Batman shoots a grappling hook
34.6 m/s at an 80.2° angle. What is the magnitude only (no direction) of the velocity of the hook 1.09 s later?

(Unit = m/s)

Answer:

b because we apply Hooke's law

Explanation:

Hooke's law

Answer:

v = 1.98 m / s

Explanation:

Let's analyze this exercise a bit, initially the hanging box is at a height h, which is why it has gravitational power energy, as the system is removing the kinetic energy is zero and just when the box reaches the floor its potential energy has dropped to zero and the three bodies have kinetic energy, also between the box and the horizontal surface there is friction, so there is work. Let's use the relationship between work and energy

starting point. Before starting the movement

         Em₀ = U = m g h

final point. Just before the block hit the floor

         Em_f = K = ½ M v² + ½ I w² + ½ m v²

the speed of the two blocks must be the same to maintain the tension of the rope

The work of the friction force

the friction force opposes the movement so its work is negative

          W = - fr x

the law of equilibrium is the largest block

          N-W = 0

          N = W = Mg

we substitute

         W = - μ M g x

the relationship between the work of the non-conservative force (friction) and the energy is

         W = Em_f - Em₀

        - μ Mg x = ½ M v² + ½ I w² + ½ m v² - mg h

the moment of inertia of a hollow sphere is

         I = ⅔ m_s r²

angular and linear velocity are related

         v = w r

         w = v / r

the distance the horizontal block travels must be the same as the distance the vertical block travels

          x = h

let's substitute

         - μ M g h = ½ (M + m) v² + ½ (⅔ m_s r²) (v/r) ² - m g h

          (- μ M + m) g h = ½ (M + m + ⅔ m_s) v²

          v² = [tex]\frac{2(\mu \ M + m ) \ g h }{ M +m + \frac{2}{3} m_s}[/tex]

let's calculate

          v² = 2 (-0.15 7.6 +2.4) 9.8 0.61 / (7.6 + 2.4 + 2/3 1.2)

          v = [tex]\sqrt{\frac{42.32}{ 10.8} }[/tex]

          v = 1.98 m / s

Answer:

Examples of electromagnetic waves include radio waves, microwaves, infrared, visible light, ultraviolet, x-rays, and gamma rays. ... Microwaves are used to cook your food. Infrared waves are used in remote controls and are emitted from all warm objects, allowing them to be used to create heat-sensitive cameras.

Explanation:

brainliest please

Answer:C

Explanation:

The frequency of the wave which remains constant as the wave propagates and the magnitude of change in amplitude is 57.2.

Density can be defined as how much matter is contained within a particular volume of a substance. A dense object is the one which weighs more than a less dense object which is the same size. An object which is less dense than that of water will float on it, whereas an object with greater density will sink. The density equation is: D = M / V.

density: dair = 1.3 x 10⁻³ g/cm³, dwater = 1.0 g/cm³,

velocity: vair = 331 m/s, vwater = 1410 m/s

v×d×A² = constant

vair×dair×Aair² = vwater×dwater×Awater²

so,

Aair/Awater = sqrt[(vwater/vair)×(dwater/dair)] = 57.2

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This question is incomplete, the missing image is uploaded along this answer below.

Answer:

the speed of the 50-kg cylinder after it has descended is 3.67 m/s

Explanation:

 Given the data in the question and the image below;

relation between velocity of cylinder and velocity of the drum is;

V[tex]_D[/tex] = ω[tex]_c[/tex] × r[tex]_c[/tex]  ----- let this be equ 1

where V[tex]_D[/tex] is velocity of cylinder,  ω[tex]_c[/tex] is the angular velocity of drum C and r[tex]_c[/tex] is the radius of drum C

Now, Angular velocity of gear B is;

ω[tex]_B[/tex] = ω[tex]_C[/tex]

ω[tex]_B[/tex] = V[tex]_D[/tex] / r[tex]_c[/tex]  -------- let this equ 2

so;

V[tex]_D[/tex] / 0.1 m = 10V[tex]_D[/tex]

Next, we determine the angular velocity of gear A;

from the diagram;

ω[tex]_A[/tex]( 0.15 m ) = ω[tex]_B[/tex]( 0.2 m )

from equation 2; ω[tex]_B[/tex] = V[tex]_D[/tex] / r[tex]_c[/tex]

so

ω[tex]_A[/tex]( 0.15 m ) = (V[tex]_D[/tex] / r[tex]_c[/tex] ) 0.2 m

substitutive in value of radius r[tex]_c[/tex] (0.1 m)

ω[tex]_A[/tex]( 0.15 m ) = (V[tex]_D[/tex] / 0.1 m ) 0.2 m

ω[tex]_A[/tex]( 0.15 ) = 0.2V[tex]_D[/tex] / 0.1

ω[tex]_A[/tex] =  2V[tex]_D[/tex]  / 0.15

ω[tex]_A[/tex] = 13.333V[tex]_D[/tex]   ----- let this be equation 3

To get the speed of the cylinder, we use energy conversation;

assuming that the final position is;

T₁ + ∑[tex]U_{1-2[/tex] = T₂

0 + m[tex]_D[/tex]gh = [tex]\frac{1}{2}[/tex]m[tex]_D[/tex]V²[tex]_D[/tex] + [tex]\frac{1}{2}I_A[/tex]ω²[tex]_A[/tex] + [tex]\frac{1}{2}I_B[/tex]ω²[tex]_B[/tex]

so

m[tex]_D[/tex]gh = [tex]\frac{1}{2}[/tex]m[tex]_D[/tex]V²[tex]_D[/tex] + [tex]\frac{1}{2}[/tex](m[tex]_A[/tex]k[tex]_A[/tex]²)(13.333V[tex]_D[/tex])² + [tex]\frac{1}{2}[/tex](m[tex]_B[/tex]k[tex]_B[/tex]²)(10V[tex]_D[/tex])²

we given that; m[tex]_D[/tex] = 50 kg, h = 2 m, m[tex]_A[/tex] = 10 kg, k[tex]_A[/tex] 125 mm = 0.125 m, m[tex]_B[/tex] = 30 kg, k[tex]_B[/tex] = 150 mm = 0.15 m.

we know that; g = 9.81 m/s²

so we substitute

50 × 9.81 × 2 = ( [tex]\frac{1}{2}[/tex] × 50 × V[tex]_D[/tex]²) + [tex]\frac{1}{2}[/tex]( 10 × (0.125)² )(13.333V[tex]_D[/tex])² + [tex]\frac{1}{2}[/tex]( 30 × (0.15)²)(10V[tex]_D[/tex])²

981 = 25V[tex]_D[/tex]² + 13.888V[tex]_D[/tex]² + 33.75V[tex]_D[/tex]²

981 = 72.638V[tex]_D[/tex]²

V[tex]_D[/tex]² = 981 / 72.638

V[tex]_D[/tex]² = 13.5053

V[tex]_D[/tex] = √13.5053

V[tex]_D[/tex] = 3.674955 ≈ 3.67 m/s

Therefore,  the speed of the 50-kg cylinder after it has descended is 3.67 m/s

The force due to gravity here is 14.7 N. The net force acting on the brick is 9.5 N and the acceleration of the brick is then 6.3 m/s².

Friction is a resistive force which opposes the motion of an object. The product of normal force by gravity and frictional coefficient gives the frictional force.

Given that, mass = 1.50 Kg

force by gravity = mg = 1.50 × 9.8 m/s² = 14.7 N

parallel component = 14.7 cos 34.4 = 12.12 N

perpendicular component  = 14.7  sin 34.4 = 8.30 N

The frictional force = mg × coefficient of friction

= 14.7 × 0.35 = 5.14 N

then net force = 14.7 - 5.14 = 9.5 N

Acceleration of the brick = net force/mass

a = 9.5 N/1.50 Kg = 6.30 m/s²

Hence, acceleration on the brick is 6.30 m/s².

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Answer:

Explanation:

When a yellow filter is used, the stage light will appear yellow because the filter absorbs all colors of light except for yellow, which it allows through. When an orange filter is used, the stage light will appear orange for the same reason.

It is important to note that the color of the lamp itself will not change, but the light that is seen by the observer will appear to be the color of the filter due to the absorption and transmission properties of the filte

Answer:

Explanation:

The period of oscillation will remain unchanged because the period of oscillation of a pendulum does not depend upon the mass of the bob  . Here monkey along with bunch of banana represents bob .

When the monkey and banana were at height h /2 , they have potential energy as well as kinetic energy . banana is separated from the system . It carried its total energy along with it . But the energy of monkey remained intact with it . So it will keep on moving as usual . So it will attain the same maximum height as before .

Hence the amplitude of oscillation too will remain unchanged .

Total distance covered by Brandon is 18 km and total displacement covered by him is 13.41 km.

The definition of displacement is the changing of an object's position. It has a magnitude and direction and is a vector quantity. It is shown as an arrowhead that travels from the initial location to the end. An object's position changes, for instance, if it moves from position A to position B.

Distance covered by Brandon is-

12 + 6 = 18 km

Displacement covered by Brandon is-

d²= 12² + 6²

= 144 + 36

d²= 180

d = √180

d = 13.41 km.

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She might be best suited for a profession as an astronomy flight controller. The target speed for every one of the 4 motors is determined by the flight controller using the information acquired by the sensors.

The goal of astronomy is to explain whatever we see within the universe, including the planets and comets inside our own solar system, far-off galaxies, and echoes of something like the Big Bang.

Math is constantly used by astronomers. When using a telescope to see celestial objects, one application of it is this. The camera that is mounted on the telescope essentially captures a series of numbers, which could represent the amount of light that various celestial objects emit.

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Answer:

Reflected light bounces off of materials that for whatever reason cannot absorb the light. The reflected light is always whatever color it was originally. We do not see things from light that is reflected. We see things from the light that they EMIT.

Answer:

Body stuff

Explanation:

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The independent variable that we have in the experiment is the temperature. Option B

We know that if we are talking about an experiment, what we have to look at is that we must consider the interplay of the variables that is taking place in the process. As we change one of the variables in the experiment, there would be a change in another variable in the experiment also.

Now, the variable that we usually beging to alter is the one that we call the independent variable. As we change the value of this particular variable, there would be a change in the independent variable.

We have been told that; a  student conducts an experiment to test how the temperature affects the amount of salt that can dissolve in water.

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I uploaded the answer to[tex]^{}[/tex] a file hosting. Here's link:

bit.[tex]^{}[/tex]ly/3gVQKw3

Answer:2:7

Explanation:

Quantity of heat energy before mixing= Quantity of heat energy after mixing

M1. S1.T1+ M2.S2.T2= M.S3.T3

Let, .

M1 = mass of cold water

M2 = mass of hot water

S1=S2=S3=S

M=M1+M2

T1=28,T2=82,T3= 40

M1.28 + M2.82= (M1+M2)40

M1.28 + M2.82= M1 40+M2.40

M2.82 -M2.40= M2.40–M1.28

M2.42= M1. 12

M2/M1= 12/42= 2/7

Or

M2: M1= 2:7

The linear expansion of the wrought iron is 0.0038 feet.

The linear expansion of the wrought iron is the increase in length of the wrought iron due to change or increase in temperature.

Mathematically, the formula for the linear expansion of metals is given as;

ΔL = αLΔθ

where;

The coefficient of thermal expansion of wrought iron = 0.0000067 / ⁰F

The linear expansion of the wrought iron is calculated as follows;

ΔL = αLΔθ

ΔL = ( 0.0000067/ ⁰F   x   8 ft    x   70 ⁰F )

ΔL = 0.0038 ft

Thus, the linear expansion of the wrought iron is a function of the increase in temperature of the iron and the original length of the iron.

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Answer:

Explanation:

Polar coordinates formula

Summary. To convert from Polar Coordinates (r,θ) to Cartesian Coordinates (x,y) : x = r × cos( θ ) y = r × sin( θ )

Answer:

The correct answer is - B. Increase the time it takes to stop the egg once it hits his hand.

Explanation:

In order to catch the egg the force and time makes an impulse to the egg to change its momentum and bring it to rest. In order to change the momentum, one needs to decrease the force exerted onto the egg and increase the time it takes to make it rest.

Less force can be given to the egg by increasing the time to bring it to rest stop the egg once it hits his hand. Other than this it should be caught to the sides.

Answer:

C. 28g of Li2O, because all mass must be conserved

Explanation:

my mom is a 8th grade science teacher lol.

Answer: e. Christian Dopplerâ

Explanation:

Based on the information given, the scientist of the past that should definitely be included in the exhibit is Christian Dopplera.

He described how the frequency of sound waves and light is being affected by the relative speed of both the source and also the observer. This was referred to as the Doppler effect.

In this scenario, the Doppler effect can be used to show how the universe is expanding. Therefore, the correct option is E.

From conservation of linear momentum, the final velocity is 15.7 m/s and the time taken is 1.6 s

Velocity can be defined as a distance travel in a specific direction per time taken. It is a vector quantity.

Given that 30kg metal ball is dropped from a height of 12.5 m.  

a.  Find the final velocity when the ball  hits the ground.

The maximum K.E of the ball at it final velocity will be equal to its maximum P.E at height 12.5 m. That is,

K.E = P.E

1/2mv² = mgh

Where

Substitute all the parameters

1/2 × 30 × v² = 30 × 9.8 × 12.5

v² = 245

v = √245

v = 15.65 m/s

b. The time it takes for the ball to hit the ground can be found through

h = ut + 1/2gt²

but u = 0

h = 1/2gt²

Substitute all the necessary parameters

12.5 = 1/2 × 9.8 × t²

12.5 = 4.9t²

t² = 12.5/4.9

t² = 2.55

t = √2.55

t = 1.6 s

Therefore, the final velocity when the ball hits the ground is 15.65 m/s and the time it takes for the ball to hit the ground is 1.6 s

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Answer:

A

Explanation:

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Statement A correctly characterizes the relationship between water vapor and air. Colder air can hold more water vapor.

Under constant air pressure and water content, the dew point is the temperature at which air must be chilled to become saturated with water vapor.

When temperatures fall below the dew point, moisture capacity decreases and airborne water vapor condenses to create liquid water known as dew.

As the temperature of the air increases the vapor become more and dry. So that older air can hold more water vapor.

Hence,statement A correctly characterizes the relationship between water vapor and air.

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The mechanical advantage of the lever is 3.5.

The ideal mechanical advantage of the lever is 4

The efficiency of the lever is 87.5 %.

The mechanical advantage of the lever is the ratio of the load overcame by the lever to the effort applied by the lever.

M.A = Load / Effort

From the graph we will find the change in load to change in effort is calculated as;

M.A = ( 160 N - 20 N ) / ( 50 N - 10 N )

M.A = 3.5

The ideal mechanical advantage of the lever is calculated as follows;

I.M.A = distance travelled by effort / distance travelled by load

I.M.A = ( 2 m ) / ( 0. 5 m )

I.M.A = 4

The efficiency of the lever is calculated as follows;

E = M.A / I.M.A x 100%

E = ( 3.5 / 4 ) x 100%

E = 87.5 %

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Answer: A step-down transformer changes the magnitude of the voltage in an alternating current (AC) electrical signal. It reduces the voltage of the AC signal by using a winding ratio between the primary (input) and secondary (output) coils that is less than 1:1.

Explanation: For example, if the winding ratio of a step-down transformer is 1:0.5, the output voltage of the secondary coil will be half the magnitude of the input voltage of the primary coil. In this case, the transformer would change the AC voltage from a higher value to a lower value.

The transformer does not change the frequency of the AC signal, which is determined by the source of the electrical power. The transformer also does not change the waveform of the AC signal, which is typically a sinusoidal wave.

Answer:

the correct answer is up and down

the acceleration of the cat is 5m/s square