 to produce 2 moles of Fe2O3. Therefore, the number of moles of O2 needed is:
Moles of O2 = Moles of Fe x (3/4)
Moles of O2 = 6.26 mol x (3/4)
Moles of O2 = 4.69 mol
Finally, we can calculate the mass of O2 needed:
Mass of O2 = Moles of O2 x Molar mass of O2
Mass of O2 = 4.69 mol x 32 g/mol
Mass of O2 = 150.08 g
Therefore, 150.08 g of O2 are needed.
4. The balanced equation is CH2 + 2O2 → CO2 + 2H2O. We know that 16 g of CH2 reacts with 64 g of O2 to produce 44 g of CO2. We need to find out how much water is produced. First, we need to calculate the number of moles of CH2 and CO2:
Moles of CH2 = Mass of CH2 / Molar mass of CH2
Moles of CH2 = 16 g / 14 g/mol
Moles of CH2 = 1.14 mol
Moles of CO2 = Mass of CO2 / Molar mass of CO2
Moles of CO2 = 44 g / 44 g/mol
Moles of CO2 = 1 mol
According to the balanced equation, 1 mole of CH2 reacts with 2 moles of O2 to produce 2 moles of H2O. Therefore, the number of moles of H2O produced is:
Moles of H2O = Moles of CH2 x (2/1)
Moles of H2O = 1.14 mol x 2
Moles of H2O = 2.28 mol
Finally, we can calculate the mass of H2O produced:
Mass of H2O = Moles of H2O x Molar mass of H2O
Mass of H2O = 2.28 mol x 18 g/mol
Mass of H2O = 41.04 g
Therefore, 41.04 g of H2O are produced.
5. The balanced equation is CaCO3 → CaO + CO2. We need to find out how much CO2 is produced from the decomposition of 200 g of CaCO3 if 112 g of CaO are produced. First, we need to calculate the number of moles of CaCO3 and CaO:
Moles of CaCO3 = Mass of CaCO3 / Molar mass of CaCO3
Moles of CaCO3 = 200 g / 100.09 g/mol
Moles of CaCO3 = 1.999 mol
Moles of CaO = Mass of CaO / Molar mass of CaO
Moles of CaO = 112 g / 56.08 g/mol
Moles of CaO = 1.999 mol
According to the balanced equation, 1 mole of CaCO3 produces 1 mole of CaO and 1 mole of CO2. Therefore, the number of moles of CO2 produced is:
Moles of CO2 = Moles of CaCO3 x (1/1)
Moles of CO2 = 1.999 mol
Finally, we can calculate the mass of CO2 produced:
Mass of CO2 = Moles of CO2 x Molar mass of CO2
Mass of CO2 = 1.999 mol x 44 g/mol
Mass of CO2 = 87.96 g
Therefore, 87.96 g of CO2 are produced.
A + B = AB is an example of a ________reaction
Answer:
A + B = AB is an example of a synthesis reaction
Explanation:
The scientific notation of 45,000
A block of aluminum occupies a volume of 28.0 mL and weighs 85.7g. What is its density?
Explanation:
The density of a substance is defined as its mass per unit volume. In this problem, we are given the volume and the mass of the aluminum block, so we can calculate its density as follows:
Density = Mass / Volume
Substituting the given values, we get:
Density = 85.7 g / 28.0 mL
Simplifying this expression, we get:
Density = 3.06 g/mL
Therefore, the density of the aluminum block is 3.06 g/mL
Answer:
3.06
Explanation:
Esters, amines, and amides have many uses in medicine. Investigate one of the following drugs further: aspirin, Benadryl, or Tylenol and give its scientific name. What kind of functional groups does it contain?
Esters, amines, and amides have many uses in medicine, and so do carboxylic acids, such as aspirin. Aspirin is the drug that will be investigated further. Its scientific name is acetylsalicylic acid.
What kind of functional groups does Aspirin contain?Acetylsalicylic acid contains two functional groups: a carboxylic acid group (-COOH) and an ester group (-COO-CH₃). The carboxylic acid group is responsible for the acidic properties of aspirin and allows it to form salts with bases. The ester group is formed from the reaction between the carboxylic acid group of salicylic acid and acetic anhydride. This esterification reaction makes aspirin more soluble in organic solvents and less irritating to the stomach than salicylic acid.
Aspirin is a widely used medication that has anti-inflammatory, analgesic, and antipyretic properties. It works by inhibiting the production of prostaglandins, which are responsible for pain, inflammation, and fever. Aspirin is commonly used to treat headaches, fever, arthritis, and other inflammatory conditions. It is also used as a blood thinner to prevent heart attacks and strokes.
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An emission spectrum has a line in the blue region. How does this occur in the atom?
A. An electron ABSORBS a photon as it goes from a HIGHER TO LOWER energy level.
B. An electron EMITS a photon as it goes from a HIGHER TO LOWER energy level.
C. An electron EMITS a photon as it goes from a LOWER TO HIGHER energy level.
D. An electron ABSORBS a photon as it goes from a LOWER TO HIGHER energy level.
B. An electron EMITS a photon as it goes from a HIGHER TO LOWER energy level.
When an electron in an atom drops from a higher energy level to a lower energy level, it releases energy in the form of a photon.
What is Spectrum?
In science, the term "spectrum" is often used to describe the range of colors of visible light, known as the "visible spectrum," which includes all the colors of the rainbow. This spectrum is produced when white light is dispersed into its component colors by a prism or other means.
This energy is specific to the atom and its electron configuration, which is why each atom emits a unique set of wavelengths, creating a distinct emission spectrum.
Since the emission spectrum in the question has a line in the blue region, it means that the energy released by the electron corresponds to a specific frequency or wavelength in the blue region of the visible spectrum.
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dry ice is solid carbon dioxide. represent carbon dioxide in the following three ways, symbolic, particulate. and macroscopic
In symbol form, ice is depicted as CO2, in particle form, as molecules of CO2 packed closely together, and in macroscopical form, as a white, crystalline substance that sublimates from a solid to a gas.
How is dry ice defined as solid carbon dioxide?Because the gas when it solidifies resembles ice, ice ice is actually just carbon dioxide that has been solidified. Unlike regular ice, it instantly transforms into CO2 gas instead of melting into a liquid.
Why is dry ice a good illustration of sublimation?Solid carbon dioxide is sometimes referred to as "dry ice." That's because when something warms up and changes state, it doesn't just dissolve into a liquid. Instead, it skips the liquid step and transforms right into a gas.
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What is the ratio of ammonia if the chemical formula is
NH3
Explanation:
The chemical formula NH3 represents ammonia, a colorless gas that is widely used in various industrial and household applications. The formula indicates that one molecule of ammonia contains one nitrogen atom and three hydrogen atoms. Therefore, the ratio of nitrogen to hydrogen in ammonia is 1:3.
This means that for every one nitrogen atom in an ammonia molecule, there are three hydrogen atoms. Alternatively, we can say that the ratio of nitrogen atoms to hydrogen atoms in ammonia is 1:3.
Carbon dioxide is an example of a greenhouse gas. Levels of carbon dioxide are increasing in the atmosphere. How are increasing levels of carbon dioxide affecting the atmosphere?
Select the two correct awnsers.
1.less water is evaporating from the oceans
2. Earthquakes and volcanic eruptions are becoming more frequent
3.patterns of rain and snow are changing
4.ice caps are becoming thicker and wider at the North Pole and South Pole
5.oceans waters are becoming warmer
Global warming brought on by rising carbon dioxide concentrations in the atmosphere is changing weather patterns and ocean temperatures. Changes in precipitation patterns are being brought on by the warming of the atmosphere.
Why does carbon dioxide serve as a representative greenhouse gas?Because it is one of the gases in the atmosphere that causes the greenhouse effect, which causes the Earth to warm, carbon dioxide is known as a greenhouse gas. Long-wavelength infrared radiation (heat) from the Earth is absorbed by carbon dioxide molecules in the atmosphere, and some of it is then radiated back downward.
What impact does an increase in atmospheric carbon dioxide have?Similarly, as air temperatures rise in response to rising carbon dioxide concentrations, more water vapor escapes into the atmosphere—which then amplifies greenhouse heating
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The diagram below represents a specimen in the low-power field of view of a compound light microscope. If the slide is not moved, which view best represents the way the specimen will look when the high-power objective lens is switched into place?
Coarse and excellent adjustment The coarse adjustment knob solely be used with the lowest electricity objective lens. Once it is in focus, you will only need to use the best focus. Using the coarse center of attention with greater lenses may result in crashing the lens into the slide.
Why does the specimen have to be founded in the field of view on low strength before going to high power?You must have the object situated before you exchange objectives to increase the magnification, because the subject of view turns into smaller; if the object is off to the side, it might also disappear when you go to higher magnification.
When viewing a specimen on a compound light microscope the photograph is right aspect up but reversed True or false?The optics of a microscope's lenses alternate the orientation of the photo that the consumer sees. A specimen that is right-side up and going through proper on the microscope slide will appear upside-down and going through left when considered through a microscope, and vice versa.
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What is the hydroxide ion concentration of a solution
with a pOH of 5.0?
Select one:
a 5.0 x 10¹¹ M
b 1.0 x 105 M
c 1.0 x 10⁹ M
d 1.0 x 109 M
Answer: 1.0 X 10^-5 M
Explanation:
to change pOH to OH- it is judt 1 X 10-pOH
so it is 1 x 10^-5
The relative atomic mass of aluminium is 27 and of oxygen is 16. The aluminium ore shown below contains 5.4kg of aluminium and 4.8kg of oxygen. What is the value of y?
Answer:
To find the value of y, we need to use the concept of molar ratios and the mole concept.
First, we need to calculate the number of moles of aluminum and oxygen in the given sample of ore. We can do this by dividing the mass of each element by its respective atomic mass:
Number of moles of aluminum = 5.4 kg / 27 g/mol = 200 moles
Number of moles of oxygen = 4.8 kg / 16 g/mol = 300 moles
Next, we can determine the ratio of the number of moles of aluminum to oxygen in the sample. This ratio is:
Aluminum : Oxygen = 200 : 300
Simplifying this ratio by dividing both sides by 100, we get:
Aluminum : Oxygen = 2 : 3
According to the chemical formula of aluminum oxide (Al2O3), it contains 2 atoms of aluminum for every 3 atoms of oxygen. Therefore, the sample of ore must contain a whole number of units of this chemical formula. Let the number of units of Al2O3 be y.
Then, we can set up the following equation to solve for y:
2 moles of aluminum * y = 200 moles of aluminum
3 moles of oxygen * y = 300 moles of oxygen
Simplifying each equation, we get:
y = 100
y = 100
Since both equations give the same value for y, we can conclude that the sample of ore contains 100 units of Al2O3. Therefore, the value of y is 100.
If 4.00 g of the unknown compound contained 0.133 mol of C and 0.267 mol of H. how many moles of oxygen, O
were in the sample?
Express your answer to three significant figures and include the
Answer:
Explanation:
convert to grams
0.133 mol C x 12 = 1.596
0.267 mol H x 1 = 0.267
Now subtract those numbers from the 4.00
4.00-1.596 -0.267 = 2.137 g O
Now convert grams O to moles
2.137 x (1mole O/16 g O) =0.1335625 moles O
3 sig figs = 0.134 moles O
You are now told that element X is in period 2 and element Y is in period 1.
What is the chemical symbol for elements X and Y?
A buffer solution is made using weak acid, HA, with a pKa of 6.98. If the ratio of [A-] to [HA] is 1.0 x 10^3, what is the pH of the buffer
1. Use the bond enthalpies to calculate the enthalpy change for this reaction. Is this reaction endothermic or exothermic?
Change in enthalpy =
Is this reaction exothermic or endothermic?
If bond formation in the products releases more heat energy than bond breaking in the reactants does.
Endothermic is either hot or cold.The reverse of exothermic processes is endothermic reactions. They take in thermal energy from the environment. This indicates that endothermic reactions cause their surroundings to get colder. This kind of response can be seen in the melting of ice.
What does it mean to be endothermic?An organism is said to be endothermic if it expends energy to control the internal temperature of its body. Ectothermic organisms, on the other hand, are those that control their body temperature through external environmental stimuli.
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1.Explain the Theory of Plate Tectonics and provide three observations about the earth
that provide evidence to support the theory. Describe how plate tectonics cause
major geological events such as ocean basins, earthquakes, and volcanic eruptions.
Be sure to:
• Use science terms appropriately
.
• Organize and develop your ideas effectively
• Choose your words carefully
.
• Edit your writing for grammar, mechanics, and spelling
The Theory of Plate Tectonics is a scientific theory that explains how the Earth's outer shell is composed of several large plates that move and interact with each other over time.
What is the theory of plate tectonics?Three observations about the Earth that provide evidence to support the Theory of Plate Tectonics are:
Earthquakes: Earthquakes occur when the movement and interaction of the tectonic plates cause rocks to fracture and shift. These seismic events are most common along the boundaries of the tectonic plates, where the movement and interaction are most pronounced. The distribution of earthquakes around the world is consistent with the theory of plate tectonics.
Volcanic Activity: Volcanic activity is closely related to the movement of tectonic plates. Many of the world's most active and well-known volcanoes are located near plate boundaries, where the movement and interaction of plates lead to the formation of magma chambers and the release of volcanic material. This relationship between volcanoes and plate boundaries supports the theory of plate tectonics.
Continental Drift: The theory of plate tectonics also explains the phenomenon of continental drift, which refers to the movement of the Earth's continents over time. According to this theory, the continents are part of the tectonic plates and have moved and shifted over millions of years. The fit of the coastlines of Africa and South America is a well-known example of continental drift and supports the theory of plate tectonics.
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!!(100 points)!! For each of the following chemical formulas, identify the elements present and the number of atoms of each element present in each molecule of the substance: H2SO4, Ca(NO3)2
Answer:
H2SO4 Chemical Name
It contains two atoms of hydrogen, one atom of sulphur, and four atoms of oxygen. It has an atomicity of seven.
Calcium Nitrate is made up of three different elements and contains a total of nine atoms. This compound's formula is Ca(NO3)2. There is one calcium atom, two nitrogen atoms, and there are six oxygen atoms in calcium nitrate.
4 Read the sentence from the introduction [paragraph 1].
Matter is capable of undergoing changes, which are classified as either physical or chemical.
Which phrase could BEST replace "is capable of undergoing" in the sentence above?
(A) has the knowledge to perform
(B) has the ability to experience
(C) has the experience to recognize
(D) has the opportunity to facilitate
Answer: A
Explanation:
You thought i was feeling you that n was a munch
5.0 L of a gas goes from 1.0 atm to 1.3 atm.
Calculate the final volume of this gas.
A 6.5 L
B 0.26 L
C 4.1 L
D 3.8 L
Answer: D) 3.8 L
Explanation:
Boyles law
P1v1=p2v2
V2= p1v1/p2
v2= 1.0 x 5.0 /1.3 = 3.84 L
Problem 1. What masses of 15% and 20% solutions are needed to prepare 200 g of 17% solution?
Problem 2. What masses of 18% and 5% solutions are needed to prepare 300 g of 7% solution?
Problem 3. 200 g of 15% and 350 g of 20% solutions were mixed. Calculate mass percentage of final solution.
Problem 4. 300 g of 15% solution and 35 g of solute were mixed. Calculate mass percentage of final solution.
Problem 5. 400 g of 25% solution and 150 g of water were mixed. Calculate mass percentage of final solution.
Problem 1:
we need 80 g of the 15% solution and 120 g of the 20% solution.
Let x be the mass of the 15% solution needed and y be the mass of the 20% solution needed.
x + y = 200 (total mass of the two solutions)
0.15x + 0.2y = 0.17(200) (total amount of solute in the two solutions)
Solving these equations, x = 80 g and y = 120 g.
Therefore, we need 80 g of the 15% solution and 120 g of the 20% solution.
Problem 2:
we need 120 g of the 18% solution and 180 g of the 5% solution.
Let x be the mass of the 18% solution needed and y be the mass of the 5% solution needed.
x + y = 300
0.18x + 0.05y = 0.07(300)
Solving these equations, x = 120 g and y = 180 g.
Therefore, we need 120 g of the 18% solution and 180 g of the 5% solution.
Problem 3:
The mass percentage of the final solution is 135 g/550 g × 100% = 24.55%.
The total mass of the final solution is 200 g + 350 g = 550 g.
The total amount of solute in the final solution is:
0.15(200 g) + 0.20(350 g) = 65 g + 70 g = 135 g.
Therefore, the mass percentage of the final solution is 135 g/550 g × 100% = 24.55%.
Problem 4:
The mass percentage of the final solution is 110 g/335 g × 100% = 32.84%.
The total mass of the final solution is 300 g + 35 g = 335 g.
The total amount of solute in the final solution is:
0.15(300 g) + 35 g = 75 g + 35 g = 110 g.
Therefore, the mass percentage of the final solution is 110 g/335 g × 100% = 32.84%.
Problem 5:
The mass percentage of the final solution is 18.18%.
Calculate the final mass of the solution:
Final mass = 400 g + 150 g = 550 g
Calculate the mass of solute in the 25% solution:
Mass of solute = 0.25 x 400 g = 100 g
Calculate the mass percentage of the final solution:
Mass percentage = (mass of solute ÷ final mass) x 100%
Mass percentage = (100 g ÷ 550 g) x 100%
Mass percentage = 18.18%
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How many moles of Ca are required to react with 2.50 mol of Cl to produce the compound CaCl2
Answer:
1.25 moles
Explanation:
The balanced chemical equation for the reaction between Ca and Cl to produce CaCl2 is:
Ca + Cl2 → CaCl2
The stoichiometry of the balanced equation tells us that one mole of Ca reacts with one mole of Cl2 to produce one mole of CaCl2. Therefore, to find out how many moles of Ca are required to react with 2.50 mol of Cl, we need to divide 2.50 mol of Cl by the coefficient of Cl2 in the balanced equation, which is 2:
2.50 mol Cl ÷ 2 = 1.25 mol Ca
Therefore, 1.25 moles of Ca are required to react with 2.50 mol of Cl to produce the compound CaCl2.
which statement describes density? Check all that apply
Density is a chemical property of an object.
The density of an object is constant.
Density is a derived unit of measure.
Density is the sum of the mass and volume of an object.
The density of an object determines whether it will sink or float.
The following sentences describe density: An object's density is constant. A derived unit of measurement called density An object's density determines whether it will float or sink.
Is an object's density a chemical characteristic?Without affecting the thing's makeup, the mass of an object can be measured. The volume of an object is comparable in this regard. As a result, there is no requirement for a chemical reaction to determine an object's density, making density a physical feature.
Is density a chemical or physical characteristic?Physical properties are characteristics of matter that are independent of changes in its chemical composition. Physical characteristics include things like density, colour, hardness, melting, and boiling points.
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what happens in a synthesis reaction
Please help almost due?
Answer:
-lithium
-atomic number
-mass number
-protons
Explanation:
Which emission spectrum represents the copper?
A.) Spectrum A
B.) Spectrum B
C.) Spectrum C
The emission spectrum of copper can be seen from the spectrum C
What is the emission spectrum?
An emission spectrum is the pattern of wavelengths of electromagnetic radiation emitted by a substance when it is excited by heat, electricity, or some other energy source. Each element, molecule, or compound has a unique emission spectrum, which can be used to identify it or to study its physical and chemical properties.
The emission spectrum is produced when electrons in the atoms or molecules are excited to higher energy levels, and then return to their ground state by releasing energy in the form of photons. The energy of each photon corresponds to a specific wavelength, and the collective emission of all the photons produces a characteristic pattern of bright lines or bands in the electromagnetic spectrum.
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Write a balanced chemical equation for the reaction between aqueous hydrogen ion, H+, and aqueous hydroxide ion, OH+
H+ (aq) + OH- (aq) → H2O (l)
A 6.55 g sample of aniline (C6H5NH2, molar mass = 93.13 g/mol) was combusted in a bomb calorimeter. If the temperature rose by 32.9°C, use the information below to determine the heat capacity of the calorimeter. 4 C6H5NH2(l) + 35 O2(g) → 24 CO2(g) + 14 H2O(g) + 4 NO2(g)
We must first determine how much heat is produced by the combustion of aniline. According to the chemical equation, 4 moles of aniline react with 35 moles of oxygen to create 4 moles of nitrogen dioxide, 24 moles of carbon dioxide, and 14 moles of water. The mole ratio of aniline to heat emitted is as a result.
How much energy is emitted when one mol is created?When one mole of water is created from hydrogen and oxygen in the opposite reaction (equation d), it exhales 285.8 kJ of energy.
How much heat energy is released when 1.8 g of glucose is burned?
C₆H₁₂O₆(s)+6O₂(g)→6CO₂(g)+6H₂O(l); ΔH = −2900kJ
One mole (about 180g) of glucose burned during combustion, releasing 2900kJ (29001801.8=29kJ) in heat.
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In an aqueous solution of magnesium bromide, the solute is
In an aqueous solution of magnesium bromide, the solute is magnesium bromide and the solvent is water.
Aqueous solution of magnesium bromideThe solute in an aqueous solution of magnesium bromide is the solid material, in this case magnesium bromide, dissolved in a liquid, which is the solvent. In this case, the solvent is water. Water is an excellent solvent because of its ability to form hydrogen bonds with other molecules, which allows it to dissolve many different substances.
In addition, it is a polar molecule, meaning that one end of the molecule has a slightly positive charge while the other end has a slightly negative charge. This polarity allows water molecules to interact with molecules of other substances, including magnesium bromide, which is also a polar molecule, allowing it to dissolve in the water.
The interaction between the polar water molecules and the polar magnesium bromide molecules causes the magnesium bromide to break up into its component ions, forming a solution. The ions are then surrounded by water molecules, which keeps them in solution until the solution is evaporated.
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Problem 1. What masses of 15% and 20% solutions are needed to prepare 200 g of 17% solution?
Problem 2. What masses of 18% and 5% solutions are needed to prepare 300 g of 7% solution?
Problem 3. 200 g of 15% and 350 g of 20% solutions were mixed. Calculate mass percentage of final solution.
Problem 4. 300 g of 15% solution and 35 g of solute were mixed. Calculate mass percentage of final solution.
Problem 5. 400 g of 25% solution and 150 g of water were mixed. Calculate mass percentage of final solution.
For each problem:
Masses of solution needed are 80 g and 120 g respectively.Masses of solution needed are 120 g and 180 g respectively.Mass percentage of final solution is 22.7%.Mass percentage of final solution is 23.9%Mass percentage of final solution is 18.2%.How to calculate mass and mass percentage?Problem 1:
Let x be the mass of the 15% solution needed and y be the mass of the 20% solution needed.
We have two equations:
x + y = 200 (total mass of the solution)
0.15x + 0.20y = 0.17(200) (total amount of solute in the solution)
Solving these equations:
x = 80 g (mass of 15% solution needed)
y = 120 g (mass of 20% solution needed)
Therefore, 80 g of 15% solution and 120 g of 20% solution need to be mixed to prepare 200 g of 17% solution.
Problem 2:
Let x be the mass of the 18% solution needed and y be the mass of the 5% solution needed.
We have two equations:
x + y = 300 (total mass of the solution)
0.18x + 0.05y = 0.07(300) (total amount of solute in the solution)
Solving these equations:
x = 120 g (mass of 18% solution needed)
y = 180 g (mass of 5% solution needed)
Therefore, 120 g of 18% solution and 180 g of 5% solution need to be mixed to prepare 300 g of 7% solution.
Problem 3:
Let x be the mass of the final solution.
The total amount of solute in the final solution is:
0.15(200 g) + 0.20(350 g) = 55 g + 70 g = 125 g
The total mass of the final solution is:
200 g + 350 g = 550 g
Therefore, the mass percentage of the final solution is:
(125 g / 550 g) x 100% = 22.7%
Problem 4:
Let x be the mass of the final solution.
The total amount of solute in the final solution is:
0.15(300 g) + 35 g = 80 g
The total mass of the final solution is:
300 g + 35 g = 335 g
Therefore, the mass percentage of the final solution is:
(80 g / 335 g) x 100% = 23.9%
Problem 5:
Let x be the mass of the final solution.
The total amount of solute in the final solution is:
0.25(400 g) = 100 g
The total mass of the final solution is:
400 g + 150 g = 550 g
Therefore, the mass percentage of the final solution is:
(100 g / 550 g) x 100% = 18.2%
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Barium – 122 has a half-life of 2 minutes. Suppose you obtain a sample weighing 20.0 g and it takes 10 minutes to set up an experiment. How many grams of Barium – 122 will remain at the point when you begin the experiment?