The question is incomplete. Here is the complete question.
As mentioned in problem 1.2 from Chapter 1, if you stand on one leg the load exerted on the hip jpint is 2.4 times your body weight. Assuming a simple cylindrical model for the implant, calculate the corresponding stress (in MPa) on a hip implant in a 175lb individual with a hip implant with cross-sectional area of 5.6cm². If the implant is made of Ti6AI4V (124 GPa elastic modulus), what is the atrain for the given loading conditions?
Answer: σ = 3.336 MPa
Strain = 2.69.[tex]10^{-5}[/tex]
Explanation: Stress is the measurement of how hard a weight works to change a material's shape. Its symbol is σ and is calculated as
[tex]\sigma = \frac{F}{A}[/tex]
where
F is force
A is cross sectional area
For the hip implant, force is 2.4x of an 175lb individual:
F = 2.4 * 175
F = 420lb
As the question is asking for Pa and 1 Pa = 1 N/m², transform lb in Newtons:
F = 420lb * 4.448N/lb
F = 1868 N
And cm² in m²:
A = [tex]5.6.10^{-4}[/tex] m²
Calculating Stress:
[tex]\sigma=\frac{1868}{5.6.10^{-4}}[/tex]
[tex]\sigma=333.6.10^{4}[/tex] Pa
or
σ = 3.336 MPa
Stress on a hip implant of an individual with weight 175lb is 3.336 MPa.
Strain is the measure of the deformation of a material due to a load. It can be calculated as:
strain = [tex]\frac{stress}{modulus}[/tex]
But first, change MPa into GPa:
3.336 MPa = [tex]3.336.10^{-3}[/tex] GPa
strain = [tex]\frac{0.003336}{124}[/tex]
strain = [tex]2.69.10^{-5}[/tex]
Ti6Al4V is a titanium alloy used in implants. So, the strain the alloy does on a hip implant of a 175lb individual is [tex]2.69.10^{-5}[/tex].
correct me if im wrong for #16
A worker pushes on a crate, and it experiences a net force of
300 N. If the crate moves with an acceleration of 0.750 m/s2
,
what is its mass?
We are given:
F = 300N
acceleration (a) = 0.750 m/s²
Solving for the mass of the object:
We know from the second equation of motion:
F = ma
replacing the variables
300 = m * 0.75
m = 300 * 100/ 75
m = 300 * 4/3
m = 100 * 4
m = 400 kg
Classes are canceled due to snow, so you take advantage of the extra time to conduct some physics experiments. You fasten a large toy rocket to the back of a sled, and take the modified sled to a large, flat, snowy field. You ignite the rocket, and observe that the sled accelerates from rest in the forward direction at a rate of 13.5 m/s2 for a time period of 3.30 s. After this time period, the rocket engine abruptly shuts off, and the sled subsequently undergoes a constant backward acceleration due to friction of 6.15 m/s2.After the rocket turns off, how much time does it take for the sled to come to a stop?By the time the sled finally comes to a rest, how far has it traveled from its starting point?
Answer:
-time it takes for the sled to come to a stop after launch of rocket = 7.244 s
-distance sled has travelled from its starting point by the time it finally comes to rest is = 234.8655 m
Explanation:
From the question, looking at the motion while accelerating, we have;
Initial velocity; u = 0 m/s
Acceleration; a = 13.5 m/s²
Time; t = 3.3 s
Let's use first equation of motion to find final velocity (v).
v = u + at
v = 0 + (13.5 × 3.3)
v = 44.55 m/s
In this forward direction, let's calculate the displacement(d1) using newton's 3rd equation of motion.
d1 = ut + ½at²
d1 = 0(3.3) + ½(13.5 × 3.3²)
d1 = 73.5075 m
Now, let's consider the motion while slowing down and our final velocity will be 0 m/s while initial velocity will now be 44.55 m/s while acceleration is 6.15 m/s².
Thus, from v = u + at, we can find the time it take for the sled to come to a stop.
Now, since it's coming to rest acceleration will be negative. Thus;
0 = 44.55 + (-6.15t)
0 = 44.55 - 6.15t
t = 44.55/6.15
t = 7.244 s
Now we want to find out how far the sled has travelled from its starting point by the time it finally comes to rest.
Thus, we'll use the equation;
v² = u² + 2as
Where s will be the second displacement which we will call d2.
Thus;
0² = 44.55² + (-2 × 6.15 × s)
0 = 1984.7025 - 12.3s
12.3s = 1984.7025
s = 1984.7025/12.3
s = 161.358
Thus, d2 = s = 161.358 m
Thus, distance sled has travelled from its starting point by the time it finally comes to rest is ;
= d1 + d2 = 73.5075 + 161.358 = 234.8655 m
Titan is special because
what is the net force?
URGENT! thank you
1. Three kids in a parking lot launch a rocket that rises
into the air along a 380-m long arc in 40s.
Determine its average speed.
Answer:
Average speed equals distance / time
380 / 40 = 9.5 m/s.
Explanation:
What are the different ways that the simulation shows you that the equation is balanced, visually? For each balanced reaction, indicate the total number of molecules (the big coefficients) in the table. Reaction Total Number of Molecules Reactant Side (left) Product Side (right) Make Ammonia Separate Water Combust Methane Is the number of total molecules on the left side of a balanced equation always equal to the number of total molecules on the right side of the equation? Explain your answer. For each balanced reaction, indicate the total number of atoms (the individual atoms) in the table. Hint: This may requiring multiplying subscript numbers by coefficients for some atoms. Example: 2NH3–There are 2 N atoms, and 6 H atoms (2 x 3). Reaction Total Number of Atoms Reactant Side (left) Product Side (right) Make Ammonia Separate Water Combust Methane Is the number of total atoms on the left side of a balanced equation always equal to the number of total atoms on the right side of the equation? What strategies did you use when you played the balancing chemical equations game? Which atoms were the easiest to start examining to try to balance the equations? Did it require trial and error? In the simulation, were you able to use non-integer numbers (like ½ or 0.43) for the coefficients in a balanced equation?
Answer:
There are three different ways that the equation is represented visually when it is balanced. First, the scale is at equilibrium when it is balanced. The balance turns yellow and a smiley face appears. Second, the graph shows equal amounts on both the reactant and product side of the equation. Third, within the individual molecule box, there should be the same number of each element on both the product and a reactant side of the equation.
Reaction Total Number of Molecules
Reactant Side (left) Product Side (right)
Make Ammonia 4 2
Separate Water 2 3
Combust Methane 3 3
No, the number of total molecules on the left side of a balanced equation is not equal to the number of total molecules on the right side of the equation. A molecule is the smallest number of atoms bonded together for a chemical reaction. The total number of atoms must be the same, but not molecules. The reactants and products will bond together in different ways leading to different numbers of reactants and products.
Reaction Total Number of Atoms
Reactant Side (left) Product Side (right)
Make Ammonia 1C, 4H, 4O 1 C, 4H, 4O
Separate Water 2H, 4O 2H, 4O
Combust Methane 2N, 6H 2N, 6H
Yes, in order for the equation to be correct, the total number of atoms on the left side of the balanced equation must always equal the total number of atoms on the right side of the balanced equation.
Answers to this question vary. A good answer could say start with the chemical with the smallest amount on each side of the equation and balance that. Alternatively, you could start with the largest and balance that first. You also could say that you examined the visual representation in the reactant and product box to see if there was an equal number of atoms. Sometimes, it does require trial and error to get an equal number of atoms on each side of the equation. You could also use math concepts such as greatest common factors to use the smallest number possible of each molecule.
No, you could not use a non-integer number.
Explanation:
PF
Answer: There are three different ways that the equation is represented visually when it is balanced. First, the scale is at equilibrium when it is balanced. The balance turns yellow and a smiley face appears. Second, the graph shows equal amounts on both the reactant and product side of the equation. Third, within the individual molecule box, there should be the same number of each element on both the product and a reactant side of the equation.
Reaction Total Number of Molecules
Reactant Side (left) Product Side (right)
Make Ammonia 4 2
Separate Water 2 3
Combust Methane 3 3
No, the number of total molecules on the left side of a balanced equation is not equal to the number of total molecules on the right side of the equation. A molecule is the smallest number of atoms bonded together for a chemical reaction. The total number of atoms must be the same, but not molecules. The reactants and products will bond together in different ways leading to different numbers of reactants and products.
Reaction Total Number of Atoms
Reactant Side (left) Product Side (right)
Make Ammonia 1C, 4H, 4O 1 C, 4H, 4O
Separate Water 2H, 4O 2H, 4O
Combust Methane 2N, 6H 2N, 6H
Yes, in order for the equation to be correct, the total number of atoms on the left side of the balanced equation must always equal the total number of atoms on the right side of the balanced equation.
Answers to this question vary. A good answer could say start with the chemical with the smallest amount on each side of the equation and balance that. Alternatively, you could start with the largest and balance that first. You also could say that you examined the visual representation in the reactant and product box to see if there was an equal number of atoms. Sometimes, it does require trial and error to get an equal number of atoms on each side of the equation. You could also use math concepts such as greatest common factors to use the smallest number possible of each molecule.
No, you could not use a non-integer number.
Long flights at midlatitudes in the Northern Hemisphere encounter the jet stream, an eastward airflow that can affect a plane's speed relative to Earth's surface. If a pilot maintains a certain speed relative to the air (the plane's airspeed), the speed relative to the surface (the plane's ground speed) is more when the flight is in the direction of the jet stream and less when the flight is opposite the jet stream. Suppose a round-trip flight is scheduled between two cities separated by 4300 km, with the outgoing flight in the direction of the jet stream and the return flight opposite it. The airline computer advises an airspeed of 930 km/h, for which the difference in flight times for the outgoing and return flights is 61 min. What jet-stream speed is the computer using
Answer:
103.52 km/h
Explanation:
We are given;
Distance between two cities; d = 4300 km
airspeed; v_as = 930 km/h
Difference in flight time; Δt = 61 min = 1.0167 h
Now, the equation of motion to find the distance is given as;
d = vt
Where v = v_as + v_js
v_as is the airspeed
v_js is the jet speed
Thus;
d = (v_as + v_js)t
Thus, time(t1) for outgoing flight is;
t1 = d/(v_as + v_js)
Meanwhile, time(t2) for the return flight, the jet stream velocity will be negative and time is;
t2 = d/(v_as - v_js)
Recall that Difference in flight time; Δt = 61 min.
Thus;
Δt = t2 - T1 = [d/(v_as - v_js)] - [d/(v_as + v_js)]
Factorizing out, we have;
Δt = d[1/(v_as - v_js)] - [1/(v_as + v_js)]
Furthermore, it gives;
Δt = d[(v_as + v_js - v_as + v_js)]/((v_as - v_js) × (v_as + v_js))
Δt = d(2v_js)/((v_as)² - (v_js)²)
Cross multiply to get;
(2dv_js)/Δt = ((v_as)² - (v_js)²)
(v_js)² + ((2dv_js)/Δt) - (v_as)² = 0
Plugging in values for d,v_as and Δt gives;
(v_js)² - ((2 × 4300 × v_js)/1.0167) - (930)² = 0
(v_js)² - (8458.7329v_js) - 864900 = 0
Using quadratic formula, we have;
v_js = 103.52 km/h
The airline computer advises an airspeed of 930 km/h, for which the difference in flight times for the outgoing and return flights is 61 min. The jet stream speed obtained using the quadratic formula is 103.52 km/h.
Given:
Distance between two cities; d = 4300 km
airspeed; v(as) = 930 km/h
Difference in flight time; Δt = 61 min = 1.0167 h
Now, the equation of motion to find the distance is given as;
d = vt
Where v = v(as) + v(js)
d = v(as) + v(js)t
At time t₁, t₁ = d/v(as) + v(js)
At time t₂, t₂ = d/v(as) + v(js)
Recall that Difference in flight time; Δt = 61 min.
Δt = d/v(as) + v(js) - d/v(as) + v(js)
Δt = d[(v(as) + v(js) - v(as) + v(js)]/((v(as) - v(js)) × (v(as) + v(js)))
Δt = d(2v(js))/((v(as))² - (v(js))²)
(2dv(js))/Δt = ((v(as))² - (v(js))²)
(v(js))² + ((2dv(js))/Δt) - (v(as))² = 0
(v(js))² - ((2 × 4300 × v(js))/1.0167) - (930)² = 0
(v(js))² - (8458.7329v(js)) - 864900 = 0
Using the quadratic formula, we have;
v(js) = 103.52 km/h
Therefore, The jet stream speed obtained using the quadratic formula is 103.52 km/h.
To know more about the quadratic formula:
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An object is traveling at a constant velocity of 10m/s for 4 seconds. What is its acceleration?
40 m/s/s
0.4 m/s/s
2.5 m/s/s
0 m/s/s
Answer:
The answer is 2.5 m/s²Explanation:
The acceleration of an object given it's velocity and time taken acting on it can be found by using the formula
[tex]acceleration = \frac{velocity}{time} \\ [/tex]
From the question
time = 4 s
velocity = 10 m/s
So we have
[tex]acceleration = \frac{10}{4} = \frac{5}{2} \\ [/tex]
We have the final answer as
2.5 m/s²Hope this helps you
If a baseball and a cannonball are dropped from the same height at the
same time, with no air resistance, which ball will hit the ground first?"
2 po
O The cannonball lands first
O The baseball lands first
O Both balls land at the same time
O The ball with the larger volume lands first
An object that gains electrons becomes ___charged?
Answer:The charge becomes nuetral
Explanation:
Whenever electrons are transferred between objects, neutral matter becomes charged. When an atom loses electrons, it becomes a positively charged ion, or cation. When an atom gains electrons, it becomes a negative charged ion, or anion.
A car traveling from rest to a velocity of 7.0 m/s accelerates uniformly at the rate of 0.80 m/s2. What is its tr. 31
time?
Answer:
54mph
Explanation:
A net force of 20 N acting on a wooden block produces an
acceleration of 4.0 m/s2 for the block. What is the mass of
the block?
Answer:
From the second law of motion:
F = ma
we are given that the force applied on the block is 20N and the block accelerates at an acceleration of 4 m/s/s
So, F= 20N and a = 4 m/s/s
Replacing the variables in the equation:
20 = 4* m
m = 20 / 4
m = 5 kg
A 63.9 kg water skier is pulled by a
125 N force at a 31.5° angle, while
the water creates a 84.8 N force
pulling directly backward. What is the
y-component of the acceleration?
Answer:
[tex]a_{x} = 0.342 \frac{m}{ {s}^{2} } \: "x \: component \: of \: acceleration"
\: \\ a_{y} = 1.02 \: \frac{m}{ {s}^{2} } \: "y \: component \: of \: acceleration" [/tex]
Explanation:
Given a mass of 63.9kg with a total applied force of 125 N at a 31.5° inclination relative to the horizontal and vertical, and a horizontal resistance force of 84.8 N. The components of acceleration can be calculated as follows:
Force = mass × acceleration
Vertical component of a vector = vector × Sin(angle)
Horizontal component of a vector = vector × Cos(angle)
extra:
V = √x^2+y^2
θ (angle, "theta") = arctan or inverse tan(y/x) (For this instance. Theta is usually an angle measure though)
x = V cos θ
y = V sin θ
____________________
To find the vertical component of acceleration we must first take the vector quantity of our force which is 125 N (Newtons) and it's angle of 31.5°.
Vertical force = 125 × sin(31.5 degrees) = 125 × 0.5225 = 65.312 N [aka the normal force]
This works because force is a vector, it has both direction(by the angle of force), and magnitude(it's quantity).
Then take the force equation, and rearrange it to solve for the upward acceleration: F = m × a → a = F/m.
a = 65.312/63.9 ≈ 1.02 m/s^2.
Then for the horizontal acceleration, take the cosine for the horizontal part
What is reduction division mean ?
Answer:
Reduction division: The first cell division in meiosis, the process by which germ cells are formed. In reduction division, the chromosome number is reduced from diploid (46 chromosomes) to haploid (23 chromosomes). Also known as first meiotic division and first meiosis.
Explanation:
Please mark as brainliest
A truck is parked at the bottom of a hill it moves from the bottom of the hill and parks at the top compared to when it was parked at the bottom of the hill at its new position in the truck now has
A. more kinetic energy
B. more potential energy
C. Less kinetic energy
D. less potential energy
In the reality television show "Amazing Race," a contestant is firing 12 kg watermelons from a slingshot to hit targets down the field. The slingshot is stretched from its equilibrium length by a distance of 1.4 m, and the watermelon is at ground level, 0.5 m below the launch point. The targets are at ground level 15 m horizontally away from the launch point. Calculate the spring constant of the slingshot (in N/m). (Assume the angle that the watermelon's velocity makes with the horizontal at the launch point is the same as the angle the slingshot makes with the horizontal when pulled back. Also assume the equilibrium length of the slingshot is negligible.) slader
Answer:
k = 930 N / m
Explanation:
For this problem we will solve it in parts, let's start with the conservation of mechanical energy
Starting point. Lower
Em₀ = [tex]K_{e}[/tex] + U₁
Final point. Higher
[tex]Em_{f}[/tex]= U₂
as there is no friction, energy is conserved
Em₀ = Em_{f}
½ m v² + mg y₁ = m g y₂
where y₁ is the initial height of y1 = -0.5 m and y² the final height y² = 15 m
Let's find speed when getting out of the sling
v = √ (2g (y₂-y₁))
let's calculate
v = √[2 9.8 (15 - (-0.5))]
v = 17.43 m / s
Now we can use Newton's second law.
The force applied by the sling is in the direction of movement (inclined) and the weight is in the vertical direction.
X axis
Fₓ = m aₓ
in the problem they indicate that the direction of the velocity at the end of the sling is the same direction of the force,
F_{e} cos θ = m a cos θ
let's replace the elastic force
k Δx = m a
Y axis
F_{y} - W = m a_{y}
k Δx sin θ - m g = m a sin θ
let's write
k Δx = m a (1)
k Δx sin θ - m g = m a sin θ
Now let's use kinematics to find the acceleration in the sling, the direction of these accelerations ta in the direction of elongation
v² = v₀² +2 a Δx
as the system starts from rest v₀ = 0
a = v² / 2Δx
a = 17.43² / (2 1.4)
a = 108.5 m / s²
we substitute in equation 1
k = m a / Δx
k = 12 108.5 / 1.4
k = 930 N / m
answer fast plz
....................
Answer:
114 m/s
Explanation:
see the image below
In most cases, what happens to a liquid when it cools? Its density increases. Its density decreases. Its mass increases. Its mass decreases. Its volume increases. Its volume decreases. (more than 1 correct answer)
Answer: density decreases
Explanation:
Because force is a vector measurement, it has both magnitude and
Which is faster +25 m/s or -250 m/s
A body rolls over a horizontal, smooth surface without slipping with a translational
kinetic energy E. Show that the kinetic energy of the body is E=(1+K 2 /R 2 )
where K is the radius of gyration and R is the radius of the body. Using the above relation, find the
total kinetic energy of a circular disc.
b) A wheel of mass 1000 kg and radius 1 m is rotating at the rate of 420 r.p.m. What is the
constant torque required to stop the wheel in 14 rotations, assuming the mass to be
concentrated at the rim of the wheel?
Answer:
I am not sure sorry wish I could help
Answer:
I also wish I could help u but am sorry I don't know it
Don't worry you will find a solution
A block suspended from a spring is oscillating vertically with a frequency of 4 Hz and an amplitude of 7 cm. A very small rock is placed on top of the oscillating block just as it reaches its lowest point. Assume that the rock has no effect on the oscillation. At what distance above the block’s equilibrium position does the rock lose contact with the block? (hint this occurs when the rock’s acceleration equals the value of gravity) What is the speed of the rock when it leaves the block? What is the greatest distance above the block’s equilibrium position reached by the rock? (Let t = 0 be when the rock is placed on the block)
Answer:
v = - 1,715 m / s , x = 0.0156 m
Explanation:
This is an oscillatory movement exercise, which is described by the expression
x = A cos (wt + Ф)
we can assume that the block is released from its maximum elongation, so the phase constant (Ф) is zero
As we are told that the stone does not affect the movement of the spring mass system, the amplitude and angular velocity do not change, in the upward movement the stone is attached to the mass, but in the downward movement the mass has an acceleration greater than g leave the stone behind, let's look for time, for this we use the definition of speed and acceleration
v = dx / dt
v = - A w sin wt
a = - Aw² cos wt
a = -g
-g = - Aw² cos wt
wt = cos⁻¹ (g / Aw²)
t = 1 / w cos⁻¹ (g / Aw²)
angular velocity and frequency are related
w = 2π f
w = 2π 4
w = 8π rad / s
remember that the angles are in radians
t = 1 / 8π cos⁻¹ (9.8 / (0.07 64π²))
t = 0.039789 1.3473
t = 0.0536 s
let's find the speed for this time
v = - A w sin wt
v = - 0.07 8π sin (8π 0.0536)
v = - 1,715 m / s
the distance is
x = A cos wt
x = 0.07 cos (8π 0.0536)
x = 0.0156 m
What were the quartering acts
Answer:
The quartering act of 1765 required the colonies to house British soldiers in barracks provided by the colonies.
what are the four planets that orbit closets to the sun
what are they and what characteristics do they have
Answer:
Explanation:The four closest to the sun — Mercury, Venus, Earth and Mars — are the terrestrial planets. They have rocky surfaces enclosed by relatively shallow atmospheres.
100 POINTS. PLEASE PROVIDE EXPLANATION
Answer:
60 kg
80 kg
Explanation:
Work is equal to the change in energy.
W = ΔE = E − E₀
Let's start with block B. The work done by the tension force is equal to the change in energy. Initially, the block has potential energy. Finally, the block has kinetic energy.
W = ΔE
FΔy = ½ mv² − mgh
T (-2.0 m) = ½ m (6.00 m/s)² − m (10 m/s²) (2.0 m)
T (-2.0 m) = m (-2 m²/s²)
T = m (1 m/s²)
Now let's look at block A. The work done by tension and against friction is equal to the change in energy. Initially, the block has no energy. Finally, it has both kinetic and potential energy.
W = ΔE
Fd = ½ mv² + mgh − 0
(T − Nμ) (2.0 m) = ½ (4.00 kg) (6.00 m/s)² + (4.00 kg) (10 m/s²) (⅗ × 2.0 m)
(T − Nμ) (2.0 m) = 120 J
T − Nμ = 60 N
Draw a free body diagram of block A and sum the forces in the perpendicular direction to find the normal force N.
N = mg cos θ
N = (4.00 kg) (10 m/s²) (⅘)
N = 32 N
Substitute:
T − 32μ = 60 N
If μ = 0, then T = 60 N and m = 60 kg.
If μ = ⅝, then T = 80 N and m = 80 kg.
Answer:did you find you answer also i answered so you can give him brainiest
Explanation:
A car drives horizontally off a cliff that is 30 meters high killing the driver on impact. The grieving widow claims her husband would never have driven faster than the posted speed limit of 35 mph and has hired a lawyer to sue the city for negligence. You are sent to investigate the crash site. You measure that the car landed 75 m from the base of the cliff [1 mph = 0.447 m/s].
A. Draw the detailed sketch for this motion with all of the relevant information, variables, and numbers contained in the sketch.
B. Write the three projectile equations with the known values and unknown variables placed into the equation.
C. Determine the time of fall. Then determine vix of the car as it flies off the cliff.
D. Based on what you were able to determine, assess whether the city is held liable for the accident
Answer:
b) 0 = y₀ + 0 - ½ g t² , v₀ₓ = x / t
c) v₀ₓ = 30.31 m / s
Explanation:
This is a projectile launching exercise, in your statement you have units of several systems, we are going to reduce everything to the SI system
v = 35 mph (0.447 m / s / 1 mph) = 15.645 m / s
y₀ = 75 m
A) In the attachment we can see a diagram of the movement of the vehicle in its fall
B) let's find the time for the fall to the base of the cliff (y = 0)
y = y₀ + [tex]v_{oy}[/tex] t - ½ g t²
when the vehicle leaves the cliff it goes horizontally, so its vertical speed is zero (v_{oy} = 0)
0 = y₀ + 0 - ½ g t²
t = √2y₀ / g
with this time we can use the equation of motion on the x axis
x = v₀ₓ t
v₀ₓ = x / t
C) we perform the calculations
t = √ (2 30 / 9.8)
t = 2.474 s
v₀ₓ = 75 / 2.474
v₀ₓ = 30.31 m / s
D) as we can see, the vehicle speed when leaving the cliff is almost twice the allowed speed (15.6 m / s)
therefore the city is not responsible for the accident
The weld bead in SMAW is formed by the?
The weld bead in SMAW is formed by the electrode wire core mixing with the molten base metal, Therefore the correct option is D.
What is Shielded Metal Arc Welding (SMAW)?It is a type of manual arc welding process which utilizes a consumable electrode covered with flux to protect the weld bead.
For SMAW either direct current or alternating current can be used to form the electric arc. The electrode melts and forms a molten weld pool with the base metal by using the thermal energy produced from the electric arc.
The weld bead in Shielded Metal Arc Welding is formed by the electrode wire core mixing with the molten base metal.
learn more about Shielded Metal Arc Welding (SMAW)
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which of the following statements describes how a balance obtains a measurement
A. A ruler is placed next to an object, and its length is noted.
B. An object is placed on one side and weights are placed on the other side until the two dishes are even.
C. The sides of an object are measured and multiplied to get the final measurement.
D. An object is placed in a cylinder, and the water displaced gives the measurement.
Which of the following statements describes how a balance obtains a measurement
Explanation:
A balance obtains a measurement by the sides of an object which are measured and multiplied to get the final measurement. Thus, the correct option is C.
How a balance obtains measurement?A balance is an instrument used for comparing the weights of two objects. It is usually for the scientific purposes, to determine the difference in mass or weight of an object.
Weighing of objects directly requires that the balance be carefully zeroed that is it reads zero with nothing on the balance pan in order to obtain accurate results of the measurement.
The sides of an object are measured and multiplied with a factor to get the final measurement of the object. Through this, a balance obtains the measurement.
Therefore, the correct option is C.
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You ill simply enter your numeric answer directy ieto the space provided to the right of the equal sign. Answor the following question by typing the numenic answer into the answer boa If you have a gross of items, you have 144 items. if you buy a gross of eggs, how many dozen eggs do you have? Express your answer in dozens. Do not enter the units; they are provided to the right of the answer box Hints number of eggs dozen Submit My Answers Give Up
Part B accistentaily entar commas, you aldl get a When entering large numbers in the answer box, do not use commas. For example, enter 3274400 for the number 1,26.400.Do not enter 1,276,403. you message that your answer is incorrect. Answer the following question by typing the numeric answer into the answer box. What is the sum of 9260 and 32407 Express your answer numerically to at least three significant figures
Answer:
a
12
b
41667
Explanation:
From the question we are told that
Generally 1 dozen of egg is equivalent to 12 pieces of eye
So given that a gross of item is equivalent to 144 items
x dozens of eggs is equivalent to a gross of item
So
[tex]x = \frac{144 * 1}{12}[/tex]
=> [tex]x = 12 \ dozens \ of \ eggs[/tex]
Generally the sum of 9260 and 32407 is
9 2 6 0
+ 3 2 4 0 7
4 1 6 6 7