A 1.5 kg ball falls onto a floor. Just before it strikes the floor, its velocity is 12 m/s. The ball bounces up with a velocity of 10 m/s. Find the impulse on the ball.

Answer:

In my opinion I think the answer is C you don't have to choose C

Answer:

A The additional potential energy the reactants must gain in order toreact

Explanation:

The electromagnetic spectrum is a frequency system that shows the wavelengths and intensities of electromagnetic radiation.

The electromagnetic spectrum is a frequency system that depicts electromagnetic radiation, wavelengths, and photon energies.

The electromagnetic spectrum that is seen as colors: violet, indigo, blue, green, yellow, orange, and red.

Radio waves, microwaves, infrared, optical, ultraviolet, X-rays, and gamma-rays are examples of frequencies found in the electromagnetic spectrum.

Hence, the above definition introduce the electromagnetic spectrum.

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The right response is a hockey puck slides along a horizontal icy frictionless surface and as a car is going along a straight road at a constant pace, according to the motion diagram.

The car is shown in the diagram starting at point a. The arrows remain pointing in the same way. This indicates that the thing is travelling directly forward. The arrows stay stationary at A. This indicates that the thing is travelling continuously.

The speed of the puck is not impacted by friction while it is moving on an ice rink surface. So, it is reasonable to suppose that it is moving at a constant speed before to impact.

The work done is zero only if there is no non-conservative force, such as friction, because the kinetic energy does not vary and the car is going along a straight, horizontal road. The work done will be force into displacement if there is friction.

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For the Direct free kick, the game restarted.

There are two different kinds of free kicks used in soccer: direct and indirect.The term "direct free kick" refers to a kick that can be used as a direct strike.Indirect free kicks require a second touch before the ball can be used as a shot at goal.

If a player attacks an opponent in a way that the referee deems to be irresponsible, reckless, or employing excessive force, the referee will award a direct free kick.jumps, kicks, or makes an attempt to kick.

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Answer: a freezer with the door shut

Explanation:

Answer:
For this I believe that your working on Ocean layers in science physics
There are actually 5 ocean zones or layers. (here they are in order)
1. Sunlight zone
2. Twighlight zone
3. Midnight zone
4. Abyssal Zone
5. Hadal zone
As a rephrase of the question I believe you meant to say
What are the marine zones?
Please correct me if wrong!!

Two charged particles are located on the x axis.

What are charged particles?

Charged particles are particles that have either a positive or negative electrical charge. These particles can be found in many forms in nature, such as electrons, protons, and ions. These particles are a key component of electricity, and can be used as a source of energy. Charged particles can be found in atoms and molecules, where they interact with other particles and affect their behavior. They can also be found in plasma, a state of matter that is made up of ions and electrons.

1. Start by writing out the equation for the electric field at the origin:

E = (kQ)/r^2

2. Substitute in the values for Q, k, and r, and solve for the unknown charge:

E = (2keQ)/a^2

E = (2k(+Q))/(3a)^2

+Q = (2kE)/(3a)^2

Since the electric field has a magnitude of 2keQ / a2, the unknown charge can be either positive or negative:

+Q = ±(2kE)/(3a)^2

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Answer:

Below

Explanation:

Mech adv = effort arm / load arm = 15 / 5 = 3

To solve this we must be knowing each and every concept related to force. and its different types. Therefore,  the mechanical advantage is 3.

A force is an outside entity that has the power to alter a body's state of rest or motion. It has a direction and a magnitude. The point where forces are applied is determined either by the force's direction as well as the application of the force.

Your training at this level should place a major emphasis on the idea which a push or even a pull was refereed to as a force. In our daily lives, forces appear in a variety of ways. as in weight and power. It refers to the force a bat applies to a ball and the strength a hairbrush has when stroking hair.

Mech adv = effort arm / load arm = 15 / 5 = 3

Therefore,  the mechanical advantage is 3.

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A full stop means that there is a complete cessation of the forward movement of the vehicle, or stop with no forward motion.

If two or more automobiles arrive at a four-way stop at the same time, the car to the right shall proceed first. "If two or more automobiles arrive at a four-way stop at the same moment, the car on the right shall proceed first."

Your headlights will allow you to see roughly 400 feet ahead of you. You should travel at a speed that permits you to stop within this distance, which is around 50 miles per hour.

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Answer:

C. 28.39 gram

Explanation:

Steps:

m = V × ρ

= 34 cubic centimeter × .835 gram/cubic centimeter

= 28.39 gram

Answer:

-21.7m

Explanation:

To find the y-component of the vector, we need to find the vertical displacement from the point at the bottom of the vector to the x-axis (or its y-coordinate value).

To calculate this we can create a triangle with the vector as the hypotenuse, the y-axis as the second side and draw an imaginary line from the end of the vector directly horizontally across to the y-axis.

We can use the given angle to find the angle between the y-axis and the angle. Since the angle of a quadrant is 90 degrees, the angle within our triangle must be [tex]90-77.1=12.9[/tex] degrees.

From here, to find the length of the side on the y-axis we can use the trigonometric cos function.

[tex]cos \theta =\frac{adjacent side}{hypotenuse}[/tex]

Therefore [tex]cos 12.9=\frac{y-component}{22.3}[/tex] and [tex]ycomponent = 22.3cos12.9[/tex]

This gives us a value of 21.7 (3.s.f) for our y-component.

Finally, the y-component is also a vector so it also needs a direction. Therefore like its coordinate, its value will be -21.7m.

The original speed of the bullet was 300.6 m/s.

A measure of the amount of matter contained in or constituting a physical body. In classical mechanics, the mass of an object is related to the force required to accelerate it and hence is related to its inertia, and is essential to Newton's laws of motion.

Given:

mV bi​ +MV wi​ =mV b​ +M Vwf​

where m= mass of bullet =10 g=10^−2 ∣kg

M= mass of wood block =5 kg

V bI​ = initial mass of bullet

Vwi​ = initial mass of wood block and V bf​ =V wf​  

=0.06 m/s 10 −2 Vbi+0(10 −2 +5)0.6 V

bi​ = 10 −2 5.01×0.6​ V

bi​ =300.6 m/s

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In the question the only nonconservative forces in play are friction and the engine's motive force. Work done by friction is -2870 J. The work done by the engine is 1285 J.

The work done by an engine can be determined by the change in kinetic energy of the car. The work-energy principle states that the net work done on an object is equal to its change in kinetic energy. The initial kinetic energy of the car is 0 J (at rest) and the final kinetic energy of the car is 1/2mv^2, where m is the mass of the car and v is its final speed. The work done by the engine is equal to the change in kinetic energy of the car, which is the final kinetic energy minus the initial kinetic energy.Work_engine = change in kinetic energy = (1/2)mv^2 - 0

Work_engine = (1/2)(1070)(3)^2 = 4155 J. The work done by friction is -2870 J, which is negative because it is opposing the motion of the car. The net work done by nonconservative forces is the sum of the work done by the engine and the work done by friction. Net work = Work_engine + Work_friction = 4155 J + (-2870 J) = 1285 J. Therefore, the work done by the engine is 1285 J.

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Explanation:

the force effect the aeroplane and ship are Gravity and drug

Answer:

The answer is GRAVITY and DRUGS

Explanation:

Hope you have a good day :)

According to reports, the biggest meteorite with lunar origin weighs 19 g. If the meteorite placed on a scale whose spring constant is 83 N/m, 0.22 m is the compression of the spring.

We can use Hooke's Law to calculate the compression of the spring caused by the meteorite. Hooke's Law states that the force exerted on a spring is directly proportional to the spring's compression or extension.

= F

= k * x

where F is the force (in newtons), k is the spring constant (in N/m), and x is the compression (in meters).

Given the mass of the meteorite is 19 g and the spring constant is 83 N/m, the force exerted on the spring can be calculated as

= F

= (mass of the meteorite) * g

= (19 g) * (9.8 m/s^2)

The compression of the spring can be found by rearranging Hooke's Law and substituting in the force and spring constant

x = F/k

x = (19 * 9.8) / 83

x = 0.22 m

The compression of the spring caused by the meteorite is 0.22 m.

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Answer:

The net force is now 12

Explanation:

The boy is applying a force of 5 newtons + his mother is helping him to apply 7 newtons = 12 newtons.

True. Keeping the terminals and cable connections clean helps to ensure a good electrical connection, which can prolong the life of the battery.

Keeping the terminals and cable connections of a battery clean is important for prolonging the battery's life. Dirt, corrosion, or other buildup on the terminals can create resistance in the circuit, which can lead to overheating and damage to the battery. This can cause the battery to charge and discharge less efficiently, reducing its overall capacity and lifespan. To clean the terminals, you can use a wire brush or a toothbrush with baking soda and water to scrub away any corrosion. Then, dry the terminals and cables thoroughly before reconnecting them to the battery. This will ensure a good electrical connection and a longer-lasting battery.

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The number of electrons that move in a circuit where a current of 2.0 A flows for 2.0 minutes will be [tex]1.5X10^2^2[/tex]. The correct option is C.

Electrical charge carriers, often electrons or atoms deficient in electrons, travel as current. The capital letter I is a typical way to represent current.

A current of 2A passes through a wire for 20 minutes. The number of electrons that crossed the cross-section in this period is

Given that,

Current =2A

Time t= 20min = 20×60s

Let,

n and e be the number and charge of electrons in time t.

So,

The total charge, q(say) in the wire is

q = ne

Hence, the current flowing in time t is

I = q/t

I = ne/t

n = It/e

[tex]n=\frac{2(20X60)}{1.6X10^{-19}} \\\\n=\frac{2400}{1.6X10^{-19}}\\\\n=1.5X10^{22}[/tex]

Thus, the answer is [tex]1.5X10^2^2[/tex], means the correct option is C.

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Your question seems incomplete, the missing options are:

[tex]1.5X10^{21}\\\\1.5X10^{20}\\\\1.5X10^{22}\\\\1.5X10^{21}\\\\1.5X10^{23}[/tex]

When a loose brick is resting on a wall, it has potential energy. When the brick is pushed off the wall and is falling down, the amount of potential energy is decreasing while the amount of kinetic energy is increasing.

Kinetic energy is motion––of waves, electrons, atoms, molecules, substances, and objects. Potential energy is stored energy and the energy of position––gravitational energy. There are several forms of potential energy.

Conservation of energy is not saving energy. The law of conservation of energy says that energy is neither created nor destroyed. When we use energy, it doesn’t disappear. We change it from one form of energy into another.

A car engine burns gasoline, converting the chemical energy in gasoline into mechanical energy. Solar cells change radiant energy into electrical energy. Energy changes form, but the total amount of energy in the universe stays the same.

Energy efficiency is the amount of useful energy you get from a system. A perfect, energy-efficient machine would change all the energy put in it into useful work—an impossible dream. Converting one form of energy into another form always involves a loss of usable energy.

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When a ball moves with faster velocity, then a greater impulse force is Imparted that causes more flour to spread out.

The momentum of a system remains constant unless the system is acted on by an external force in which case the acceleration of center of mass satisfies. The force on a system of particles is the external force because the internal force is zero.

The external force is equal to the change in momentum of the system and is proportional to the acceleration of the center of mass. For a fixed choice of system, if there are no external forces acting on the system then the momentum of the system is constant is constant.

The external force may be zero in one direction but not others. The component of the system momentum is constant in the direction that the external force is zero. The component of system momentum is not constant in a direction in which external force is not zero.

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It will take 1.5 seconds for Marissa's car to accelerate from 26. 4 m/s to 28. 6 m/s.

Acceleration can be calculated by looking at the change in velocity over a specific period of time. It is an important concept in physics as it is used to explain the motion of objects in the real world.

Acceleration is a measure of how quickly an object is changing its velocity on average, and it is usually expressed in meters per second squared (m/s2).

This simple calculation of Marissa's car acceleration can be determined by using the formula: Delta speed / Acceleration rate = Time taken.

In this case, that would be 2.2 m/s (28.6-26.4) / 3.6 m/s2

= 0.6 s or 1.5 sec (rounded up).

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The force of gravitational attraction is 489.18N

                                          [tex]F = \frac{Gm_{1} m_{2} }{r^{2} }[/tex]

Where,

F is the gravitational force between two bodies

m1 is the mass of the first body = 50 Kg

m2 is the mass of the second body = [tex]5.97 * 10^{24} Kg[/tex]

r is the distance between the centres of two bodies = [tex]6.38 * 10^{6} m[/tex]

G = gravitational constant = [tex]6.67 * 10^{-11}[/tex]

Putting these values in above equation we get: F = 489.18N

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Answer:

An amp is one C per second. Two minutes is 120 seconds. So current is 10 C/120 sec which is 1/12 th of an Amp.

The average angular acceleration has a value of 0.74 rad/s2.

Applying a force tangential to the rim and in the direction of the instantaneous velocity of the piece of the rim you are applying the force to will most likely increase the angular speed. Reversing the direction of the force will slow down the angular speed.

(rad/s)/s or rad/s2 are the units of angular acceleration. If rises, is a positive number. is negative if it decreases. Remember that the positive direction is counterclockwise and the negative direction is clockwise.

F = m r α . τ=mr2α. τ = m r 2 α

initial rotaton speed=10rad/s

final speed=6.3rad/s

time=5sec.

α=(10-6.3)/5 =.74rad/s

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Given :

A 2kg object is moving with speed 5m/s. then hits a  wall in 0.5s before reversing its direction with a speed of 2m/s.

To Find :

The impulse.

Solution :

Impulse can be calculated by change in momentum :

[tex]I = mv_f - mv_i\\\\I = 2\times( -2 + 5 )\ kg \ m/s\\\\I = 6 \ kg \ m/s[/tex]

Therefore, the impulse is 6 kg m/s.

Answer: The battery casing will explode

Explanation: Hydrogen gas will be released because of the heat which may cause an explosion.

Answer: -39200.45 Nm^2/C^2       This is rough work

Explanation:

So, the net force will be felt on particle [tex]\sf{q_1}[/tex] approximately 15.39 N to the right.

Hi! Here I will explain the net force of three charges that interacts. Remember that this question can be solved using Coulomb's Law. Coulomb's Law states that the interaction force between two interacted charges will be proportional to the magnitude of the charges that have specific interaction but inversely proportional to the square of the value of the distance between each other. So, with this concept, we can calculate the magnitude of coulomb force with this equation:

[tex] \boxed{\sf{\bold{F = k \cdot \frac{q_1 \cdot q_2}{(r_{12})^2}}}} [/tex]

On this condition, the net force will be felt only by the first charge, so we must define the position of the first charge as a fixed one. So, we can calculate the magnitude of coulomb force concerning the first charge with this equation:

[tex] \boxed{\sf{\bold{\sum F_{q1} = k \cdot (\frac{q_1 \cdot q_2}{(r_{12})^2} + \frac{q_1 \cdot q_3}{(r_{13})^2})}}} [/tex]

With the following condition:

[See the attached image to know how to solve this problem]

So, the net force will be felt on particle [tex]\sf{q_1}[/tex] approximately 15.39 N to the right.