Answer:
Explanation:
slit separation d = 1.13 x 10⁻³ m
screen distance D = 3.75 m
wavelength of light λ = 647 x 10⁻⁹ m
Distance of first bright fringe = fringe width = λ D / d
λ D / d = 647 x 10⁻⁹ x 3.75 m / 1.13 x 10⁻³ m
= 2.147 x 10⁻³ m
= 2.147 mm .
Distance of first bright fringe = 2.147 mm .
Distance of second dark fringe = 1.5 x fringe width
= 1.5 x 2.147 mm .
= 3.22 mm .
A sign which weighs 38.3 N is supported symmetrically by two cables which make an angle of 1.0 degrees with the horziontal. A single cable will pull upward on the sign with a force of how may Newtons?
The single cable will pull upward on the sign with a force of 38.3 N.
What is single cable?Single cable is a type of cable that is composed of a single electrical conductor. It is most commonly used in low voltage applications such as wiring for computers and domestic appliances. Single cable is typically insulated with rubber, PVC or other insulating materials. The insulator protects the conductor from short circuits and other electrical hazards.
This is because the sign is supported symmetrically by two cables, which means that the total downward force on the sign is equal to the total upward force. Since the two cables make an angle of 1.0 degrees with the horizontal, the total downward force on the sign is equal to the combined weight of the sign (38.3 N) and the two cables pulling down on it. Therefore, the single cable must pull up with a force of 38.3 N in order to keep the sign in equilibrium.
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Two protons are held a distance d apart. The electrostatic force and the gravitational force that one proton exerts on the other are Fe and Fg, respectively. Which of the following correctly compares the magnitude and direction of these forces?
Fe > Fg, opposite direction
a. Fe > Fg, same direction
b. Fe < Fg opposite direction
c. Fe < Fg same direction
Answer:
Explanation:
charge on each proton = 1.6 x 10⁻¹⁹ C
mass of proton = 1.67 x 10⁻²⁷ kg
Electrostatic force of repulsion Fe = 9 x 10⁹ x ( 1.6 x 10⁻¹⁹ )² / d²
= 23.04 x 10⁻²⁹ / d²
Gravitational force of attraction = G Mm / d²
M = m = 1.67 x 10⁻²⁷ kg
Gravitational force of attraction Fg = 6.67 x 10⁻¹¹ x ( 1.67 x 10⁻²⁷ )² / d²
= 18.60 x 10⁻⁻⁶⁵ / d²
So Fg is far less than Fe and former is attractive , later is repulsive .
Fe > Fg, opposite direction , is the answer .
Q.2. Assertion: When distance between two bodies is doubled and also mass of each body is doubled. then the gravitational force between them remains the same. Reason: According to Newton's law of gravitation, force is directly proportional to the product of mass of the two bodies and inversely proportional to square of the distance between them. ent to
Answer:
True:
F1 = G M1 M2 / R^2
F2 = G (2 M1) * (2 M2) / (2 R)^2
F1 = F2
PLEASE HURRY I GIVE BRAINLIST and extra points !!!!!!
1 What happens to the energy from the light when the material changes?
2 What happens to the energy from the light when the material does not change?
Answer:
2 stays the same 1 it will go bad or go good depends on which material you use
A ruler partially hangs over the end of a bench. It is supported at one end and made to vibrate at the other end in an attempt to display simple harmonic motion. If the ruler has an amplitude of 0.22 cm and makes twelve complete vibrations in 0.12 seconds, how far does the end of the ruler travel in 4.7 seconds?
30. How do you make a conclusion?
How much force is needed to accelerate a 100 kilogram car 5 meters per second?
The force needed to accelerate the mass of 100 kg is 500 N.
What is force?Force is the product of mass and acceleration. The S.I unit of force is Newton (N).
To calculate the amount of force needed to accelerate the mass of 100 kg, we use the formula below.
Formula:
F = ma.................. Equation 1Where:
F = Forcem = Mass a = AccelerationFrom the question,
Given:
m = 100 kga = 5 m/s²Substitute these values into equation 1
F = 100×5F = 500 NHence, the force is 500 N.
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During launches, rockets often discard unneeded parts. A certain rocket starts from rest on the launch pad and accelerates upward at a steady 3.45m/s2 . When it is 230m above the launch pad, it discards a used fuel canister by simply disconnecting it. Once it is disconnected, the only force acting on the canister is gravity (air resistance can be ignored).
1- How high is the rocket when the canister hits the launch pad, assuming that the rocket does not change its acceleration?
2- What total distance did the canister travel between its release and its crash onto the launch pad?
Answer:
Explanation:
Time elapsed to reach the height of 230 m be t
s = ut + 1/2 at²
230 = .5 x 3.45 t²
t = 11.55 s
velocity at height of 230 m
v = u + at
= 0 + 3.45 x 11.55 = 39.84 m/s
This velocity will be attained by canister .
time to reach zero velocity at the top position t
v = u - gt
0 = 39.84 - 9.8 t
t = 4.06 s
height travelled by canister during this 4.06 s
v² = u² - 2gH
0 = 39.84² - 2 X 9.8 H
H = 80.98 M
Total height attained by canister = 80.98 + 230 = 310.98 m
Time of fall by canister t
s = 1/2 gt²
310.98 = .5 x 9.8 t²
t = 7.97 s
Total time taken by canister to reach the ground after its release from rocket
= 4.06 + 7.97 = 12.03 s
Distance travelled by rocket in 12.03 s
s = ut + 1/2 a t²
= 39.84 x 12.03 + .5 x 3.45 x 12.03²
= 479.27 + 249.64
= 728.91 m
height of rocket required = 230 + 728.91
= 958.91 m
2 )
Distance travelled by canister between its release and fall on the ground
= 80.98 + 80.98 + 230
= 391.96 m.
when a resistor is connected to a battery, current flows through the resistor. If the voltage of the battery is doubled, the current will be?
Resistors limits the current/amps but keep the voltage the same.
What happens if you connect the resistor to the battery?You don't want to attach them together with a wire since there would be too much current loose through, such that the battery heats up till it blows or something.
Current is directly corresponding to voltage; a doubling of the voltage will double the current. But the current is also inversely comparable to the resistance; a doubling of the resistance will halve the current.
So we can conclude that Resistance residue is the same, but power becomes four times i.e. multiplication. If the current is I and the voltage is V,
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both of yall are right and wrong its b and d
Answer:
Yup
Explanation:
A brick is thrown upward from the top of a building at an angle of 10° to the horizontal and with an initial speed of 15 m/s. If the brick is in flight for 2.9 s, how tall is the building? any help would be greatly appreciated
The total height of the building from which the brick is thrown is 33.60 meters.
What is Speed?
Speed is the rate of change of position of an object in any direction with respect to time. Speed is measured as the ratio of distance to the time in which the distance was covered. The SI unit of speed is m/s (meter per second).
The time of flight of the object from the building is:
t = 2μ sinθ/ g
t = 2 × 15 × sin10/ 9.8
t = 30 × 0.175/ 9.8
t = 0.535 seconds
Total time to cover the distance = 2.9 seconds
Total time = 2.9 - 0.535
Total time = 2.365
μg = μ sinθ
h = 15 × sin10 × 2.365 + 1/2 × 9.8 × (2.365)²
h = 2.625 × 2.365 + 1/2 × 9.8 × (2.365)²
h = 6.20 + 4.9 × 5.59
h = 6.20 + 27.40
h = 33.60 meters
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A solenoid is connected to a battery as shown in the figure, and a bar magnet is placed nearby. What is the direction of the magnetic force that this solenoid exerts on the bar magnet? (Hint: Think of the solenoid as a bar magnet, and identify what would be its north and south poles.)
According to the right-hand rule, the magnetic field of the solenoid will be directed towards the left direction.
What is Right-hand rule?Right Hand Thumb Rule is the rule which is used If a current carrying conductor is imagined to be held in the right hand direction such that the thumb always points along the direction of the current flow, then the direction of the wrapped fingers in the hand will give the direction of the magnetic field lines of the bar magnet.
By the application of the right-hand rule, the magnetic field of the solenoid will be directed towards the left hand direction.
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PLEASE HELPPP ASAP, I'LL GIVE BRAINLEST
Answer:
a) Joules
b) W (symbol for work) (J is symbol for Joules)
c) seconds
d) watts
What is another way to describe the vector 100 m/s down
Answer:
Describe how one-dimensional vector quantities are added or subtracted.
Can anyone help with this?
Answer:
Explanation:
Add a horizontal line. An object that is not moving has no change in distance with respect to time.
Critical angle of glass is 42 .what does it mean?
Answer:
i think..its fraction that its have multiple fractions on it..if you minus the 397 000-355 it should be 381+ so i say if you get the 5 multiply it by 9!! so you will get it!
Explanation:
HOPE IT HELPS!!
It takes one year for ______.
a.earth to circle the sun one time
b.earth to rotate on its axis one time
c. The sun to circle earth one time
d.the sun to rotate on its axis one time
Answer: A. Earth to circle the sun one time.
Pls help :(( I need help!! Its physics! motion and forces!
Answer: Pedaling your bike : acceleration :: applying the brakes : inertia.
The reason I think this to be the answer to the analogy is because there is energy and work used in both processes (and the unit focuses on forces); gravity is constant and does not change whether one pedals or applies brakes. And I do not think it's deceleration, as deceleration tends to equate to acceleration within the physics perspective.
Edit: I should also add that since you clarified that your unit is motion and forces, Newtons 1st law is the law of inertia. The way to change an objects motion for it to slow down is by applying an additional force. That resistance the bike experiences to slow is the process of inertia. Inertia happens in order to accelerate an object (either by slowing it down, or speeding it up): i.e., the resistance to change.
the valu
In an experiment the value of thickness of a
wire was found to be 1.54, 1.53, 1.44, 1.54, 1.56
and 1.45 in successive measurements. Then the
percentage error is
(1) 28%
(2).09 %
(3) 9%
(4) 2.8%
Answer:
[tex]\% Error = 2.6\%[/tex]
Explanation:
Given
[tex]x: 1.54, 1.53, 1.44, 1.54, 1.56, 1.45[/tex]
Required
Determine the percentage error
First, we calculate the mean
[tex]\bar x = \frac{\sum x}{n}[/tex]
This gives:
[tex]\bar x = \frac{1.54+ 1.53+ 1.44+ 1.54+ 1.56+ 1.45}{6}[/tex]
[tex]\bar x = \frac{9.06}{6}[/tex]
[tex]\bar x = 1.51[/tex]
Next, calculate the mean absolute error (E)
[tex]|E| = \sqrt{\frac{1}{6}\sum(x - \bar x)^2}[/tex]
This gives:
[tex]|E| = \sqrt{\frac{1}{6}*[(1.54 - 1.51)^2 +(1.53- 1.51)^2 +.... +(1.45- 1.51)^2]}[/tex]
[tex]|E| = \sqrt{\frac{1}{6}*0.0132}[/tex]
[tex]|E| = \sqrt{0.0022}[/tex]
[tex]|E| = 0.04[/tex]
Next, calculate the relative error (R)
[tex]R = \frac{|E|}{\bar x}[/tex]
[tex]R = \frac{0.04}{1.51}[/tex]
[tex]R = 0.026[/tex]
Lastly, the percentage error is calculated as:
[tex]\% Error = R * 100\%[/tex]
[tex]\% Error = 0.026 * 100\%[/tex]
[tex]\% Error = 2.6\%[/tex]
Which increases the rate of soil formation?
A. mixed layers
B. more precipitation
C. cooler temperatures
D. very hard parent material
Answer:
a
Explanation:
Answer: b. more precipitation
Explanation:
I cant solve this problem, and our teacher said that this would be in the test we'll have tomorrow, can someone help me?
A body of m = 6.8kg is launched with a speed of 7.5 m / s towards the top of an inclined plane of 15 ° with respect to the horizontal. in the absence of friction, what displacement does it make before reversing the direction of motion?
Answer:
d = 11.1 m
Explanation:
Since the inclined plane is frictionless, this is just a simple application of the conservation law of energy:
[tex] \frac{1}{2} m {v}^{2} = mgh[/tex]
Let d be the displacement along the inclined plane. Note that the height h in terms of d and the angle is as follows:
[tex] \sin(15) = \frac{h}{d} \\ or \: h = d \sin(15) [/tex]
Plugging this into the energy conservation equation and cancelling m, we get
[tex] {v}^{2} = 2gd \sin(15)[/tex]
Solving for d,
[tex]d = \frac{ {v}^{2} }{2g \sin(15) } = \frac{ {(7.5 \: \frac{m}{s}) }^{2} }{2(9.8 \: \frac{m}{ {s}^{2} })(0.259)} \\ = 11.1 \: m[/tex]
what change do you need to make when comparing objects going upward against gravity versus downward with gravity?
A. Different amount of time in motion
B. Different length of displacement
C. Different sign + or - on the acceleration
D. Different changes to velocity
If an object is working against gravity, that means gravity must have the opposite sign of the object (this is why we see objects slow down at their peak height and return to us if we throw them in the air!). If the object is working with gravity, though, they must both be moving in the same direction, therefore gravitational acceleration would be the same sign as the velocity (positive or negative depending on how you define your axes).
Therefore, your answer should be C. Different sign + or - on the acceleration.
I hope this helps!
The magnitude of the charge on an electron compared to the magnitude of the charge on a proton (3 points)
a) is greater
b) is smaller
c) is the same
Option C is correct.
The magnitude of the charge on an electron compared to the magnitude of the charge on a proton is same.
We have a electron and a proton.
We have to estimate the fact whether the magnitude of the charge on an electron compared to the magnitude of the charge on a proton is -
a) is greater
or
b) is smaller
or
c) is the same
What is the Electric charge ?The sufficiency or deficiency of electrons is called electric charge.
According to the question -
The charge on a electron is - q(e) = - 1.6 x [tex]10^{-19}[/tex] Coulombs
The charge on a proton is - q(p) = + 1.6 x [tex]10^{-19}[/tex] Coulombs
But, according to the property of magnitude :
| + x| = + x
| - x| = - (- x) = + x
In the similar manner -
|q(e)| = |q(p)| = 1.6 x [tex]10^{-19}[/tex] coulombs
Hence, the magnitude of the charge on an electron compared to the magnitude of the charge on a proton is same.
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At what separation will two charges, each of magnitude 6.0 μC, exert a force of 0.70 N on
each other?
The two charges, each of magnitude 6.0 μC, exert a force of 0.70 N at separation of 1.47 meters.
What is electric force?Electric force is the attracting or repulsive interaction between any two charged things. Similar to any force, Newton's laws of motion describe how it affects the target body and how it does so. One of the many forces that affect objects is the electric force.
We know that electric force can be defined as:
Force: F = kQq/r²
0.70 = 9.0 × 10⁹ × (6.0×10⁻⁶)²/r²
r = 1.47 meter.
Hence, the separation between them is 1.47 meters.
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How does heat transfer?
which of the following changes will increase the period of an oscillating spring mass system?
a. an increase in the mass on the spring.
b. an increase in the initial displacement of the spring. c. an increase in the spring constant.
d. more than one of the above.
e. none of the above.
explain your answer.
NO LINKS.
Answer:
a. an increase in the mass on the spring.
Explanation:
An increase in the mass on the spring will increase the period of an oscillating spring mass system.
Mathematically, the period of an oscillating spring mass system is given by the formula;
T = 2π √(m/k)
Where;
T is the period.
m is the mass of the spring.
k is the spring constant.
Hence, the mass of a spring is directly proportional to the period of oscillation of the spring.
This ultimately implies that, as the mass of the spring increases, the period of oscillation will increase. Similarly, the period of oscillation will decrease with an increase in the spring constant i.e there exist an inverse relationship between the period and spring constant.
Ball A with a mass of 0.280kg makes an elastic head-on collision with ball B initially at rest. After collision, ball B moves off with half the original speed of ball A. Is the momentum conserved in the collision? Why?
The mass of ball B and the final velocity of ball A can complement the conservation of linear momentum. The answer is yes.
What is Momentum ?Momentum can simply be defined as the product of mass and velocity. It is a vector quantity.
Given that ball A with a mass of 0.280kg makes an elastic head-on collision with ball B initially at rest. After collision, ball B moves off with half the original speed of ball A.
In an elastic head-on collision, momentum is mostly always conserved. That is, the sum of the momentum before collision will be equal to the sum of the momentum after collision.
Mathematically, MaUa = MaVa + MbVb
Is the momentum conserved in the collision?
The answer is yes!
Why?
Because we need to consider the mass of the ball B and the final velocity of the ball A.
Therefore, In consideration of the mass of the ball B and the final velocity of the ball A, we can say that the momentum is conserved.
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Which model below describes the processes of Gamma radiation?
A
B.
C.
D.
Answer:
C
Explanation:
Two parallel plates are charged
with 4.98*10^-7 C of charge.
What must the area of the plates
be to create an electric field of
8720 N/C?
(Unit = m^2)
Answer:
6.45
Explanation:
Got it right on Acellus
While skiing in Jackson, Wyoming, your friend Ben (of mass 63.2 kg) started his de- scent down the bunny run, 11.5 m above the bottom of the run. If he started at rest and converted all of his gravitational potential energy into kinetic energy, what is Ben's kinetic energy at the bottom of the bunny run? Use g = 9.8 m/s² Answer in units of J.- answer :7100J part 2 of 2 What is his final velocity? Answer in units of m/s.
Answer:
12.3 m/s
Explanation:
To calculate the final velocity of Ben, we can use the equation KE = 1/2mv^2, where KE is the kinetic energy and m is the mass of Ben. Inserting the given values, we get:
7100 = 1/2 (63.2 kg) v^2
Therefore, v^2 = 7100/31.6
v = √(7100/31.6)
v = 12.3 m/s