Can someone please help meeeeee please

Answer:

if it is a gene mutation then it is during the S phase, and if it is a chromosome mutation, then during metaphase or anaphase.

Explanation: I think it happens in the interphase

When a mutation occurs in mitosis, stage of Mitosis is interphase.

Mutation that occurs in mitosis typically causes tumor.

Genetic mutations occur during the S phase of the cell cycle i.e during interphase before mitosis begins. When DNA is replicated, error would cause a mutation in the genetic code. Chromosomal nondisjunction denotes the failure of replicated chromosomes to separate causing extra or missing chromosomes in the daughter cells to occur. This mutation can occur during mitosis.

Thus, When a mutation occurs in mitosis, stage of Mitosis is interphase.

Learn more about mutation.

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Answer:

not always ot depends mostly on the mass of each object and how the collode

Answer:

6.7*10^8 mi/hr

Explanation:

(3*10^8 m)/1s * (3600 s)/ 1 hr * (1 mi)/ 1609 m

6.7*10^8 mi/hr

Answer:

I would say that the 1 kg ball weighs 1 kg. I don't see the answer choices.

Answer:

Fir wat glasss

Explanation:

Answer:

i think the answer is 50 kW.h

Answer:

Given -

[tex] \\ [/tex]

To find -

[tex] \\ [/tex]

Solution -

[tex] \\ \sf \: A = \frac{v - u}{t} \\ \\ \\ \implies \sf \: A = \frac{12 - 0}{36} \\ \\ \\ \implies \sf \: A = \frac{12}{36} \\ \\ \\ \implies \sf \underline{A = 0.33 \: m \: / {s}^{2} } \\ [/tex]

Therefore, the acceleration of the ball is 0.33 m/s².

Answer:

a) y = 16.51 [m]

b) t = 1.83 [s]

Explanation:

To solve this problem we must use two kinematics equations, the first to determine the height to which the ball reaches, and the second equation to determine how long it lasts in the air.

[tex]v_{f} ^{2}= v_{i} ^{2} - (2*g*t)\\[/tex]

where:

Vf = final velocity = 0

Vi = initial velocity = 18 [m/s]

g = gravity acceleration = 9.81[m/s^2]

t = time [s]

Note: the negative sign of the Equation indicates that the acceleration of gravity acts in the opposite direction to the movement of the ball.  The final velocity is zero, since the ball reaches its maximum altitude when the velocity is zero.

Now replacing:

0 = (18)^2 - (2*9.81*y)

y = 16.51 [m]

b)

[tex]v_{f} = v_{i} - (g*t)[/tex]

0 = 18 - (9.81*t)

t = 1.83 [s]

Answer:

D

Explanation: just trust me

Answer:

16 km

Explanation:

Drawing a right triangle to model the problem helps. I started by drawing the lines of the triangle to model the hiker's journey- a vertical straight line for 11 km north and then a horizontal line connected to the top of it for 11 km east; I then drew the hypothenuse to connect the two lines.

The hypothenuse is what we have to solve for, so we will use the Pythagorean Theorem, a^2 + b^2 = c^2. Since both distances are 11 km both a and b in the equation are 11.

11^2 + 11^2 = c^2

121 + 121 = c^2

242 = c^2

c = 15.56

Rounding the answer makes it 16 km for the hiker's magnitude of displacement.

wellll that would be in earth crust

Answer:

in space

Explanation:

its a planet

Answer:

melting.

Explanation:

The process in which a solid changes to a liquid is called melting. The melting point is the temperature at which a solid changes to a liquid. 

the space between the liquid. particles. increase. the particles of liquid. move faster the liquid gains thermal energy the liquid change. to gas.

Answer:

the space between the liquid. particles. increase. the particles of liquid. move faster the liquid gains thermal energy the liquid change. to gas.

Explanation:

Answer:

Explanation:

1.25 m/s

Answer:

D. 4 m/s²

Explanation:

Given;

initial velocity of the car, u = 0

distance traveled by the car, s = 18 m

time of motion of the car, t = 3.0 s

The magnitude of the car's acceleration is given by;

s = ut + ¹/₂at²

s = 0 + ¹/₂at²

s = ¹/₂at²

2s = at²

a = 2s / (t²)

a = ( 2 x 18) / (3²)

a = 4 m/s²

Therefore, the  magnitude of the car's acceleration is 4 m/s²

Explanation:

t=2s

u=10

v=5

a=?

v=u+at

5=10+2a

2a=-5

a=-2.5

Answer:

no lol

Explanation:

Answer:

A

Explanation:

Gravity

Answer:

v= +12cm

Explanation:

m = (size of image)/(size of the object) = -v/u  

u = - 8 cm

 3/2 = -v/u 

3/2 = -v/-8 

v = +12 cm

Using mirror formula, 

1/v + 1/u = 1/f  ...(i)

1/12 + 1/(-8) = 1/f 

f = -24 cm

Focal length is 24 cm

Answer:

d. is formed from pressure and heat

Explanation:

it is formed from hot magam

Answer:

(a). The value of [tex]\dfrac{N_{1}}{N_{2}}[/tex] is [tex]\dfrac{1}{20}[/tex]

(b). The output current is 0.05 A

Explanation:

Given that,

Secondary voltage = 10000 V

Primary voltage = 500 V

Primary current = 1 A

(a). We need to calculate the value of [tex]\dfrac{N_{1}}{N_{2}}[/tex]

Put the value into the formula

[tex]\dfrac{V_{s}}{V_{p}}=\dfrac{N_{2}}{N_{1}}[/tex]

[tex]\dfrac{N_{1}}{N_{2}}=\dfrac{V_{p}}{V_{s}}[/tex]

Put the value into the formula

[tex]\dfrac{N_{1}}{N_{2}}=\dfrac{500}{10000}[/tex]

[tex]\dfrac{N_{1}}{N_{2}}=\dfrac{1}{20}[/tex]

(b). We need to calculate the output current

Using formula of current

[tex]\dfrac{I_{s}}{I_{p}}=\dfrac{N_{1}}{N_{2}}[/tex]

[tex]I_{s}=I_{p}\times\dfrac{N_{1}}{N_{2}}[/tex]

Put the value into the formula

[tex]I_{s}=1\times\dfrac{1}{20}[/tex]

[tex]I_{s}=0.05\ A[/tex]

Hence, (a). The value of [tex]\dfrac{N_{1}}{N_{2}}[/tex] is [tex]\dfrac{1}{20}[/tex]

(b). The output current is 0.05 A

Answer:

has no air on it and no animals or plants live there.

Answer:

Big stars, about 5 - 25 times the mass of sun, usually they collect so much of matter and energy that they just explode, this explosion is called supernova. A supernova is a powerful and luminous stellar explosion. This astronomical event occurs during the last evolutionary stages of a massive star.

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Answer:

400J

Explanation:

s=d/t

s=800/40

s=20m/s

K.E= 1/2mv^2,

=1/2*40*20

=400 J