A man on the moon with a mass of 90 kilograms weighs 146 newtons. The radius of the moon is 1.74 x 10^6
meters. Find the mass of the moon

equation- F= G m1 m2/ d^2

Answer:

its 15 J i belive

Explanation:

Answer:

5.66 m/s

Explanation:

p=mv

255 = 45v

v = 255/45

v = 5.66 m/s

If you want to verify your answer, just insert your value to the equation.

The empirical formula of the compound is Li₂CO₃

First, we will determine the respective number of moles of each element present in the compound by dividing by their atomic masses

Lithium                      Carbon                          Oxygen

6.25÷6.94                 5.40÷12.01                    21.60÷16.00

0.9006                      0.4496                          1.35

Now, divide through by the smallest number of moles, that is, 0.4496

Lithium                      Carbon                          Oxygen

0.9006÷0.4496        0.4496÷0.4496            1.35÷0.4496

2                                      1                                    3

Hence, the empirical formula of the compound is Li₂CO₃

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Answer:

Od- Wooden

Explanation:

It would not make sense if it was non-wood because that make it no a wood base product, OC is not right because its not a a plant that produces wood as its structural tissue and thus has a hard stem.   An OA justT o take or get a supply of wood. so its Od

Answer: It's an area that's an optimal distance from the sun for potentially supporting  life

Answer:

A)250-240

=10+960

=970

Answer:

The energy of motion is known as kinetic energy.

Explanation:

Answer:

P V = N R T      ideal gas equation

V = .19 * A      volume of enclosed gas

.19 P = N R T / A      using volume of enclosed gas

P = Po + Phg       pressure on gas = atmospheric (Po) + Phg pressure due to column of mercury

.19 (Po + Phg) = N R T / A which is what was asked

Note Phg = density of Hg * height of Hg * acceleration due to gravity

A tube of constant circular cross-section, sealed at on end, contains an ideal gas trapped by a cylinder of mercury of length 0.035m. There will atmospheric pressure and pressure due to mercury column on trapped gas column  having length 0.19m which is given by,

(p₀+pm)×0.190 = nRT÷A.

Pressure is defined as force per unit area. i.e. P = F/A it gives the force on unit area.  its SI unit is Pascal (Pa) which is equal to N/m².  is a scalar quantity. its dimensions are [M¹ L⁻¹ T⁻²].

Looking at the figure from top to bottom, we can see the top end of the tube is opened. There is 0.035m of mercury column below which we have a air 0.190m of gas column.

We can feel the physics behind this figure what is happening here, top of the tube is open so there is atmospheric pressure acting on the mercury column and mercury column is above the gas column, it means that both atmospheric pressure and mercury pressure will act on gas column.

i.e.  (p₀+pm) = pressure on the air column

this (p₀+pm) is downward pressures, hence gas inside the tube gets compressed due to this pressure because bottom end is closed. it means that back pressure will be created inside the gas in upward direction and both pressures becomes equal at equilibrium.

i.e. (p₀+pm) = back pressure inside the gas column......1)

according to ideal gas equation, PV=nRT

pressure inside the air column is P = nRT÷V

where V is volume of gas that is A×0.190.

P = nRT÷(A×0.190).....( back pressure inside the gas column).

equation 1 becomes

(p₀+pm) = nRT÷(A×0.190).

Hence we get

(p₀+pm) ×0.190= nRT÷(A).

Hence proved.

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Answer:

afcorse 1 miles

Explanation:

yep plz make me the brainliest

The distance travelled by car is displacement which is

Displacement is defined to be the change in position of an object.

[tex]s=\frac{1}{2} (v+u)t[/tex]

[tex]s=\frac{1}{2} (25+20)4\\s= 90 m[/tex]

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[tex] \huge \bf༆ Answer ༄[/tex]

The given terms in the question are : -

We have been given the task to find out time (t)

The formula that can be used to find time is : -

[tex] \sf \: I = \dfrac{ Q}{t}{} [/tex]

Rearrange the formula,

[tex] \sf \: t = \dfrac { Q}{I }[/tex]

Solve for time (t)

[tex]꧁ \: \large \frak{Eternal \: Being } \: ꧂[/tex]

Answer:

Nuclear Fusion

Explanation:

At large distances, two nuclei repel one another because of the repulsive electrostatic force between their positively charged protons. If two nuclei can be brought close enough together, however, the electrostatic repulsion can be overcome by the attractive nuclear force, which is stronger at close distances.

Hi there!

Since we are dealing with such large distances, we can approximate.

Recall that the equation for speed is:

displacement / time = velocity

OR:

d/t = v

Begin by converting one hour to seconds:

1 hr  = 3600 sec

Now, we can solve for velocity:

(-2.0 × 10⁷) / 3600 = -5555.6 m/s ⇒ D: -5.55 × 10³ m/s

Answer:

Solar eclipses occur when the Moon passes between Earth and the Sun, leaving a moving region of shadow on Earth's surface. Lunar eclipses occur when Earth passes between the Sun and the Moon, casting a shadow on the Moon. This is an annular eclipse.

(credits to "britannica")

Explanation:

Answer:

The box will move diagonally down to the right

Answer:

please check the image

Explanation:

I hope this image helps you please follow the steps. Thank you

Answer:

1kg/```````2

Explanation:

solution

Please find attached photographs for your answer.

Hope it helps.

Do comment if you have any query.

Hi there!

[tex]\large\boxed{ME = 50 J}}[/tex]

Mechanical Energy = Potential Energy + Kinetic Energy, or:

E = U + K

Plug in the given potential and kinetic energies:

E = 12.5 + 37.5 = 50 J

Answer:

Your answer would be D :)

Explanation:

An object with a higher mass will always fall faster due to gravity acting upon it. 15 N is more massive than the 10 N object, so statement D is correct.

The weight of the block and normal reaction are equal in magnitude but opposite in direction. Also, the frictional force and applied force are equal in magnitude but opposite in direction.

The forces acting on the wooden block moving at a constant speed include the following;

The free-body diagram is presented below;

                                              N

                                              ↑

                               [tex]F_f[/tex]      ←  ⊕  →   F

                                              ↓

                                              W

The block is moving at a constant speed, we will have the following;

[tex]W = N \\\\F = F_f[/tex]

Thus, we can conclude that the weight of the block and normal reaction are equal in magnitude but opposite in direction. Also, the frictional force and applied force are equal in magnitude but opposite in direction.

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Answer:

I belive it is 38 degrees

Explanation:

The magnitude of the vertical acceleration of the ball during the total time interval that the ball is in the air, the acceleration remains the same.

A projectile can be defined as an object that is in flight after being projected. The acceleration acting in the vertical direction which is because of gravity in a projectile motion. Therefore, we can apply the equations of motion separately on X-axis and Y-axis to find the parameters.

If any projectile is projected with the velocity 'v' and is making an angle θ from horizontal. The horizontal component of the initial velocity of the projectile will be equal to vcosθ.

The vertical component of the initial velocity of the projectile is v sinθ. The horizontal component remains the same as no acceleration is acting horizontally.

The ball will experience only one force which is gravity if there is no air resistance. The gravity remains constant if there is no initial speed of the ball. The acceleration of the ball will be in the downward direction and stays constant.

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Geometric optics allows you to find which the correct answer about which false statement is:

  B)  All rays of light refracted by the lens pass through the principal focus.

Geometric optics studies the formation of images using the light geometric properties of optical systems, the main expression for this is:

      [tex]\frac{1}{f} = \frac{1}{p} + \frac{1}{q}[/tex]  

Where f is the focal length, p and q the distance to the object and the image respectively.

There are some points of special interest:

Let's analyze the claims.

A) True. A parallel ray comes from infinity and the image is formed at the focal point.

B) False. The image point is given by the expression above and depends on the distance to the object.

C) True. This is the definition of focal length.

D) True. All distances are measured from the main axis.

In conclusion, using geometric optics we can find that the correct answer about which false statement  is:  

      B)  All rays of light refracted by the lens pass through the principal focus.

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Answer:

(B) The number of protons - only the number of protons in the nucleus determines the element - mass and neutrons can vary for the same element

Answer:  The magnitude of the ball's momentum change is  

      Δp=m∣ν  

i

​

−ν  

f

​

∣=(0.70kg)∣(5.0m/s)−(−2.0m/s)∣=4.9kg⋅m/s.

Explanation:

input

work is done by effort input.

hope it helps

[tex] \: [/tex]

Answer:

I'm not a genius ok?

Explanation:

1. Radar communication, Analysis of the molecular and atomic structure, telephone communication

2. c

When calculating the binding energy, z multiplied by the sum of mass of proton and mass of electron.

Z in binding energy calaculation is the number of protons in the nuclides.

To calculate the binding energy we use the formula below;

E = Z (mp + me) + Nmn − mn

Where;

Thus, when calculating the binding energy, z multiplied by the sum of mass of proton and mass of electron.

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Answer:

5300km/h

Explanation:

That's an easy question. You can solve it yourself.

The answer can be found by dividing the Distance traveled by the Time.

Now you can solve all the problem of this rule.

Answer:

Choice C: Approximately [tex]1.64[/tex].

(Assuming that light entered into this glass block from air.)  

Explanation:

Let [tex]n_{1}[/tex] denote the refractive index of the first medium (in this example, air.) Let [tex]\theta_{1}[/tex] denote the angle of incidence.

Let [tex]n_{2}[/tex] denote the refractive index of the second medium (in this example, the glass block.) Let [tex]\theta_{2}[/tex] denote the angle of refraction.

By Snell's Law:

[tex]n_{1} \, \sin(\theta_{1}) = n_{2}\, \sin(\theta_{2})[/tex].

Rearrange the equation to find an expression for [tex]n_{2}[/tex], the refractive index of the second medium (the glass block.)

[tex]\begin{aligned}n_{2} = \left(\frac{\sin(\theta_{1})}{\sin(\theta_{2})}\right)\, n_{1}\end{aligned}[/tex].

The refractive index of air is approximately [tex]1.00[/tex]. Substitute in the values and solve for [tex]n_{2}[/tex], the refractive index of the glass block:

[tex]\begin{aligned}n_{2} &= \left(\frac{\sin(\theta_{1})}{\sin(\theta_{2})}\right)\, n_{1} \\ &= \left(\frac{\sin(46^{\circ})}{\sin(26^{\circ})}\right)\times 1.00 \\ &\approx 1.64\end{aligned}[/tex].