A window is 150cm wide and 90cm high what is the area of the window in square metres

Answer:

Step-by-step explanation:

the minimum mark the student should obtain is 32

To maintain an average of 79, Aldo must obtain a score of 82 in his upcoming exam.

To get the solution, let's calculate the total of the first five scores.

Total of the first five scores = 77 + 88 + 77 + 87 + 63 = 392

Now we know that there are a total of six scores, so to get the mean, we will divide the total by six.

Mean = Total/Number of ScoresTherefore, 79 = 392 + x/6

We need to find the value of x that will satisfy the above equation.

Now we will solve for x.79 = 392 + x/6

(Multiply both sides by 6) 6 * 79 = 6 * 392 + x6 * 79 = 2352 + xx = 6 * 79 - 392x = 474 - 392x = 82

Therefore, Aldo needs to score 82 on his next test to achieve an average of 79.


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a) Xiao is 13 hours short of his sleep goal for the week.

b) After 4 nights, Xiao is 5 hours short of his sleep goal.

a) Given,Xiao's goal is to get 8 hours of sleep per weeknight, which means he aims to get 40 hours of sleep (8 hours per night x 5 weeknights) during the week. To find the difference between the amount of sleep he got and his goal, we need to calculate the total amount of sleep he got during the week and subtract it from his goal:

Total sleep = [tex]6 \frac{1}{2} + 7 \frac{1}{2} + 5 \frac{3}{4} + 8 \frac{1}{4} = 27[/tex]

Difference from goal = 40 - 27

= 13

Therefore, Xiao is 13 hours short of his sleep goal for the week.

b. After 4 nights, Xiao has slept for a total of:

Total sleep = 27

Since he aims to get 8 hours of sleep per weeknight, he would have gotten a total of 32 hours of sleep (8 hours per night x 4 weeknights) if he had met his goal. To find out how much he is ahead or behind in his sleep goal, we need to calculate the difference between the total amount of sleep he got and his goal:

Difference from goal = 32 - 27 = 5

Therefore, after 4 nights, Xiao is 5 hours short of his sleep goal.

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The correct answer is 69 percent.

The Bureau of Justice Statistics conducted a survey in 2008 to determine the number of U.S. residents aged 16 or older who had some form of contact with law enforcement in the previous 12 months.

The survey found that approximately 26.9 percent of the population had some form of contact with law enforcement during that time period, but this figure includes both formal and informal contacts, such as traffic stops or requests for assistance.

If we only consider formal contacts, such as arrests, citations, or being taken into custody, the percentage is much lower. According to the same survey, only about 1.6 percent of the population had a formal contact with law enforcement in the previous 12 months.

Therefore, the correct answer to the question "what percentage of U.S. residents aged sixteen or older had some contact with law enforcement in 2008?" depends on whether formal or informal contacts are being considered. If we include informal contacts, the answer is 26.9 percent. If we only consider formal contacts, the answer is 1.6 percent.

Neither 6.9 percent nor 16.9 percent are accurate answers. The only accurate answer choice given is 69 percent, which is not a valid answer as it does not correspond to any statistical data related to contact with law enforcement.

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Answer:

There were 62 people on the train to begin with.

Step-by-step explanation:

Firstly,i I subtracted 21 with 18 so i got 3.

It means that the train got 3 more people from the start.

Then i subtracted 65 with 3.

And so i got 62.

Answer:

Step-by-step explanation:

First, we need to calculate the annual interest rate from the given APR.

APR = 2.25%

Daily interest rate = 2.25% / 365 = 0.00616438

Now, we can use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where:

A = the final amount

P = the principal (initial amount)

r = the annual interest rate (as a decimal)

n = the number of times the interest is compounded per year

t = time in years

In this case, P = $2,000, r = 0.00616438, n = 365 (daily compounding), and t = 4.

A = 2000(1 + 0.00616438/365)^(365*4)

A = 2000(1.00616438)^1460

A = $2,388.34 (rounded to the nearest cent)

Therefore, the answer is option D) $2,388.34.

Amy is picking her fall term classes, including probability 101, 102, and 103 so,

Probability refers to potential. A random event's occurrence is the subject of this area of mathematics. The range of the value is 0 to 1. Mathematics has included probability to forecast the likelihood of certain events. The degree to which something is likely to happen is basically what probability means.

You will understand the potential outcomes for a random experiment using this fundamental theory of probability, which is also applied to the probability distribution.

a) the probability that she will get 101

P = [tex]\frac{^1C_1*^1^9C_2}{^2^0C_3}[/tex]

= 171/1140

P = 0.15

probability that she will get 101 = 0.15.

b) the probability that she will get 101 and 102.

P = [tex]\frac{1*1*18}{20!*3!(20-3)!}[/tex]

P = 18/1140

= 0.0158

probability that she will get probability 101 and probability 102 is 0.0158.

c) the probability she will get all three probability courses

P = [tex]\frac{^3C_3}{^2^0C_3}[/tex]

= 1/1140

P = 0.0009

The probability she will get all three probability courses is 0.0009.

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Complete question:

Amy is picking her fall term classes. She needs to fill three time slots, and there are 20 distinct courses to choose from, including probability 101, 102, and 103. She will pick her classes at random so that all outcomes are equally likely.

(a) What is the probability that she will get probability 101?

(b) What is the probability that she will get probability 101 and probability 102?

(c) What is the probability she will get all three probability courses?

We can write the integral of f(x) as the sum of the integral of the even component, e(x), and the integral of the odd component, o(x). This gives us the following equation:  ∫f(x)dx = ∫e(x)dx + ∫o(x)dx

Integrals can be written as the sum of the integral of an odd function and the integral of an even function. This is because any function can be broken down into its even and odd components. Even functions are those that remain unchanged when reflected over the x-axis. This means that the result of evaluating the function for any x-value is the same as the result for its negative. Odd functions are those that change sign when reflected over the x-axis. This means that the result of evaluating the function for any x-value is the negative of the result for its negative.

The integral of an even function is the same regardless of whether it is written as the sum of the integral of an odd function and the integral of an even function, or if it is written just as an integral of the even function. The integral of an odd function is the negative of the integral of the even function when written as the sum of the two integrals.

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The bonus question asks for the application of the integral test to determine the convergence of the series given by 2n*e^(-a).

The integral test is a method used to determine the convergence or divergence of a series by comparing it to the integral of a related function. In this case, we are given the series 2n*e^(-a), and we can use the integral test because the terms of the series involve the variable 'n', and the function e^(-a) can be integrated.

To apply the integral test, we consider the integral of the function corresponding to the series. In this case, we integrate the function f(x) = 2x*e^(-a) from 1 to infinity. If this integral converges, then the series is also convergent. Conversely, if the integral diverges, then the series is divergent.

By evaluating the integral of f(x) and analyzing its convergence or divergence, we can determine whether the given series 2n*e^(-a) converges or diverges. Showing all the steps in evaluating the integral and discussing the convergence properties of the resulting integral will be necessary to receive full credit for this question.

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Answer
Y. Answer:

y=30

Step-by-step explanation:

(3)^2 equals 9, so the first blank is 9.

You then multiply it by the 2, so second blank is 18.

18+15=33

33-3=30=y

Answer:

30

Step-by-step explanation:

first space should be 9 since 3² is 9

second space should be 18 since 2×9=18

final space should be 30 since 18+15 is 33-3=30

Option a) The finding that the reputation of lawyers with the general public has declined because of advertising is NOT supported by several studies about lawyer advertising.

Lawyer advertising refers to advertising or soliciting the services of lawyers. It is designed to attract potential clients to retain their services. Lawyer advertising may involve a wide variety of mediums, including television, radio, print media, billboards, and the internet. Legal professionals may advertise their services on a wide range of platforms in order to reach as many people as possible.

According to several studies about lawyer advertising, the public considers the ads a valuable source of information. However, the public objects when advertising is invasive. The findings show that the negative effects of lawyer advertising on the reputation of lawyers with the general public are not supported by empirical data. In other words, the reputation of lawyers with the general public has not declined because of advertising.

The following are some of the other findings of several studies about lawyer advertising:

However, the public also perceives lawyer advertising as an attempt to lure them into hiring a lawyer. Lawyer advertising can increase public awareness about the availability of legal services, but it can also lead to unrealistic expectations regarding the outcome of legal disputes.

Hence option a) is correct.

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Answer:

[tex]y = \frac{1}{7} x + 5[/tex]

Step-by-step explanation:

[tex]x - 7y = - 21[/tex]

[tex] - 7y = - x - 21[/tex]

[tex]y = \frac{1}{7} x + 3[/tex]

The rocket will be 30 feet from the ground approximately 0.4 seconds or 9.6 seconds after it is launched.

To solve this problem, we need to find the value of t for which the height of the rocket is 30 feet. We can use the given equation to set up an equation for this as follows:

-16t² + 160t + 90 = 30

Simplifying and rearranging, we get:

-16t² + 160t + 60 = 0

Dividing by -4, we get:

4t² - 40t - 15 = 0

Using the quadratic formula, we get:

t = [40 ± √(40² - 4(4)(-15))] / (2×4)

t = [40 ± √(1840)] / 8

t = [40 ± 2×√(460)] / 8

t = 5 ± (1/2)×√(460)

Therefore, the rocket will be 30 feet from the ground at t = 5 - (1/2)×√(460) seconds or t = 5 + (1/2)×√(460) seconds. These are the two possible solutions to the equation. We can simplify them as follows:

t = 0.4 seconds or t = 9.6 seconds

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The value of angle x in the given figure is 79°.

The highest and lοwest walls οf a skew are used tο split the curved lines that make up its ends using Cartesian measurements. A cοllisiοn between twο pοles at an intersectiοn is a pοtential. Angle is anοther οutcοme οf twο things interacting. They resemble dihedral fοrms the mοst clοsely. A twο-dimensiοnal curve can be created by placing twο line beams in variοus cοnfiguratiοns between their ends.

In ΔBFG, ∠FBG = 46°

So according to angle sum property

46° + ∠BFG + BGF = 180°

Here ΔBFG is an isosceles triangle

46° + 2∠BFG = 180°

2∠BFG = 180° - 46°

2∠BFG  = 134

∠BFG = 134/2

∠BFG = 67° = ∠BGF

Using Vertically opposite angle

∠AFJ =  67°

With that in mind ∠BFA = ∠JFG

2∠JFG + 2∠AFJ = 360°

2∠JFG  = 360° - 2∠AFJ

2∠JFG  = 360° - 2(67)

2∠JFG  = 360° - 134

2∠JFG  = 226

∠JFG  = 226/2

∠JFG = 113°

In ΔFDC, ∠JFG  + ∠JDI + ∠HCG = 180°

113° + 33° + ∠HCG = 180°

∠HCG = 180° - (113° + 33°)

∠HCG = 34°

Also, ∠HGC = ∠BGF = 67°

Now, In ΔCGH, ∠HGC + ∠HCG + x = 180°

67° + 34° + x = 180°

x = 180° - (67° + 34°)

x = 79°

Thus, the value of angle x in the given figure is 79°.

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Plates that slip and slide past each other form a transform boundary.

At a divergent boundary, two tectonic plates move away from each other. In the case of a mid-ocean ridge, the boundary occurs between two oceanic plates. As the plates move apart, magma from the mantle beneath rises up to fill the gap created by the separation. This magma cools and solidifies, adding new material to the ocean floor and creating a continuous chain of underwater mountains, known as a mid-ocean ridge.

Mountains often form at convergent boundaries because the plates are pushed together, causing the crust to fold and buckle, leading to the formation of mountain ranges.

Evidence that would help determine the type of plate boundary that exists between tectonic plates on Earth includes the topography of the surrounding areas, the presence of volcanoes and earthquakes, and the direction and speed of plate motion.

When the mantle rock is heated, the particles begin to move faster and spread apart, so its density decreases. This change in density causes the hot mantle rock to rise. As the mantle rock moves farther away from the core towards the crust, it begins to cool. The density of the mantle rock will increase because it is cooler. This causes the mantle rock to sink. The mantle rock moves back towards the core and the cycle restarts.

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Image transcribed:

Plates that slip slide past each other form a __________ boundary.

10. Explain why a mid-ocean ridge can form at a divergent boundary.

11. Why do mountains often form at convergent boundaries?

12. What evidence would help you determine the type of plate boundary that exists between tectonic plates on Earth?

13. Use these words to complete the paragraph: decreases, rise, density, crust, cool, sink, increase.

When the mantle rock is heated, the particles begin to move faster and spread apart, so its density ________. This change in density causes the hot mantle rock to ________. As the mantle rock moves farther away from the core towards the _______, it begins to _________. The _______ of the mantle rock will _________ because it is cooler. This causes the mantle rock to ______. The mantle rock moves back towards the core and the cycle restarts.

14. Complete the grid.

Boundary Type | Describe the Plate Motion | What Happens on the Surface of Earth He-

Transform |  _____________________  |  ______________________

Divergent |  _____________________  |  ______________________

In circle S with m∠RST= 56 and RS = 19 units, the length of arc RT ≈ 8.87 units (rounded to two decimal places).

An arc of a circle is a portion of the circumference of the circle. It is defined by two endpoints and the collection of all points on the circle's circumference that lie between these endpoints. The length of an arc is proportional to the measure of its corresponding central angle. The formula to find the length of an arc of a circle is L = (m/360) x 2πr, where L is the length of the arc, m is the measure of the central angle, and r is the radius of the circle. The symbol for an arc is a segment of the circle with a curved line over it.

We know that in a circle with radius r, the measure of the arc of a central angle with measure θ degrees is (θ/360) × 2πr units.

In circle S with center S, we are given that RS = ST = r (say) and m∠RST = 56 degrees. So, the measure of minor arc RT is also 56 degrees.

Therefore, the length of arc RT = (56/360) × 2πr = (7/45) × 2πr.

We are also given that RS = 19 units. Since RS = ST = r, we have r = 19 units.

Substituting this value of r, we get:

Length of arc RT = (7/45) × 2πr = (7/45) × 2π(19) ≈ 8.87 units (rounded to two decimal places).

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Answer:

RT= 18.57

Step-by-step explanation:

TRUST THE PROCESS

Answer:

Sure, here are the numbers arranged from greatest to least

Step-by-step explanation:

Order from greatest to least

1.3, 4.5%, 1/3, -4/5, -0.04, -21.5%

Answer:

From the greatest to least

Step-by-step explanation:

1.3, 4.5%, 1/3, -4/5, -0.04, -21.5%

You can identify which number is greater than other by using a number line.

What is a number line?

A number line is what a math student can use to find the answer to addition and subtraction questions. A straight line, theoretically extending to infinity in both positive and negative directions from zero, that shows the relative order of the real numbers.

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The mean of the sampling distribution of means will be equal to the mean of the population from which the samples were drawn when the sampling distribution is unbiased.

The unbiased sampling distribution of means is one in which the sample means are drawn such that their average equals the population mean. Therefore, an unbiased sample should be representative of the population mean.The sampling distribution is a statistical term that refers to the probability distribution of a given random sample of size n that is taken from the population's larger dataset.

The distribution of the statistics collected from different samples is known as the sampling distribution. The mean of the sampling distribution is equal to the population mean. Sampling distribution provides insight into the sample data's variation, which can be used to make population inferences.

The mean of the sampling distribution of means is also known as the expected value of the sampling distribution. It is the mean of the population, which is equal to the mean of the sampling distribution of means. If the sample means are unbiased, the mean of the sampling distribution of means equals the population mean. The central limit theorem states that, as the sample size increases, the sampling distribution of means approaches a normal distribution with a mean equal to the population mean.

The mean of the sampling distribution is a critical statistic in inferential statistics because it aids in determining the statistical significance of the sample. If the sample mean is significantly different from the population mean, the results of the test can be used to reject or accept the null hypothesis.

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The 90% confidence interval for the population standard deviation of the thicknesses of all linoleum tiles in this factory (3.27, 7.78)

To construct the 90% confidence interval for the population standard deviation of the thicknesses of all linoleum tiles in the factory, we need to use the chi-square distribution since the population standard deviation is unknown.

1. Identify the sample size (n) and sample standard deviation (s):
n = 13 (13 randomly selected linoleum tiles)
s = 4.76 (standard deviation of the thicknesses)

2. Determine the degrees of freedom (df):
df = n - 1 = 13 - 1 = 12

3. Find the chi-square values for the 90% confidence interval using a chi-square table or calculator:
The lower tail value (with 5% in the lower tail) is χ² = 4.404
The upper tail value (with 5% in the upper tail) is χ² = 21.026

4. Calculate the confidence interval for the population standard deviation:
Lower limit = √[(n - 1) * s² / χ²_upper] = √[(12 * (4.76)²) / 21.026] ≈ 3.27
Upper limit = √[(n - 1) * s² / χ²_lower] = √[(12 * (4.76)²) / 4.404] ≈ 7.78

The 90% confidence interval for the population standard deviation is approximately (3.27, 7.78).

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ans- <CDF+<FDE=90(Being right angle)

or, 2x+x+9=90

or, 3x+9=90

or, 3x=90-9

or, 3x=81

or, x=81/3

:.x=27,,

a)  The radius of the circle is r = 18 cm, b)  angle AOC is a right angle, which is π/2 radians, c)  the area of the shaded region is 125.66 cm², d)  the perimeter of the shaded region is  57.85 cm.

A circle is a two-dimensional geometric shape that is defined as the set of all points in a plane that are at a constant distance from a given point in the plane, called the center of the circle. The distance between the center of the circle and any point on the circle is called the radius of the circle. Alternatively, the diameter of a circle is the distance across the circle passing through the center, and it is twice the length of the radius.

A circle has several important properties, including:

Circumference: The circumference of a circle is the distance around its outer edge. It is calculated using the formula C = 2πr, where π (pi) is a mathematical constant approximately equal to 3.14 and r is the radius of the circle.

Area: The area of a circle is the amount of space inside its boundary. It is calculated using the formula A = πr², where π (pi) is the mathematical constant approximately equal to 3.14 and r is the radius of the circle.

a) To find the radius r, we can use the Pythagorean theorem to solve for the length of segment OP, which is the height of the rectangle:

OP² + AP² = OA²

OP² + 6² = r²

OP² = r² - 6²

We can also use the fact that AC is a diameter of the circle to find the length of segment OC:

AC = 2r

36 = 2r

r = 18

Substituting this value into the equation for OP² gives:

OP² = 18² - 6²

OP² = 300

OP = 10√3

Therefore, the radius of the circle is r = 18 cm.

b) Angle AOC is a central angle of the circle that intercepts segment AC. Since AC is a diameter, angle AOC is a right angle, which is π/2 radians.

c) The shaded region is the difference between the area of segment ABC and the area of triangle AOC. The area of segment ABC is equal to the area of sector AOC minus the area of triangle AOC. The area of sector AOC is:

(1/2) r² angle AOC

Substituting r = 18 cm and angle AOC = π/2 radians gives:

(1/2) (18)² (π/2) = 81π

The area of triangle AOC is:

(1/2) OA OC sin AOC

Substituting OA = OC = r = 18 cm and AOC = π/2 radians gives:

(1/2) (18)(18) sin(π/2) = 162

Therefore, the area of the shaded region is:

81π - 162 ≈ 125.66 cm²

d) The perimeter of the shaded region is the sum of the lengths of segments AB, BC, and the arc of the circle between A and C. To find the length of the arc, we can use the formula for the length of an arc of a circle:

length of arc = radius x central angle

Substituting r = 18 cm and angle AOC = π/2 radians gives:

length of arc = 18 x (π/2) = 9π

Therefore, the perimeter of the shaded region is:

AB + BC + length of arc = 36 + 2(6) + 9π ≈ 57.85 cm.

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Roll a 5: There is only one way to roll a 5 out of six possible outcomes, so the probability of rolling a 5 is 1/6.

Roll a 6: Similarly, there is only one way to roll a 6 out of six possible outcomes, so the probability of rolling a 6 is 1/6.

Roll a c or 4: There are two ways to roll a 4 (rolling a 4 or rolling a 3) and one way to roll a 3, so there are three ways to roll a 4 or c out of six possible outcomes. Therefore, the probability of rolling a 4 or c is 3/6, simplifying it to 1/2.

Roll an odd number: There are three odd numbers (1, 3, 5) out of six possible outcomes, so the probability of rolling an odd number is 3/6, simplifying to 1/2.

Roll an even number: There are three even numbers (2, 4, 6) out of six possible outcomes, so the probability of rolling an exact number is 3/6 or 1/2.

Roll a number greater than 3: There are three numbers greater than 3 (4, 5, 6) out of six possible outcomes, so the probability of rolling a number greater than 3 is 3/6, which simplifies to 1/2.

Roll an even number less than 5: There is only one number less than 5 (2) out of six possible outcomes, so the probability of rolling an actual number less than 5 is 1/6.

Roll a multiple of 2 (2, 4, 6): There are three multiples of 2 out of six possible outcomes, so the probability of rolling a multiple of 2 is 3/6, simplifying to 1/2.

Roll a factor of 6 (1, 2, 3, 6): There are four factors of 6 out of six possible outcomes, so the probability of rolling a factor of 6 is 4/6, which simplifies to 2/3.

So the probabilities for each event expressed as fractions are:

Roll a 5: 1/6

Roll a 6: 1/6

Roll a 4 or c: 1/2

Roll an odd number: 1/2

Roll an even number: 1/2

Roll a number greater than 3: 1/2

Roll an even number less than 5: 1/6

Roll a multiple of 2: 1/2

Roll a factor of 6: 2/3

Thus, the distance of ladder from the building is found to be 11.53 ft.

Exactly single right angle measure 90 degrees characterises a right triangle.

The hypotenuse of the a right triangle's square is equal to the sum of its other two sides, according to the Pythagorean Theorem. It is written as a²+b²=c² in equation form.

Pythagoras is in the form of;

a²+b²=c²

Let the distance of ladder from the building be 'x'.

Height of ladder from ground h = 6 ft.

Length of ladder l = 13 ft.

Here, using the Pythagorean theorem;

x² + 6² = 13²

x²  = 13² -  6²

x²  = 169 - 36

x²  = 133

x = √133

x = 11.53

Thus,  the distance of ladder from the building is found to be 11.53 ft.

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The first inequality -4 ≤ x ≤ 3 represents the values of x that fall between the two vertical lines, while the second inequality 1 ≤ y ≤ 6 represents the values of y that fall between the two horizontal lines.

An inequality is a mathematical statement that compares two quantities or expressions using inequality symbols such as "<" (less than), ">" (greater than), "<=" (less than or equal to), ">=" (greater than or equal to), or "!=" (not equal to).

Inequalities can involve variables or constants, and can be expressed in one variable or multiple variables. The solution to an inequality is the set of values that satisfy the inequality.

For example, the inequality 2x + 3 > 7 is true for values of x that are greater than 2, since if we substitute x = 2, we get 2(2) + 3 = 7, which is not greater than 7. On the other hand, if we substitute x = 3, we get 2(3) + 3 = 9, which is greater than 7, so the inequality is true for x > 2.

Inequalities have many applications in mathematics and other fields, such as economics, physics, and engineering. They are used to represent constraints in optimization problems, to model relationships between variables, and to describe ranges of possible values for a quantity or variable.

To determine the double inequalities that define the shaded region, we need to find the equations of the two boundary lines that form the sides of the shaded region.

The two vertical lines are x=-4 and x=3. The two horizontal lines are y=1 and y=6.

The shaded region is enclosed by these four lines, so the double inequalities that define it are:

-4 ≤ x ≤ 3 and 1 ≤ y ≤ 6

The first inequality -4 ≤ x ≤ 3 represents the values of x that fall between the two vertical lines, while the second inequality 1 ≤ y ≤ 6 represents the values of y that fall between the two horizontal lines. Together, they define the rectangular shaded region with vertices (-4,1), (-4,6), (3,6), and (3,1).

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The probability using the demand distribution of a stockout is given as 0.6293.

Out-of-stock situations, commonly referred to as stockouts, occur when a company runs out of a product that a client is prepared to purchase. Stockouts have a direct influence on customer satisfaction and are a major reason for bad reviews, additional expenses, and lost revenue or, worse, customers.

Let X = no of demand for the toy

μ =20,000

P(10000 < X < 30000) = 0.90

X follows  normal distribution

z=x−μ​/σ

P(10000 < X < 30000)=0.90

P((10000−20000​)/σ) < (x−20000​)/σ < (30000−20000​)/σ )=0.90

as probability is 0.90, the z-score =1.645.

(30000−20000)​/σ =1.645

10000​/σ=1.645

σ=10000​/1.645

σ=6079

1.P(X>15,000)

=P(Z> (15000−20000​)/6079)

=P(Z> −0.82)

=P(Z< 0.82)

=0.5+0.1293

=0.6293

2. P(X> 24000)

=P(Z> (24000−20000​)/6079)

=P(Z> 0.66)

=0.5−0.2454

=0.2546

3.Expected profit = (profit per unit )*(no of sold units) + (loss per unit )*(of units unsold)

profit = $8

loss = -$11

a. profit if 15000 units are sold =(8)(15000) + (-11)(0) = $120,000

b. if there is demand for 15,000 units but orders only 18000 units profit is (8)(15000) + (-11)(3000) = $87,000

c. if there is demand for 18,000 units but orders only 24000 units profit is (8)(18000)+(-11)(6000)= $78,000.

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Complete question:

(a) What is the expected profit if all 15,000 units are sold? type your answer...

(b) Suppose there is demand for 15,000 units, but Specialty Toys orders 18,000 units? What is the expected profit? type your answer...

(c) Suppose there is demand for 18,000 units, but Specialty Toys orders 24,000 units? What is the expected profit? type your answer... 15 3 points Based on what you know about the distribution of demand, the probability of stock-outs, and the expected profit, how many units of Weather Teddy do you recommend that Specialty Toys purchase?

The dimensions of the box that will maximize the enclosed volume are l = √(45/2) m and h = (22.5 - l²)/2 m.

To determine the dimensions of the box that will maximize the enclosed volume if we have 45 m² of material to build a box with a square base and no top, we can use the following steps:

Step 1: Write the formula for the volume of the box.V = l²h

Step 2: Write the formula for the surface area of the box.S = 2l² + 4lh

Step 3: Substitute S = 45 m² and simplify.2l² + 4lh = 45 m²l² + 2lh = 22.5 m²h = (22.5 - l²)/2

Step 4: Substitute the value of h in the formula for the volume and simplify.V = l²[(22.5 - l²)/2]V = (22.5l² - l⁴)/2

Step 5: Take the derivative of V with respect to l.dV/dl = 45l - 2l³

Step 6: Set dV/dl = 0 and solve for l.45l - 2l³ = 0l(2l² - 45) = 0l = 0 or l = √(45/2)

Step 7: Determine if the critical point is a maximum or a minimum by taking the second derivative of V with respect to l.d²V/dl² = 45 - 6l²d²V/dl² > 0 for l = √(45/2)

Therefore, the dimensions of the box that will maximize the enclosed volume are l = √(45/2) m and h = (22.5 - l²)/2 m.

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The circumference of Circle C is found as 53π.

In the given figure:

AD = 28 and DB = 45

∠ADB = 1/2 *∠ACB

∠ADB = 90

Applying Pythagorean theorem in ΔABD.

AB² = AD² + DB²

AB² = 28² + 45²

AB = √2809

AB = 53

Radius = 53/2

circumference of Circle C:

C = 2πr

C = 2*π* (53/2)

C =  53π

Thus, the circumference of Circle C is found as 53π.

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The probability that the waves are turbulent given that the water is cold is approximately 0.112 (rounded to the nearest millionth).

Given that the water is cold, the probability that the waves are turbulent needs to be found. Let's apply the Bayes' Theorem to find the probability of the waves being turbulent given that the water is cold.

The formula for Bayes' Theorem is as follows:

P(B|A)={P(A|B)\ P(B)} * {P(A)}

Where, P(B|A) is the probability of event B given that event A has occurred, P(A|B) is the probability of event A given that event B has occurred, P(A) is the probability of event A, and P(B) is the probability of event B. The question requires us to find the probability of the waves being turbulent given that the water is cold. So, the conditional probability we need to find is P(T|C), where T represents the event of waves being turbulent and C represents the event of the water being cold. The given probabilities are:

P(T)=0.36

P(T^C)=0.64

P(C|T)=0.21

P(C|T^C)=0.51

By the complement rule, P(C)=1-P(C^C)

P(C)=1-0.15=0.85

Let's substitute the given probabilities into the Bayes' Theorem formula and solve for

P(T|C) :

(T|C)={P(C|T)\ P(T)} * {P(C|T)\P(T)+P(C|T^C)\ P(T^C)}={0.21\ 0.36} * {0.21\0.36+0.51\ 0.64} = 0.112

Therefore, the probability that the waves are turbulent given that the water is cold is approximately 0.112 (rounded to the nearest millionth).

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The required equation models the future cost of gasoline with price increment of 0.3% per month is given by x = 1.19(1.003)^t .

Let us consider 'x' represents the cost of gasoline.

And 't' represents the number of months since January 1, 1999.

The price of gasoline increased by 0.3% per month.

This implies,

Increased by = 0.003 times the original cost each month.

The cost of gasoline after 't' months can be modeled by,

x = 1.19(1 + 0.003)^t

Simplifying the above equation we get,

x = 1.19(1.003)^t

Therefore, the equation x = 1.19(1.003)^t models the future cost of gasoline, assuming the price of gasoline continues to increase at a rate of 0.3% per month from January 1, 1999.

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There are 2(24!) - 23! arrangements of the 26-letter alphabet that contain "the" or "of."

To find the number of arrangements of the 26-letter alphabet that contain "the" or "of," we can use the principle of inclusion-exclusion.

First, we find the total number of arrangements of the 26-letter alphabet, which is 26! (26 factorial).

Next, we find the number of arrangements that contain "the." To do this, we treat "the" as a single letter and arrange the remaining 24 letters along with it. Since there are 24 letters to arrange, the number of arrangements that contain "the" is 24! (24 factorial).

Similarly, we find the number of arrangements that contain "of" by treating it as a single letter and arranging the remaining 24 letters along with it. The number of arrangements that contain "of" is also 24!.

However, if we simply add the number of arrangements that contain "the" and "of," we will be double-counting the arrangements that contain both "the" and "of." To correct for this, we subtract the number of arrangements that contain both "the" and "of."

To find the number of arrangements that contain both "the" and "of," we treat "the of" as a single letter and arrange the remaining 23 letters along with it. Since there are 23 letters to arrange, the number of arrangements that contain both "the" and "of" is 23! (23 factorial).

Using the principle of inclusion-exclusion, the total number of arrangements that contain "the" or "of" is:

24! + 24! - 23! = 2(24!) - 23!

Therefore, there are 2(24!) - 23! arrangements of the 26-letter alphabet that contain "the" or "of."

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