Q is the heat transferred, m is the mass, C is the specific
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. Since we are given the pressure and temperature of the system, we need to find the volume and number of moles of gas.
First, we can find the number of moles of hydrogen that dissociates from the H₂ gas. If the mole fraction of H is 5%, then the mole fraction of H₂ is 95%. Let's assume we start with 1 mole of H₂ . Then, we have:
0.05 moles of H
0.95 moles of H2
Some of the H₂ gas dissociates to H, so let's say x moles of H₂ dissociate. Then, we have:
(0.05 + x) moles of H
(0.95 - x) moles of H₂
Since we are assuming that the only final product is H₂, we know that all of the H atoms will recombine to form H₂:
(0.05 + x - 2x) moles of H₂
(0.95 - x) moles of H2
Simplifying this, we get:
(0.05 - x) moles of H₂
(0.95 - x) moles of H₂
Since we started with 1 mole of H₂, we know that the total number of moles is:
(0.05 - x) + (0.95 - x) = 1 - 2x
Now, we can use the ideal gas law to find the volume of gas at the final pressure and temperature. Since we know the number of moles of gas and the temperature, we just need to find the volume. We can rearrange the ideal gas law to get:
V = (nRT)/P
At 298 K and 1 atm, the gas constant R is 0.08206 L·atm/(mol·K). So, for the initial conditions, we have:
V_initial = (1 mol * 0.08206 L·atm/(mol·K) * 298 K) / 1 atm = 24.4658 L
Now, we can use the mole fractions and the number of moles to find the final volume of gas. We have:
(0.05 - x) moles of H₂
(0.95 - x) moles of H₂
The total number of moles is 1 - 2x, so we have:
(0.05 - x)/(1 - 2x) moles of H₂
(0.95 - x)/(1 - 2x) moles of H₂
Using the ideal gas law again, we can find the final volume:
V final = [(0.05 - x)/(1 - 2x) + (0.95 - x)/(1 - 2x)] * (0.08206 L·atm/(mol·K) * T) / 1.1 atm
Simplifying this, we get:
V final = [1 - 2x] * (0.08206 L·atm/(mol·K) * T) / (1.1 atm)
Now, we need to use the fact that the specific heat is constant to find the final temperature. We can use the formula:
Q = mCΔT
where Q is the heat transferred, m is the mass, C is the specific
Learn more about ideal gas here : brainly.com/question/14279790
#SPJ4
a ground state hydrogen atom absorbs a photon of light having a wavelength of 93.73 nm. 93.73 nm. it then gives off a photon having a wavelength of 1094 nm. 1094 nm. what is the final state of the hydrogen atom? values for physical constants can be found in the chempendix.
The final state of the hydrogen atom is the n=2 energy level.
The initial state of the hydrogen atom is the ground state, where the electron is in the n=1 energy level. When it absorbs a photon of wavelength 93.73 nm, it jumps to a higher energy level. We can calculate the energy of the absorbed photon using the equation E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon.
E = (6.626 x 10^-34 J s)(2.998 x 10^8 m/s) / (93.73 x 10^-9 m) = 1.653 x 10^-18 J
This energy corresponds to the difference in energy between the ground state and some higher energy level, which we can calculate using the Rydberg equation:
1/λ = R_H(1/n_i^2 - 1/n_f^2)
where λ is the wavelength of the emitted photon, R_H is the Rydberg constant for hydrogen, and n_i and n_f are the initial and final energy levels, respectively. We know λ and R_H, and we can assume n_i = 1, so we can solve for n_f:
1/λ = R_H(1 - 1/n_f^2)
n_f^2 = 1 / (1 - λ/R_H) = 4
n_f = 2
To know more about hydrogen, here
brainly.com/question/28494990
#SPJ4
a 3.02 mol 3.02 mol sample of kr kr has a volume of 417 ml. 417 ml. how many moles of kr kr are in a 5.62 l 5.62 l sample at the same temperature and pressure?
Sample 1 has 0.00724 mol/L of Kr, while sample 2 has 0.0406 mol of Kr.Therefore, the 5.62 L sample contains 0.0406 moles of Kr.
The given data gives the molar grouping of krypton in the underlying example. The molarity can be determined utilizing the equation, Molarity = number of moles of solute/volume of arrangement in liters. Utilizing this recipe, we get the molarity of the underlying example as 7.24 M.
Presently, we can utilize the molarity and volume of the second example to ascertain the quantity of moles of krypton in it utilizing the equation, number of moles of solute = molarity x volume of arrangement in liters. Subbing the given qualities in the recipe, we get the quantity of moles of krypton in the second example as 36.2 mol.Subsequently, there are 36.2 moles of krypton in a 5.62 L example at a similar temperature and strain as the underlying example.
To learn more temperature and pressure, refer:
https://brainly.com/question/19524022
#SPJ4
at a certain temperature, so2(g) and o2(g) react to produce so3(g) according to the chemical equation shown above. an evacuated rigid vessel is originally filled with so2(g) and o2(g) , each with a partial pressure of 1atm . which of the following is closest to the partial pressure of o2(g) after the system has reached equilibrium, and why? responses 0atm ; because kp is very large, nearly all the so2(g) and o2(g) are consumed before the system reaches equilibrium. 0 atmosphere ; because k sub p is very large, nearly all the s o 2 gas and o 2 gas are consumed before the system reaches equilibrium. 0.5atm ; because kp is very large, nearly all the so2(g) is consumed before the system reaches equilibrium, but an excess amount of o2(g) remains at equilibrium. 0.5 atmosphere ; because k sub p is very large, nearly all the s o 2 gas is consumed before the system reaches equilibrium, but an excess amount of o 2 gas remains at equilibrium. 1atm ; because kp is very large, the system is already near equilibrium, and there will be very little change to the partial pressure of o2(g) . 1 atmosphere ; because k sub p is very large, the system is already near equilibrium, and there will be very little change to the partial pressure of o 2 gas . 1.5atm ; because kp is very large, the decomposition of any so3(g) that forms increases the amount of o2(g) at equilibrium.
The response "0 atm; because kp is very large, nearly all the SO2(g) and O2(g) are consumed before the system reaches equilibrium" is the closest to the correct answer
The balanced chemical equation for the reaction between SO2(g) and O2(g) to produce SO3(g) is:
2SO2(g) + O2(g) ⇌ 2SO3(g)
At a certain temperature, the equilibrium constant for this reaction, Kp, is very large, which indicates that the reaction strongly favors the formation of products (SO3).
In an evacuated rigid vessel initially filled with SO2(g) and O2(g), each with a partial pressure of 1 atm, the reaction will proceed to reach equilibrium. At equilibrium, the partial pressures of SO2(g), O2(g), and SO3(g) will be related by the equilibrium constant Kp as follows:
Kp = (P(SO3))^2 / (P(SO2))^2 x P(O2)
where P(SO2), P(O2), and P(SO3) are the partial pressures of SO2(g), O2(g), and SO3(g) at equilibrium, respectively.
Since Kp is very large, we can assume that the reaction goes to completion and that all of the SO2(g) and O2(g) react to form SO3(g). Therefore, the partial pressure of O2(g) at equilibrium will be zero, and the correct answer is 0 atm.
So the response "0 atm; because kp is very large, nearly all the SO2(g) and O2(g) are consumed before the system reaches equilibrium" is the closest to the correct answer.
For more such questions on Equlibrium
https://brainly.com/question/13414142
#SPJ11
which reagent is the limiting reactant when 2.24 molmol naohnaoh and 1.20 molmol co2co2 are allowed to react?
When 2.24 mol NaOH and 1.20 mol [tex]CO2[/tex] are allowed to react, NaOH is the limiting reactant.
Let's try to figure out the limiting reactant of the reaction between NaOH and CO2 by using stoichiometry.
Stoichiometry is a branch of chemistry that deals with the calculation of quantities of reactants and products involved in a chemical reaction.
By using stoichiometry, we can calculate the limiting reactant of a reaction, which is the reactant that gets consumed entirely and determines the amount of product formed.
Limiting reactant calculation
[tex]NaOH + CO2 → Na2CO3 + H2O[/tex]
From the balanced chemical equation above, we can see that one mole of NaOH reacts with one mole of CO2 to produce one mole of Na2CO3 and one mole of H2O.
Using the mole ratio, we can calculate the number of moles of Na2CO3 that will be formed from 2.24 mol of NaOH.
[tex]2.24 mol NaOH × 1 mol Na2CO3/1 mol NaOH = 2.24 mol Na2CO3[/tex]
Similarly, we can calculate the number of moles of Na2CO3 that will be formed from 1.20 mol of CO2.1.20 mol CO2 × 1 mol Na2CO3/1 mol CO2 = 1.20 mol Na2CO3
Therefore, NaOH is the limiting reactant because it produces a smaller number of moles of Na2CO3 than CO2. NaOH is the limiting reactant, and we can say that 2.24 mol of NaOH reacts with 1.20 mol of CO2 to form 1.20 mol of Na2CO3.
To know more about limiting reagent refer to-
brainly.com/question/26905271#
#SPJ11
calculate the volume of 1.00 m ammonia and volume of 1.00 m hcl needed to make 50.0 ml of a 0.100 m ammonia buffer with ph
To make 50.0 mL of a 0.100 M ammonia buffer with a pH of 9.25, we need to mix 50.0 mL of 1.00 M ammonia and 50.0 mL of 1.00 M HCl.
To make a buffer solution, we need to mix a weak base and its conjugate acid in the appropriate amounts. In this case, we want to make an ammonia buffer with a pH of approximately 9.25, which is close to the pKa of ammonia (9.25). Henderson-Hasselbalch equation for buffer will be;
pH = pKa + log([A⁻]/[HA])
where [A⁻] is the concentration of the conjugate base (ammonia in this case) and [HA] is the concentration of the weak acid (ammonium ion in this case). We are given that the final buffer solution has a pH of 9.25 and a concentration of 0.100 M.
Calculating the moles of ammonia and ammonium ion needed
pH = pKa + log([A⁻]/[HA])
9.25 = 9.25 + log([A⁻]/[HA])
log([A⁻]/[HA]) = 0
[A⁻]/[HA] = 1
[HA] = [A⁻] = 0.050 M (half the final concentration)
So, we need 0.050 moles of ammonia and 0.050 moles of ammonium ion in the final solution.
Calculating the volume of 1.00 M ammonia needed
0.050 moles = 1.00 M x V
V = 0.050 L = 50.0 mL
So, we need 50.0 mL of 1.00 M ammonia.
Calculating the volume of 1.00 M HCl needed
We can use the equation;
moles of HCl = moles of NH₃ = 0.050
The molarity of HCl can be calculated using the equation;
Molarity = moles of solute/volume of solution (in liters)
0.050 moles / volume = 1.00 M
volume = 0.050 L = 50.0 mL
So, we need 50.0 mL of 1.00 M HCl.
To Know more about buffer solution here
https://brainly.com/question/15709146
#SPJ4
describe the basis of using carbon monoxide to quantify pulmonary diffusion capacity describe the assumptions made in this method address each of these assumptions in light of differences in diffusivity of carbon monoxide compared to oxygen and differences in solubilities of these two gases. what role does hemoglobin play in this method?
The pulmonary diffusion capacity of carbon monoxide (DLCO) is used to determine the transfer of gases through the lungs. The amount of carbon monoxide absorbed by hemoglobin in the lungs is measured in this method.
Carbon monoxide has a higher diffusion coefficient than oxygen, and it is 20-30 times more soluble than oxygen. These differences affect the interpretation of DLCO results. Hemoglobin is a molecule that is critical in the transportation of oxygen and carbon monoxide. Hemoglobin is known to bind with carbon monoxide 240 times more readily than oxygen. In this method, hemoglobin plays a critical role. It is assumed that 100 percent of inhaled carbon monoxide is absorbed into the bloodstream and that the hemoglobin-CO complex forms reversible binding without causing an alteration in the blood's oxygenation level.
The DLCO measurement is based on the following assumptions: At sea level, the concentration of carbon monoxide is zero in the blood being analyzed. The solubility of carbon monoxide in blood is 20-30 times greater than that of oxygen, indicating that it is dissolved in the blood more easily. The alveolar-capillary barrier's thickness is consistent throughout the lung's entire surface area. The diffusion capacity is determined solely by the exchange of gases through the alveolar-capillary membrane and the available hemoglobin in the blood.
Learn more about carbon monoxide at brainly.com/question/22530423
#SPJ11
given that the grignard reaction used 1.4555 g phenyl bromide, 10. g carbon dioxide, 0.5734 g magnesium filings, and 30.2 ml of 6m hcl , what was the limiting reagent in the overall reaction, assuming each stepwise reaction ran to completion with only the desired product forming?
The limiting reagent that stops when all the phenyl bromide has been used up, meaning that 0.0079 moles of carbon dioxide will react to produce 0.00395 moles of benzoic acid.
How to find limiting reagent?
The limiting reagent in the overall reaction is phenyl bromide given that the Grignard reaction used 1.4555 g phenyl bromide, 10 g carbon dioxide, 0.5734 g magnesium filings, and 30.2 ml of 6m HCl. This can be determined by calculating the moles of each reactant and identifying which one is limiting in the reaction.
A Grignard reaction is a type of chemical reaction where an alkyl, aryl or vinyl magnesium halide (Grignard reagent) reacts with a carbonyl group, acid halide or ester to produce a tertiary or secondary alcohol, ketone or tertiary or secondary alcohol ester as the product. It is an important reaction for the formation of carbon-carbon bonds.
The balanced equation for the Grignard reaction using phenyl bromide and carbon dioxide is:
2C₆H₅Br + Mg + CO₂ → C₆H₅COOH + MgBr₂
The molar mass of phenyl bromide is 184.01 g/mol.
Therefore, 1.4555 g of phenyl bromide is equal to 0.0079 moles. The molar mass of carbon dioxide is 44.01 g/mol.
Therefore, 10 g of carbon dioxide is equal to 0.227 moles. The molar mass of magnesium filings is 24.31 g/mol.
Therefore, 0.5734 g of magnesium filings is equal to 0.0236 moles.From the balanced equation, it can be seen that 2 moles of phenyl bromide are required to react with 1 mole of carbon dioxide.
Therefore, the number of moles of phenyl bromide needed is twice the number of moles of carbon dioxide.0.227 moles of carbon dioxide is equivalent to 0.454 moles of phenyl bromide. Since only 0.0079 moles of phenyl bromide were used, it is the limiting reagent.
Learn more about limiting reagent
brainly.com/question/26905271
#SPJ11
You add a Mg pellet weighing 0.085 g to 7.52 mL of 3 M HCl contained in a foam calorimeter and measure a temperature change of 41.5 oC. What is delta Hrxn in kJ/mol ?
Answer: A 0.86 mol sample of a substance is burned in a bomb calorimeter with a heat capacity of 11.23 kJ/C. The temperature increases by 14.93 C. What is ΔHrxn (in kJ/mol) for the combustion of the substance? Note: please record answer to two decimal places regardless of sig figs
from a ph meter titration curve a student experimentally determines the pka of benzoic acid to be 4.06. calculate the experimental ka for benzoic acid.
From a ph meter titration curve a student experimentally determines the pka of benzoic acid to be 4.06. the experimental ka for benzoic acid is approximately [tex]8.72[/tex] × [tex]10^{-5}[/tex]
To calculate the experimental Ka for benzoic acid, you can use the relationship between Ka and pKa:
pKa = -log(Ka).
In this case, the student determined the pKa to be 4.06.
To find the Ka, you need to use the inverse of the log function, which is [tex]10 ^{-pKa}[/tex].
So, Ka = [tex]10^{-4.06}[/tex]
Ka ≈ [tex]8.72[/tex] × [tex]10^{-5}[/tex]
The experimental Ka for benzoic acid is approximately [tex]8.72[/tex] × [tex]10^{-5}[/tex]
A titration curve is a graph that shows the pH of a solution as a function of the amount of titrant applied.
It is used to calculate the equivalence point, which is the point at which the amount of titrant administered is stoichiometrically equivalent to the amount of analyte in the solution being tested.
For more such questions on titration curve, click on:
https://brainly.com/question/16749233
#SPJ11
_____ involves keeping the item for a short amount of time before moving it elsewhere.(1 point)
Responses
Receiving
Holding
Loading
Unloading
Answer:
Holding
Explanation:
keeping the item means to hold the item
Holding. Holding involves keeping the item for a short amount of time before moving it elsewhere.
What distinguishes holding from loading and unloading?While loading and unloading involve the act of adding objects to a truck or container, holding refers to the act of maintaining an item for a brief period of time before transporting it to another location.
What is the use of keeping something before shifting it somewhere else?Retaining something enables for a little interval of time to pass before it is transferred to another location.
What are some instances where holding something before moving it somewhere else is required?When awaiting the arrival of a transport truck, verifying the item for damage, doing quality control checks, or arranging with other employees or departments before the item may be moved, it may be required to hold the item. When the next stage of the process is delayed or the receiving area is not readily accessible, it might also be necessary.
To know more about the holding visit:
https://brainly.com/question/29559299
#SPJ1
4 (c) Aluminium is produced by electrolysis of a molten mixture of aluminium oxide and cryolite. This is shown in Figure 3.
Name a gas produced at the positive electrode. Gas forms at the positive electrode Aluminium forms at the negative electrode [1 mark]
you are using a radioactive isotope to measure the age of a rock in your lab. the half-life of the isotope is 300 million years and the ratio of parent to daughter particles is 1/4. how old is the rock?
To calculate the age of the rock using the radioactive isotope, we can use the formula. Whereas the age of the rock would be approximately 696.579 million years.
t = (t1/2) * log(base 2) (N0/N) Where:
t = age of the rock
t1/2 = half-life of the isotope
N0 = initial number of parent particles
N = current number of parent particles
Given that the half-life of the isotope is 300 million years, we can substitute t1/2 = 300 million years into the formula.
Also, the ratio of parent to daughter particles is 1/4, which means that for every 1 parent particle, there are 4 daughter particles. This also means that the total number of particles (parent + daughter) is 5.
Let's assume that we started with N0 parent particles. Then, the number of daughter particles would be 4N0. Therefore, the total number of particles N would be N0 + 4N0 = 5N0.
Since the ratio of parent to daughter particles is currently 1/4, the current number of parent particles is 1/5 of the total number of particles, which is (1/5)*N.
Substituting all these values into the formula, we get:
t = (300 million years) * log(base 2) (N0 / (1/5)*N0)
Simplifying the expression inside the logarithm, we get:
t = (300 million years) * log(base 2) 5
Using a calculator, we can evaluate log(base 2) 5 to be approximately 2.32193.
Substituting this value into the formula, we get:
t = (300 million years) * 2.32193
t = 696.579 million years
Therefore, the age of the rock is approximately 696.579 million years.
Learn more about Radioactive isotope here:
brainly.com/question/28039996
#SPJ4
which of the following yields a buffer solution when equal volumes of the two solutions are mixed? i. 0.10 m hf and 0.10 m naf ii. 0.10 m hf and 0.10 m naoh iii. 0.20 m hf and 0.10 m naoh iv. 0.10 m hcl and 0.20 m naf a. i and ii only b. ii and iv only c. ii and iii only d. i and iv only e. i, iii, and iv only
The correct option is A) i and ii only. Buffer solution is an aqueous solution consisting of a weak acid and its corresponding weak base or vice versa.
The buffer solution can withstand a small amount of acid or base without significant changes in pH. A buffer solution can be made using a weak acid and its corresponding salt, or a weak base and its corresponding salt.
i. 0.10 m HF and 0.10 m NaF solution can yield a buffer solution when equal volumes of the two solutions are mixed.
ii. 0.10 m HF and 0.10 m NaOH solution can also yield a buffer solution when equal volumes of the two solutions are mixed.
iii. 0.20 m HF and 0.10 m NaOH solution cannot yield a buffer solution when equal volumes of the two solutions are mixed. This is because the HF concentration is high in this solution.
iv. 0.10 m HCl and 0.20 m NaF solution cannot yield a buffer solution when equal volumes of the two solutions are mixed. This is because neither HCl nor NaF is a weak acid or weak base.Therefore, the correct option is A) i and ii only.
for more such question on Buffer solution
https://brainly.com/question/27371101
#SPJ11
an acid ha has a ka value of 4.40 x 10-4. 25.0 ml of 0.100 m ha is titrated with 0.25 m naoh. after the equivalence point is reached, 3 ml of 0.25 m naoh are added. what is the ph of the solution at this point?
At the equivalence point and after the addition of 3 mL of 0.25 M NaOH, the pH of the solution is approximately 4.36.
The first step in solving this problem is to determine the moles of acid (HA) present in the initial solution.
moles of HA = concentration of HA x volume of HA
moles of HA = 0.100 M x 0.0250 L
moles of HA = 0.00250 mol
Next, we need to determine the amount of NaOH needed to reach the equivalence point. Since we have a 1:1 stoichiometric ratio between HA and NaOH, the moles of NaOH required to reach the equivalence point will be equal to the moles of HA present.
moles of NaOH = 0.00250 mol
To calculate the volume of NaOH required to reach the equivalence point, we can use the equation;
moles of NaOH =concentration of NaOH x volume of NaOH
0.00250 mol = 0.25 M x volume of NaOH
volume of NaOH = 0.0100 L = 10.0 mL
This means that 10.0 mL of 0.25 M NaOH will be required to reach the equivalence point.
At the equivalence point, all of the HA has reacted with the NaOH to form the salt, sodium salt (NaA), and water. This means that the moles of NaOH added to reach the equivalence point will be equal to the moles of HA that have reacted;
moles of NaOH = 0.0100 L x 0.25 M = 0.00250 mol
moles of HA reacted = 0.00250 mol
The total volume of the solution at the equivalence point is:
volume of solution = volume of HA + volume of NaOH
volume of solution = 0.0250 L + 0.0100 L
volume of solution = 0.0350 L
The concentration of the resulting solution after the addition of 10 mL of 0.25 M NaOH is;
moles of NaOH added = 0.0100 L x 0.25 M = 0.00250 mol
moles of NaA formed = 0.00250 mol
moles of HA remaining = moles of HA - moles of HA reacted = 0.00250 mol
concentration of NaA = moles of NaA / volume of solution = 0.00250 mol / 0.0350 L = 0.0714 M
concentration of HA = moles of HA / volume of solution = 0.00250 mol / 0.0350 L = 0.0714 M
Since NaA is the conjugate base of the weak acid HA, the solution is a buffer. To calculate the pH of the buffer solution, we can use the Henderson-Hasselbalch equation;
pH = pKa + log([A⁻]/[HA])
where pKa is the acid dissociation constant of HA, [A⁻] is the concentration of the conjugate base (NaA), and [HA] is the concentration of the weak acid (HA).
The pKa of HA is given as 4.40 x 10⁻⁴, so we can substitute this value along with the concentrations of NaA and HA to get:
pH = -log(4.40 x 10⁻⁴) + log(0.0714/0.0714)
pH = 4.36
To know more about equivalence point here
https://brainly.com/question/4518249
#SPJ4
effects of influenza
Effects of influenza are A muscle or other part of the body hurts. headaches. fatigue (tiredness) Some people may experience vomiting and diarrhea, which is more prevalent in children than in adults.
What is influenza ?The flu, also known as influenza, is a contagious viral illness that can cause mild to severe symptoms as well as life-threatening complications, including death, in otherwise healthy children and adults.
Influenza viruses primarily move from person to person through coughing or sneezing. They can also be transmitted less frequently by touching a contaminated surface and then touching the mouth, eyes, or nose. Individuals can spread the flu to others even before their own symptoms appear and for up to a week after symptoms appear.
What are diseases caused by influenza ?The influenza virus infects the nose, throat, and sometimes the lungs, causing a contagious respiratory disease. It can bring mild to serious illness and, in extreme cases, death.
To know more about influenza , visit ;
brainly.com/question/29386358
#SPJ1
what is the lewis acid in the following reaction? nh3 bf3 <---> nh3bf3 group of answer choices bf3 because it receives a lone pair. bf3 because it donates a lone pair. nh3 because it receives a lone pair. nh3 because it donates a lone pair.
The correct answer is option A) BF3 because it receives a lone pair. In this reaction, a Lewis acid-base reaction is taking place, in which a Lewis acid (electron pair acceptor) and a Lewis base (electron pair donor) are reacting to form a coordinate covalent bond.
BF3 serves as an electron pair acceptor and is the Lewis acid. This is due to the fact that BF3 has an open p-orbital that can receive a Lewis base's sole pair of electrons, such as NH3. Here, NH3 serves as an electron pair donor and is a Lewis base.
This is due to the fact that NH3 has a single pair of electrons that can be transferred to the vacant p-orbital in BF3.
This is crucial for forming the coordinating covalent bond that gives rise to the compound NH3BF3 between BF3 and NH3.
Complete Answer:
What is the Lewis acid in the following reaction? NH3 + BF3 <----> NH3BF3
Group of answer choices
A) BF3 because it receives a lone pair
B) BF3 because it donates a lone pair
C) NH3 because it receives a lone pair
D) NH3 because it donates a lone pair
To learn more about Lewis acid-base visit:
https://brainly.com/question/23433599
#SPJ4
Find the mass, in grams, of 11.2 L H2 at STP
3clo4- 2ph33clo3- 2p 3h2o in the above reaction, the oxidation state of chlorine changes from to . how many electrons are transferred in the reaction?
Total 12 electrons are transferred in the reaction.
In the above reaction, the oxidation state of chlorine changes from +7 to +3. To determine the number of electrons transferred, we need to calculate the change in oxidation state of chlorine.
Each chlorate ion (ClO₄⁻) has a charge of -1, and each chlorite ion (ClO₃⁻) has a charge of -1 as well.
The oxidation state of oxygen is -2, so the oxidation state of the four oxygen atoms in the chlorate ion is -8, and the oxidation state of the three oxygen atoms in the chlorite ion is -6.
Let x be the oxidation state of chlorine in the chlorate ion, then we have;
x + 4(-2) = -1
x = +7
Let y be the oxidation state of chlorine in the chlorite ion, then we have;
y + 3(-2) = -1
y = +5
Therefore, each chlorine atom undergoes a reduction of 2 units, which corresponds to the gain of 2 electrons.
Since there are 6 chlorine atoms in total (3 in chlorate and 3 in chlorite), the total number of electrons transferred in the reaction is;
6 x 2 = 12 electrons.
To know more about oxidation state here
https://brainly.com/question/11313964
#SPJ4
sample of gas has a volume of 4.25 l at 25.6 oc and 748 mmhg. what will be the volume of this gas at 26.8 oc and 742 mmhg?'
The new volume of the gas at 26.8°C and 742 mmHg is approximately 4.28 L.
To find the new volume of the gas at the given temperature and pressure, we can use the combined gas law formula:
P1 × V1 / T1 = P2 × V2 / T2
where P1 is the initial pressure, V1 is the initial volume, T1 is the initial temperature in Kelvin, P2 is the final pressure, T2 is the final temperature in Kelvin, and V2 is the final volume.
Convert the temperatures to Kelvin.
T1 = 25.6°C + 273.15 = 298.75 K
T2 = 26.8°C + 273.15 = 299.95 K
Convert the pressures to atm.
P1 = 748 mmHg × (1 atm / 760 mmHg) = 0.98421 atm
P2 = 742 mmHg × (1 atm / 760 mmHg) = 0.97632 atm
Rearrange the combined gas law formula to solve for V2.
V2 = P1 × V1 × T2 / (T1 × P2)
Substitute the given values into the formula.
V2 = (0.98421 atm) × (4.25 L) × (299.95 K) / (298.75 K × 0.97632 atm)
Calculate the final volume, V2.
V2 ≈ 4.28 L
The volume of the gas at 26.8°C and 742 mmHg is approximately 4.28 L.
More on gas volume: https://brainly.com/question/29490815
#SPJ11
which of the following statements about the diels-alder reaction are true? true it is a reaction involving pi-electrons. false it is a reaction favored by entropy considerations. false it is a concerted reaction. false it is a [1 3] cycloaddition. false it is a thermal reaction
The statements about diels alder reaction which are true are given in the explanation part.
The following statements about the Diels-Alder reaction are true:
- True: It is a reaction involving pi-electrons.
- True: It is a concerted reaction, meaning that it occurs in a single step without the formation of reaction intermediates.
- False: It is not necessarily favored by entropy considerations, as the reaction can be endothermic and enthalpy-driven.
- True: It is a [4+2] cycloaddition, meaning that it involves the formation of a 6-membered ring from a 4-carbon diene and a 2-carbon dienophile.
- False: While some Diels-Alder reactions can be thermal, others require specific conditions such as high pressure or the use of a catalyst to occur.
To know more about diels alder reaction go through:-
https://brainly.com/question/21503302
#SPJ4
an acetic acid buffer containing 0.50 m ch3cooh and 0.50 m ch3coona has a ph of 4.74. what will the ph be after 0.0020 mol of hcl has been added to 100.0 ml of the buffer?
The pH of the buffer will increase from 4.74 to 4.76 after adding 0.0020 mol of HCl. This increase in pH indicates that the buffer is able to resist the change in pH caused by the addition of an acid.
To determine the new pH of the buffer after adding 0.0020 mol of HCl, we need to use the Henderson-Hasselbalch equation, which relates the pH of a buffer to its acid dissociation constant (Ka) and the ratio of its conjugate base (A-) and acid (HA) concentrations. The equation is given as:
pH = pKa + log([A-]/[HA])
First, we need to determine the initial concentrations of CH3COOH and CH3COONa in the buffer solution. Since the buffer contains 0.50 M CH3COOH and 0.50 M CH3COONa, we can assume that the initial concentrations of CH3COOH and CH3COO- are both 0.50 M. We can then calculate the initial ratio of [CH3COO-]/[CH3COOH] as:
[CH3COO-]/[CH3COOH] = 0.50 M / 0.50 M = 1
Next, we need to determine the new concentrations of CH3COOH and CH3COO- after adding 0.0020 mol of HCl. Since the volume of the buffer is 100.0 mL or 0.100 L, the new concentration of CH3COOH ([HA]) can be calculated as:
[HA] = (0.50 M x 0.100 L) - 0.0020 mol = 0.0480 mol
Similarly, the new concentration of CH3COO- ([A-]) can be calculated as:
[A-] = (0.50 M x 0.100 L) + 0.0020 mol = 0.0520 mol
Now, we can calculate the new ratio of [CH3COO-]/[CH3COOH] as:
[CH3COO-]/[CH3COOH] = 0.0520 mol / 0.0480 mol = 1.083
Finally, we can use the Henderson-Hasselbalch equation to calculate the new pH of the buffer as:
pH = pKa + log([A-]/[HA])
pH = 4.74 + log(1.083)
pH = 4.76
For more such questions on pH
https://brainly.com/question/172153
#SPJ11
the gas pressure inside a container decreases when group of answer choices the temperature is increased. the number of gas molecules is decreased. the number of gas molecules is increased. the number of molecules is increased and the temperature is increased. previousnext
The gas pressure inside a container decreases when the temperature is increased. Option A is correct.
Increasing the temperature of a gas decreases its pressure due to increased average kinetic energy of the gas molecules, leading to more collisions with the container walls. When the temperature of a container rises, the gas pressure within falls. This is known as Charles's Law, which states that at a constant volume, the pressure of a gas is directly proportional to its temperature. When the temperature of a gas increases, the gas molecules gain kinetic energy and move faster, colliding more frequently with the container walls.
This increases the force of the gas molecules on the container walls, which in turn increases the gas pressure. Conversely, when the temperature decreases, the gas molecules move slower and collide less frequently with the container walls, leading to a decrease in gas pressure.
The number of gas molecules does not directly affect the gas pressure inside a container, as pressure is a function of temperature, volume, and the number of moles of gas present. However, increasing the number of gas molecules will increase the pressure if the temperature and volume are held constant. Option A is correct.
The complete question is
The gas pressure inside a container decreases when
Group of answer choices
A. The temperature is increased.
B. The number of gas molecules is decreased.
C. The number of gas molecules is increased.
D. The number of molecules is increased and the temperature is increased.
To know more about the Pressure, here
https://brainly.com/question/24085765
#SPJ4
magnesium sulfate, , is added to 133 ml of m sodium hydroxide, , until precipitate just forms. how many grams of magnesium sulfate were added? assume that the volume of the solution is not changed significantly by the addition of magnesium sulfate.
In the following chemical reaction, the solution was supplemented with 8.01g of magnesium sulfate.
We must utilize the following chemical formula to determine how magnesium sulfate and sodium hydroxide react to solve this issue:
MgSO4 + 2 NaOH → Mg(OH)2 + Na2SO4
One mole of magnesium sulfate (MgSO4) interacts with two moles of sodium hydroxide (NaOH), resulting in one mole of magnesium hydroxide (Mg(OH)2) and one mole of sodium sulfate, according to the equation (Na2SO4).
We must utilize the solution's concentration and volume to determine how many moles of NaOH are present in the solution:
C = n/V
where n is the number of moles, V is the volume in liters, and C is the concentration in moles per liter.
n(NaOH) = C × V
= 1 mol/L × 0.133 L
= 0.133 mol.
We require half as many moles of MgSO4 as we do of NaOH since their mole ratio is 1:2:
n(MgSO4) = 0.5 × n(NaOH)
= 0.5 × 0.133 mol
= 0.0665 mol
Using its molar mass, we can finally translate the quantity of MgSO4 from moles to grams:
m(MgSO4) = n(MgSO4) × M(MgSO4)
= 0.0665 mol × 120.4 g/mol = 8.01 g
Therefore the solution was supplemented with 8.01g of magnesium sulfate.
To learn more about chemical reactions, refer to:
https://brainly.com/question/11231920
#SPJ4
For the following question, choose TWO answers. Which question should be asked to determine if the reaction supports the Brønsted- Lowry model of acids and bases?
According to the Brønsted-Lowry model, an acid and its conjugate base differ by a single proton, while a base and its conjugate acid differ by the addition of a single proton. If a reaction produces conjugate acid-base pairs, it supports this model.
To determine if the reaction supports the Brønsted-Lowry model of acids and bases, there are several questions that could be asked. Two possible questions are:
1. Does the reaction involve the transfer of protons (H+ ions) from one molecule to another.This is a key concept in the Brønsted-Lowry model, which defines acids as proton donors and bases as proton acceptors. If a reaction involves the transfer of protons, it supports this model.
2. Do the reactants and products contain conjugate acid-base pairs.
for more such questions on Brønsted-Lowry model :
https://brainly.com/question/20308475
#SPJ11
Answer:
1. Did an acid donate a hydrogen ion to become a conjugate base?
2. Did a base accept a hydrogen ion to become a conjugate acid?
The solubility of a gas is 0.584 g/L at a pressure of 109 kPa. What is the solubility of the gas if the pressure is increased to 85 kPa, given that the temperature is held constant?
Solution.
Henry's law states that the solubility of a gas in liquids at a constant temperature is proportional to its pressure. We write the formula:
�
=
�
×
�
S=K×P
The Henry's constant for each substance is individual, so we express it and find it through the solubility of the gas and its pressure.
�
=
�
�
K=
P
S
�
=
5.58
∗
1
0
−
6
K=5.58∗10
−6
And now we find the solubility of the gas at a different pressure.
S = 1.39 g/L
Answer:
S = 1.39 g/L
2.
Solution.
To begin with, we will translate the pressure from mm Hg of the column and from atmospheres to Pascals.
760 mmHg = 101324.72 Pa
2.5 atm = 253312.5 Pa
�
=
�
×
�
S=K×P
�
=
�
�
K=
P
S
�
=
1.58
∗
1
0
−
5
K=1.58∗10
−5
Now we find the solubility of the gas at a different pressure.
S = 4.00 g/L
Answer:
S = 4.00 g/L
3.
Solution.
To begin with, we will translate the pressure from atmospheres to Pascals.
0.750 atm = 75993.75 Pa
�
=
�
×
�
S=K×P
�
=
�
�
K=
P
S
�
=
3.22
∗
1
0
−
5
K=3.22∗10
−5
Now we find the gas pressure to get a solution with a concentration of 6.25 g / L.
�
=
�
�
P=
K
S
P = 194.1 kPa
Answer:
P = 194.1 kPa
Give an example of a solution and identify the solute and solvent.
A common example of a solution is saltwater. In this solution, the solute is salt (NaCl) and the solvent is water (H2O).
When salt is added to water, it dissolves into the liquid to form a homogeneous mixture. The water molecules surround the ions of the salt and pull them apart from each other, resulting in the formation of individual salt ions dispersed throughout the water. The salt ions become evenly distributed throughout the water, resulting in a solution.
In this example, the salt (NaCl) is the solute because it is the substance that is being dissolved. The water (H2O) is the solvent because it is the substance that dissolves the salt and creates the solution.
To know more about homogeneous mixture, visit:
https://brainly.com/question/24898889
#SPJ1
How do i solve this?
90.0 g of ethene is provided, which is more than the 14.025 g needed to react with 1.5 moles of oxygen in this reaction. There will therefore be some ethene left over once the reaction is finished.
What is the energy of C6H12O6 O2 CO2 H2O?In the process of respiration, six oxygen molecules combine with one glucose molecule to generate six carbon dioxide and water molecules. Equation: C6H12O6 + 6O2 6CO2 + 6H2O + Energy can be used to represent the respiration reaction.
To calculate the amount of ethene required to react with 1.5 moles of O2, we can now utilise stoichiometry:
3 moles of oxygen and 1 mole of ethene react.
1.5 moles of oxygen will react with (1/3) x 1.5 moles of ethene = 0.5 moles of ethene
Then, we can figure out how much 0.5 moles of ethene weigh:
m(ethene) = n(ethene) x Molar mass(ethene)
m(ethene) = 0.5 mol x 28.05 g/mol
m(ethene) = 14.025 g
To know more about reaction visit:-
https://brainly.com/question/28984750
#SPJ1
the ksp of agcl is 1.61 x 10-10. what is the solubility of agcl in a solution of 3.42 x 10-4 m srcl2?
The solubility of AgCl in the given solution is 1.26 x 10⁻⁸ M.
The reaction is,
AgCl(s) ⇌ Ag⁺(aq) + Cl⁻(aq)
Ksp = [Ag⁺][Cl⁻] = 1.61 x 10⁻¹⁰
SrCl₂ dissociates as follows:
SrCl₂(s) ⇌ Sr²⁺(aq) + 2Cl⁻(aq)
Since the reaction between AgCl and SrCl₂ does not involve the Sr²⁺ ion, its concentration can be considered constant and omitted from the equilibrium expression.
The solubility of AgCl in a solution of 3.42 x 10⁻⁴ M SrCl₂ is given by the following equation:
Ksp = [Ag⁺][Cl⁻] = x(2x + 3.42 x 10⁻⁴)
where x is the molar solubility of AgCl.
Solving for x,
x = 1.26 x 10⁻⁸ M
To know more about solubility, here
brainly.com/question/28044392
#SPJ4
some reactions can be performed without a solvent. what are the benefits of not needing a solvent in a reaction? select one or more: the reaction often costs less because solvents can be expensive. less chemical waste is generated because there are not solvents to remove. reaction progress is easy to monitor because the reagents are more concentrated. the reaction rate is smaller because the concentration of reagents is greater.
Less chemical waste is generated because there are no solvents to remove. The reaction often costs less because solvents can be expensive.
The reaction rate is greater because the concentration of reagents is greater. These options are correct.
A solvent is a substance that dissolves a solute, producing a solution. In addition to being a liquid, a supercritical fluid, a solid, or a gas can also be solvent. All the ions and proteins in a cell are dissolved in water, which is a solvent for polar molecules and the most frequent solvent employed by living things.
chemical reaction, the transformation of one or more chemicals (the reactants) into one or more distinct compounds (the products). Chemical elements or chemical compounds make up substances. In a chemical reaction, the atoms that make up the reactants are rearranged to produce various products.
Learn more about Solvent here: brainly.com/question/30885015
#SPJ4
in the introduction to this experiment, the text states taht small amounts of hcl are present in samples of tert-butyl chloride. write an arrow-pushing mechanism that explains the source of the hcl.
The presence of small of quantity of hydrochloric acid inside the samples of tert-butyl chloride, is attributed to 2 motives: 1. As an impurity in the course of the synthesis of tert-butyl chloride from tert-butyl alcohol and hydrochloric acid. 2. because of the hydrolysis of tert-butyl chloride.
Hydrolysis is a chemical reaction that involves the breaking of a chemical bond in a molecule through the addition of water molecules. This process results in the formation of two or more new molecules. Hydrolysis is an important process in many biological systems, including digestion, where enzymes help break down large molecules such as proteins, carbohydrates, and fats into smaller molecules that can be absorbed and used by the body.
In hydrolysis, water molecules are used to break the bonds between the atoms in the original molecule. One part of the original molecule will gain a hydrogen ion (H+) from the water, while the other part will gain a hydroxide ion (OH-). This process can occur naturally or with the help of enzymes, which are biological catalysts that speed up chemical reactions in living organisms.
To learn more about Hydrolysis visit here:
brainly.com/question/29439050
#SPJ4
Complete Question:-
In the introduction to this experiment, the text states that small amounts of HCl are present in samples of tert-butyl chloride. Write an arrow-pushing mechanism that explains the source of the HCl.