As a result, the combined Honda-Toyota system's post-collision speed is 7.5 m/s.
How can you calculate the entire momentum prior to a collision?The system's center of mass was v/2 before to the collision since one automobile had a velocity of v and the other zero. The total momentum is equal to the entire mass times the velocity of the center of mass, or (2m)(v/2) = mv before and after.
Initial momentum of Honda = m1 * v1
= 200 kg * 30 m/s
= 6000 kg·m/s
Final momentum of combined system = (m1 + m2) * v_final
Setting the two momenta equal to each other, we get:
6000 kg·m/s = 800 kg * v_final
Solving for v_final, we get:
v_final = 6000 kg·m/s / 800 kg
= 7.5 m/s
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A stuntman of mass 55 kg is to be launched horizontally out of a spring- loaded cannon. The spring that will launch the stuntman has a spring coefficient of 266N / m and is compressed 5 m prior to launching the stuntman. If friction and air resistance can be ignored, what will be the approximate velocity of the stuntman once he has left the cannon?
The approximate velocity of the stuntman, once he has left the cannon, is 11 m/s.
StepsWe can use the conservation of energy, where the potential energy stored in the compressed spring is converted into the kinetic energy of the stuntman as he is launched out of the cannon.
The potential energy stored in the spring is given by:
PE = (1/2)kx²
where k is the spring constant and x is the distance the spring is compressed.
PE = (1/2)(266 N/m)(5 m)² = 3325 J
This potential energy is then converted into kinetic energy:
KE = (1/2)mv²
where m is the mass of the stuntman and v is his velocity.
3325 J = (1/2)(55 kg)v²
v² = (2*3325 J) / 55 kg
v² = 121 m²/s²
v = √(121 m²/s²) = 11 m/s
Therefore, the approximate velocity of the stuntman, once he has left the cannon, is 11 m/s.
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an electron of hydrogen is present in the 3.4eV energy state find angular momentum of electron
To find the angular momentum of an electron in the hydrogen atom, we can use the formula:
L = n * h / (2 * π)
where L is the angular momentum, n is the principal quantum number, h is Planck's constant, and π is a mathematical constant approximately equal to 3.14159.
First, we need to determine the value of n for the electron in the 3.4 eV energy state. We can use the formula for the energy of an electron in a hydrogen atom:
E = -13.6 eV / n^2
where E is the energy of the electron and -13.6 eV is the energy of the electron in the ground state of the hydrogen atom.
Solving for n, we get:
n^2 = (-13.6 eV) / E
n^2 = (-13.6 eV) / (3.4 eV)
n^2 = 4
n = 2
Therefore, the electron is in the second energy level of the hydrogen atom.
Now, we can calculate the angular momentum using the formula above. Substituting the values, we get:
L = 2 * h / (2 * π)
L = h / π
We can approximate π as 3.14159 and use the value of Planck's constant as h = 6.626 x 10^-34 J s. Substituting these values, we get:
L = (6.626 x 10^-34 J s) / (3.14159)
L = 2.104 x 10^-34 J s
Therefore, the angular momentum of the electron in the second energy level of the hydrogen atom is 2.104 x 10^-34 J s.
Bob travels 60km north turns around and travels 20km south what is his total distance travelled? what is his displacement
Explanation:
Total distance travelled is 60 + 20 = 80 km
He went 60....then turned around and headed back 20 km
so his displacement ( distance from starting point) is 60 - 20 = 40 km
Gas pressure is defined as
Select one:
O a. mass per unit area
O b.
O c. force per unit area
O d. force per unit volume
acceleration per unit volume
Answer: b. force per unit area.
Explanation:
A rocket takes off from a space station, where there is no gravity other than the negligible gravity due to the space station, and reaches a speed of 110 m/s in 10.0 s. If the exhaust speed is 1,600 m/s and the mass of fuel burned is 118 kg, what was the initial mass (in kg) of the rocket?
The initial mass of the rocket was 106 kg.
What is the initial mass of the rocket?We can use the principle of conservation of momentum to solve this problem.
The momentum of the rocket before takeoff is zero, since it is at rest, and the momentum after takeoff is the product of the mass of the rocket and its velocity.
However, during the takeoff, the rocket ejects a mass of fuel at a certain velocity, which creates a backward force (thrust) that propels the rocket forward.
This thrust can be calculated using the equation:
Thrust = (mass flow rate) x (exhaust velocity)
mass flow rate = (mass of fuel burned) / (burn time)
The mass of the rocket at any given time can be calculated using the equation:
mass = (initial mass) - (mass of fuel burned)
Using these equations, we can solve for the initial mass of the rocket:
Calculate the thrust:
Thrust = (118 kg / 10.0 s) x 1600 m/s = 1,888 N
Calculate the mass of the rocket at the end of the burn:
mass(end) = (initial mass) - (mass of fuel burned) = (initial mass) - 118 kg
Use the principle of conservation of momentum to find the initial mass:
momentum before = momentum after
0 = (mass(end) + 118 kg) x 110 m/s
mass(end) = -118 kg / 110 m/s = -1.07 kg/s
mass(end) = (initial mass) - 118 kg
(initial mass) = mass(end) + 118 kg
(initial mass) = (-1.07 kg/s x 10.0 s) + 118 kg
(initial mass) = 106 kg
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If a 9 V battery is connect to a 4 ohm resistor, what is the current?
O2.3 A
O 36 A
O 0.44 A
5 A
Answer: Given data
The resistance of the first resistor is R1 = 4 ohm
The resistance of the second resistor is R2 = 5 ohm
The potential difference of the battery is V = 9 V
The resistors are connected in series. The expression for the equivalent resistance is given as:
The expression for the current in the 4-ohm resistor is given as:
Thus, the magnitude of the current flows through the 4-ohm resistor is 1 A.
Explanation:
A carpenter tosses a shingle off a 9.4 m high roof, giving it an initial horizontal velocity of 7.2 m/s.] How far does it move horizontally in this time
Answer:
Explanation:
Assuming negligible air resistance, the horizontal velocity of the shingle will remain constant and the vertical motion will be influenced by gravity.
We can use the kinematic equations of motion to determine the horizontal distance traveled by the shingle. The relevant equation is:
d = v * t
where d is the distance, v is the initial horizontal velocity, and t is the time of flight.
To find the time of flight, we can use the equation for the vertical displacement of an object under constant acceleration:
y = v0t + (1/2)at^2
where y is the vertical displacement, v0 is the initial vertical velocity (which is zero), a is the acceleration due to gravity (-9.8 m/s^2), and t is the time of flight. Solving for t, we get:
t = sqrt((2y)/a)
where sqrt means square root.
Substituting the given values, we have:
y = 9.4 m
a = -9.8 m/s^2
t = sqrt((2*9.4 m) / -9.8 m/s^2) = 1.45 s (using the positive root since time cannot be negative)
Now, we can use the horizontal velocity to find the distance traveled in this time:
d = v * t = 7.2 m/s * 1.45 s = 10.44 m
Therefore, the shingle moves a horizontal distance of 10.44 meters in this time.
6. An 8000.0 kg truck starts off from rest and reaches a velocity of 18.0 m/s in 6.00 seconds. What is the truck’s acceleration and how much momentum does it have after it has reached this final velocity?
The truck's acceleration is 3.0m/s² and the momentum of the truck is 144000 kg m/s.
What is acceleration?It is the rate at which the speed and direction of a moving object vary over time.
We can use the following equation to calculate the acceleration of the truck:
a = (v - u) / t
where
a = acceleration
v = final velocity = 18.0 m/s
u = initial velocity = 0 m/s (the truck starts from rest)
t = time taken = 6.00 s
Substituting the values, we get:
a = (18.0 m/s - 0 m/s) / 6.00 s
a = 3.00 m/s²
Therefore, the acceleration of the truck is 3.00 m/s².
We can use the following equation to calculate the momentum of the truck:
p = m * v
where
p = momentum
m = mass of the truck = 8000.0 kg
v = final velocity = 18.0 m/s
Substituting the values, we get:
p = 8000.0 kg * 18.0 m/s
p = 144000 kg m/s
Therefore, the momentum of the truck after it has reached its final velocity is 144000 kg m/s.
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A student uses 800 W microwave for 30 seconds how much energy does a student use
Answer:
The student used 24000 Joules of energy.
Explanation:
We can use the Energy Power equation to solve this example.
[tex]\sf E=Pt[/tex]
Where
[tex]\sf E[/tex] is the energy in Joules (J)
[tex]\sf P[/tex] is the power in Watts (W)
[tex]\sf t[/tex] is the time in seconds (s)
Numerical Evaluation
In this example we are given
[tex]\sf P=800\\t=30[/tex]
Substituting our given values into the equation yields
[tex]\sf E=800 \cdot 30[/tex]
[tex]\sf E=24000[/tex]
24000 Joules
[tex]\Large\bold{SOLUTION}[/tex]
To calculate the energy used by the student in this scenario, we can use the formula:
[tex]\sf{Energy\: (in\: Joules) = Power\: (in\: Watts) \times Time\: (in\: seconds)}[/tex]
Given that the student uses an 800 W microwave for 30 seconds, we can plug in these values to the formula:
[tex]\sf Energy = 800\: W \times 30\: s = 24,000\: J[/tex]
Therefore, the student uses 24,000 Joules of energy in this scenario.
[tex]\rule{200pt}{5pt}[/tex]
A uniform electric field makes an angle of 60.0∘ with a flat surface. The area of the surface is 6.66×10−4m2. The resulting electric flux through the surface is 4.44 N⋅m2/C.
Calculate the magnitude of the electric field.(Express your answer with the appropriate units.)
Answer:
Explanation:
The electric flux through a surface is given by the equation:
Φ = EAcos(θ)
where Φ is the electric flux, E is the electric field, A is the area of the surface, and θ is the angle between the electric field and the surface normal.
We are given Φ = 4.44 N⋅m2/C, A = 6.66×10−4 m2, and θ = 60.0∘. Substituting these values into the equation above and solving for E, we get:
E = Φ / (Acos(θ))
= 4.44 N⋅m2/C / (6.66×10−4 m2cos(60.0∘))
= 1.62×10^4 N/C
Therefore, the magnitude of the electric field is 1.62×10^4 N/C.
The magnitude of the electric field is 13,320 N/C.
What is electric flux?The electric flux through a surface is defined as the product of the electric field and the area of the surface projected perpendicular to the electric field. Mathematically, we can write:
Φ = EAcos(θ)
where Φ is the electric flux, E is the electric field, A is the area of the surface, and θ is the angle between the electric field and the surface normal.
Here in the Question,
We are given the electric flux Φ = 4.44 N·m^2/C, the area A = 6.66×10^-4 m^2, and the angle θ = 60.0°. We can solve for the magnitude of the electric field E by rearranging the equation as follows:
E = Φ / (A*cos(θ))
Substituting the given values, we get:
E = 4.44 N·m^2/C / (6.66×10^-4 m^2*cos(60.0°))
Simplifying the denominator, we get:
E = 4.44 N·m^2/C / (6.66×10^-4 m^2*0.5)
E = 13,320 N/C
Therefore, 13,320 N/C is the magnitude of the electric field.
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What is the defining property of an mechanical wave?
A. It travels by compressing particles.
B. It travels up and down.
C. It does not need a medium to travel.
D. It needs a medium to travel.
Answer: D. It needs a medium to travel.
Explanation:
One way to categorize waves is on the basis of the direction of movement of the individual particles of the medium relative to the direction that the waves travel. Categorizing waves on this basis leads to three notable categories: transverse waves, longitudinal waves, and surface waves.
460miles per hour with the wind nd 420 per hour gainst the wind
The speed of the wind is 20 miles per hour.
To solve this problem, we can use the formula:
Speed = Distance/Time
Let's assume that the speed of the wind is x miles per hour.
With the wind, the plane travels at a speed of 460 miles per hour. This means that its speed relative to the ground is the sum of its airspeed and the speed of the wind:
460 = Airspeed + x
Against the wind, the plane travels at a speed of 420 miles per hour. This means that its speed relative to the ground is the difference between its airspeed and the speed of the wind:
420 = Airspeed - x
We can solve this system of equations to find the airspeed of the plane:
460 = Airspeed + x
420 = Airspeed - x
Adding the two equations gives:
880 = 2Airspeed
Dividing both sides by 2 gives:
Airspeed = 440 miles per hour
Now that we know the airspeed of the plane, we can find the speed of the wind by substituting this value into one of the equations we obtained earlier:
460 = Airspeed + x
460 = 440 + x
x = 20
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What factors would create an ideal circuit?
An ideal circuit is a theoretical representation of an electrical circuit, where all components are perfect and all parameters such as resistance, capacitance, and inductance are zero.
The ideal circuit also has no energy losses, making it an ideal electrical system. To create an ideal circuit, the following factors must be considered:
1. Perfectly Conductive Wires: The wires and other conductors used in the circuit should be perfect conductors, which means the resistance should be zero. This will ensure that no energy is lost in the form of heat.
2. Zero Inductance: Inductance is a property of a circuit which causes a voltage drop when current flows through it. The ideal circuit should have no inductance so that the current can flow freely.
3. Zero Capacitance: Capacitance is a property in which electric charge builds up when current passes through it. To create an ideal circuit, the capacitance should be zero.
4. Zero Impedance: Impedance is the opposition to the flow of current in an electrical circuit. The ideal circuit should have zero impedance so that the current can flow freely.
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A loudspeaker of mass 15.0 kg is suspended a distance of h = 1.00 m below the ceiling by two cables that make equal angles with the ceiling. Each cable has a length of l = 2.70 m .
1. What is the tension T in each of the cables?
Use 9.80 m/s2 for the magnitude of the free-fall acceleration.
Answer:
To solve the problem, we use the equations of equilibrium to find the tension in each cable holding up the loudspeaker. Since the loudspeaker is in equilibrium, the sum of the forces acting on it is zero. The weight of the loudspeaker is calculated first, and then we use trigonometry to find the horizontal and vertical components of the tension in one of the cables. We then apply the equation of equilibrium in the y direction to find the tension in each cable. The final answer is that the tension in each cable is approximately 81.1 N, which balances the weight of the loudspeaker.
___
Given:
Mass of loudspeaker (m) = 15.0 kg
Distance from ceiling (h) = 1.00 m
Length of cable (l) = 2.70 m
Acceleration due to gravity (g) = 9.80 m/s^2
Weight of loudspeaker:
Fg = mg
Fg = (15.0 kg)(9.80 m/s^2)
Fg = 147 N
Horizontal and vertical components of tension in one cable:
sinθ = h/l
sinθ = 1.00 m / 2.70 m
θ = sin^(-1)(1.00/2.70)
θ ≈ 21.6°
T_x = T sinθ
T_y = T cosθ
where T is the tension in the cable.
Equation of equilibrium in y direction:
ΣF_y = 2T cosθ - Fg = 0
Solving for T:
2T cosθ = Fg
T = Fg / (2 cosθ)
Plugging in the values:
T = (147 N) / (2 cos(21.6°))
T ≈ 81.1 N
(a) Find the frequency ratio between the two frequencies fi =256 Hz and f2 = 320 Hz. (b) Add the interval of a fifth to f2 to obtain fs, and find the frequency ratio fs/fi. (c) Find the frequency of f3.
(a) The frequency ratio between the two frequencies fi = 256 Hz and f2 = 320 Hz is:
[tex]\frac{f_2}{f_i} = \frac{320}{256} = \frac{5}{4} = 1.25[/tex]
So the frequency ratio is 1.25.
(b) Adding the interval of a fifth to f2 = 320 Hz gives:
fs = f2 * (3/2) = 320 * (3/2) = 480 Hz
The frequency ratio fs/fi is:
[tex]\frac{f_s}{f_i} = \frac{480}{256} = \frac{15}{8} = 1.875[/tex]
So the frequency ratio is 1.875.
(c) To find the frequency of f3, we need to add the interval of a fourth to f2:
f3 = f2 * (4/3) = 320 * (4/3) = 426.67 Hz
Therefore, the frequency of f3 is 426.67 Hz.
a mass of 20kg is held stationary by a rope passing over a frictionless pally. what is the tension T in the rope?
The tension in the rope is 196.2 N. The rope is exerting a force of 196.2 N on the object to keep it stationary.
Assuming that the mass is not accelerating, the tension in the rope must be equal to the weight of the mass. The weight of the mass can be found using the formula:
weight = mass x acceleration due to gravity
where acceleration due to gravity is approximately 9.81 m/s².
Therefore, the weight of the mass is:
weight = 20 kg x 9.81 m/s² = 196.2 N
Since the mass is held stationary, the tension in the rope must be equal to the weight of the mass, which is 196.2 N. So the tension T in the rope is 196.2 N.
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1 Suppose the displacement of particle P from origin at time t is given by x(t)=t²-6t find the average velocity and acceleration of p over the time interval 1 <=t<=3 sec
Answer:
-2 m/s and the average acceleration is 2 m/s².
Explanation:
To find the average velocity of particle P over the time interval 1<=t<=3 sec, we need to use the following formula:
average velocity = (final displacement - initial displacement) / (final time - initial time)
In this case, the initial time is 1 sec and the final time is 3 sec. Therefore, the initial displacement is:
x(1) = 1² - 6(1) = -5
And, the final displacement is:
x(3) = 3² - 6(3) = -9
Now, we can substitute the values in the formula:
average velocity = (-9 - (-5)) / (3 - 1) = -2 m/s
To find the average acceleration of particle P over the time interval, we need to use the following formula:
average acceleration = (final velocity - initial velocity) / (final time - initial time)
We know that the initial time is 1 sec, the final time is 3 sec, and the initial velocity is the velocity at time t=1 sec. Therefore, the initial velocity is:
v(1) = 2t - 6 = 2(1) - 6 = -4 m/s
We also know that the final velocity is the velocity at time t=3 sec. Therefore, the final velocity is:
v(3) = 2t - 6 = 2(3) - 6 = 0 m/s
Now, we can substitute the values in the formula:
average acceleration = (0 - (-4)) / (3 - 1) = 2 m/s²
Therefore, the average velocity of particle P over the time interval 1<=t<=3 sec is -2 m/s and the average acceleration is 2 m/s².
If you lift one load up one story, how much more work do you do lifting one load up
three stories?
Answer:
Explanation:
alot
A 2.1 x 103 kg car starts from rest in a driveway. An average force of 4.0 x 103 N act on the car so that the car’s speed at the end of the driveway is 3.8 m/s. What was the length of the driveway?
Answer:
Explanation:
We can use the kinematic equation v^2 = u^2 + 2as to solve for the length of the driveway. Here, u = 0 (since the car starts from rest), v = 3.8 m/s, a = F/m = 4.0 x 10^3 N / 2.1 x 10^3 kg = 1.9 m/s^2. Solving for s, we get:
s = (v^2 - u^2) / 2a = (3.8^2) / (2 x 1.9) = 3.8 m
So the length of the driveway is 3.8 meters.
What might happen if people did not have the rights established in Miranda v. Arizona
Answer:
If people did not have the rights established in Miranda v. Arizona, they could be subjected to police coercion and forced confessions without a lawyer present. This could lead to wrongful convictions and denial of due process, which are essential components of the American justice system
A 300 g football is kicked with an initial velocity of 140 m/s in a direction that
makes a 30° angle with the horizon. Find the peak height of the football.
Answer:
Explanation:
Assuming that air resistance is negligible, we can use the following kinematic equations to solve for the peak height:
v_f^2 = v_i^2 + 2ad
where v_f = 0 m/s (at the peak height) and a = -9.8 m/s^2 (acceleration due to gravity)
and
d = v_i t + (1/2)at^2
where d is the displacement or the peak height we want to find, v_i is the initial velocity, t is the time it takes to reach the peak height.
First, we need to resolve the initial velocity into its vertical and horizontal components:
v_i_x = v_i cos(30°) = 121.1 m/s
v_i_y = v_i sin(30°) = 70.0 m/s
Next, we can use the vertical component of the initial velocity to find the time it takes to reach the peak height:
v_f = v_i_y + at
0 m/s = 70.0 m/s + (-9.8 m/s^2)t
t = 7.14 s
Finally, we can use the time we found and the kinematic equation for displacement to find the peak height:
d = v_i_y t + (1/2)at^2
d = (70.0 m/s)(7.14 s) + (1/2)(-9.8 m/s^2)(7.14 s)^2
d = 247.5 m
Therefore, the peak height of the football is 247.5 meters.
a metal block of density 900kg weight 60newton in air find it's weight when it is immersed in paraffin wax of density 800kg
Answer:
We can use the concept of buoyancy to solve this problem.
The weight of the metal block in air is equal to the force of gravity acting on it, which is given as 60 Newtons. When the block is immersed in paraffin wax, it displaces a certain volume of wax equal to its own volume, and experiences an upward force due to buoyancy that partially cancels out the force of gravity acting on it.
The buoyant force acting on the block is given by the formula:
buoyant force = weight of fluid displaced
= density of fluid x volume of fluid displaced x acceleration due to gravity
The weight of the metal block in the paraffin wax is then equal to the difference between the weight of the block in air and the buoyant force acting on it.
Let's calculate the volume of the metal block first:
density of metal block = 900 kg/m³
weight of metal block in air = 60 N
acceleration due to gravity = 9.81 m/s²
weight of metal block = density of metal block x volume of metal block x acceleration due to gravity
volume of metal block = weight of metal block / (density of metal block x acceleration due to gravity)
= 60 N / (900 kg/m³ x 9.81 m/s²)
= 0.006536 m³
Now, let's calculate the weight of the metal block in the paraffin wax:
density of paraffin wax = 800 kg/m³
buoyant force = density of fluid x volume of fluid displaced x acceleration due to gravity
= 800 kg/m³ x 0.006536 m³ x 9.81 m/s²
= 51.02 N
weight of metal block in paraffin wax = weight of metal block in air - buoyant force
= 60 N - 51.02 N
= 8.98 N
Therefore, the weight of the metal block when it is immersed in paraffin wax of density 800 kg/m³ is 8.98 Newtons.
When a ball is thrown into the air, its kinetic energy is lowest
A at its highest point.
B. at the moment it is released.
C. as it begins to fall back to the ground.
waves are generated in a rope of length 6m. What is the speed of the wave if its period is 25.m
The speed of the wave would be0.48 m/s.
Speed of a waveThe speed of a wave is given by the formula:
v = λ/T
where v is the wave speed, λ (lambda) is the wavelength, and T is the period.
To solve this problem, we need to know the wavelength of the wave. We can find the wavelength using the formula:
λ = 2L
where L is the length of the rope. Substituting L = 6 m, we get:
λ = 2 × 6 m = 12 m
Now we can use the formula for wave speed:
v = λ/T
Substituting λ = 12 m and T = 25 s, we get:
v = 12 m/25 s = 0.48 m/s
Therefore, the speed of the wave is 0.48 m/s.
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Which type of marco molecules help a cell break down food?
Answer: Each macromolecule is broken down by a specific enzyme. For instance, carbohydrates are broken down by amylase, sucrase, lactase, or maltase. Proteins are broken down by the enzymes pepsin and peptidase, and by hydrochloric acid. Lipids are broken down by lipases.
Explanation:
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Student A has a mass of 95 kg and student B has a mass of 82 kg. If their centers of mass are
0.6 meters apart, what will be the gravitational force each student exerts on the other?
Round your answer to the nearest whole number.
Answer:
0 Newtons, to the nearest whole number
Explanation:
Using the formula attached to this answer,
F = (6.67 x 10-¹¹ • 95 • 82) / 0.6²
F = 5.19593 x 10-⁷ / 0.36
F = 1.4433 x 10-⁶ N
F = 0.000001443 N
To the nearest whole number
F = 0 N
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It is fun to exercise outside, but you have to be careful when it's hot. What are two things you should always do when you exercise in the heat?
Answer:
When exercising in the heat, it's important to take precautions to prevent heat-related illnesses. Two things you should always do when exercising in the heat are:
1.Stay hydrated: Drink plenty of water before, during, and after your workout to avoid dehydration. Sip water frequently, even if you don't feel thirsty.
2.Take breaks and rest in the shade: If you start feeling dizzy, lightheaded, or excessively fatigued, take a break in a cool, shaded area. Resting can help your body cool down and prevent heat exhaustion or heat stroke.
Explanation:
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Which of the following does a scientist NOT need to calculate the age of something?
Amount of radioactive isotope within a sample
Half-life of radioactive isotope
Abundance on Earth
100g of the sample
Answer:
Abundance on Earth is not necessary for calculating the age of something using radioactive dating methods.
In contrast, the amount of radioactive isotope within a sample and its half-life are crucial for determining the age of the sample using radioactive dating methods. The amount of sample, such as 100g, is also important for determining the quantity of radioactive isotopes present, which is used in the calculation of the age of the sample.
Two hot air balloons with the same mass and amount of helium put inside of them if one is a rigid material and the other expands which one would be the highest?
Answer:
One is that atmospheric pressure is dramatically reduced at high altitudes, so a helium balloon expands as it rises and eventually explodes. If you inflate a balloon beyond its limits at room temperature, it will break into small pieces up to about ten centimetres long
Explanation:
Use the data in the table to determine the identities of the two gasses that you found could be components of water. Provide evidence to support your claim.
The two gases that could be components of water are indeed hydrogen and oxygen.
Evidence to support this claim:
1. The chemical formula for water is H2O, which means that it is composed of two hydrogen atoms and one oxygen atom.
2. The table of elements shows that hydrogen (H) and oxygen (O) are both elements that exist in nature.
3. The atomic mass of hydrogen (1.008) and oxygen (15.999) matches the molecular mass of water (18.015).
4. Water is produced when hydrogen gas (H2) is burned in the presence of oxygen gas (O2), according to the following equation: 2H2 + O2 → 2H2O.
Overall, the evidence supports the conclusion that hydrogen and oxygen are the two gases that could be components of water.
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