BONUS QUESTION

you are stuck with a problem. You need to measure pH of a solution known to be made from a metal hydroxide, but you don't have a meter or any indicators. You do happen to have some lead(II) nitrate that is soluble, and you remember that lead (II) hydroxide is insoluble. You add some to 1 liter of your own unkown solution and a precipitate forms. You add more unttil the precipitate stops forming and then a bit more just in case. After you filter and dry the precipitate, you have 3.81 grams of it. What was the approximate pH of the original solution?

*This is just a bonus question but I'm very confused on it so any help would be appreciated*

Answer:

3.4

373.4

.45.=2

46.=3 .6.2=4

Answer:

The formula for kinetic energy is KE= 1/2mv²

Explanation:

Hope it helps you

PLS RATE AS BRAINLIEST ANSWER

Answer:

The last one.

Explanation:

The other ones add more force or give the same but the last one reduces it.

Grams of aluminum that will be produced if 1.0 g of Ba react with 1.80 g of Al2(SO4)3 will be 0.28g Al. Hence option c) is correct.

A balanced equation is a chemical equation where mass is conserved and there are equal numbers of atoms of each elements on both the sides of equation.

Given, 1.80 g of Al2(SO4)3 and 1.0 g of Ba

So, (1.8 g)/(341.96 g) = 0.00526 moles of Al2(SO4)3

And, 1 mole = 341.96g Al2(SO4)3

Now, (0.00526 moles of Al2(SO4)3)*(2 moles of Al)

= 0.01052 moles of Al

So, (0.01052 moles of Al)*(27 grams of Al)

= 0.28g Al

Hence, option c is correct.

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A synthetic ingredient is a substance that has been synthesized in a lab using different chemical procedures. Its goal is to mimic a natural chemical to duplicate its structure and, consequently, its fragrance.

In most cases, it refers to a naturally occurring substance, like hyaluronic acid, which was formerly extracted from animals and has now been molecularly copied in a laboratory to provide the same results. Not everything that is manufactured or chemical is inherently harmful to you. Although not all synthetic cosmetic components are the same, some have been proven to be toxic, accumulate in the body over time, and have been associated with cancer as well as irritations of the skin and mucous membranes.

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One mole of the propane produces three moles of the carbon dioxide from mole ratio.

When we talk about the mole ratio, we mean the ratio of the species that can be found in the reaction. We can be able to get the mole ratio from the balanced reaction equation and we apply it to solve problems from the stoichiometry of the reaction.

Given the fact that we have the reaction as it has been written in the question, it is clear that we would need about one mole of the propane to produce three moles of carbon dioxide.

We can see that there are three atoms of carbon in the propane and the implication of this is that we are going to produce three atoms of carbon dioxide in the product.

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Based on the information provided, I would recommend the Sunburst Variety of corn as the best choice for growing in the drought conditions of the desert environment.

Sunburst Variety of corn has been specifically developed to be drought-tolerant, meaning that it can survive and produce a good yield even with minimal rainfall.

Therefore, I would recommend the Sunburst variety of corn as the best choice for growing in the desert environment due to its drought-tolerance, deep root system, heat tolerance, high yield, and good quality grain.

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Answer: not 100% sure.

Explanation:

The vapor pressure at 49.5 °C is:

DP = 48.8 kJ/mol / 8.314 J/mol*K * (1/451.0 K - 1/322.65 K) * 49.5

DP = 0.24 torr (approx)

The vapor pressure of benzaldehyde at 49.5°C is approximately 0.24 torr.

The heat of vaporization (ΔHvap) and the normal boiling point (Tb) can be used to determine the vapor pressure of a liquid at a given temperature using the Clausius-Clapeyron equation. The Clausius-Clapeyron equation states that the change in vapor pressure (DP) with temperature (DT) is directly proportional to the heat of vaporization (ΔHvap) and inversely proportional to the absolute temperature (T) in kelvin.

DP/DT = ΔHvap / R * (1/T)

where R is the gas constant.

We can use this equation to solve for the vapor pressure of benzaldehyde at 49.5°C.

First, convert 49.5°C to kelvin:

T = 49.5°C + 273.15 = 322.65 K

Next, we need to use the Clausius-Clapeyron equation to solve for vapor pressure at a temperature T and the normal boiling point Tb:

DP/DT = ΔHvap / R * (1/T) = ΔHvap / R * (1/Tb - 1/T)

DP = ΔHvap / R * (1/Tb - 1/T) * DT

The vapor pressure at 49.5 °C is:

DP = 48.8 kJ/mol / 8.314 J/mol*K * (1/451.0 K - 1/322.65 K) * 49.5

DP = 0.24 torr (approx)

The vapor pressure of benzaldehyde at 49.5°C is approximately 0.24 torr.

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The vapor pressure of the benzaldehyde is  196 torr.

We know that the vapor pressure would have to do with the ease that we can use to convert the substance that is in question from liquid to gas. When we have two substances that are at different temperatures than we have;

ln(P2/P1) = -ΔH/R(1/T1 - 1/T2)

P2 = final pressure

P1 = initial pressure

R = gas constant

T1 = initial temperature

T2 = final temperature

Thus;

ln(P2/1) = -48.8* 10^3/8.314(1/451 - 1/322.5)

lnP2 = -5869.6(0.0022 - 0.0031)

lnP2 = 5.28

P2 =e^5.28

P2 = 196 torr

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Answer:

48 this answer is wrong so don't

The flame test used for to identify an unknown sample by its emission spectrum

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Answer: to identify an unknown sample by its emission spectrum

Explanation:

Complete question is;

Which statements regarding the Henderson-Hasselbalch equation are true?

1. If the pH of the solution is known as is the pKa for the acid, the ratio of conjugate base to acid can be determined.

2. At pH = pKa for an acid, [conjugate base] = [acid] in solution.

3. At pH > pKa for an acid, the acid will be mostly ionized.

4. At pH < pKa for an acid, the acid will be mostly ionized.

A. All of the listed statements are true. B. 1, 2, and 3 are true.

C. 2, 3, and 4 are true.

D. 1, 2, and 4 are true.

Answer:

B. 1, 2, and 3 are true.

Explanation:

The formula for the Henderson-Hasselbalch equation is:

pH = pka + log₁₀([A^(-)]/[HA])

Where;

PH is acidity of solution

ka is acid dissociation constant

A^(-) is concentration of conjugate base

HA is concentration of Acid

- For statement 1; If the pH of the solution is known as is the pKa for the acid, the ratio of conjugate base to acid can be determined;

pH = pka + log₁₀([A^(-)]/[HA])

pH - pka = log₁₀([A^(-)]/[HA])

10^(pH - pka) = ([A^(-)]/[HA])

Since we can find the ratio as seen, then the statement is true

- For statement 2: At pH = pKa for an acid, [conjugate base] = [acid] in solution;

We will substitute pH for pKa;

pH = pH + log₁₀([A^(-)]/[HA])

This give;

0 = log₁₀([A^(-)]/[HA])

10^(0) = [A^(-)]/[HA]

1 = [A^(-)]/[HA]

Thus; [A^(-)] = [HA]

Thus, the statement is true

- For statement 3: At pH > pKa for an acid, the acid will be mostly ionized;

This means that;

pH - pKa is greater than 0 and thus;

10^(pH - pKa) is greater than 1.

Thus;

[A^(-)]/[HA] > 1

[A^(-)] > [HA]

So more acid is ionized than base.

So the statement is true.

- For statement 4: At pH < pKa for an acid, the acid will be mostly ionized;

This means that;

pH - pKa is less than 0 and thus;

10^(pH - pKa) is less than 1.

Thus;

[A^(-)]/[HA] < 1

[A^(-)] < [HA]

So we have more base ionized than acid. So statement is false

Answer:

Molarity =Moles of solute/Volume of Solution (L)

Molarity=2.5/2.6

=0.962M

Answer:

wow okay um so first you go home, get in bed, never open that computer again

Explanation:

Answer:

A. By the circumference of the epicenter

Explanation:

If the Earth's lithospheric plates begin to move slowly, stresses emanate in the crust, most at times close to the plate boundaries. These stresses (compression, tension strain, and shear) accumulate in the crust until they surpass the rock's strength or the pressure around an internal fault. And there's a sudden slippage of rock around a fault.

The planet shakes and the rocks lurch to their new position in a matter of seconds as the stress energy is released. Seismic waves move away from the broken portion of the fault, just like ripples from a pebble landing on calm water.

Seismologists may estimate when the slippage started on a fault, the area of the slipping fault, the sum of slippage or fault throw (i.e. just how much the crust moved), and the length of time it takes for the slippage to happen by measuring the circumference of the epicenter which is the mapped area where the earthquake is taken place.

Answer:

-1396 kJ

Explanation:

Let's consider the following balanced equation.

4 NH₃(g) + 7 O₂(g) ⇒ 4 NO₂(g) + 6 H₂O(l)

We can calculate the standard change in enthalpy for the reaction (ΔHr) using the following expression.

ΔHr = ∑ np × ΔHf(p) - ∑ nr × ΔHf(r)

where,

ΔHr = 4 mol × ΔHf(NO₂(g)) + 6 mol × ΔHf(H₂O(l)) - 4 mol × ΔHf(NH₃(g)) - 7 mol × ΔHf(O₂(g))

ΔHr = 4 mol × (34 kJ/mol) + 6 mol × (-286 kJ7mol) - 4 mol × (-46 kJ/mol) - 7 mol × (0 kJ/mol) = -1396 kJ

Answer:

The answer is lithium bromide because it is the combination of a metal (lithium) and a nonmetal (bromine). The indicator that this is the correct name, rather than lithium bromate, is that the compound is composed of only two elements and does not contain oxygen. Yes, this is why NaNO3 is Sodium Nitrate; it is composed of three different elements (sodium, nitrogen, and oxygen).

Explanation:

Answer:

Nitrogen dioxide does not rekindle a glowing splinter becuase it is a not a very good oxidant. However, it will support the combustion of burning substances that are able to decompose it into nitrogen and oxygen gas.

NO₂ (g) ----> N₂ (g) + O₂

The oxygen then produced will go ahead to rekindle the glowing splinter.

Explanation:

Nitrogen dioxide isa reddish brown gas that is given when trioxiponitrate (v) salts, for example Lead (ii) trioxonitrate (v) of heavy metals are heated.

It is an mild oxidizing agent due to the presence of oxygen in the molecule of the compound.

It does not support combustion and does not burning air because of the inertnesss of the nitrogen atom. However, it will support the combustion of burning substances that are able to decompose it into nitrogen and oxygen gas.

For example, phosphorus is a very combustible material due to its low ignition temperature of 35°C. It catches fire spontaneously in air. Nitrogen dioxide is decomposed by burning phosphorus to nitrogen and oxygen. The oxygen produced supports further combustion of the burning phosphorus.

NO₂ (g) ----> N₂ (g) + O₂

Bi-phosphate detergents

Hypochlorous

Answer:

oxygen-16 is a stable isotope of oxygen, having 8 neutrons and 8 protons in its nucleus. It has a mass of 15. u

Answer:

3.3atm is the new pressure of the container

Explanation:

In the car, the temperature of the container increases from 25°C  =298K to 55°C = 328K. To solve this question we must use the Boyle's law that state that the pressure of a gas is directly proportional to its absolute temperature under constant volume. The equation is:

P1T2 = P2T1

Where P is pressure and T absolute temperature of 1, initial state of the gas and 2, final state.

Replacing:

P1 = 3atm

T2 = 328K

P2 = ?

T1 = 298K

3atm*328K = P2*298K

P2 = 3.3atm is the new pressure of the container

Answer:

3.3 atm

Explanation:

First we convert 25 °C and 55 °C to K:

We can solve this problem by using Gay Lussac's law, which states that at constant volume:

Where in this case:

We input the data:

And solve for P₂:

The boiling points increase down the group.Thus, option C is the answer.

Group 0, also known as the noble gases, is a group of chemical elements in the periodic table. These elements are all characterized by having a full valence shell of electrons, which gives them little tendency to gain or lose electrons and makes them generally unreactive. As a result, the elements in Group 0 are not very reactive and do not form many compounds.

The boiling points of the elements in Group 0 generally increase as you go down the group. This trend is due to the increasing atomic radius of the elements as you go down the group. The larger the atomic radius, the more space there is between the atoms in a substance, and the more energy is required to overcome the attractive forces between the atoms. This results in a higher boiling point.

In contrast, the relative atomic masses (Ar) of the elements in Group 0 generally decrease as you go down the group. This is because the atomic radius increases as you go down the group, but the number of protons in the nucleus (and therefore the atomic mass) does not change significantly. As a result, the relative atomic mass decreases as the atomic radius increases.

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Answer:

B. C, A, B

Explanation:

We can measure the age of an artifact by comparison of the activities a living sample with that of the artifact. This is so because the activity of the living sample represents the original activity of the artifact.

So, the steps involved in determining the age of an artifact is to measure the ratio of the parent and daughter nuclei. Then we use the half life of carbon to find out how many half lives have passed. Using this number of half lives that has passed, we can compute the age of the object.

Answer: B.A.C

Explanation:

Answer:

Different because it depends how long the planets take a single orbit around the sun. :) Hope this helps

Explanation:

Other planets, such as Mars and Jupiter, have year-lengths that are different than the length of a year on Earth.

A planet can be defined as a large astronomical (celestial) body that has sufficient mass to allow for self-gravity and make it assume a nearly circular shape, which is known as hydrostatic equilibrium.

Based on astronomical records, a planet revolves in its orbit around the Sun in the solar system and as such, a planet which is closest to the Sun would travel the fastest while experiencing stronger gravitational pull.

In this context, other planets, such as Mars and Jupiter, have year-lengths that are different than the length of a year on Earth because of the difference in time to perform a single orbit around the Sun.

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The new volume of the system can be found to be 4.9 L.

We have to know that we do use the Boyle's law when we are trying to get the association that we know that does exist when we are looking at the volume and the pressure of the gas and the both can be shown to be inversely proportional.

We then have that;

Initial pressure(P1) =  765 mmHg

Initial volume (V1) = 5 L

Final pressure (P2)= 780 mmHg

Final volume (V2) = ?

Then;

P1V1 = P2V2

V2 = 765 * 5/780

V2 = 4.9 L

As such, we can see from the calculation that the new volume that we would obtain is 4.9 L

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