A boy is launching a toy rocket he got for his birthday from the top of an 80 ft building. The function representing
the height is f(0) = -16x? +64x + 80 where x represents time in seconds.
How many seconds did it take the rocket to reach it's maximum height?
A
144 sec
B)
2 sec
Eliminate
1.5 sec
D)
128 sec
Answers
Answer:
2 seconds, assuming the "?" in the equation is supposed to be ^2 (the exponent of 2): f(h) = -16x^2 +64x + 80
Step-by-step explanation:
You can either graph the functuion or take the first derivative to find the maximum height. The first derivative will give us the slope for a values of x. The slope at the top height of the rocket is zero, since it has stopped and is starting it's way back down.
First Derivative:
f(x) = -16x^2 +64x + 80
f'(x) = -32x + 64
Set this equal to zero and solve for x
0 = -32x + 64
x = 2 seconds.
Use 2 seconds in the original equation to find the height at 2 seconds.
f(2) = -16x^2 +64x + 80
f(2) = -16(2)^2 +64*(2) + 80
f(2) = 144 feet
Graph:
A graph is attached. You can locate the maximum at (2,144)
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Step-by-step explanation:
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Step-by-step explanation:
Let me know if this is right!
Hope it helps
Y= 132, X=32.6
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Step-by-step explanation:thank you
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============================================================
Explanation:
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After all of the points have been reflected, you'll get what is shown in figure 1.
------------------
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Answer:
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Below!
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Answers
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Answer:
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Step-by-step explanation:
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Follow Me:-
[tex]3x + 4 + 2x + 2 = - 24 \\ \\ = > 5x + 6 = - 24 \\ \\ = > 5x = - 24 - 6 \\ \\ = > 5x = - 30 \\ \\ = > x = \cancel \frac{ - 30}{5} \\ \\ = > x = - 6[/tex]
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Answer:
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Step-by-step explanation:
Answer:
%7 1400
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