The empirical formula of iron sulfide is FeS. The empirical formula represents the simplest whole number ratio of atoms in the compound, but it may not represent the actual molecular formula.
What is Empirical Formula?
The empirical formula of a chemical compound is the simplest whole number ratio of atoms of each element present in the compound. It can be determined from the mass or percentage composition of the elements in the compound.
We can use the given mass of iron and the mass of the product formed to determine the amount of sulfur that reacted with the iron.
First, we need to determine the mass of sulfur in the product:
mass of sulfur = mass of product - mass of iron
mass of sulfur = 1.574 g - 1.000 g
mass of sulfur = 0.574 g
Next, we can use the mass of iron and sulfur to calculate the number of moles of each element:
moles of iron = mass of iron / molar mass of iron
moles of iron = 1.000 g / 55.85 g/mol
moles of iron = 0.0179 mol
moles of sulfur = mass of sulfur / molar mass of sulfur
moles of sulfur = 0.574 g / 32.06 g/mol
moles of sulfur = 0.0179 mol
The mole ratio of iron to sulfur in the compound can be determined by dividing each value by the smaller of the two:
mole ratio of iron to sulfur = moles of iron / moles of sulfur
mole ratio of iron to sulfur = 0.0179 mol / 0.0179 mol
mole ratio of iron to sulfur = 1:1
Learn more about Empirical Formula from the given link
https://brainly.com/question/1603500
#SPJ1
When quartz undergoes metamorphism (exposure to extreme heat and pressure), what kind of metamorphic rock can it become?
The term used to describe the non-living parts of an eco system
Answer:
Abiotic Factor
Explanation:
Is a non-living part of an ecosystem that shapes its enviroment.
A sample of gas has an initial pressure of 740 mmHg and an initial volume of 32.0 L. If the volume is changed to 21.8 L, what is the new pressure? Assume temperature and amount remain constant
Answer:
1086.2 mmHg
Explanation:
P1×V1=P2×V2
740mmHg×32.0L=P2×21.8L
23680L mmHg= P2×21.8L
divide both sides by 21.8L
1086.2mmHg=P2
Suppose that the microwave radiation has a wavelength of 12.4 cm. How many photons are required to heat 205 mL of coffee from 25.0 ∘C to 62.0 ∘C ? Assume that the coffee has the same density, 0.997 g/mL, and specific heat capacity, 4.184 J/(g⋅K), as water over this temperature range.
Answer:
To calculate the number of photons required to heat the coffee, we can follow these steps:
Calculate the mass of the coffee using its volume and density:
mass = volume x density = 205 mL x 0.997 g/mL = 204.185 g
Calculate the amount of heat required to raise the temperature of the coffee using its mass, specific heat capacity, and temperature change:
q = m x c x ΔT = 204.185 g x 4.184 J/(g⋅K) x (62.0 - 25.0) °C = 32289.6 J
Calculate the energy of each photon using the formula E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength of the microwave radiation:
E = (6.626 x 10^-34 J⋅s) x (3.00 x 10^8 m/s) / (0.124 m) = 5.067 x 10^-23 J
Calculate the number of photons required to deliver the amount of energy needed to heat the coffee:
number of photons = q / E = 32289.6 J / 5.067 x 10^-23 J = 6.368 x 10^25 photons
Therefore, approximately 6.368 x 10^25 photons are required to heat 205 mL of coffee from 25.0 ∘C to 62.0 ∘C using microwave radiation with a wavelength of 12.4 cm.
How is an ellipse described numerically?
An ellipse is described numerically by its mathematical equation, which includes the center, major and minor axes, and values of a and b. The foci of ellipse can also be calculated from its equation.
How is an ellipse described numerically?An ellipse is a geometric shape that is defined by two points called foci and a constant sum of distances from any point on the ellipse to the two foci. This constant sum is called the major axis or the length of the ellipse, while the distance between the center of ellipse and the foci is called the minor axis or width of the ellipse.
To describe an ellipse numerically, we use its mathematical equation, which is in the form of: ((x-h)² / a²) + ((y-k)² / b²) = 1
(h, k) is center of ellipse
a is length of major axis divided by 2; b is length of minor axis divided by 2
The values of a and b determine the shape of ellipse. If a = b, the ellipse is a circle. If a > b, ellipse is stretched horizontally and is called an oblong ellipse. If a < b, ellipse is stretched vertically and is called a flat ellipse.
Two foci of ellipse can also be calculated using: c = √(a² - b²)
c is distance from the center of the ellipse to either of the foci.
To know more about ellipse, refer
https://brainly.com/question/9702250
#SPJ1
A 1.0 L of a 6.0 M solution of HCl acid is titrated with a 0.2 M basic solution. How much base is needed to reach its titration endpoint?
(I only have four more questions to ask lol)
Answer:
No worries, happy to help! To find out how much base is needed to reach the titration endpoint, we need to use the balanced chemical equation for the reaction between HCl and the basic solution, and the stoichiometry of the reaction. The balanced chemical equation is: HCl + NaOH → NaCl + H2O From the equation, we can see that 1 mole of HCl reacts with 1 mole of NaOH. We also know that the initial volume of HCl solution is 1.0 L, and the initial concentration is 6.0 M. This means we have: moles of HCl = volume x concentration = 1.0 L x 6.0 mol/L = 6.0 mol To reach the titration endpoint, we need to add enough NaOH solution to completely neutralize all
16. How many molecules are present in 3.0 X 102 grams of calcium
carbonate? [Calcium - 40 g/m;Carbon - 12g/m. Oxygen - 16 g/m]
A) 6.02 X 1023
B 81.1 X 1023.
C) 1.81 X 1024
To solve this problem, we need to use the concept of Avogadro's number and molecular weight.
The molecular weight of calcium carbonate (CaCO3) can be calculated as follows:
Calcium (Ca) atomic weight = 40 g/molCarbon (C) atomic weight = 12 g/molOxygen (O) atomic weight = 16 g/molMolecular weight of CaCO3 = (1 x 40) + (1 x 12) + (3 x 16) = 100 g/molNow, we can calculate the number of molecules in 3.0 x 10^2 grams of CaCO3 as follows:
Convert the mass of CaCO3 to moles using the formula:moles = mass / molecular weight
moles = 3.0 x 10^2 g / 100 g/mol
moles = 3.0 x 10^0 mol
Use Avogadro's number to calculate the number of molecules:number of molecules = moles x Avogadro's number
number of molecules = 3.0 x 10^0 mol x 6.02 x 10^23 molecules/mol
number of molecules = 1.806 x 10^24
Therefore, the answer is C) 1.81 x 10^24.