are cells smaller and simpler than either tissues or organs
Answer:
yes
Explanation:
tissues and organs are made of cells therefore cells have to be smaller and simpler
A bullet having the mass of 110g is fired. If it's velocity is 50m/s, calculate the kinetic energy
[tex]\text{Kinetic energy,}\\\\E_k = \dfrac 12 mv^2\\\\~~~~~=\dfrac 12 \cdot 110 \times 10^{-3} \cdot 50^2\\\\~~~~~=137.5~ \text{J}[/tex]
Answer: 137.5 Joules
Explanation:
The SI units for kinetic energy is Joules, the SI units for mass is kilograms, and the SI units for velocity is meters per second. We are given the mass in grams, so we must convert it to kilograms. There are 1,000 grams in 1 kilogram:
[tex]110g*\frac{1kg}{1000g} =0.11kg[/tex]
Kinetic energy is the energy the system has due to its motion. It is defined to be:
[tex]KE=\frac{1}{2} mv^2[/tex]
Plug everything in:
[tex]KE=\frac{1}{2} (0.11kg)(50m/s)^2[/tex]
[tex]KE=137.5J[/tex]
Question 4 (1 point) ✓ Saved
The term 'recruitment' refers to the process by which people decide on the kinds of
environments they will join.
True
False
Which of the following mathematical operations are and are not not allowed on two quantities with different unit dimensions?
A) Allowed : Multiplication, Division, Equality , Not Allowed : Addition, Subtraction
B) Allowed : Addition, Subtraction , Not Allowed : Multiplication, Division, Equality
C) Allowed : Multiplication, Division , Not Allowed : Addition, Subtraction, Equality
D) Allowed : Addition, Multiplication , Not Allowed : Subtraction, Division, Equality
E) Allowed : Addition, Subtraction, Equality , Not Allowed : Multiplication, Division
The following mathematical operations are and are not allowed on two quantities with different unit dimensions are C) Allowed : Multiplication, Division , Not Allowed : Addition, Subtraction, Equality
To answer the question, we have to know what mathematical operations are.
What are Mathematical operations?Mathematical operations are operations which are performed to change the value of a variable. The arithmetic mathematical operations we have are
addition, subtraction, multiplication, subtraction and equality which shows the relationship between two quantities.Now, for two quantities with different unit dimensions, addition, subtraction and equality are not allowed because these mathematical operations require the quantities to be in the same unit dimensions
Also, for two different quantities with differnt unit dimensions, multiplication and division are allowed because these mathematical operations do not require the quantities to be in the same unit dimensions.
So, the mathematical operations that are allowed are multiplication and division while the mathematical operations that are not allowed are addition, subtraction and equality.
So, the following mathematical operations are and are not allowed on two quantities with different unit dimensions are C) Allowed : Multiplication, Division , Not Allowed : Addition, Subtraction, Equality
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Does magnitude effect the strength of attraction more than distance?
Or
Does distance effect the strength of attraction more than magnitude?
Explanation:
Increasing the separation distance between objects decreases the force of attraction or repulsion between the objects. And decreasing the separation distance between objects increases the force of attraction or repulsion between the objects.
The force acting on a body of mass 200 g is equal to 0. Determine the velocity of the body 3 seconds after the start of the observation, if at the initial moment of the observation its velocity is 5 m / s?
Answer:
5 m/sExplanation:
Formula (Force)
F = maBut, a = v - u / t [First Equation of Motion]F = m (v - u / t)We have the values of :
F = 0m = 200 g = 0.2 kgt = 3 su = 5 m/sSubstitution
0 = 0.2 (v - 5 / 3)v - 5 / 3 = 0v - 5 = 0v = 5 m/sif every Galaxy have black hole in center than is that mean there used to humongous star that collapsed that formed galaxy and supermassive black hole?
Answer:
Yes, It does mean that there was a Red Giant in the middle of the galaxy.
Explanation:
The star at the middle of the galaxy will forever stay at the middle from the gravity it has on itself and it implodes and turns into a black hole with a mass equal to at least 10 suns
What initial speed is required for a 1 m (39.4”) vertical jump?
Answer: 4.4m/s
Explanation:
The girl in the picture is using an oar to push the water backwards. At the same time the canoe iS moving forward with
the same amount of force. Which of Newton's Laws would explain why for every action there is an opposite and equal
reaction?
Newton's First Law of Motion
Newton's Second Law of Motion
C) Newton's Third Law of Motion
Newton's Thired Law of Motion
my son needs help the question is What is the Law of Conservation of Mass and Energy
Answer:
Explanation:
The total amount of mass and energy in the universe is constant.....energy may change to mass and mass may change to energy, but the total is a constant.
How might a quota on foreign cars affect US economy?
Answer:
The numerical limits imposed on imported goods through quotas ultimately leads to higher prices paid by consumers. Essentially, the import quota prevents or limits domestic consumers from buying imported goods. The import quota reduces the supply of imports.
Explanation:
find the potential,electric field,charge density.
Answer:
The answer is Model the charge distribution as the sum of infinitesimal point charges, dq, and add together the electric potentials, dV, from all charges, dq. ...
Calculate the electric field (either as a integral or from Gauss' Law), and use: ΔV=V(→rB)−V(→rA)=−∫BA→E⋅d→r.
Explanation:
The marble has its maximum gravitational potential energy when it is at the starting point: the
highest point on the roller coaster. How much of this potential energy is converted to the
marble's kinetic energy?
Answer:
Explanation:
This depends on the height.
Using the formula mgh + 1/2mv^2 = total mechanical energy, we can determine the amount of kinetic and potential energy. I'm assuming your talking about if the marble goes all the down, then all of the energy is converted.
A 8.2 kg solid sphere, made of metal whose density is 2300 kg/m3, is suspended by a cord. When the sphere is immersed in a liquid of unknown density, the tension in the cord is 23 N. The density of the liquid is
The density of the liquid is 1470.43 kg/m³. Density is an important parameter in order to understand the fluid and its properties. Its unit is kg/m³.
What is density?Density is defined as the mass per unit volume. The mass and density relation is given as;
mass = density × volume
The given data in the problem is as ;
m is the mass of a solid sphere=8.2 kg
[tex]\rm \rho_s[/tex] is the density of the metal= 2300 kg/m³
T is the tension in the cord = 23 N.
The volume of the liquid is found as;
[tex]\rm V_{sphere} = \frac{m}{\rho} \\\\ \rm V_{sphere} =\frac{8.2}{2300} \\\\ \rm V_{sphere} = 0.00356 \ m^3[/tex]
The volume of the sphere is equal to the volume displaced;
Volume displaced = 0.00356 m³
The buoyant force is found as;
[tex]\rm F_B = \rho g V \\\\[/tex]
From the given condition it is observed that the weight of the sphere is equal to the sum of buoyancy force and the tension in the cord.
[tex]\rm mg = \rho g V+T \\\\ 8.2 \times 9.81 = \rho \times 9.81 \times 0.00356+23 \\\\\ 80.442=\rho \times 0.0349 +23 \\\\ \rho = 1645.90 \ kg/m^3[/tex]
Hence the density of the liquid is 1645.90 kg/m³.
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What is the density of the unknown liquid?
The density of the unknown liquid is 650.67 kg/m³
Determine the density of the unknown liquidFirst step : determine the mass in air
The Tension in air = mg
therefore Mass in air ( m ) = Tension in air / g
= 3.78 kg
Considering Tension in water
T = 29.6 N
29.6 = 4/3 * πR³ * ( р - б ) g ----- ( 1 )
where : р = mass density, б = water density
Considering Tension in other liquid
T = 19.1 N
19.1 = 4/3 * πR³ * ( р - б' ) g ------ ( 2 )
Final step : Determine the density of the unknown liquid
Divide equation ( 1 ) by equation ( 2 )
1.54 = ( р - б ) / ( р - б' )
0.54 р + б = 1.54 * б'
therefore ( б' ) density of uknown liquid
= 650.67 Kg/m³
Hence we can conclude that The density of the unknown liquid is 650.67 kg/m³
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a coil of standard annealed copper having a resistance of 50 ohms at 15° is embedded in the core of a large transformer after the transformer has been in operation for several hours the resistance of the material is measured as 58 ohms determine its temperature the temperature coefficient of resistance of the conductor material is 0.04 250 degree celsius at 0 degrees Celsius.
determine its temperature?
The temperature of the transformer after the transformer has been in operation for several hours at the given resistance is 21.2 degrees Celsius.
Relationship between resistance and temperature
The relationship between resistance and temperature is given as;
R = R₀( 1 + αΔθ)
From the first resistance, we will have the following equation,
R₁ = R₀( 1 + αΔθ)
50 = R₀(1 + 15α) ------ (1)
From the second resistance, we will have the following equation,
58 = R₀(1 + αT) ------ (2)
Divide (1) by (2)
[tex]\frac{50}{58} = \frac{R_0(1 + 15\alpha)}{R_0(1 + T\alpha)} \\\\\frac{50}{58} = \frac{(1 + 15\alpha)}{(1 + T\alpha)} \\\\50(1 + T\alpha) = 58(1 + 15\alpha)\\\\50 + 50T\alpha = 58 + 870\alpha \\\\50(0.0425)T = (58- 50) + 870(0.0425)\\\\2.125T = 44.975\\\\T = 21.2\ ^0C[/tex]
Thus, the temperature of the transformer after the transformer has been in operation for several hours at the given resistance is 21.2 degrees Celsius.
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Changes of state
Study the heating curve shown.
Which statement is best supported by the information in
the heating curve?
Heating Curve of a Substance
T
U
O At segment T-U, the substance changes from a liquid
to a gas and does not change temperature.
At segment T-U, the substance changes from a gas
to a liquid and changes temperature.
O At segment Q-R, the substance releases heat and
increases in temperature.
O At segment Q-R, the substance absorbs heat and
decreases in temperature.
Temperature (Cº)
R
20
s
o
Heat Added (J)
Answer:
liquid to a gas and doesn't change T
Explanation:
that part of the line has no slope
Answer:
A. At segment T-U, the substance changes from a liquid to a gas and does not change temperature.
Explanation:
A light plastic cart and a heavy steel cart are both pushed with the same force for 1.0 s, starting from rest. After the force is removed, the momentum of the light plastic cart is ________ that of the heavy steel cart.
Answer:
my friend give options .............
An industrial/organizational psychologist wants to improve worker productivity for a client firm, but first he needs to gain a better understanding of the life of the typical white-collar professional. Fortunately, he has access to the 2020 Workplace Productivity Survey, commissioned by LexisNexis and prepared by WorldOne Research, which surveyed a sample of 650 white-collar professionals (250 legal professionals and 400 other professionals).
One of the survey questions was, "During the average workday, how many hours do you spend attending meetings?" For the subsample of legal professionals (n = 200), the mean response was M = 2.0 hours, with a sample standard deviation of s = 5.1 hours.
The estimated standard error is = 0.323.
The psychologist can be 99% confident that the interval from _____ to _____ includes the unknown population mean µ.
Based on the research data, the psychologist can be 99% confident that the interval from 1.07 to 2.94 includes the unknown population mean µ.
What is confidence Interval?A confidence interval is a range of values within which a researcher can be fairly certain that the true value of the mean can be found.
The confidence Interval of the survey above is calculated using the formula:
[tex] x ± z( σ/√n)[/tex]
where
x is the sample mean,σ is the population standard deviation,n is the sample size, and z is the z-value for the selected confidence level.From the data provided;
x = 2.0
σ = 5.1
n = 200
z = 2.576 for 99% confidence
Therefore, the confidence Interval is:
[tex] 2.0 ± 2.576( 5.1/√200)[/tex]
Confidence interval = 2.0 ± 0.93.
Therefore, the psychologist can be 99% confident that the interval from 1.07 to 2.94 includes the unknown population mean µ.
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3. The property of sound called intensity is proportional
to the rate at which energy flows through
A.an area perpendicular to the direction of
propagation.
B.an area parallel to the direction of propagation.
C.a cylindrical tube.
D.a sound wave of a certain frequency.
Answer:
A. an area perpendicular to the direction of propagation.
Explanation:
The property of sound called intensity is proportional
to the rate at which energy flows through an area perpendicular to the direction of propagation.
A police car siren emits a frequency of
2010 Hz when stationary. Another car
hears a 1920 Hz sound when it drives
away from the stationary police car.
How fast is the second car driving?
(Speed of sound = 343 m/s)
(Unit = m/s)
Speed of second car will be 15.35 m/s
What is Doppler effect ?The Doppler effect is the apparent change in frequency of a wave when the observer and the source of the wave move relative to each other.
f0= observed frequency = 1920 Hz
v = speed of source = 343 m/s
v0 = speed of observer = ?
fs = frequency of source = 2010 Hz
from Doppler effect
f0 = (v -v0 / v) * fs
1920 / 2010 = (343 - v0)/ 343
(192/ 201) * 343 = 343 - v0
v0 = (343 * 9) / 201 = 15.35 m/s
Speed of second car will be 15.35 m/s
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A particle with a charge of +8nC is in a uniform electric field directed to the left. It is released from rest and moves to the left. After it as moved 3cm, its kinetic energy was found to be 5x 10^(-4) J. What work was done by electric force?
The work done by the electric force of the charge is equal to the change in kinetic energy, equal to 5x [tex]10^{-4}[/tex] J.
What is the work-energy theorem?The work done by the body in motion is equal to the change in kinetic energy or the difference between the final and initial kinetic energy.
[tex]W=[/tex]Δ[tex]K.E=K.E_{f} -K.E_{i}[/tex]
Given, the kinetic energy found when the charge has moved 3 cm is 5x [tex]10^{-4}[/tex] J.
Therefore, work done by the electric force, [tex]W=[/tex] 5x [tex]10^{-4}[/tex] J.
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in the diagram, q1,q2, and q3 are in a straight line. each of these particles has a charge of -2.35x10^-6 C. particles q1 and q2 are separated by 0.100 m and particles q2 and q3 are separated by 0.100 m. what is the net force on particle q3?
The magnitude of the net force that is acting on particle q₃ is equal to 6.2 Newton.
Given the following data:
Charge = [tex]-2.35 \times 10^{-6}[/tex] C.
Distance = 0.100 m.
Scientific data:
Coulomb's constant = [tex]8.988\times 10^9 \;Nm^2/C^2[/tex]
How to calculate the net force.In this scenario, the magnitude of the net force that is acting on particle q₃ is given by:
F₃ = F₁₃ + F₂₃
Mathematically, the electrostatic force between two (2) charges is given by this formula:
[tex]F = k\frac{q_1q_2}{r^2}[/tex]
Where:
q represent the charge.r is the distance between two charges.k is Coulomb's constant.Note: d₁₃ = 2d₂₃ = 2(0.100) = 0.200 meter.
For electrostatic force (F₁₃);
[tex]F_{13} = 8.988\times 10^9 \times \frac{(-2.35 \times 10^{-6} \times [-2.35 \times 10^{-6}])}{0.200^2}\\\\F_{13} = \frac{0.0496}{0.04}[/tex]
F₁₃ = 1.24 Newton.
For electrostatic force (F₂₃);
[tex]F_{13} = 8.988\times 10^9 \times \frac{(-2.35 \times 10^{-6} \times [-2.35 \times 10^{-6}])}{0.100^2}\\\\F_{13} = \frac{0.0496}{0.01}[/tex]
F₂₃ = 4.96 Newton.
Therefore, the magnitude of the net force that is acting on particle q₃ is given by:
F₃ = 1.24 + 4.96
F₃ = 6.2 Newton.
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Answer:
6.2
Explanation:
acellus
A negative charge of -6.0x10-6 C exerts an
attractive force of 65 N on a second charge that is
0.050 m away. What is the magnitude of the second
charge?
The magnitude of the second charge given that the first is –6×10¯⁶ C and is located 0.05 m away is +3.0×10¯⁶ C
Coulomb's law equationF = Kq₁q₂ / r²
Where
F is the force of attraction K is the electrical constant q₁ and q₂ are two point charges r is the distance apart How to determine the second charge Charge 1 (q₁) = –6×10¯⁶ CElectric constant (K) = 9×10⁹ Nm²/C²Distance apart (r) = 0.05 mForce (F) = 65 NCharge 2 (q₂) =?F = Kq₁q₂ / r²
Cross multiply
Fr² = Kq₁q₂
Divide both side by Kq₁
q₂ = Fr² / Kq₁
q₂ = (65 × 0.05²) / (9×10⁹ × 6×10¯⁶)
q₂ = +3.0×10¯⁶ C (since the force is attractive)
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Oxygen is needed by all cells of most organisms for the release of
energy from what in photosynthesis?
Answer:
From the SUN
Explanation:
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The turn signal belongs to which subsystem of an automobile?
A.
transmission
B.
fuel
C.
suspension
D.
control
The turn signal belongs to the control subsystem of an automobile.
What turn signal ?Turn signals serves as the control that help motorists to react and plan for road user making a turn in front of them.
This is part of the subsystem of an automobile. which help to maintain the best driving experience on the road.
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Which of the following is an example of a chemical reaction?
hydrogen peroxide and yeast are combined, producing lots of bubbles and heat
atoms of silver are bonded together to make a silver nugget
heat is applied to melt chocolate chips
red and blue paints are mixed to make purple paint
You are in a car traveling at 25.6 m/s. A second car is moving toward you at the same speed. Its horn is sounding at 482 Hz. What frequency do you hear to two decimal places?
Answer: Let the speed of sound equal 331 m/s
f = f0 ( (V ± Vo) / V) observer moving
f = 482 (331 + 25.6) / 331 = 519 /s (observer moving towards source)
f = 519 (331 / (331 - 25.6) = 563 / s (source moving towards observer)
Check: For both moving:
f = f0 ((331 + 25.6) / (331 - 25.6)) = 1.17 f0 = 482 * 1.17 = 563 / s
An electric space heater is connected across a 120 V outlet the heater dissipates 1320 W of power in the form of electromagnetic radiation and heat calculate the resistance of the heater
The resistance of the electric space heater dissipating the given amount of power is 10.9Ω.
Ohm's lawOhm's law states that "the voltage across the cross-section of a conductor is directly proportional to the current passing through it.
It is expressed as;
V = I × R
Where V is voltage, I is current and R is resistance.
Also, electrical power is the product of current and voltage.
P = I × V meaning I = P/V
Hence,
V = (P/V) × R
R = V² / P
Given the data in the question;
Voltage V = 120VPower P = 1320WResistance of the heater R = ?To determine the resistance of the heater, we substitute our given values into the derived expression above.
R = V² / P
R = (120V)² / 1320W
R = 14400V² / 1320W
R = 10.9Ω
Therefore, the resistance of the electric space heater dissipating the given amount of power is 10.9Ω.
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What is the rate of acceleration if the object has a force of 857 N and a mass of 8000 kg