Circle 1 is centered at (−4,−2) and has a radius of 3 centimeters. Circle 2 is centered at (5,3) and has a radius of 6 centimeters.

What transformations can be applied to Circle 1 to prove that the circles are similar?

Enter your answers in the boxes.

The circles are similar because you can translate Circle 1 using the transformation rule ( , ) and then dilate it using a scale factor of .

Answer:

y^10 + (5/8xy^5 - 5/8xy^6) - (25/64x^2)

Step-by-step explanation:

To simplify the given expression, we can expand it using the distributive property:

(5/8x + y^5)(y^5 - 5/8x)

Expanding the expression yields:

= (5/8x * y^5) + (5/8x * -5/8x) + (y^5 * y^5) + (y^5 * -5/8x)

= (5/8xy^5) - (25/64x^2) + y^10 - (5/8xy^6)

Combining like terms, we have:

= y^10 + (5/8xy^5 - 5/8xy^6) - (25/64x^2)

Hope this help! Have a good day!

Answer:

Step-by-step explanation:

The future value of the loan, or the total amount due at the end of 6 months, is $9,450.

We can use the following formula to calculate the future value of a loan:

[tex]A = P + P * r * t[/tex]

Given: $9,000 principal (P).

10% interest rate (r) = 0.10

6 months is the time period (t).

When we enter these values into the formula, we get:

A=9,000+9,000*0.10*6/12

First, compute the interest portion:

Interest is calculated as = 9,000*0.10*6/12=450

We may now calculate the future value:

A=9,000+450=9,450

As a result, the loan's future value, or the total amount payable in 6 months, is $9,450.

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Answer:

chemical reaction that releases heat energy to the surroundings is known as endothermis reaction

The different coordinates after respective rotation are:

1) A'(2, 0)

2) A'(0, -2)

3) A'(-2, 0)

There are different methods of transformation such as:

Translation

Rotation

Dilation

Reflection

Now, the coordinate of the given point A is: A(0, 2)

1) The rule for rotation of 90 degrees clockwise is:

(x, y) →(y,-x)

Thus, we have:

A'(2, 0)

2) The rule for rotation of 180 degrees is:

(x, y) → (-x,-y)

Thus, we have:

A'(0, -2)

3) The rule for rotation of 180 degrees is:

(x, y) → (-y,x)

Thus, we have:

A'(-2, 0)

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Given the following diagram: We need to find the coordinates of triangle ABC, translate the triangle (-2, 5) and draw the new image on the grid above, and determine the amount each coordinate will move on the x-axis and y-axis during translation.

1. Coordinates of triangle ABC:A = (2, 6)B = (5, 8)C = (6, 3)2. Translation of triangle (-2, 5)The translation of a triangle can be done by adding or subtracting a constant value from the x-coordinates and y-coordinates of each vertex of the original triangle.

For example, if we want to translate a triangle by 3 units to the right and 2 units up, we would add 3 to the x-coordinates and add 2 to the y-coordinates of each vertex of the original triangle. Using this method, we can translate the triangle (-2, 5) as follows:

New coordinates of A = (2 + (-2), 6 + 5) = (0, 11)New coordinates of B = (5 + (-2), 8 + 5) = (3, 13)New coordinates of C = (6 + (-2), 3 + 5) = (4, 8)3. New image of triangle (-2, 5)The new image of the triangle (-2, 5) is shown in the following diagram:4. Amount each coordinate moves on x-axis During translation, each coordinate moves 2 units to the right (from -2 to 0).5. Amount each coordinate moves on y-axis During translation, each coordinate moves 6 units up (from 5 to 11).

Therefore, the coordinates of the translated triangle image are (0, 11), (3, 13), and (4, 8).

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The resulting equation after multiplying the first equation by 2 and subtracting the second equation is:

-5y = -375

1. Given equations:

  - x + 3y = 350    (Equation 1)

  - 2x + 4y = 625   (Equation 2)

2. Multiply Equation 1 by 2:

  - 2(x + 3y) = 2(350)

  - 2x + 6y = 700    (Equation 3)

3. Subtract Equation 2 from Equation 3:

  - (2x + 6y) - (2x + 4y) = 700 - 625

  - 2x - 2x + 6y - 4y = 75

  - 2y = 75

4. Simplify Equation 4:

  -2y = 75

5. To isolate the variable y, divide both sides of Equation 5 by -2:

  y = 75 / -2

  y = -37.5

6. Therefore, the resulting equation is:

  -5y = -375

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[tex] \sf \hookrightarrow \: {8}^{2} + {b}^{2} = {17}^{2} [/tex]

[tex] \sf \hookrightarrow \: 8 \times 8 + {b}^{2} = 17 \times 17[/tex]

[tex] \sf \hookrightarrow \: 8 \times 8 + {b}^{2} = 289[/tex]

[tex] \sf \hookrightarrow \: 64 + {b}^{2} = 289[/tex]

[tex] \sf \hookrightarrow \: {b}^{2} = 289 - 64[/tex]

[tex] \sf \hookrightarrow \: {b}^{2} = 225[/tex]

[tex] \sf \hookrightarrow \: b = \sqrt{225} [/tex]

[tex] \sf \hookrightarrow \: b = \sqrt{15 \times 15} [/tex]

[tex] \sf \hookrightarrow \: b = 15[/tex]

The expression for m<3 is 349° - 7x.

To find the measure of angle 3 (m<3), we need to apply the angle sum property, which states that the sum of the angles around a point is 360 degrees.

In the given figure, angles 1, 2, 3, and 4 form a complete revolution around the point. Therefore, we can write:

m<1 + m<2 + m<3 + m<4 = 360°

Substituting the given angle measures, we have:

(x + 6)° + (2x + 9)° + m<3 + (4x - 4)° = 360°

Combining like terms:

7x + 11 + m<3 = 360°

To isolate m<3, we subtract 7x + 11 from both sides:

m<3 = 360° - (7x + 11)

m<3 = 360° - 7x - 11

m<3 = 349° - 7x

Therefore, the expression for m<3 is 349° - 7x.

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Answer:

X intercepts: (-2, 0), (2, 0)

Y intercept: (0, 4)

Edited because I forgot to put in point form earlier. Depends on whether your teacher wants it in point form. If not, ignore the 0s.

Step-by-step explanation:

X intercepts are the points where a line crosses the x axis. Y intercepts are the points where a line crosses the y axis.

Answer:

A. x-intercept: (-2,0), (2,0)

A. y-intercept: (0,4)

Step-by-step explanation:

If you want to find the x and y-intercept of a line, you need to know its equation. But don't worry, it's not as hard as it sounds. Here are some tips to help you out.

One type of equation is y = mx + c, where m is the slope and c is the y-intercept. This means that the line crosses the y-axis at c. To find the x-intercept, just plug in y = 0 and solve for x. You'll get x = -c/m. Easy peasy!

For example, if the equation is y = 2x + 4, then the y-intercept is 4 and the x-intercept is -2.

Another type of equation is ax + by + c = 0, where a, b and c are constants. To find the x-intercept, plug in y = 0 and solve for x. You'll get x = -c/a. To find the y-intercept, plug in x = 0 and solve for y. You'll get y = -c/b. Piece of cake!

For example, if the equation is 3x + 2y - 6 = 0, then the x-intercept is 2 and the y-intercept is -3.

Now you know how to find the x and y-intercept of a line from its equation.Let us understand the calculations to find the x and y intercept, through the steps in the below table.

Answer:

0.090909

Step-by-step explanation:

I used a calculator

Hence, the arrangements to the quadratic equation  (3x-1)(x-2) = 5x + 2 are x = and x = 4.

To unravel the quadratic equation  (3x-1)(x-2) = 5x + 2, let's to begin with grow the cleared out side of the equation:

(3x - 1)(x - 2) = 5x + 2

Growing the condition:

3x^2 - 6x - x + 2 = 5x + 2

Streamlining the condition:

3x^2 - 7x + 2 = 5x + 2

Another, let's move all terms to one side of the condition:

3x^2 - 7x - 5x + 2 - 2 =

Combining like terms:

3x^2 - 12x =

Presently, we have a quadratic condition in standard shape: ax^2 + bx + c = 0, where a = 3, b = -12, and c = 0.

To fathom the quadratic equation, able to calculate out the common calculate of x:

x(3x - 12) =

From this equation, we are able see that the esteem of x can be or unravel for 3x - 12 = 0:

3x - 12 =

Including 12 to both sides:

3x = 12

Isolating both sides by 3:

x = 4

Hence, the arrangements to the condition (3x-1)(x-2) = 5x + 2 are x = and x = 4.

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Answer:

[tex]x^{3}[/tex] - 4[tex]x^{2}[/tex] + 2x - 4

Step-by-step explanation:

(8x + 2[tex]x^{3}[/tex] - 4[tex]x^{2}[/tex]) - (4 + [tex]x^{3}[/tex] + 6x)

= 8x + 2[tex]x^{3}[/tex] - 4[tex]x^{2}[/tex] - 4 - [tex]x^{3}[/tex] - 6x

= 2x + [tex]x^{3}[/tex] - 4[tex]x^{2}[/tex] - 4

= [tex]x^{3}[/tex] - 4[tex]x^{2}[/tex] + 2x - 4

Answer:

log(3x⁹y⁴) = log 3 + 9 log x + 4 log y

Answer:

[tex]\log 3+ 9\log x +4 \log y[/tex]

Step-by-step explanation:

Given logarithmic expression:

[tex]\log 3x^9y^4[/tex]

[tex]\textsf{Apply the log product law:} \quad \log_axy=\log_ax + \log_ay[/tex]

[tex]\log 3+\log x^9 +\log y^4[/tex]

[tex]\textsf{Apply the log power law:} \quad \log_ax^n=n\log_ax[/tex]

[tex]\log 3+ 9\log x +4 \log y[/tex]

Answer:

Multiply to remove the fraction, then set it equal to 0 and solve.

Exact Form: x = −124/5

Decimal Form: x = −24.8

Mixed Number Form: x = −24 4/5

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The value of "c" such that the random variable cY has an x² distribution is 4.

To find the value of "c" such that the random variable cY has a chi-squared (x²) distribution, we need to consider the properties of the chi-squared distribution and the given expression for Y.

The chi-squared distribution with "k" degrees of freedom is obtained by summing the squares of "k" independent standard normal random variables. Each standard normal variable contributes one degree of freedom to the chi-squared distribution.

In the given expression for Y, we have two squared terms: (X₁ + X₃ + X₅ + X₇)² and (X₂ + X₁ + X₆ + X₈)². To obtain an x² distribution, we need to rewrite the expression in terms of squared standard normal random variables.

To achieve this, we can divide each squared term by its corresponding degrees of freedom and take the square root:

Y = (X₁ + X₃ + X₅ + X₇)² + (X₂ + X₁ + X₆ + X₈)²

= (1/4)(X₁ + X₃ + X₅ + X₇)² + (1/4)(X₂ + X₁ + X₆ + X₈)²

Now, we can rewrite Y as:

Y = (1/4)χ²₁ + (1/4)χ²₁

Here, χ²₁ and χ²₂ represent chi-squared random variables with 1 degree of freedom each.

To obtain an x² distribution, we need to make the coefficients of the chi-squared random variables equal to their degrees of freedom. In this case, we want the coefficient to be 1.

So, setting the coefficient of χ²₁ to 1, we get:

(1/4) = 1/c

Solving for "c", we find:

c = 4

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The cross section of the geometric solid is (d) rectangle

From the question, we have the following parameters that can be used in our computation:

The geometric solid

Also, we can see that

The geometric solid is a cylinder

And the cylinder is divided vertically

The resulting shape from the division is a rectangle

This means that the cross section of the geometric solid is (d) rectangle

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The shape of the cross-section for the geometric solid given in the diagram is a rectangle.

The cross section of the geometric solid represents the shape which extends beyond the actual geometric solid which is a cylinder.

A rectangle has opposite side being equal. This means that the width and and length are of different length.

Therefore, the shape of the cross-section is a rectangle.

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Answer:

c) 54 feet

Step-by-step explanation:

Let the  side of the square be x

perimeter = 4x

⇒ 36 = 4x

⇒ x = 36/4 = 9 feet

Each side is 9 feet

When we join the two squares, it becomes a rectangle with

b = 9

l = 9 + 9 = 18

The perimeter of a rectangle is 2(l + b)

perimeter = 2(18 + 9)

= 2(27)

= 54 feet

Answer:

Option (c) 54 feet

Step-by-step explanation:

Perimeter of one square is 36 feet.

Side of square = 36 / 4 = 9 feet

When combined together one side of each square merged.

So, the perimeter of rectangular shape will be;

(9+9+9) + (9+9+9)

27 + 27

54 feet.

Answer:

(x + 13)(x - 7) = 69

x² + 6x - 91 = 69

x² + 6x - 160 = 0

(x + 16)(x - 10) = 0

x = 10, so the area of the original square is 100 m².

Answer:10cm 5cm 7 Jim's lunch box is in the shape of a half cylinder on a rectangular box. To the nearest whole unit, what is a The total volume it contains? b The total area of the sheet metal in 10 in needed to manufacture it? This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts

Step-by-step explanation:

The vertex of h(x) is (-3, 3), and the range is y ≥ 3.

To find the vertex of the quadratic function h(x), we can use the formula x = -b/2a, where the quadratic function is in the form [tex]ax^2 + bx + c[/tex].

From the given table, we can observe that the x-values of the vertex correspond to the minimum points of the function.

The minimum point occurs between -4 and -3, which suggests that the x-coordinate of the vertex is -3. Therefore, x = -3.

To find the corresponding y-coordinate of the vertex, we look at the corresponding h(x) value in the table, which is 3. Hence, the vertex of the function h(x) is (-3, 3).

To determine the range of h(x), we need to consider the y-values attained by the function.

From the table, we see that the lowest y-value is 3 (the y-coordinate of the vertex), and there are no other y-values lower than 3. Therefore, the range of h(x) is all real numbers greater than or equal to 3.

The vertex of h(x) is (-3, 3), and the range is y ≥ 3.

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The vertex of the quadratic function is (-4, 12).

The range of h(x) is [3, ∞).

To find the vertex and range of the quadratic function h(x) based on the given table, we can use the properties of quadratic functions.

The vertex of a quadratic function in the form of f(x) = ax² + bx + c can be determined using the formula:

x = -b / (2a)

The domain of h(x) is all real numbers, we can assume that the quadratic function is of the form h(x) = ax² + bx + c.

Looking at the table, we can see that the x-values are increasing from left to right.

Additionally, the y-values (h(x)) are increasing from -6 to -4, then decreasing from -4 to -1.

This indicates that the vertex of the quadratic function lies between x = -4 and x = -3.

To find the exact x-coordinate of the vertex, we can use the formula mentioned earlier:

x = -b / (2a)

Based on the table, we can choose two points (-4, 4) and (-3, 3).

The difference in x-coordinates is 1, so we can assume that a = 1.

Plugging in the values of (-4, 4) and a = 1 into the formula, we can solve for b:

-4 = -b / (2 × 1)

-4 = -b / 2

-8 = -b

b = 8

The equation of the quadratic function h(x) can be written as h(x) = x² + 8x + c.

Now, let's find the y-coordinate of the vertex.

We can substitute the x-coordinate of the vertex, which we found as -4, into the equation:

h(-4) = (-4)² + 8(-4) + c

12 = 16 - 32 + c

12 = -16 + c

c = 28

The equation of the quadratic function h(x) is h(x) = x² + 8x + 28.

The range of the quadratic function can be determined by observing the y-values in the table.

From the table, we can see that the minimum y-value is 3.

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Answer/Step-by-step explanation:

C., the first proof we would be given if a little box is shown, which indicates a 90 degree angle at the place where to lines touch  in a T kind of manor. So C is the answer.

Answer:

Step-by-step explanation:Angle EDH=Angle FDH, so A must be correct.

Also, we don't have more information to prove B, C, D is right

Answer:

A.

Step-by-step explanation:

An angle bisector is a line, ray, or segment that divides an angle into two equal parts. It divides the angle into two congruent or equal angles. The angle bisector originates from the vertex of the angle and extends towards the interior of the angle. It essentially cuts the angle into two smaller angles of equal measure.

The z - score z = (x - μ)/σ equals z = (p' - p)/[√(pq/n)]

The z-score is the statical value used to determine probability in a normal distribution

Given the z-score z = (x - μ)/σ where

We need to show that

z = (p' - p)/√(pq/n)

We proceed as follows

Now, the z-score

z = (x - μ)/σ

Substituting in the values of μ and σ into the equation, we have that

So, z = (x - μ)/σ

z = (x - np)/[√(npq)]

Now, dividing both the numerator and denominator by n, we have that

z = (x - np)/[√(npq)]

z = (x - np) ÷ n/[√(npq)] ÷ n

z = (x/n - np/n)/[√(npq)/n]

z = (x/n - p)/[√(npq/n²)]

z = (x/n - p)/[√(pq/n)]

Now p' = x/n

So, z = (x/n - p)/[√(pq/n)]

z = (p' - p)/[√(pq/n)]

So, the z - score is z = (p' - p)/[√(pq/n)]

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The slope of a line that is perpendicular to the given line x + 6y = 3 is 6.

To determine the slope of a line that is perpendicular to the given line, we need to find the negative reciprocal of the slope of the given line.

The equation of the given line is x + 6y = 3.

To find the slope of the given line, we can rearrange the equation into slope-intercept form (y = mx + b), where m represents the slope:

x + 6y = 3

6y = -x + 3

y = (-1/6)x + 1/2

From the equation y = (-1/6)x + 1/2, we can see that the slope of the given line is -1/6.

To find the slope of a line that is perpendicular, we take the negative reciprocal of -1/6.

The negative reciprocal of -1/6 can be found by flipping the fraction and changing its sign:

Negative reciprocal of -1/6 = -1 / (-1/6) = -1 * (-6/1) = 6

Therefore, the slope of a line that is perpendicular to the given line x + 6y = 3 is 6.

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The initial stress is 1.273 × [tex]10^9[/tex] N/[tex]m^2[/tex], the resultant stress is 1.273 × [tex]10^9[/tex] N/[tex]m^2[/tex] and the induced force in the bar when the temperature reaches 50°C is 100.03 kN.

To calculate the initial stress in the tie bar, we can use the formula:

Stress = Load/Area

The area of the tie bar can be calculated using the formula for the area of a circle:

Area = π * [tex](diameter/2)^2[/tex]

Plugging in the values, we get:

Area = π * [tex]10 mm^{2}[/tex] = π *[tex](5 mm)^2[/tex] = 78.54 [tex]mm^2[/tex]

Converting the area to square meters, we have:

Area = 78.54 [tex]mm^2[/tex]* (1 m^2 / 1,000,000 [tex]mm^2[/tex]) = 7.854 × 1[tex]0^-5 m^2[/tex]

Now we can calculate the initial stress:

Initial Stress = 100 kN / 7.854 ×[tex]10^-5 m^2[/tex] = 1.273 × [tex]10^9 N/m^2[/tex]To calculate the resultant stress when the temperature rises to 50°C, we need to consider the thermal expansion of the tie bar. The change in length can be calculated using the formula:

ΔL = α * L0 * ΔT

Where ΔL is the change in length, α is the coefficient of linear expansion, L0 is the initial length, and ΔT is the change in temperature.

The induced force in the bar can be calculated using the formula:

Induced Force = Initial Stress * Area + E * α * ΔT * Area

Plugging in the values, we get:

Induced Force = (1.273 × 10^9 N[tex]m^2[/tex] * 7.854 × [tex]10^-5 m^2[/tex]) + (200 × [tex]10^9[/tex] N/[tex]m^2[/tex] * 14 × [tex]10^-6[/tex] /K * (50 - 15) K * 7.854 × [tex]10^-5 m^2[/tex])

Simplifying the equation, we find:

Induced Force = 100.03 kN

Therefore, the initial stress is 1.273 × [tex]10^9[/tex] N/[tex]m^2[/tex], the resultant stress is 1.273 × [tex]10^9[/tex] N/[tex]m^2[/tex], and the induced force in the bar when the temperature reaches 50°C is 100.03 kN.

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The probable question may be:

A rigidly held tie bar in a heating chamber has a diameter of 10 mm and is tensioned to a load of 100 kN at a temperature of 15°C. What is the initial stress, the resultant stress and what will be the induced force in the bar when the temperature in the chamber has risen to 50°C? E= 200 GN/ m2 and the coefficient of linear expansion of the material for tie bar = 14 × 10−6 /K.

The length of the unknown side x using the concept of similar triangles is: x = 4

Similar triangles are referred to as triangles that have the same shape but different sizes. All equilateral triangles and squares of any side length are examples of similar objects. In other words, if two triangles are similar, their corresponding angles are the same and their corresponding side proportions are the same.

Now, we are told that triangle PQR is similar to Triangle STU and as such their corresponding sides are similar and therefore to find the missing side x, we have:

12/x = 15/5

x = (12 * 5)/15

x = 60/15

x = 4

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Answer:

?

Step-by-step explanation:

?