When an object is placed at 20.6 cm to the left of a converging lens with focal length 11.9, the distance between the object and the image is approximately 7.57 cm. This can be found by finding the image distance.
To find the distance between the object and the image, we need to first determine the image distance using the lens formula. The lens formula is given by:
1/f = 1/do + 1/di
Where:
- f is the focal length of the lens (11.9 cm)
- do is the object distance (20.6 cm)
- di is the image distance, which we need to find.
Step 1: Plug in the given values into the lens formula:
1/11.9 = 1/20.6 + 1/di
Step 2: Find a common denominator for the fractions:
(20.6*di) / (11.9*20.6) = (11.9*di) / (11.9*20.6) + (20.6*11.9) / (11.9*20.6)
Step 3: Simplify the equation:
(20.6*di) / 246.14 = (11.9*di + 245.14) / 246.14
Step 4: Cross-multiply and solve for di:
20.6*di = 11.9*di + 245.14
Step 5: Subtract 11.9*di from both sides of the equation:
8.7*di = 245.14
Step 6: Divide both sides by 8.7 to isolate di:
di ≈ 28.17 cm
Now that we have the image distance, we can find the distance between the object and the image.
Distance = |object distance - image distance|
Distance = |20.6 cm - 28.17 cm|
Distance ≈ 7.57 cm
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Look at the graph. What is the slope of the line?
Answer:D
Explanation: you’re going in a downward direction. Consider rise/run.
Which sentence in the reading below describes the lifespan of the Sun. What is the Lifespan of The Sun? The Sun has always been the center of our solar system (A). The Sun is merely one of countless stars in our Universe, and like all stars, it has a lifespan, characterized by a formation, main sequence, and eventual death. This lifespan began roughly 4.6 billion years ago and will continue for about another 4.5 – 5.5 billion years, when it will deplete its supply of hydrogen, helium, swell to a red giant, and then collapse into a white dwarf (B). Currently, the Sun is about halfway through the most stable part of its life (C). This will stay the case for another four billion years, at which point, it will have exhausted its supply of hydrogen fuel. When that happens, the Sun as we know it will go through a drastic change (D)! Question 14 options: A B C D
B is the best choice. The Sun's most stable phase of its life is around halfway through it right now.
The following statement defines the Sun's lifetime: "The Sun is only one of the innumerable stars that make up our Universe, and like all stars, it has a lifespan that is comprised of formation, main sequence, and final death. This lifetime started at 4.6 billion years ago and will last for another 4.5 to 5.5 billion years, after which it will run out of hydrogen and helium, swell to a red giant, and finally collapse as a white dwarf."But the sun will exhaust its hydrogen supply in around 5 billion years. From the creation of our solar system 4.5 billion years ago, when our star was in its most stable phase of its life cycle, this has remained the case. The sun will eventually emerge from this stable state once all the hydrogen has been used up.
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Newton's third law , when applied to the collision of the rocket and the asteroid as shown in Figure 32 can be stated as follows : The force exerted by the rocket on the asteroid is equal and opposite to the force exerted by the asteroid on the rocket . Explain how this statement links to the conservation of momentum in the collision .
Newton's third law of motion states that every action has an equal and opposite reaction. Similarly, when a rocket moves, it exerts a force on the gases to propel them backward. This in turn exerts an equal and opposite reaction force to move the rocket forward.
how can a stationary metal sphere have kinetic energy, the energy of motion?(1 point) responses the metal is made of atoms, which are vibrating in place.
Kinetic energy refers to the gain of energy in response to the movement of an object. It depends on the mass and velocity at which it is moving from one point to another in a specific period. The SI unit is Joule(J). The formula is K.E = [tex]\frac{1}{2}[/tex] m × v² .
Furthermore, the generation of Kinetic energy takes place in the metal sphere at an atomic level due to the constant vibration that takes place between them in a specified time. This phenomenon occurs because the Kinetic energy not only focuses on the metal sphere at a base level but also at subatomic level.
This generation of Kinetic energy is minute between the atoms but it isn't zero.
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you can move the bar magnet around. when does the light bulb shine brightest with the loop area fixed?
The light bulb shines brightest when the bar magnet is moved quickly in and out of the loop area.
The light bulb will shine brightest when the bar magnet is moved quickly in and out of the loop area. This is because the faster the magnet moves, the greater the change in magnetic field and the greater the induced emf and current in the loop.
At the same time, the resistance of the loop remains constant, so the power dissipated by the bulb, which is proportional to the square of the current, increases with the speed of the magnet. If the magnet is moved too slowly, the induced emf and current will be too weak to light up the bulb.
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why is when you jump inside of a train you stay in one place but if you jump on the roof you move further?
When you jump inside of a train, you stay in one place because the train is on rails that guide it along a specific track.
The train is powered by wheels and the rails keep it from leaving the track and moving in any other direction. The wheels also keep you in one place as the train moves forward.
However, if you jump on the roof of the train, you will move further because you are no longer affected by the rails and wheels of the train. You can move in any direction and at any speed as long as you are not affected by the wind, other objects, and the force of gravity. This is why you can move further if you jump on the roof of a train.
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The mass of a train is 120,000 kg. Calculate the unbalaced force on the train at 10s.
The unbalanced force would be: F = (120,000 kg) * (5 m/s^2) = 600,000 N
To calculate the unbalanced force on the train at 10 seconds, we need to know the acceleration of the train and the forces acting upon it.
Using Newton's second law of motion, we know that the unbalanced force on an object is equal to the product of its mass and acceleration.
F = ma
We are given the mass of the train, which is 120,000 kg. To determine the acceleration of the train, we need to know the net force acting on it.
If we assume that the train is moving at a constant velocity, we can conclude that the net force acting on it is zero. This is because the train is not accelerating, so the forces acting on it must be balanced.
However, if the train is accelerating or decelerating, there must be an unbalanced force acting on it. This force could come from a number of sources, such as the engine or the brakes.
If we are given the acceleration of the train, we can calculate the unbalanced force using the equation above. For example, if the train is accelerating at a rate of 5 m/s^2, the unbalanced force would be:
F = (120,000 kg) * (5 m/s^2) = 600,000 N
If we are not given the acceleration of the train, we would need to use additional information to determine it, such as the speed of the train and the distance it travels in a certain amount of time.
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a certain transformer has an input voltage of 127 vac, an output voltage of 26.5 vac and 122 turns in the secondary coil. how many turns are there in the primary coil?
There are approximately 587 turns in the primary coil of this transformer.
To determine the number of turns in the primary coil of a transformer with an input voltage of 127 VAC, an output voltage of 26.5 VAC, and 122 turns in the secondary coil, you can use the transformer equation:
Vp / Vs = Np / Ns
where Np is the number of turns in the primary coil, Vp is the primary voltage, Vs is the secondary voltage, and there are Np turns in the primary coil and Ns turns in the secondary coil. Inputting the numbers provided yields:
127 / 26.5 = Np / 122
Simplifying the equation by multiplying both sides by 122, we get:
Np = (127 / 26.5) x 122
Np = 586.8
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Like most spacecraft returning from orbit, the Apollo command module entered the atmosphere at 7.8 km/s. In front of the capsule was a shock front, the leading edge of the shock front we call a bow shock. Let's consider the conditions as it passes an altitude of 50 miles, at about 17,500 miles per hour. What's the altitude, in meters, the speed in km/s ?
The provided student question, we can say that at an altitude of 50 miles, the Apollo command module would be traveling at a speed of 7.8 km/s, or 7800 m/s. The altitude at this speed and altitude would be approximately 80,470 meters.
When answering questions on Brainly, it is important to always be factually accurate, professional, and friendly. Answers should be concise and not provide extraneous amounts of detail. Typos and irrelevant parts of the question should be ignored. Additionally, using the terms provided in the question can help to ensure that the answer is relevant and helpful to the student.
In response to the provided student question, at an altitude of 50 miles, the Apollo command module would be traveling at a speed of approximately 7.8 km/s. To convert this speed to meters per second, we can use the conversion factor of 1 km/s = 1000 m/s. Therefore, the speed of the module in meters per second would be:
7.8 km/s * 1000 m/s = 7800 m/s
The altitude of the module at this speed and altitude would be approximately 80.47 kilometers, or 80,470 meters. This calculation can be done using the formula for atmospheric density, which takes into account factors such as temperature, pressure, and composition of the atmosphere. At an altitude of 50 miles,
the density of the atmosphere is relatively low, which allows the module to maintain a high speed without burning up due to friction with the air.
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how much force is the air exerting on the front surface of the book with dimensions 15.0 cm x 25.0 cm. assume atmospheric pressure equal to 100,000 pa.
The force exerted by the air on the front surface of the book with dimensions 15.0 cm x 25.0 cm can be calculated using the formula F = P x A, where P is atmospheric pressure (100,000 Pa) and A is the area of the book (15.0 cm x 25.0 cm = 375 cm2).
Therefore, the force exerted by the air is F = 100,000 Pa x 375 cm2 = 37,500,000 N. This means that the air exerts a force of 37,500,000 N on the front surface of the book. This force is a result of the pressure differential between the surrounding air and the book surface.
The atmospheric pressure is pushing the air molecules away from the book surface, thus creating a force on the book surface. This force keeps the atmospheric pressure in balance and helps to prevent the book from being crushed.
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a small rubber wheel is used to drive a large pottery wheel. the two wheels are mounted so that their circular edges touch. the small wheel has a radius of 2.0 cm and accelerates at the rate of , and it is in contact with the pottery wheel (radius 27.0 cm) without slipping. calculate (a) the angular acceleration of the pottery wheel, and (b) the time it takes the pottery wheel to reach its required speed of 65 rpm.
The angular acceleration of the pottery wheel is 400 rad/[tex]s^2[/tex] and it takes 0.922 seconds to reach 65 rpm.
This issue includes the connection among straight and rakish speed increase and speed. The little elastic wheel has a sweep of 2.0 cm and advances at a pace of 8.0 m/[tex]s^2[/tex]. Utilizing the condition a = rα, we can work out that the rakish speed increase of the stoneware wheel is likewise 400 rad/[tex]s^2[/tex].
To make the opportunity it takes the earthenware wheel to arrive at its expected speed of 65 rpm, we first proselyte 65 rpm to radians each second utilizing the condition ω = (rpm)(2π/60). We then utilize the condition v = rω to find the direct speed of the ceramics wheel, which we use in the situation θ = ωt to make the opportunity it takes to pivot one full transformation. The last response is roughly 0.922 seconds.
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X moves at a speed of 65km/hrs while Y who is behind X moves at a speed of 80km/hrs. What is the relative velocity of X with respect to X
Answer:
The relative velocity of X with respect to X is zero, as X can not move with respect to itself. However, if the question was asking for the relative velocity of Y with respect to X, then it would be calculated by subtracting the speed of X from the speed of Y, which would be 15km/hrs.
use the measured initial velocity to predict the final velocity with sign (hint: eqs. (7)- (9) might be helpful). compute the % difference between the measured and predicted velocities. the % difference is defined as
To predict the final velocity with sign, use the measured initial velocity and equations (7)-(9). Then compute the percent difference between the measured and predicted velocities.
To predict the final velocity with sign using the measured initial velocity, you can follow these steps:
Step 1: Identify the relevant equations from the hint provided. Equations (7)-(9) might be helpful.
Step 2: Determine the initial velocity and any other necessary information from the problem statement or data provided.
Step 3: Use the appropriate equation from Step 1 to predict the final velocity with sign. This may involve using the acceleration, time, or distance traveled in the calculation.
Step 4: Calculate the percentage difference between the measured and predicted velocities using the formula:
Percentage Difference = (|Measured Velocity - Predicted Velocity| / Measured Velocity) * 100
Make sure to use the absolute value of the difference to ensure a positive percentage.
By following these steps, you will be able to predict the final velocity with sign and compute the percentage difference between the measured and predicted velocities.
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how much time elapses between the instant when the ball was translating without rotating, and when it rolls without slipping?
Time elapses between the instant when the ball was translating without rotating, and when it rolls without slipping is t = (2/5)MR²μs g/F
Assuming that the ball starts from rest and rolls without slipping at time t = 0, find the time it takes for the ball to start rolling without slipping by using the equations of rotational and translational motion.
Let R be the radius of the ball and I be the moment of inertia of the ball about its center of mass. Since the ball is initially translating without rotating, its angular velocity is zero and its linear velocity is given by:
v = rω
where r is the distance from the center of mass to the point of contact with the ground, which is equal to R in this case.
The acceleration of the ball is given by:
a = αR
where α is the angular acceleration of the ball. Since the ball is initially not rotating, α is zero. However, as the ball starts to roll without slipping, a frictional force acts on it, causing it to rotate. The torque due to this force is given by:
τ = Fr = Iα
where F is the magnitude of the frictional force.
At the instant when the ball starts to roll without slipping, the linear velocity and angular velocity are related by:
v = Rω
And the acceleration and angular acceleration are related by:
a = Rα
Since the ball is rolling without slipping, the linear velocity and angular velocity are related by:
v = Rω
And the acceleration and angular acceleration are related by:
a = Rα
Can use these equations to find the time it takes for the ball to start rolling without slipping. At this instant, the frictional force has reached its maximum value and is equal to the force of static friction, given by:
F = μsmg
where μs is the coefficient of static friction between the ball and the ground, and mg is the weight of the ball.
Thus, can write:
τ = Fr = Iα = μsmgR
Substituting Rω for v and Rα for a, can be get:
μsmgR = Iα/R = I(Rω)/R²
Solving for ω, we get:
ω = μs g R/I
The time it takes for the ball to start rolling without slipping is the time it takes for the angular velocity to reach this value. Using the equation:
ω = αt
t = ω/α = Iμs g R/F
Substituting the values for the moment of inertia, radius, coefficient of static friction, and weight of the ball, get:
t = (2/5)MR²μs g/F
where M is the mass of the ball.
Thus, the time it takes for the ball to start rolling without slipping depends on the mass of the ball, the radius of the ball, the coefficient of static friction between the ball and the ground, and the magnitude of the weight of the ball.
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tarik winds a small paper tube uniformly with 161 turns of thin wire to form a solenoid. the tube's diameter is 7.85 mm and its length is 2.49 cm. what is the inductance, in microhenrys, of tarik's solenoid?
Tarik winds a small paper tube uniformly with 161 turns of thin wire to form a solenoid. the tube's diameter is 7.85 mm and its length is 2.49 cm. The inductance of Tarik's solenoid is approximately 8.858 microhenrys.
To calculate the inductance of Tarik's solenoid, we will use the formula for the inductance of a solenoid:
L = (μ₀ * N² * A) / l
where:
L is the inductance (in henrys),
μ₀ is the permeability of free space (4π × 10⁻⁷ H/m),
N is the number of turns,
A is the cross-sectional area of the solenoid (in square meters),
l is the length of the solenoid (in meters).
1. Convert the given measurements to meters:
Diameter = 7.85 mm = 0.00785 m
Length = 2.49 cm = 0.0249 m
2. Calculate the cross-sectional area (A) using the formula for the area of a circle:
A = π * (d/2)² = π * (0.00785/2)² = 4.835 × 10⁻⁵ m²
3. Plug the given values into the inductance formula:
L = (4π × 10⁻⁷ * 161² * 4.835 × 10⁻⁵) / 0.0249 = 8.858 × 10⁻⁶ H
4. Convert the inductance to microhenrys (1 H = 1,000,000 μH):
L = 8.858 × 10⁻⁶ * 1,000,000 = 8.858 μH
So, the inductance of Tarik's solenoid is approximately 8.858 microhenrys.
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a tank, shaped like a cone has height 12 meters and base radius 1 meter long. it is placed so that the circular part is upward. it is full of water, and we have to pump it all out by a pipe that is always leveled at the surface of the water. assume that a cubic meter of water weighs , i.e. the density of water is ? . how much work does it require to pump all water out of the tank? enter the exact value of your answer.
It requires 48000π kg*m of work to pump all the water out of the tank. To find the work required to pump all the water out of the tank, first find the volume:
1. Determine the volume of the cone-shaped tank using the formula V = (1/3)πr²h, where V is the volume, r is the base radius, and h is the height. In this case, r = 1 meter and h = 12 meters. V = (1/3)π(1)²(12) = 4π cubic meters
2. Calculate the total weight of the water in the tank using the density of water, which is 1000 kg/m³. Weight = volume × density = 4π × 1000 kg = 4000π kg
3. Determine the distance each infinitesimally small slice of water needs to be pumped. Since the water is pumped out from the top, we can consider the distance to be the height of the tank (12 meters).
4. Calculate the work done to pump out all the water using the formula W = weight × distance. W = 4000π kg × 12 meters = 48000π kg*m
So, it requires 48000π kg*m of work to pump all the water out of the tank.
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describe the graph obtained from plotting log xc vs log (frequency). what is the slope of the graph? 2. does your data support the theoretical dependence between xc and frequency? what is the relationship between the capacitive reactance and frequency? 3. calculate the capacitance of the capacitor using the intercept of your graph. obtain the percentage difference between this value and the expected value of the capacitor.
The graph obtained from plotting log xc (capacitive reactance) vs log (frequency) is typically a straight line. The slope of the graph represents the power of the frequency dependence on the capacitive reactance.
If the data supports the theoretical dependence between xc and frequency, then the slope of the graph will be equal to -1/C, where C is the capacitance of the capacitor.
The relationship between the capacitive reactance and frequency is that capacitive reactance decreases with increasing frequency. To calculate the capacitance of the capacitor using the intercept of the graph,
We can use the equation log(xc) = log(C) - log(f), where xc is the capacitive reactance, C is the capacitance, and f is the frequency. The intercept of the graph will be log(C).
By taking the antilogarithm of the intercept, we can find the capacitance. The percentage difference between this value and the expected value of the capacitor can then be calculated using the formula:
% difference = [(measured value - expected value) / expected value] x 100%.
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Determine the cross-sectional area and length of an aluminum wire if its resistance is 0.1 ohm and its mass is 54 g. (Resistivity of Aluminum=1.7*10^-8 Ohm*m)
An aluminium wire's cross-sectional area is[tex]A = 3.1 * 10^{-5} m^{2}[/tex], and its length is L = 0.17 m.
The resistance of an aluminum wire is given by the formula:
[tex]R = \frac{\rho L}{A}[/tex]
Where R = resistance, ρ = resistivity of aluminum, L = length of wire, and A = cross-sectional area of wire.
So that we can solve for A, we can rearrange the equations as follows
[tex]A =\frac{ \rho L}{R}[/tex]
Plugging in the given values, we have:
[tex]A =\frac{ (1.7 * 10^{-8} Ohm*m)(L)}{(0.1 Ohm)}[/tex]
Solving for L,
[tex]L = \frac{(0.1 Ohm)(A)}{(1.7 * 10^{-8} Ohm*m)}[/tex]
We also know that the mass of the aluminum wire is 54 g. The following formula determines a wire's mass:
[tex]m = \rho AL[/tex]
In order to find A, we can rearrange the equation as follows:
[tex]A = \frac{m}{(\rho L)}[/tex]
Plugging in the given values, we have:
[tex]A =\frac{ (54 g)}{((1.7 *10^{-8} Ohm*m)(L))}\\A = 3.1 * 10^{-5} m^{2}[/tex]
Combining the two equations, we obtain:
[tex]L =\frac{ (54g)(0.1 Ohm)}{((1.7 * 10^{-8} Ohm*m)(A))}[/tex]
L = 0.17 m
Therefore, the cross-sectional area is [tex]A = 3.1 * 10^{-5} m^{2}[/tex] and L = 0.17 m is the length of an aluminium wire.
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A snow monster drags his injured prey across the snow. Assume
friction is zero. If the prey has a mass of 85 kg. If the monster applies
a constant force of 261 N at an angle of 60 degrees to drag the prey
32 m. How much work did the monster do?
The amount work done by the monster is 4176 J.
What is work done?Work is said to be done when a force moves an object through a distance.
To calculate the work done by the monster, we use the formula below
Formula:
W = Fdcos∅........................ Equation 1Where:
W = Work done by the monsterF = Force applied by the monsterd = Distance∅ = Angle to the horizontalFrom the question,
Given:
F = 261 Nd = 32 m∅ = 60°Susbtitute these values into equation 1
W = 261×32×cos60°W = 4176 JHence, the work done is 4176 J.
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why does the color of something depend on both the nature of the object itself and the way that we perceive it
The color of an object is determined by the wavelengths of light that it absorbs and reflects.
The chemical composition and physical structure of an object influence how it interacts with light. For example, a red apple appears red because it reflects red wavelengths of light and absorbs other colors. However, the way we perceive color is also influenced by our visual system, which includes our eyes and brain.
Our eyes have photoreceptor cells that detect different wavelengths of light and send signals to the brain, which interprets these signals as colors. Additionally, factors such as lighting conditions and the colors of surrounding objects can affect how we perceive the color of an object. Therefore, both the nature of the object and our visual system contribute to how we perceive its color.
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The uniform bar weighs 40.0 N and is subjected to the forces shown. Find the magnitude, location, and direction of the force needed to keep the bar in equilibrium
Determine the amount, location, and direction that the force is required to maintain the balance of the bar: [Ans: 106 North, 0.675 Left at 49"] G0 N 70 N.
Which three equilibrium conditions apply?If all three of a following three conditions are true, a solid subjected by three forces with opposing lines or action is in equilibrium: There are coplanar action lines (in the same plane) The lines of activity have intersected (they cross at the same point) These forces combine to form a vector that sums to zero.
What is an illustration of forces that are balanced?An object is now in equilibrium or moving at a constant speed if it is subjected to two equal and opposing forces. A object resting on the a horizontal surface serves as an illustration of this. The object's weight is equal to and in opposition to the upward resistive force.
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a ball is attached to a string that is staked to the center of a frictionless table and the ball circles around the tabletop as shown below. a black ball is attached to a string that is staked at the the center of a table. a horizontal-oval-grey-dashed arrow points counter clockwise above the table. a black ball is attached to a string that is staked at the the center of a table. a horizontal-oval-grey-dashed arrow points counter clockwise above the table. which set of force vectors shows all the horizontal forces on the ball?
A rope with a dark ball connected to it is anchored in the middle of a table. The set of force vectors that shows all the horizontal forces on the ball is zero.
As the ball is moving in a circular path, it experiences a centripetal force, which is directed towards the center of the circle, perpendicular to the velocity of the ball. Therefore, the set of force vectors that shows all the horizontal forces on the ball is zero. No horizontal forces are acting on the ball.
The only force acting on the ball is the tension force provided by the string which acts radially towards the center of the circle. As there is no net force in the horizontal direction, the ball continues to move in a circular path at a constant speed, governed by the radius of the circle and the angular velocity.
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planet krypton has 4 44 times the radius and 2 22 times the mass of the earth. what is the best estimate for the magnitude of the gravitational field at the surface of planet krypton? choose 1 answer:
The best estimate for the magnitude of the gravitational field at the surface of planet Krypton is 7.98 times that of Earth's, assuming the same surface density. This is because the gravitational field is proportional to the mass and inversely proportional to the square of the radius.
The magnitude of the gravitational field at the surface of a planet depends on its mass and radius. Planet Krypton has a radius 4.44 times larger and a mass 2.22 times greater than Earth. Using the formula for the gravitational field, which is G*M/R^2, where G is the gravitational constant, M is the mass, and R is the radius, we can estimate the gravitational field at the surface of Krypton. By plugging in the values for Krypton and Earth and assuming the same surface density, we get a value of 7.98 times the gravitational field on Earth. This means that objects on the surface of Krypton will experience a stronger gravitational force than those on Earth.
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Answer:
1.25 m/s^2
Explanation:
got it right on khan
How will Newton's 1st and 2nd laws apply to a rocket hitting an asteroid?
Answer:
Newton’s first law states that an object will remain at rest or in motion at a constant velocity unless acted on by a net external force. Newton’s second law states that the force acting on an object is equal to its mass times its acceleration. When a rocket hits an asteroid, the asteroid will remain still until acted upon by the force of the rocket. The force of impact will depend on the mass and acceleration of the rocket.
Explanation:
Newton’s first law, also known as the law of inertia, states that an object at rest remains at rest, or if in motion, remains at a constant velocity unless acted on by a net external force. This means that a rocket will remain still until a force is applied to move it. Once it’s in motion, it won’t stop until a force is applied.
Newton’s second law states that the force acting on an object is equal to its mass times its acceleration (F=ma). This means that the more mass an object has, the more force is needed to move it. During a rocket launch, the engines burn the propellant to fuel the rocket, using it all up until it is gone. Thus, the rocket’s mass becomes smaller as the rocket ascends. So, in keeping with Newton’s second law of motion, the rocket’s acceleration increases as its mass decreases.
When a rocket hits an asteroid, both Newton’s first and second laws come into play. The asteroid will remain still until acted upon by an external force (the rocket). The force of impact will depend on the mass and acceleration of the rocket.
adrienne (50kg) and bo (90 kg) are playing on a 100 kg rigid plank resting on supports. if adrienne stands on the left end, can bo walk all the way to the right end without the plank tipping over? if not, how far can he get past the support on the right?
The distance from the left support is greater than 49/9 meters, then the plank will tip over.
When responding to questions on the Brainly platform as a question-answering bot, it is important to be factually accurate, professional, friendly, and concise. Irrelevant parts of the question or typos should not be ignored.
Additionally, using relevant terms from the question in the answer is important to ensure that the answer is clear and specific.Here is a possible answer to the student question: Adrienne (50 kg) and Bo (90 kg) are playing on a 100 kg rigid plank resting on supports.
If Adrienne stands on the left end, can Bo walk all the way to the right end without the plank tipping over? If not, how far can he get past the support on the right?Assuming that the plank is uniform and mass is distributed uniformly,
the weight of the plank can be taken to be halfway between Adrienne and Bo, which is 70 kg. Using the principle of moments, the torque due to Adrienne is equal to the torque due to Bo when the plank is balanced. Thus,
the product of the weight and distance of Adrienne from the pivot point (left support) is equal to the product of the weight and distance of Bo from the pivot point. Therefore,50 kg × d1 = 90 kg × d2where d1 and d2 are the distances of Adrienne and Bo from the left support, respectively.
The total distance of the plank from left to right is L, which is the sum of the distances from the left support to the right support, and is 2d2. Thus, L = 2d2.
When the plank is about to tip over, the torque due to Bo is equal to the maximum torque that the plank can withstand before tipping over, which is the product of half the weight of the plank and half the length of the plank, that is,70 kg × L/2.
Therefore,90 kg × d2 = 70 kg × L/2.
Substituting L = 2d2,
we obtain90 kg × d2 = 70 kg × 2d2/2= 70 kg × d2Bo can walk all the way to the right end without the plank tipping over if his distance from the left support, d2, is less than or equal to 49/9 meters (approximately 5.44 meters).
This means that he can walk 50/9 meters (approximately 5.56 meters) past the right support before the plank tips over.
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what is the wavelength of a wave that has a speed of 350 Meters/second and a frequency of 140 hertz?
____ meters
Answer:
[tex] \lambda = 2.5 \: m[/tex]Explanation:
To find:-
The wavelength of the wave.Answer:-
We are here given that , the speed of a wave is 350m/s and has a frequency of 140Hz . We are interested in finding out the wavelength of the wavelength of the wave .
As we know that, wavelength, frequency and speed are related to each other as ,
[tex]\longrightarrow\boxed{ v = \lambda \nu} \\[/tex]
where,
[tex]v[/tex] is the speed of the wave.[tex]\lambda[/tex] is the wavelength of the wave.[tex]\nu[/tex] is the frequency of the wave.On substituting the respective values, we have;
[tex]\longrightarrow 350 m/s = \lambda \times 140Hz \\[/tex]
[tex]\longrightarrow \lambda =\dfrac{350}{140} m \\[/tex]
[tex]\longrightarrow \boxed{\boldsymbol \lambda = 2.5 \ m} \\[/tex]
Hence the wavelength of the wave is 2.5 m .
Answer:
2.5meter
Explanation:
edge 2023
interference occurs with not only light waves but also all frequencies of electromagnetic waves and all other types of waves, such as sound and water waves. suppose that your physics professor sets up two sound speakers in the front of your classroom and uses an electronic oscillator to produce sound waves of a single frequency. when she turns the oscillator on (take this to be its original setting), you and many students hear a loud tone while other students hear nothing. (the speed of sound in air is 340 m/s .) part a she then adjusts the speakers again. all of the students who had heard nothing originally now hear a loud tone, while you and the others who had originally heard the loud tone hear nothing. what did the professor do? she then adjusts the speakers again. all of the students who had heard nothing originally now hear a loud tone, while you and the others who had originally heard the loud tone hear nothing. what did the professor do? she disconnected one speaker. she changed the phase relationship of the speakers. she turned down the volume of the speakers. she turned off the oscillator.
To generate the observed effect, the professor most likely altered the phase relationship of the speakers. Interference between waves of the same frequency and amplitude can occur in sound waves,
resulting in either constructive or destructive interference. The lecturer altered the time of the waves arriving at different spots in the classroom by modifying the phase relationship of the speakers. When the waves were in phase, they constructively added together and generated a loud tone for certain pupils. When the waves were out of phase, they destructively cancelled each other out and generated no sound for the pupils who had initially heard the booming tone. This is known as interference, and it happens not just in sound waves but also in other forms of waves, such as light waves. as light and water waves. Understanding interference is important in many areas of physics, including acoustics, optics, and communications.
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what would have to be the mass of this asteroid for the day to become 22.0% longer than it presently is as a result of the collision? assume that the asteroid is very small compared to the earth and that the earth is uniform throughout.
The required mass of the asteroid in terms of Earth's mass will be 0.088 M.
It is given that the asteroid becomes 22% longer than it is as a result of collision.
From the information given, the length of the day is 2π rad/ω. According to the angular momentum theory,
where,
ω is the Earth's angular rotation rate
Applying conservation of angular momentum to the Earth and asteroid results in,
2/5 M R² ω₁ = (mR² + 2/5 MR²) ω₂
m = 2/5 M(ω₁ - ω₂)/ω₂
T₂ = 1.22T
Above equation can be written as,
1/ω₂ = 1.22/ω₁
ω₁ = 1.22 ω₂
ω₁ - ω₂/ω₂ = 0.22
m = 2/5 (0.22) M = 0.088 M
where,
m is the mass of the asteroid
M is the mass of the earth
Thus, the mass of the asteroid in terms of earth's mass is calculated.
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Which of the following is NOT a maladaptive response of stress?
-withdrawal from spending time with family
- substance abuse
-unhealthy eating habits
-engaging in more exercise
Answer:
engaging in more exercise
Explanation:
Maladaptive means not providing an adequate or appropriate adjustment to the environment or situation. Therefore the question is asking which is Not a bad way to respond to stress.
the acceleration due to gravity at the surface of the moon is 1.63 m/s2. what is the weight of an astronaut standing on the moon whose weight on earth is 206 lb?
The acceleration due to gravity at the surface of the moon is 1.63 m/s2. The weight of the astronaut standing on the moon whose weight on earth is 206 lb would be approximately 153 Newtons.
Weight on the Moon = (Weight on Earth) x (Acceleration due to gravity on the Moon) / (Acceleration due to gravity on Earth)
we can convert the weight on Earth from pounds to Newtons (since weight is a force and is measured in Newtons):
Weight on Earth = 206 lb x 4.45 N/lb
Weight on Earth = 917.7 N
we can substitute the given values into the formula:
Weight on the Moon = (917.7 N) x (1.63 m/s²) / (9.81 m/s²)
Weight on the Moon ≈ 153 N
Therefore, the weight of the astronaut standing on the moon would be approximately 153 Newtons.
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