A new social media site is increasing its user base by approximately 3% per month. If the site currently has 37,030 users, what will the approximate user base be 7 months from now?

The probability of drawing a red marble on the first draw is 3/8 since there are 3 red marbles out of 8 total marbles.

After the first marble is drawn, 7 marbles are remaining, so the probability of drawing a white marble on the second draw is 4/7 since 4 white marbles are remaining out of 7 total marbles.

To find the probability of drawing a red marble followed by a white marble, we multiply the probabilities of each event:

P(red, then white) = (3/8) x (4/7) = 12/56

Simplifying this fraction by dividing both the numerator and denominator by their greatest common factor of 4, we get:

P(red, then white) = 3/14

Therefore, the probability of drawing a red marble followed by a white marble is 3/14.

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Answer:

No.

Step-by-step explanation:

To determine whether eight-digit numbers with no digits 9 in their decimal representations constitute more than half of all eight-digit numbers, we need to calculate the total number of eight-digit numbers and the number of eight-digit numbers with no digit 9.There are 10 possible digits for each position in an eight-digit number, so there are 10^8 (or 100,000,000) total eight-digit numbers.

To count the number of eight-digit numbers with no digit 9, we can note that each digit in the number has 9 possible choices (0, 1, 2, 3, 4, 5, 6, 7, or 8), and since there are eight digits in the number, there are 9^8 (or 43,046,721) eight-digit numbers with no digit 9.Therefore, the proportion of eight-digit numbers with no digit 9 is:

9^8 / 10^8 = 0.43046721

This is less than half, so we can conclude that eight-digit numbers with no digits 9 in their decimal representations do not constitute more than half of all eight-digit numbers.

No, eight-digit numbers with no digit 9 in their decimal representations do not constitute more than half of all eight-digit numbers.

There are a total of 9 digits (0-9) in the decimal system, and an eight-digit number can have any of these digits in each of its eight places.

So, the total number of eight-digit numbers that can be formed is:

9 × 9 × 9 × 9 × 9 × 9 × 9 × 9 = 43,046,721

Out of these, there are 8 × 8 × 8 × 8 × 8 × 8 × 8 × 8 = 16,777,216 numbers that can have digits other than 9 in each of the eight places.

Therefore, the remaining numbers (43,046,721 - 16,777,216 = 26,269,505) will have at least one 9 in their decimal representations.

So, the eight-digit numbers with no digit 9 in their decimal representations constitute:16,777,216 / 43,046,721 = 0.3906 or approximately 39.06%of all eight-digit numbers. Therefore, they do not constitute more than half of all eight-digit numbers.
No, eight-digit numbers with no digit 9 in their decimal representations do not constitute more than half of all eight-digit numbers.

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For the given linear equations, x = 63/4 i.e. None of the above options.

What is a linear equation, exactly?

Each term in a linear equation is either a constant or the product of a constant and a single variable raised to the first power. A linear equation in one variable has the general form: axe + b = 0, where a and b are constants and x is the variable. This equation's answer is a single value of x that solves the problem.

Now,

To use Cramer's Rule to solve this system of linear equations, we need to set up the following matrices:

A = 2/5 1/4

2/3 5/12

B = 9/20

3/4

The determinant of A is given by:

|A| = (2/5)(5/12) - (1/4)(2/3) = 1/30 - 1/18 = -1/90

The determinant of the matrix obtained by replacing the first column of A with B is given by:

|A1| = (9/20)(5/12) - (3/4)(2/3) = 9/80 - 1/4 = -7/40

The determinant of the matrix obtained by replacing the second column of A with B is given by:

|A2| = (2/5)(3/4) - (1/4)(9/20) = 3/10 - 9/80 = 3/40

Now, we can use Cramer's Rule to find the value of x:

x = |A1|/|A| = (-7/40)/(-1/90) = 63/4

Therefore, the value of x

x = 63/4

So the answer is not any of the given options.

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As per the given scenario, a cereal comes in three different package sizes.

The ratio of the cost of an 8-ounce box to a 16-ounce box of cereal can be calculated as follows :Ratio of 8-ounce box to 16-ounce box= 8 : 16Here, the ratio of 8 and 16 can be simplified by dividing both the terms by [tex]8.8 : 16 = 1 : 2[/tex]

Therefore, the ratio of the cost of an 8-ounce box to a 16-ounce box of cereal is 1 : 2.

Note: The answer should be represented in the simplest form possible.

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Answer:

  0 < m < 4-√12 ≈ 0.535898

Step-by-step explanation:

You want to know the range of values of m that will give |(x-1)(x-3)| = mx four distinct solutions.

The quadratic function f(x) = (x -1)(x -3) will be negative for values of x between the zeros: 1 < x < 3. Hence the absolute value function will invert the graph in that interval, as shown by the red curve in the attachment.

The line y = mx can only intersect that graph in 4 places in the first quadrant. The value of m must be greater than 0 and less than 1.

The upper limit of the slope will be defined by the value of m that makes the line intersect the inverted quadratic exactly once. That is, the discriminant of mx -(-f(x)) = 0 will be zero.

  mx +(x -1)(x -3) = x² +(m -4)x +3 = 0

  D = (m -4)² -4(1)(3) = (m -4)² -12 = 0

Solving for m gives ...

  (m -4)² = 12

  m -4 = ±√12

  m = 4 ±√12 ≈ 0.54 or 7.46

We can see from the attached graph that m ≈ 7.46 is an extraneous solution. This means the range of m will be ...

  0 < m < 4-√12

With these steps, you can successfully find the mean, mode, and range of the data represented in the dot plot.

To find the mean, mode, and range of the dot plot, follow these steps:
Step 1: Count the total number of data points (dots) in the dot plot.
Step 2: Add up the values represented by the data points.
Step 3: Divide the sum from Step 2 by the total number of data points from Step 1 to calculate the mean.
Step 4: Identify the mode by finding the value(s) that appears most frequently in the dot plot (i.e., the value with the highest number of dots).
Step 5: Determine the range by finding the difference between the highest and lowest values in the dot plot.

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Answer:

1 2 3 6 9 and 18

Step-by-step explanation:

the 111 factors of 18 is 1 2 3 6 9 ang 18

Answer:

Kate is 3 years old, Jane is 9 years old

Step-by-step explanation:

1.) First, assign variables to all of their ages. If we say Kate's age is x, Jane's age is 3 times this, which can be written as j, is 3x.

2.) Jane's age is also 2 less than twice of Kate's in 5 years. This means that her age is also 2(x+5) - 2 = j + 5. With a little simplification, you get that 2x + 8 = j + 5.

3.) Since j, Jane's age, is also 3x, we can substitute 3x in for j in the second equation. If you do this, you get 2x + 8 = 3x + 5.

4.) By moving the x onto one side and the numbers onto another, you get x = 3. X was Kate's age, meaning that Kate is 3 years old.

5.) Finally, since Jane's age is 3 times Kate's age, Jane's age is 3 * 3, which is 9. Jane is 9 years old.

Jane is 9 years old and Kate is 3 years old.To solve the problem, let's first establish variables for Jane and Kate's ages.

Let J represent Jane's age and K represent Kate's age.
According to the student question, Jane is 3 times as old as Kate, which can be represented as:
J = 3K
In 5 years, Jane's age will be 2 less than twice Kate's age, which can be represented as:
J + 5 = 2(K + 5) - 2
Now we can solve the equations step by step:

Substitute the first equation into the second equation to eliminate one of the variables:
3K + 5 = 2(K + 5) - 2
Distribute the 2 on the right side of the equation:
3K + 5 = 2K + 10 - 2
Simplify the equation by combining like terms:
3K + 5 = 2K + 8
Move the 2K term to the left side of the equation:
K = 3
now we know that Kate is currently 3 years old.
Substitute K's value back into the first equation to find Jane's age:
J = 3K
J = 3(3)
Simplify to find Jane's age:
J = 9
So, Jane is currently 9 years old.
Jane is 9 years old and Kate is 3 years old.

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The cell that contributed most to the final result was Cell (1,2) with a contribution of 8.44.

we need to calculate the expected frequencies for each cell in the contingency table. We can use the formula:

Expected frequency = (row total x column total) / grand total

The grand total for the table is 80, so we can calculate the expected frequencies for each cell as follows:

Expected frequency of Cell (1,1) = (44 x 42) / 80 = 23.1

Expected frequency of Cell (1,2) = (44 x 38) / 80 = 20.9

Expected frequency of Cell (2,1) = (36 x 42) / 80 = 18.9

Expected frequency of Cell (2,2) = (36 x 38) / 80 = 17.1

Next, we need to calculate the contribution of each cell to the chi-square statistic. We can do this by subtracting the expected frequency from the observed frequency, squaring the result, and then dividing by the expected frequency.

The contributions of each cell to the chi-square statistic are as follows:

Contribution of Cell (1,1) = (37 - 23.1)2 / 23.1 = 8.30

Contribution of Cell (1,2) = (7 - 20.9)2 / 20.9 = 8.44

Contribution of Cell (2,1) = (9 - 18.9)2 / 18.9 = 4.52

Contribution of Cell (2,2) = (27 - 17.1)2 / 17.1 = 6.04

Finally, we can sum up the contributions of all the cells to get the chi-square statistic:

Chi-square statistic = 8.30 + 8.44 + 4.52 + 6.04 = 27.30

The cell that contributed most to the final result was Cell (1,2) with a contribution of 8.44. This cell had an observed frequency of 7, which was much lower than the expected frequency of 20.9. This indicates that there is a significant association between the two variables in this cell, and it is driving the overall result of the test.

In conclusion, by breaking down the chi-square statistic into its individual components, we can identify the cells that contribute most to the result and gain a deeper understanding of the relationship between the variables.

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The patient is recieving nearly 35.5 miligrams of the drugs for  per kilogram per 24 hours.

First, we need to convert the child's weight from pounds to kilograms:

99 lbs / 2.205 = 44.9 kg

Next, we calculate the recommended dose for this weight:

40 mg/kg/24h x 44.9 kg = 1796 mg/24h

Since the recommended dose is divided into four equal doses, each dose should be:

1796 mg/24h ÷ 4 doses = 449 mg/dose

However, the physician ordered 400 mg every 6 hours, which is not the same as 449 mg every 6 hours. To calculate the actual dose per kilogram per 24 hours, we need to convert the ordered dose to the recommended dose:

400 mg/dose x 4 doses = 1600 mg/24h

Then, we divide the actual dose by the child's weight in kilograms:

1600 mg/24h ÷ 44.9 kg = 35.6 mg/kg/24h

Therefore, the patient is receiving 35.6 mg/kg/24h, which is slightly lower than the recommended dose of 40 mg/kg/24h.

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The angle of elevation of the ramp to the nearest degree is 34°.

we can use trigonometry to determine the angle of elevation of the ramp.To begin, we need to draw a diagram to visualize the problem.

Let's assume that the height of the end of the ramp is h, and the horizontal distance from the bottom of the ramp to the building is d.

From the diagram, we can see that we have a right-angled triangle where the height of the triangle is h, the base of the triangle is d, and the hypotenuse of the triangle is the length of the ramp.

Using the tangent ratio, we can write:

tanθ = opposite/adjacent

where opposite is the height of the triangle, and adjacent is the base of the triangle. Substituting the values we have, we get:

tanθ = h/d

Rearranging this formula, we can write:

θ = tan⁻¹(h/d)

Substituting the values we have, we get:θ = tan⁻¹(10/15)θ = 33.69°

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The area of the given triangle in the question is 48cm².

Area = (1/2) x base x height

where the base is 8cm and the height is 12cm, as given in the question.

Substituting these values, we get:

Area = (1/2) x 8cm x 12cm

Area = 48cm²

Therefore, the area of the triangle with a base of 8cm, a height of 12cm, and an angle of 59° is 48cm². A triangle is a 2-dimensional geometric shape that consists of three line segments or sides and three angles. The sum of the interior angles of a triangle is always 180 degrees. The area of a triangle is the amount of space inside the triangle and is calculated using the formula A = (1/2) x b x h, where A is the area, b is the base of the triangle, and h is the height of the triangle. The base of a triangle is any one of its sides and the height is the perpendicular distance from the base to the opposite vertex. The area of a triangle can be used to solve various real-world problems, such as calculating the amount of material needed to construct a roof or a sail.

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The vector FC is (14, 0, 3/2, -7, -8, 6).

If you are given two vectors FC and F and C, with F represented as F(-2, 0, 0, 8, 2, 1) and C represented as C(12, 0, 3/2,

1, -6, 7), you can find the vector FC by subtracting the F vector from the C vector component-wise.

Step 1: Write down the F and C vectors.

F = (-2, 0, 0, 8, 2, 1)

C = (12, 0, 3/2, 1, -6, 7)

Step 2: Subtract the F vector from the C vector component-wise.

FC = C - F

FC = (12 - (-2), 0 - 0, 3/2 - 0, 1 - 8, -6 - 2, 7 - 1)

Step 3: Simplify the subtraction.

FC = (14, 0, 3/2, -7, -8, 6)

So, the vector FC is (14, 0, 3/2, -7, -8, 6).

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we have expressed log146 - log14 3 2 as a single logarithm in terms of natural logarithms, which is ln (2/3) / ln 14.

Using the properties of logarithms, we can simplify the given expression as follows:

[tex]log_{14}[/tex](6) = [tex]log_{14}[/tex](4) - [tex]log_{14}[/tex]([tex]3^{2}[/tex])

= 1 - 2[tex]log_{14}[/tex](3)

So the expression log146 − log1432 can be written as [tex]log_{14}[/tex](6) = 1 - 2[tex]log_{14}[/tex](3).

The first step used the property [tex]log_{a}[/tex] (b/c) =  [tex]log_{a}[/tex](b) -  [tex]log_{a}[/tex](c), and the second step used the property  [tex]log_{a}[/tex](b^c) = c [tex]log_{a}[/tex](b).

In simpler terms, we can say that the given expression is equivalent to subtracting the logarithm of [tex]3^{2}[/tex] from the logarithm of 4, both to the base 14. We can then use the rules of logarithms to simplify the expression into a single logarithm of 6 to the base 14, with a coefficient of -2 in front of the logarithm of 3 to the base 14.

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An exponential function y = abx for a graph that passes through (2, 1) and (3, 4) is [tex]y = (1/16)(4)^x[/tex].

To write an exponential function in the form[tex]y = ab^x[/tex] that passes through the points (2, 1) and (3, 4), follow these steps:
Step 1: Write the general form of the exponential function:
[tex]y = ab^x[/tex]
Step 2: Plug in the coordinates of the first point (2, 1):
[tex]1 = ab^2[/tex]
Step 3: Plug in the coordinates of the second point (3, 4):
[tex]4 = ab^3[/tex]
Step 4: Solve for "a" and "b" using the equations from Steps 2 and 3.
We have two equations:
1)[tex]1 = ab^2[/tex]
2) [tex]4 = ab^3[/tex]
Divide equation 2 by equation 1 to eliminate "a":
[tex](4/1) = (ab^3)/(ab^2)[/tex]
4 = b.

Now that we have found "b," we can find "a" by plugging "b" back into either equation 1 or 2.

We'll use equation 1:
[tex]1 = a(4)^21 = a(16)[/tex]
a = 1/16
Step 5: Write the final exponential function using the values of "a" and "b":
[tex]y = (1/16)(4)^x[/tex].

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Answer:

There are 46 numbers in this sequence.

Yes, The function with a frequency of 2 has a greater period than a function with a frequency of 1/2.

What does the word" function" signify in calculation?

As a set of inputs with one for each, a function is defined as a relationship between them. A function, expressed simply, is an association between inputs where each input is connected to one and only one affair. A sphere, codomain, or range exists for every function. generally, f( x), where x is the input, is used to represent a function.

frequency of f(x) = 1/period of f(X)

              2 = 1/[tex]T_{f}[/tex]

             [tex]T_{g}[/tex] = 1/2

 frequency of g(X) = 1/period of g(X)

                   1/2 = 1/[tex]T_{g}[/tex]

                     [tex]T_{f}[/tex] = 2

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Answer:

A

Step-by-step explanation:

r=d/2

=6/2 =3

2πr

2×3.14×3

=18.84

Step-by-step explanation:

This is kinda like the Pythagorean Theorem with THREE dimensions instead of two

diagonal^2 = 3^2 + 4^2  +  2^2

diagonal = sqrt ( 29) = 5.39 ft

The best type of graph to display the results of this survey would be a histogram. A histogram is a graph that uses bars to represent the frequency distribution of a set of data. In this case, the shoe sizes would be grouped into intervals (e.g., 1-3, 4-6, 7-9, etc.) and the height of each bar would represent the number of students who have shoe sizes within that interval. A histogram is an effective way to show the overall pattern of the distribution of shoe sizes in the class.

A circle graph, also known as a pie chart, is useful for showing parts of a whole. It may not be the best choice for this survey since it does not show the distribution of shoe sizes as effectively as a histogram would.

A line plot, also known as a dot plot, is useful for showing the frequency of individual values in a small data set. It may not be the best choice for this survey since it may not be practical to list every individual shoe size.

A box plot, also known as a box-and-whisker plot, is useful for showing the distribution of a large data set. It may not be the best choice for this survey since the data set is likely to be small, and a histogram would be more appropriate for displaying the results.

The following points are 5 or more units apart: A and B, G and D, G and F, G and E, F and E, E and B, (4, 3 and (4, -2), (6, -2) and (0, -2), (3, -7) and (3, -1)

When two points on a graph are 5 or more units apart, it means that there is a significant difference in the values of the function at those points.

For example, if we have two vertical or horizontal points (x1, y1) and (x2, y2) on a graph such that |x1 - x2| ≥ 5, it means that the x-values of the two points are at least 5 units apart.

Similarly, if |y1 - y2| ≥ 5, it means that the y-values of the two points are at least 5 units apart.

Using the above as a guide, the following points are 5 or more units apart

A and B, G and D, G and F, G and E, F and E, E and B, (4, 3 and (4, -2), (6, -2) and (0, -2), (3, -7) and (3, -1)

We have

N = (6, 8)

The point that is 8 or more units apart from N could be

Point = (6, 8 + at least 8)

So, we have

Point = (6, 8 + 9)

Point = (6, 17)

Hence, the point is (6, 17)

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The area οf the trapezium is 351 cm². Given that 2x² + x-351=0, sο the value οf x is 13 cm.

The sοlutiοns tο the quadratic equatiοn are the values οf the unknοwn variable x, which satisfy the equatiοn. These sοlutiοns are called rοοts οr zerοs οf quadratic equatiοns. The rοοts οf any pοlynοmial are the sοlutiοns fοr the given equatiοn.

We have the equatiοn 2x² + x - 351 = 0.

We can sοlve fοr x by factοring οr using the quadratic fοrmula. Since the cοefficient οf x² is 2, it's easier tο use the quadratic fοrmula:

x = (-b ± √(b² - 4ac)) / 2a

Here, a = 2, b = 1, and c = -351. Plugging in these values, we get:

x = (-1 ± √(1² - 4(2)(-351))) / 2(2)

x = (-1 ± √(1 + 2808)) / 4

x = (-1 ± √(2809)) / 4

We can simplify [tex]\sqrt{(2809)[/tex] tο 53, since 53² = 2809. Sο we have:

x = (-1 ± 53) / 4

Taking the pοsitive sοlutiοn, we get:

x = (53 - 1) / 4

x = 52 / 4

x = 13

Therefοre, the value οf x is 13 cm.

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Sοlving the equatiοn we get x=7

In mathematics an equatiοn is a mathematical statement which is built by twο expressiοns cοnnected by an equal ('=')sign. Fοr example, 3x – 8 = 16 is an equatiοn. Sοlving this equatiοn, we get the  x = 8.

Given that,

3/x²= x-4/3x² +2/x²

Tο sοlve the given equation  at first we will take LCM of the denominator of RHS

⇒ [tex]\frac{3}{x^{2} }[/tex]=[tex]\frac{x-4+6}{3x^{2} }[/tex]

⇒[tex]\frac{3}{x^{2} }[/tex] = [tex]\frac{x+2}{3x^{2} }[/tex]

By crο ss multiplicatiοn we get,

  x+2= 9

Subtracting 2 frοm both sides of equation we get

  x= 9-2

 x=7

Hence sοlving the equation we get x=7

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Note that the sum of all the regions equals the size of the universal set U, as it should be:

5 + 12 + 4 + 24 + 19 + 9 + 5 + 6 = 70.

To fill in the Venn diagram, we start with the given information:

n(A) = 33

n(B) = 36

n (B ∩ C) = 14

n (A ∩ C) = 9

n (A ∩ B ∩ C) = 5

n(U) = 70

n(C) = 24

n (A ∩ B) = 17

We can use the formula for the size of a set union to find n (B ∪ C):

n (B ∪ C) = n(B) + n(C) - n (B ∩ C)

n (B ∪ C) = 36 + 24 - 14

n (B ∪ C) = 46

We can also use the formula for the size of a set intersection to find n(A ∩ B):

n (A ∩ B) = n(A) + n(B) - n (A ∪ B)

n (A ∪ B) = n(A) + n(B) - n (A ∩ B)

n (A ∪ B) = 33 + 36 - 17

n (A ∪ B) = 52

n (A ∩ B) = 33 + 36 - 52

n (A ∩ B) = 17

Now we can start filling in the Venn diagram:

I = A ∩ B ∩ C = 5

II = A ∩ B - C = 12 (since n(A ∩ B) = 17 and n(A ∩ B ∩ C) = 5)

III = A ∩ C - B = 4 (since n(A ∩ C) = 9 and n(A ∩ B ∩ C) = 5)

IV = A - B - C = 24 (since n(A) = 33 and n(A ∩ B) = 17 and n(A ∩ C) = 9 and n (A ∩ B ∩ C) = 5)

V = B - A - C = 19 (since n(B) = 36 and n(A ∩ B) = 17 and n(B ∩ C) = 14 and n (A ∩ B ∩ C) = 5)

VI = B ∩ C - A = 9 (since n(B ∩ C) = 14 and n(A ∩ B ∩ C) = 5)

VII = C - A - B = 5 (since n(C) = 24 and n(A ∩ C) = 9 and n(B ∩ C) = 14 and n (A ∩ B ∩ C) = 5)

VIII = U - (A ∪ B ∪ C) = 6 (since n(U) = 70 and n(A) = 33 and n(B) = 36 and n(C) = 24)

Therefore, the completed Venn diagram would have:

I = 5

II = 12

III = 4

IV = 24

V = 19

VI = 9

VII = 5

VIII = 6

Note that the sum of all the regions equals the size of the universal set U, as it should be:

5 + 12 + 4 + 24 + 19 + 9 + 5 + 6 = 70

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Hence inverse of the function h is

h⁻¹ :x→  2/(x-1)  -1

An inverse function is a function that "undoes" the action of another function. In other words, if a function f(x) takes an input x and produces an output y, then its inverse function, denoted as f⁻¹(y) or sometimes as g(y), takes the output y and produces the input x such that f(x) = y.

 A function is a rule that associates each element of a set (called the domain) with a unique element of another set (called the range or codomain).

Given function

f(x)=1+1/x for x>0

g(x)=(x+1)/2  for x>0

Given: h=fg

h=f(g(x))

h=1+1/(x+1)/2

Now, taking the inverse of the function h,

h=1+1/(x+1)/2

h-1=1/(x+1)/2

1/(h-1)=(x+1)/2

2/(h-1)=x+1

x=2/(h-1) -1

Hence inverse of the function h is

h⁻¹:x→ 2/(x-1) -1

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Radius of cylindrical container is 10 cm, if cylindrical container holds 4.4 litres of water when full and If the height of the container is 14 cm.

How to measure radius of the cylinder?

To solve this problem, we can use the cylinder volume formula:

Volume of cylinder =

π × radius^2 × height

We know that the volume of water that the cylinder can hold is 4.4 litres. We can convert this to cubic centimeters (cm^3) by multiplying by 1000, since there are 1000 cm^3 in a liter:

4.4 litres =

4.4 × 1000 = 4400 cm^3

We also know the height of the cylinder is 14 cm. So we can plug in these values and solve for the radius:

4400 = π × radius^2 × 14

Dividing both sides by 14π, we get:

radius^2 = 4400 / (14 × π) = 100

Taking the square root of the both sides yields:

radius = √100 = 10 cm

As a result, the cylindrical container's radius is 10 cm.

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The product of the binomials (x-9) and (x+2) is x² - 7x - 18.

To find the product of the binomials (x-9) and (x+2), we can use the FOIL method, which stands for First, Outer, Inner, Last.

First: Multiply the first terms of each binomial: xx = x²

Outer: Multiply the outer terms of each binomial: x × 2 = 2x

Inner: Multiply the inner terms of each binomial: -9 × x = -9x

Last: Multiply the last terms of each binomial: -9 × 2 = -18

Now we can add up these four products to get the final answer:

x² + 2x - 9x - 18

Simplifying this expression, we get:

x² - 7x - 18

Therefore, the product of the binomials (x-9) and (x+2) is x² - 7x - 18.

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