A package is dropped from an air balloon two times. In the first trial the distance between the balloon and the surface is Hand in the second trial 4H. Compare the FINAL VELOCITY'S for the packages right as they hit the
ground (or right before)?

Answer:

The magnitude of the hiker’s displacement is 2.96 km

Explanation:

Let the initial displacement of the hiker, = x = 2km

the final displacement of the hiker, = y = 1.4 km

The resultant of the two vectors, According to Pythagorean theorem is the vector sum of the two vectors.

R' = x' + y'

Check the image uploaded for solution;

Answer:

Explanation:

Newtons third law says an applied force will produce an equal but opposite force.

[tex]F_A_B =-F_B_A[/tex]

Answer: 490m

Explanation: 1/2 * 9.8m/s/s * 10s

Answer:

a) [tex]\beta = 1.111\times 10^{-7}[/tex], b) [tex]\beta = 9\times 10^{-7}[/tex], c) [tex]\beta = 3.087\times 10^{-6}[/tex], d) [tex]\beta = 2.5\times 10^{-5}[/tex], e) [tex]\beta = 0.5[/tex], f) [tex]\beta = 0.877[/tex]

Explanation:

From relativist physics we know that [tex]c[/tex] is the symbol for the speed of light, which equal to approximately 300000 kilometers per second. (300000000 meters per second).

a) A car traveling 120 kilometers per hour:

At first we convert the car speed into meters per second:

[tex]v = \left(120\,\frac{km}{h} \right)\times \left(1000\,\frac{m}{km} \right)\times \left(\frac{1}{3600}\,\frac{h}{s} \right)[/tex]

[tex]v = 33.333\,\frac{m}{s}[/tex]

The ratio [tex]\beta[/tex] is now calculated: ([tex]v = 33.333\,\frac{m}{s}[/tex], [tex]c = 3\times 10^{8}\,\frac{m}{s}[/tex])

[tex]\beta = \frac{33.333\,\frac{m}{s} }{3\times 10^{8}\,\frac{m}{s} }[/tex]

[tex]\beta = 1.111\times 10^{-7}[/tex]

b) A commercial jet airliner traveling 270 meters per second:

The ratio [tex]\beta[/tex] is now calculated: ([tex]v = 270\,\frac{m}{s}[/tex], [tex]c = 3\times 10^{8}\,\frac{m}{s}[/tex])

[tex]\beta = \frac{270\,\frac{m}{s} }{3\times 10^{8}\,\frac{m}{s} }[/tex]

[tex]\beta = 9\times 10^{-7}[/tex]

c) A supersonic airplane traveling Mach 2.7:

At first we get the speed of the supersonic airplane from Mach's formula:

[tex]v = Ma\cdot v_{s}[/tex]

Where:

[tex]Ma[/tex] - Mach number, dimensionless.

[tex]v_{s}[/tex] - Speed of sound in air, measured in meters per second.

If we know that [tex]Ma = 2.7[/tex] and [tex]v_{s} = 343\,\frac{m}{s}[/tex], then the speed of the supersonic airplane is:

[tex]v = 2.7\cdot \left(343\,\frac{m}{s} \right)[/tex]

[tex]v = 926.1\,\frac{m}{s}[/tex]

The ratio [tex]\beta[/tex] is now calculated: ([tex]v = 926.1\,\frac{m}{s}[/tex], [tex]c = 3\times 10^{8}\,\frac{m}{s}[/tex])

[tex]\beta = \frac{926.1\,\frac{m}{s} }{3\times 10^{8}\,\frac{m}{s} }[/tex]

[tex]\beta = 3.087\times 10^{-6}[/tex]

d) The space shuttle, travelling 27000 kilometers per hour:

At first we convert the space shuttle speed into meters per second:

[tex]v = \left(27000\,\frac{km}{h} \right)\times \left(1000\,\frac{m}{km} \right)\times \left(\frac{1}{3600}\,\frac{h}{s} \right)[/tex]

[tex]v = 7500\,\frac{m}{s}[/tex]

The ratio [tex]\beta[/tex] is now calculated: ([tex]v = 7500\,\frac{m}{s}[/tex], [tex]c = 3\times 10^{8}\,\frac{m}{s}[/tex])

[tex]\beta = \frac{7500\,\frac{m}{s} }{3\times 10^{8}\,\frac{m}{s} }[/tex]

[tex]\beta = 2.5\times 10^{-5}[/tex]

e) An electron traveling 30 centimeters in 2 nanoseconds:

If we assume that electron travels at constant velocity, then speed is obtained as follows:

[tex]v = \frac{d}{t}[/tex]

Where:

[tex]v[/tex] - Speed, measured in meters per second.

[tex]d[/tex] - Travelled distance, measured in meters.

[tex]t[/tex] - Time, measured in seconds.

If we know that [tex]d = 0.3\,m[/tex] and [tex]t = 2\times 10^{-9}\,s[/tex], then speed of the electron is:

[tex]v = \frac{0.3\,m}{2\times 10^{-9}\,s}[/tex]

[tex]v = 1.50\times 10^{8}\,\frac{m}{s}[/tex]

The ratio [tex]\beta[/tex] is now calculated: ([tex]v = 1.5\times 10^{8}\,\frac{m}{s}[/tex], [tex]c = 3\times 10^{8}\,\frac{m}{s}[/tex])

[tex]\beta = \frac{1.5\times 10^{8}\,\frac{m}{s} }{3\times 10^{8}\,\frac{m}{s} }[/tex]

[tex]\beta = 0.5[/tex]

f) A proton traveling across a nucleus (10⁻¹⁴ meters) in 0.38 × 10⁻²² seconds:

If we assume that proton travels at constant velocity, then speed is obtained as follows:

[tex]v = \frac{d}{t}[/tex]

Where:

[tex]v[/tex] - Speed, measured in meters per second.

[tex]d[/tex] - Travelled distance, measured in meters.

[tex]t[/tex] - Time, measured in seconds.

If we know that [tex]d = 10^{-14}\,m[/tex] and [tex]t = 0.38\times 10^{-22}\,s[/tex], then speed of the electron is:

[tex]v = \frac{10^{-14}\,m}{0.38\times 10^{-22}\,s}[/tex]

[tex]v = 2.632\times 10^{8}\,\frac{m}{s}[/tex]

The ratio [tex]\beta[/tex] is now calculated: ([tex]v = 2.632\times 10^{8}\,\frac{m}{s}[/tex], [tex]c = 3\times 10^{8}\,\frac{m}{s}[/tex])

[tex]\beta = \frac{2.632\times 10^{8}\,\frac{m}{s} }{3\times 10^{8}\,\frac{m}{s} }[/tex]

[tex]\beta = 0.877[/tex]

Answer: poor construction of houses

Explanation:

Majority of the people that died in Iran were as a result of poor building methods coupled with the fact that there was lack of proper regulation.

California experienced a similar earthquake but due to safer construction methods, about three people died.

Due to population boom in Iran and house shortage, this resulted in builders building cheap houses which were not strong enough.

Answer:

ok can u m a e the question make more sense like break ot down cs i wanna give u a answer but i dont really understand the question

Answer:

24.69 meters

Explanation:

sorry if it's not right.

answer:

[tex]h=24.69m[/tex]

step-by-step explanation:

[tex]eg=mgh \\ek=\frac{1}{2} mv^2[/tex]

eg= gravitational energy

ek= kinetic energy

now, since no mass is given of the ball, both equations on their own do nothing for us, except leave us scratching our heads wondering how to figure out the problem. but, since the question states, “and no air resistance,” we now know, according to the law of conservation of energy, that the energy of the two equations will equal each other because none of the energy has dissipated or left the system.

the amount of energy present during the initial phase of the woman about to throw the ball will be present in the final phase, which will be at its highest point (according to this problem).

so now [tex]eg=ek[/tex]

knowing this, we can now set the equations equal

[tex]eg=ek\\mgh=\frac{1}{2} mv^2[/tex]

the two m’s cancel out, making the mass of the ball insignificant and not influential; next, substitute the values we are given in the problem

[tex](22m/s),(9.8m/s^2)\\m(9.8m/s^2)h=\frac{1}{2} m(22m/s)^2\\(9.8 m/s^2)h=\frac{1}{2} (22m/s)^2\\(9.8m/s^2)h=1/2 (484m^2/s^2)\\(9.8m/s^2)h=1/2 (242m^2/s^2)\\\\h= (242m^2/s^2)/(9.8m/s^2)[/tex]

as you can see, all units that need to be canceled out are indeed canceled, leaving us with just m, meters, which is what height is measured in

therefore, [tex]h=24.69m[/tex]

Answer:

In the event of a disease caused by an unknown pathogen, it is hard to know which reagent to pick. ... EM, though it may not be able to identify a virus beyond the family level, at least ... Negative staining of stool specimens from these cattle demonstrated a ... This results in a fuzzy halo around the particles in negative stains.Explanation:

Answer: the proper diameter is 6.137 ft

Explanation:

first we find the volume of box using the relation, which is;

V = 2 x 5 x 1.5 = 15 ft³

we  find the buoyant force on the box by calculating the weight of water displaced.

FB = V x y

where  y is the specific weight of sea water(62.4 lbf/ft³)

so we Substitute

FB = 15 x 62.4 = 936 lbf  

now we find the upward force required by the balloon

FR = (W - FB) x 120%

= 1.2 (W - FB)

where W is the weight of the box treasure(7000 lb)

so we  Substitute,

FB = 1.2( 7000 - 936 ) = 7276.8 lbf

Because the universal gas constant contains a Rankine in its units, we make use of Rankine for our temperature

so we find the density of air at 3 atm using ideal gas relation,

Pair = p/RT

Here, p is the pressure acting (3 atm), R is the universal gas constant (1716 ft²/S²-R), and T is the temperature (520°R),

Substitute so we substitute

Pair = (3 * 2116.22) / (1516 * 520)

= 0.007114  lbf.ft³

next we find the specific weight of air;

Yair = Pair * g

g is acceleration due to gravity(32.2 ft/s²)

Yair =  

0.007114 * 32.2

= 0.23 Ibf /ft³

Now we find diameter of the balloon by balancing the net force required

FR = (y - yair) * V - Wb

= (y - yair) x (π/6)d³ - Wb  

d is the diameter of the balloon.

so we Substitute, 7276.8 lbf for FR,

62.4 Ibf/ft³ for  y, 0.23 for lbf/ft³ for Yair, 350 lb for Wb

so

7276.8 = (62.4 - 0.23)πd³  - 250

d³ = 231.23 ft³

d = 6.137 ft   

Therefore, the proper diameter is 6.137 ft

Answer:

152,000 N

Explanation:

(a) Initial potential energy = final kinetic energy

mgh = ½ mv²

v = √(2gh)

v = √(2 × 10 m/s² × 3.00 m)

v = 7.75 m/s

(b) Work done on pile hammer = change in energy

FΔy = 0 − (mgh + ½ mv²)

F (-0.074 m) = -((365 kg) (10 m/s²) (0.074 m) + ½ (365 kg) (7.75 m/s)²)

F (-0.074 m) = -11220.1 J

F ≈ 152,000 N

Answer:

The change in potential energy of the mass as it goes up the incline is 0.343 joules.

Explanation:

We must remember in this case that change in the potential energy is entirely represented by the change in the gravitational potential energy. From Work-Energy Theorem and definition of work we get that:

[tex]U_{g}= m\cdot g\cdot \Delta y[/tex]

Where:

[tex]U_{g}[/tex] - Gravitational potential energy, measured in Joules.

[tex]m[/tex] - Mass, measured in kilograms.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]\Delta y[/tex] - Change in vertical height, measured in meters.

This work is the energy needed to counteract effects of gravity at given vertical displacement.

If we know that [tex]m = 0.5\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]\Delta y = 0.07\,m[/tex], the change in the potential energy of the mass as it goes up the incline is:

[tex]U_{g} = (0.5\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.07\,m)[/tex]

[tex]U_{g} = 0.343\,J[/tex]

The change in potential energy of the mass as it goes up the incline is 0.343 joules.

The change in the potential energy (in Joules) of the mass as it goes up the incline is 0.343 J.

We know that

Potential energy = m*g*h

Here m means the mass = 0.5 kg

g means the gravity = 9.8

And, the h means the height  = 7cm = 0.07m

So, the change in the potential energy should be

=0.5*9.8*0.07

=0.343 J

hence, we can conclude that the  change in the potential energy (in Joules) of the mass as it goes up the incline is 0.343 J.

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Answer:

(assume moving in the positive direction, vi = + 20 m/s)

Explanation:

Answer:

5 billion years ago...ends 4.9 billion years later

Answer:

That's correct... you can mark them brainliest now. You have to have both slots answered before you can mark them. So, you're welcome :)

Explanation:

Answer:

Option B 150 Metre

Answer:

B. 150 m

Explanation:

In order to answer the question, it is important to know the formula for "velocity."

velocity = [tex]\frac{distance}{time}[/tex]

What is being asked? The distance covered if the time taken is 10 sec.

So this means: velocity x  time = distance

Step 1: Convert 10 sec. to hour.

10 sec. x [tex]\frac{1 hour}{3,600 sec.}[/tex] = 0.00278 hr.

Step 2: Plug in the values to the formula.

distance = 54 [tex]\frac{km}{hr}[/tex] x 0.00278 hr.

distance = 0.150 km

Step 3: The choices are in meters (m), so let's convert 0.150 km to meter.

0.150 km x [tex]\frac{1,000 m}{1 km}[/tex] = 150 meters

The answer is: 150 m

Answer:

maybe the answer is in is D part

Answer:

Please mark me brainliest and thank me and rate me

Answer:

obviously 2 hours cuz 850/425

Explanation:

Answer:

Height = 1.54 m

Explanation:

Given:

Velocity = 41 m/s

Distance = 23 m

Find:

Height

Computation:

We know that

a = 9.8 m/s²

Time = Distance / Velocity

Time = 23 / 41

Time = 0.56 second

Height = (1/2)(9.8)(0.56)²

Height = 1.54 m

Answer:

the material

Explanation:

weight is defined as the amount of force on the object because of gravity. ping pong balls and bouncy balls are made out of different materials that are different weights. most bouncy balls are also not hollow, unlike ping pong balls. these factors affect the weight of these objects.

Answer:

energy

Explanation:

Energy can't be destroyed or created, just transferred.

Answer:

1.84m

Explanation:

Given parameters:

Initial velocity  = 6m/s

Unknown:

height of jump  = ?

Solution:

To solve this problem, we have to apply the right motion equation:

        V²  = U²  - 2gH

V is the final velocity

U is the initial velocity

g is the acceleration due to gravity  = 9.8m/s²

H is the height

   Final velocity is 0

  Solve;

           0² = 6² - 2x9.8xH

           -36  = -19.6H

               H = 1.84m

Answer:

C

Explanation:

Answer:

that car got obliterated almost like the day my uncle said come with me

Explanation:

the outcome was not good

Answer:

1- t^3

2- t^2

3- t1

Explanation:

The acceleration produced in a body, while travelling in a circular motion, due to change in direction of motion is called centripetal acceleration. The formula of the centripetal acceleration is as follows:

ac = v²/r

where,

ac = centripetal acceleration

v = speed

r = radius

for a constant radius the centripetal acceleration will be directly proportional to the speed of object. The speed of pendulum will be lowest at t1 due to zero speed initially. Then the speed will increase gradually having greater speed at t^2 and the highest speed and centripetal acceleration at t^3. Therefore, the three instants in tie can be written in following order from greatest centripetal acceleration to lowest:

1- t^3

2- t^2

3- t1

Astroid one has less asked her to. Able to use enough force to not only change or keep it self go in the same direction.

(a) If the initial speed both asteroids before collision is the same, then the asteroid with greater mass will have more momentum before collision while the asteroid with lesser mass will have greater momentum after collision.

(b) The force of the impact depends of the velocity change and time of collision of the asteroids.

According to the principle of conservation of linear momentum, the sum of the momentum of each asteroid  before collision must equal the sum of their momentum after collision.

[tex]m_1 u_1 + m_2 u_2 = m_1v_1 + m_2 v_2[/tex]

where;

If the initial speed both asteroids before collision is the same, then the asteroid with greater mass will have more momentum before collision while the asteroid with lesser mass will have greater momentum after collision to conserve the momentum.

The force of the impact depends of the velocity change and time of collision of the asteroids.

[tex]F = \frac{m\Delta v}{t}[/tex]

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