The weight of the block and normal reaction are equal in magnitude but opposite in direction. Also, the frictional force and applied force are equal in magnitude but opposite in direction.
The forces acting on the wooden block moving at a constant speed include the following;
weight of block acting downwards, Wnormal reaction on the block acting upwards, Napplied force on the block acting towards positive x-direction, Ffrictional force acting towards negative x-direction, [tex]F_f[/tex]The free-body diagram is presented below;
N
↑
[tex]F_f[/tex] ← ⊕ → F
↓
W
The block is moving at a constant speed, we will have the following;
[tex]W = N \\\\F = F_f[/tex]
Thus, we can conclude that the weight of the block and normal reaction are equal in magnitude but opposite in direction. Also, the frictional force and applied force are equal in magnitude but opposite in direction.
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what we have learned about the different cultures of Native Americans
Native Americans worldview is deep and intense and infused with spiritual meaning. Everything in their culture ties into their belief system and their love for their land and people.
which forces have physicists shown to be the same force under conditions of very high temperature, as confirmed by experiments in particle accelerators?
Answer:
the electromagnetic and weak forces
Explanation:
Imagine you have a ball tied to the end of a string. You hold the other end of the string and swing it around. Suppose the string breaks, what direction will the ball travel
A helicopter travelling at a velocity of 15 m/s [W] accelerates uniformly at a rate of 7.0 m/s2 [E] for 4.0 s. What is the helicopter’s final velocity?
If we take West to be the negative direction, then the initial velocity is -15 m/s and the acceleration (which points East) is +7.0 m/s².
After t = 4.0 s, the helicopter's velocity is
-15 m/s + (7.0 m/s²) (4.0 s) = +13 m/s
or 13 m/s [E].
Please find attached photograph for your answer.
Hope it helps.
Do comment if you have any query.
A 29000-kg open railroad car, initially coasting at 0.825 m/s with negligible friction, passes under a hopper that dumps 117500 kg of scrap metal into it.
a)What is the final speed, in meters per second, of the loaded freight car?
b)How much kinetic energy is lost, in joules, when the freight car receives this scrap metal? Ignore the free-fall kinetic energy of the scrap metal.
Answer:
a) Answer: 0.16331 m/s
b) Answer: 8522.66 joules
Explanation:
The final speed is 0.1633 m/s.
When the freight car receives this scrap metal, 7915.72 Joule kinetic energy is lost.
What is momentum?A body has momentum while it is moving, according to our understanding. It is said that a body's momentum is equal to the sum of its mass and speed. A body's direction is important when discussing momentum. Its direction belongs to the body's direction of motion.
(a) Given parameter:
Mass of the railroad car, M = 2900 Kg.
Mass of the scrap metal, m= 11750 Kg.
Initial speed of the car, u = 0.0825 m/s.
Initial speed of the scrap metal = 0 m/s.
Final speed of the system, v = ?
Then, initial momentum of the system = initial momentum of the car + initial momentum of the scrap metal .
= (29000×0.825 + 117500×0) kg.m/s.
= 23925 kg.m/s.
Final momentum of the system = total mass of the system× final speed
= (29000 + 117500)× v kg.m/s
= 146500v kg.m/s.
Hence, from principle of conservation of momentum,
initial momentum of the system = Final momentum of the system
⇒ 23925 = 146500v
⇒ v = 0.1633 m/s.
The final speed of the loaded freight car is 0.1633 m/s.
(b) Lost in kinetic energy = initial kinetic energy of the car - final kinetic energy of the loaded car.
= 1/2*29000*0.825² -1/2*(29000 + 117500)* 0.1633² Joule.
= 7915.72 Joule.
Hence, 7915.72 Joule kinetic energy is lost in this process.
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mars one mission essay
so bassicly Mars is a planet
Explanation:
planet
16g 2g/cm3 what is the Volume
Answer:
V = 1.25E-7 cubic meter
As the distance between two objects changes, how does the gravitational force between them change?
Answer:
Explanation:
The gravitational force = G * m1 * m2 / r^2
That means as the distance increases, r get's bigger and m1 and m2 don't change, the force decreases. Read that sentence carefully. In physics, it is very important to know what goes up and goes down means and especially why.
Which choice can be classified as a pure substance?
A. homogeneous mixture
B. compound
C. heterogeneous mixture
D. solution
An object of mass of 2.0 kg rotates at constant speed in a horizontal circle of radius 5.0 m. The time
for one complete revolution is 3.0 s. What is the magnitude of the resultant force acting on the object.
Explanation:
follow the above attachment to get the answer.
A 455 kg cannon fires a 21 kg cannonball at 26 m/s. If the cannon is on wheels, at what velocity does it move backward?
Answer:
A cannon ball of mass 4.0 kg is fired from a stationary 96 kg cannon at 120 m/s. Calculate the velocity of the cannon immediately after firing.
total momentum of cannon and cannon ball before = 0 kg m/s - because neither object is moving
total momentum of cannon and cannon ball after collision = 0 kg m/s - because momentum is conserved
Momentum of cannon ball after firing = 4.0 × 120 = 480 kg m/s.
Momentum of cannon after firing = -480 kg m/s (because it recoils in the opposite direction and 480 - 480 = 0 kg m/s, the total momentum after collision).
Rearrange p = m v to find v:
v = p/m
v = 480 divided by 96
v = 5.0 m/s
Note that the forward velocity of the cannon ball was given a positive value. The negative value for the cannon's velocity shows that it moved in the opposite direction.
Why does time seem to flow only in one direction? ...
Answer:
Mass is relative too. Thus, as much fuel as you pack you will never reach the velocity of light. At the velocity of light, if you were somehow to reach it, your mass will be infinite and it will so require infinite force to push you, so no going beyond that speed. This is the reason time flows in a single direction.
Explanation:
Block 1, of mass m1, moves across a frictionless surface with speed ui. It collides elastically with block 2, of mass m2, which is at rest (vi=0). (Figure 1)After the collision, block 1 moves with speed uf, while block 2 moves with speed vf. Assume that m1>m2, so that after the collision, the two objects move off in the direction of the first object before the collision. What is the final speed vf of block 2?
The conservation of the momentum allows to find the velocity of the second body after the elastic collision is:
[tex]v_f = \frac{2u_o}{1- \frac{m_2}{m_1} }[/tex]
the momentum is defined by the product of the mass and the velocity of the body.
p = mv
The bold letters indicate vectors, p is the moment, m the mass and v the velocity of the body.
If the system is isolated, the forces during the collision are internal and the it is conserved. Let's find the momentum is two instants.
Initial instant. Before crash.
p₀ = m₁ u₀ + 0
Final moment. After crash.
[tex]p_f = m_1 u_f + m_2 v_f[/tex]
The momentum is preserved.
p₀ = [tex]p_f[/tex]
[tex]m_1 u_o = m_1 u_f + m_2 v_f[/tex]
Since the collision is elastic, the kinetic energy is conserved.
K₀ = [tex]K_f[/tex]
½ m₁ u₀² = ½ m₁ [tex]u_f^2[/tex] + ½ m₂ [tex]v_f^2[/tex]
Let's write our system of equations.
[tex]m_1 u_o = m_1 u_f + m_2 v_f \\m_1 u_o^2 = m_1 u_f^2 + m_2 v_f^2[/tex]
Let's solve
[tex]u_f = u_o - \frac{m_2}{m_2} \ v_f \\u_f^2 = u_o^2 - \frac{m_2}{m_1} \ v_f^2[/tex]
[tex]( u_o - \frac{m_2}{m_1} v_f)^2 = u_o - \frac{m_2}{m_1} \ v_f^2 \\u_o^2 - 2 \frac{m_2}{m_1} \ u_o v_f + (\frac{m_2}{m_1} )^2 v_f^2 = u_o^2 - \frac{m_2 }{m_1} \ v_f^2[/tex]
[tex]2 \frac{m_2}{m_1} \ u_o = \frac{m_2}{m_1} v_f \ ( 1 - \frac{m_2}{m_1}) \\v_f = \frac{2u_o}{1-\frac{m_2}{m_1} }[/tex]
In conclusion, using the conservation of momentum, we can find the velocity of the second body after the elastic collision is:
[tex]v_f = \frac{2u_o}{1-\frac{m_2}{m_1} }[/tex]
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A crankshaft of an engine increases its spin from 1,000 rpm to 1,500 rpm in 0.5 s. What is its angular acceleration? (1 rev=2π rad)
600 rad/s2
100 rad/s2
500 rad/s2
60 rad/s2
the answer is 100 rad/s2
20 examples of electropositive radical
10. Which of the following will happen to the respiratory-associated muscles if you were to blow up a balloon?
A. Diaphragm contracts, Internal intercostal would relax
B. Diaphragm would contract, external intercostal would relax
C. Internal intercostal and abdominal muscles would contract
D. External intercostal would contract and diaphragm would relax
Answer:
C
for sure
go for it
..............
a force that is at rest or moves in at a constant speed and in a constant direction is called a what force
The question is fishing for "balanced force".
But the description in the question is terrible.
If you had a stain on your shoe, what would you do to cover it?
Answer: depends what kind of stain and color shoe.
Explanation:
Answer:
Wash the shoe
Explanation:
If the stain is unwashable, then I'd either get new shoes or paint over them.
IF THE VECTOR COMPONENTS OF VECTOR A ARE MULTIPLIED BY 9 THEN THE MAGNITUDE OF VECTOR A IS INCREASES BY A FACTOR OF .........
Answer:
it increased by 29 sorry hope this helps
ignore this i put the wrong grade sorry
Answer:
Oh its fine i am not in college but its still fine
Explanation:
calculate the relative density of a block having dimension 4m x 3m x 2m given its mass in 48000g
Answer:
in the picture
Explanation:
CARRY ON LEARNING
If professor X can move things with his mind.Then why cant he move his legs?
Answer: Varies
Explanation:
Because moving his legs require force.
Answer:
He is also a low-level telekinetic
Explanation:
He is a telepath and doesn’t have telekinesis btw.
What are nucleic acids, and what are their function and structure? Give an example
what is the main difference between a substance going through a physical change and one going through a chemical ?
Answer: Physical changes only change the appearance of a substance, not its chemical composition. Chemical changes cause a substance to change into an entirely substance with a new chemical formula. Chemical changes are also known as chemical reactions.
Answer:
just give the other person brainlyest
Explanation:
The surface of this planet is obscured by an atmosphere of thick clouds and toxic gases. What planetary body is it
Answer:
Venus....
Explanation:No explanation just simple answers
Cuáles son las diferencias, con respecto al proceso de extracción y tratamiento, entre
el gas propano y el gas metano.
Answer:
la burguesía era de clase alta y en su mayoría rica. La gente de clase trabajadora generalmente trabajaba con un salario mínimo y solo tenía suficiente dinero para poner comida en la mesa. En este momento, la gente veía a los trabajadores de clase media como menos que otras personas.
Explanation:
I will give Brainliest answer and 5 stars
Jay decides to walk home from school today. He lives 3 miles from school and can walk home in 45 minutes. At what rate is Jay traveling?
A. 1 mile/10 minutes
B. 1 mile/15 minutes
C. 1 mile/20 minutes
D. 1 mile/30 minutes
Answer:
James is traveling at 4 miles per hour.
Explanation:
3 miles per 45 minutes
x miles per 60 minutes(1 hour)
___________________
3*60=45*x
180=45x |:45
x=4
Alex drops a soccer ball and a table tennis ball from the top of a ladder. He wants to compare the velocities of the balls just before they hit the ground.
Which formula should Alex use to calculate the velocity of each ball,
assuming they are in free fall?
A) v=Gt
B) g=vt
C) t=vg
D) v=G/t
Answer:
d is the correct answer
Explanation:i did this math
In a titration, 50.00 cm3 of 0.300 mol/dm3
sodium hydroxide solution is exactly neutralized by 25.0
cm3 of a dilute solution of hydrochloric acid.
NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)
Calculate the concentration of the hydrochloric acid. Show your work out
PLS URGENT ANS
Answer:
Step 1: Calculate the amount of sodium hydroxide in moles
Volume of sodium hydroxide solution = 50.0 ÷ 1,000 = 0.05 dm3
Rearrange:
Concentration in mol/dm3 = amount of solute in molvolume in dm3
Amount of solutein mol = concentration in mol/dm3 × volume in dm3
Amount of sodium hydroxide = 0.300 × 0.05
= 0.01 5mol
Step 2: Find the amount of hydrochloric acid in moles
The balanced equation is: NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)
So the mole ratio NaOH:HCl is 1:1
Therefore 0.015 mol of NaOH reacts with 0.015 mol of HCl
Step 3: Calculate the concentration of hydrochloric acid in mol/dm3
Volume of hydrochloric acid = 25.00 ÷ 1000 = 0.025 dm3
Concentration in mol/dm3 = amount of solute in molvolume in dm3
Concentration in mol/dm3 = 0.015/0.025
= 0.6 mol/dm3
Step 4: Calculate the concentration of hydrochloric acid in g/dm3
Relative formula mass of HCl = 1 + 35.5 = 36.5
Mass = relative formula mass × amount
Mass of HCl = 36.5 × 0.6
= 21.9 g
So concentration = 21.9 g/dm3
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The answer is D
I hope this helps :)