Are Figures A and B congruent? Explain your reasoning.

Answer:

Answer is b because scientific notation is a variable between 0-10 to the power of a number depending on how many digits it has.

A number from 1-10 in 238,900 miles is 2.389 so the base variable is 2.389. The decimal got moved from 238900. to the left. It moved 5 places.

It went like this;

1 left: 23890.0

2 left: 2389.00

3 left: 238.900

4 left: 23.8900

5 to the left: 2.38900

So the scientific notation is 2.389^5

Answer:

25/52, bcos there are 25 odd numbers from 1 to 52

X= 8/3 :)) hope this helps !

Answer: 41 minutes

Step-by-step explanation: I just counted by 10s until I got to 57 then added 10 seconds to make it 5:07, added 1 and boom 41 minutes

The time taken by Lee to go to the mall, when he left to go to the mall at 4:27 pm he arrived at 5:08 pm, is 41 minutes.

To subtract the time, follow the steps,

Lee left to go to the mall at 4:27 pm he arrived at 5:08 pm. Subtract time in the following way,

As the 8 minute is shorter than 27 minute, thus borrow 60 minute from the hour and subtract 1 from the hour. Thus,

  4 hours 68 minutes

-  4 hours 27 minutes

_________________

  0 hours 41 minutes

_________________

Thus, the time taken by Lee to go to the mall, when he left to go to the mall at 4:27 pm he arrived at 5:08 pm, is 41 minutes.

Learn more about the subtraction of time here;

https://brainly.com/question/16788360

#SPJ2

Answer: XY should be the answer

Step-by-step explanation: A guess I took and got right

Answer: It’s $15,219.20

a.k.a D at least that’s what it says on mine

Step-by-step explanation:

Hope this helps and just answered question correct on edg so yea

Answer: Anywhere along the negative x axis

For example, the point could be (-1,0) or (-2,0)

All that matters is that x is negative and y = 0

Any point is on the x axis when y = 0

The negative portion of the x axis is to the left of the y axis.

Answer:

All you have to do is turn x-2y=6 into y=mx+b form. That would mean you need to get y by itself. Subtract x from 6. Then you have -2y=6-x. Now you have to divide both sides of the equation by -2. So then you have -2y/-2 = 6-x/-2. That turns out to y=3-1/2x Which is easier read by: y=1/2x - 3

ima go with B my dude good luck

Answer: f-1x(fx2) answer = -f  

             f(2)= 2 answer 2f

              f-1x1 answer f-1

Answer:

Step-by-step explanation:

Give the height of the observation deck modeled by the equation

h= -16t^2+149 where t is in seconds;

To get the time it will take the object to be 5 feet above the valley floor, we wil substitute h = 5ft into the modeled equation and calculate t;

h= -16t^2+149

5= -16t^2+149

-16t^2 = 5-149

-16t^2 = -144

t² = 144/16

t² = 9

t = √9

t = 3secs

Hence the time it will take for the object to be 5 feet above the valley​ floor is 3secs

Answer:

x=(-1+i√119)/4

AND

x=(-1-i√119)/4

Step-by-step explanation:

[tex]2x^{2} +x+15=0[/tex]

step1: identify a,b and c from the equation.

a=2

b=1

c=15

step2: use the quadratic formula.

[tex]x=\frac{-b+or- √b^{2}-4ac }{2a}[/tex]

(sub a,b and c)

[tex]x=\frac{-1+or- √1^{2}-4*2*15 }{2*2}[/tex]

(simplify)

[tex]x=\frac{-1+or-√-119}{4}[/tex]

(write the two possible answers)

[tex]x=-\frac{1+i√119}{4}[/tex]  

AND

[tex]x=-\frac{1-i√119}{4}[/tex]

Answer:

Chapter 2 The Language of Algebra

Simplify:

1.5(3+2·6)−82

Solve:

2.17=y−13

3.p+14=23

Translate into an algebraic expression.

4.11 less than the product of 7 and x.

Translate into an algebraic equation and solve.

5.Twice the difference of y and 7 gives 84.

6.Find all the factors of 72.

7.Find the prime factorization of 132.

8.Find the least common multiple of 12 and 20.

Chapter 3 Integers

Simplify:

9.|8−9|−|3−8|

10.−2+4(−3+7)

11.27−(−4−7)

12.28÷(−4)−7

Translate into an algebraic expression or equation.

13.The sum of −5 and 13, increased by 11.

14.The product of −11and8.

15.The quotient of 7 and the sum of −4andm.

16.The product of −3 and is −51.

Solve:

17.−6r=24

Chapter 4 Fractions

18.Locate the numbers on a number line.  

7

8

,

5

3

,3

1

4

,5.

Step-by-step explanation:

How can I compare linear relationships?

We have measured simple relationships between the size of different species and their weight (biomass). They are linear regressions (sometimes semilog). The type of question I would like to answer is, for example, if I have 4 species of snail, each with a separate linear equation representing the relationship between size and biomass, are those relationships significantly different, or does one relationship suffice for all my snail species?

I'm not sure how to do this comparison. Each species often has different sample sizes. I thought about just doing the separate relationships, then pooling all samples and comparing the resulting slope to the species-wise relationships with t tests. However I'm worried that species with more samples will bias the results. I could randomly remove samples from those species to equalize them. Another alternative might be to do an ancova with species put in as a dummy variable and look for interactions with species as a test of parallelism. Does that seem reasonable? It seems like a good idea to me because it will also be a test of whether the intercepts are the same.

The approach using a dummy variable and looking for interaction terms will work. It only works for comparing models of the same type (transformed or not). The pooling idea is the start of trying randomization tests (or computer intensive methods in general), but it will not work well if used in the way that you suggest.

The randomization test starts by treating the data as if the null hypothesis was true. One then calculates the probability of withdrawing two samples from your data that have a difference that is equal to or greater than the observed difference. So you resample the data, calculate differences, order these differences, and see how many are equal to or larger than the observed difference. Divide that by the total number of randomizations, and you have your answer.

Answer: Linear relationships can be compared using their initial values, or y-intercepts, and their rates of change, or slopes. Initial values can tell you which relationship started with a greater value. Comparing slopes can tell you which relationship is rising or falling faster.

Step-by-step explanation:

Answer:

Angle 6 = 91 degrees

Step-by-step explanation:

There are several ways you could use to find angle 6.

You could either find angle 5 then 6, 2, then 6, or 4 then 6 as they can all be found using the given angle with different rules.

First, we can find angle 5 using the corresponding angles rule which states that angles in the same corresponding quadrant are equal. That is angles that are in the same corresponding 'section' in their groups of angles at both intersect points. E.g. Angle 5 and 89 are corresponding angles, therefore angle 5 is equal to 89.

From here we can find angle 6 by using the rule that states that angles on a straight line add to 180. Angle 6 and angle 5 make up a straight line together which we know is 180 degrees. Therefore 180 - angle 5 = angle 6

180 - 89 = 91

Angle 6 is 91 degrees.

We also could have done this by first finding angle 2, which in on a straight line with the given angle. Therefore 180 - 189 = angle 2

Angle 2 = 91

Then used the corresponding angle rule to find angle 6. Angle 2 = Angle 6

Angle 6 = 91.

The final way we could have found it is by finding angle 4 first. The opposite angles rule states that opposite angles sharing a vertex are equal. This means that 89 and Angle 4 are equal. From there we can use the co-interior rule which states that angles in the same 'section' between parallel lines are co-interior (Angle 4 and angle 6) and are equal.

Therefore angle 4 = angle 6

Angle 6 = 91

Sorry if this answer was a bit confusing, hope it helps!

Answer:

Intersects two or more coplanar lines

Step-by-step explanation:

In geometry, the transversal line is a line that passes through two separate lines on the same plane (coplanar) at 2 distinct points.

Answer:

A, C, and E

Explanation:

Answer:

The equation is [tex]199+49+79m=880[/tex]

Kyle has had cable for 8 months.

Step-by-step explanation:

Let m denotes number of months cable services have been used.

Initial charge for the cable box = $199

Setup fee = $49

Monthly charges for cable services = $79

Also,

Total bill over a certain number of months, m = $880

Therefore,

[tex]199+49+79m=880[/tex]

Now solve the equation.

[tex]199+49+79m=880\\248+79m=880\\79m=632\\m=\frac{632}{79}\\ m=8[/tex]

That is Kyle has had cable for 8 months.

Answer:

23.8. I think

Step-by-step explanation:

So we already have 2/3 parts of the line, so SQ-RS=QR=23.8. because 68.4 minus 44.6 equals 23.8. Hope this helps.

I think is 182.205,182.105,182.0.25,182.05

Answer:

  4) 16√3 in²

  5) 63 cm²

Step-by-step explanation:

The formula to use in these cases is ...

  A = (1/2)ab·sin(θ)

where a, b are the side lengths and θ is the angle between them.

It helps to know the trig functions of the "special" angles used here.

  sin(120°) = sin(60°) = (√3)/2

  cos(60°) = 1/2

  sin(135°) = cos(45°) = (√2)/2

__

4) The external angle at the base is the supplement of 120°, so is 60°. Then the length of the missing segment between the end of the base and the right angle at h is ...

  x = (8 in)cos(60°) = (8 in)(1/2) = 4 in

So, the bottom edge of the triangle is 12 in - 4 in = 8 in.

The area is ...

  A = (1/2)(8 in)(8 in)sin(120°) = (1/2)64(√3)/2 in² = 16√3 in²

__

5) As in the previous problem, the difference between the given horizontal dimension and the base of the triangle is ...

  x = (18 cm)cos(180°-135°) = 18(√2)/2 cm = 9√2 cm

Then the base of the triangle is ...

  16√2 cm -9√2 cm = 7√2 cm

The area is then ...

  A = (1/2)(18 cm)(7√2 cm)(√2)/2 = 63 cm²

Answer:

f(x)=x^2+9x-10

Step-by-step explanation:

Standard Form of Quadratic Function

The standard form of a quadratic function is:

[tex]f(x)=ax^2+bx+c[/tex]

where a,b, and c are constants.

The factored form of a quadratic equation is:

[tex]f(x)=a(x-\alpha)(x-\beta)[/tex]

Where [tex]\alpha[/tex] and [tex]\beta[/tex] are the roots or zeros of f, and a is constant.

We know the zeros of the function are 1 and -10. The function is:

[tex]f(x)=a(x-1)(x-(-10))[/tex]

[tex]f(x)=a(x-1)(x+10)[/tex]

Operating:

[tex]f(x)=a(x^2+10x-x-10)[/tex]

Joining like terms:

[tex]f(x)=a(x^2+9x-10)[/tex]

Since we are not given any more restrictions, we can choose the value of a=1, thus. the required function is:

[tex]\boxed{f(x)=x^2+9x-10}[/tex]

Answer:

Use the figure at the right for Exercises 1-4

1) Name a pair of vertical angles.

Name a pair of adjacent angles with vertex M.

3) Name a pair of adjacent angles with vertex S.

N

4) Name a linear pair.

Step-by-step explanation:

Answer:

45°

Step-by-step explanation:

If you walk forwards, and make a 90° turn and walk the same amount, the angle will be half of 90, which is 45.

$6.50g+$3.50=$23.00