7-13 if the bod5 of two wastes having k values of 0.0800 d^-1 and 0.120 d^-1 is 280.0 ml/l, what would be the ultimate bod for each?

The empirical formula for the compound is [tex]Fe_{3} O_{4}[/tex].

The chemical includes 27.66 g of oxygen and 72.34 g of iron per 100 g.

1. An element's atomic weight and molar mass are equivalent.

Molar mass of Fe {Iron} = 55.845(g/mol)

Molar mass of O {Oxygen} = 15.9994(g/mol)

Divide each percentage by the total entered percentages to bring the entered percentages' sum to 100% as it is less than 100% (current sum is 99.98%).

Fe {Iron} ⇒ 72.34(old%), 72.35447(new%)

O {Oxygen} ⇒ 27.64(old%), 27.64553 (new%)

If you have 100g of substance, you can calculate the mass of each element by multiplying 100g by the percentage as follows:

Mass of Fe {Iron} = 72.35447gm

Mass of O {Oxygen} =27.64553gm

Divide the mass by the molar mass of each element (from step 1) to determine the number of moles:

Fe {Iron}= 72.35447gm/ 55.845(g/mol) *100 = 129.56302moles

O {Oxygen} = 27.64553gm/15.9994(g/mol) *100 = 172.79104moles

Look for the element with the fewest moles. Iron has the fewest moles of any metal, at just 129.56302425316. divide all mole values by this number:

Moles ÷ Moles Fe

Fe {Iron} = 1

O {Oxygen} = 1.33364

The existing mole levels are not particularly near to whole numbers, yet we need full numbers. Divide all sums by the fractional portion of each non-whole quantity to make them nearly whole:

FO = 0.33364466884954

Fe÷ FO = 1/0.33364466884954

Fe {Iron} = 2.9972

O {Oxygen} = 1.33364/0.33364466884954 = 3.9972

The final mole ratios are obtained by rounding each mole quantity to the closest integer:

Fe {Iron}=3

O {Oxygen} = 4

As a result, the compound's empirical formula is [tex]Fe_{3} O_{4}[/tex].

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The pH of the solution is 2.46. It is important to note that the answer should have the correct number of significant digits, which in this case is three.

To calculate the pH of the solution, we need to first determine the concentration of the solution.

Concentration (M) = moles of solute (n) / volume of solution (V)Concentration of solution = 0.2500 mol / 2.500 L

= 0.100 M

Now that we have the concentration, we can calculate the pH of the solution by using the pH formula:

pH = -log [H+]

The concentration of H+ in the solution can be calculated using the ionization constant of perchloric acid.

Ka = [H+][ClO4-]/[HClO4]1.2 x 10^-2

= [H+]^2/[0.100 M]

Therefore, [H+] = 0.00347 M

Now we can substitute this value into the pH formula:

pH = -log (0.00347)

= 2.46

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The emulsifying agent in the given context  is " the oil in mayonnaise."

An emulsifying agent is a substance that stabilizes emulsions by reducing the surface tension between the two phases, such as oil and water. In the context of mayonnaise, oil is the emulsifying agent that binds oil and vinegar or lemon juice into a stable suspension.

The oil in mayonnaise is responsible for the smooth texture and consistent thickness of the condiment. Without the emulsifying action of oil, the vinegar or lemon juice would separate from the oil and create an unpleasant, lumpy texture.

Therefore, the oil in mayonnaise is the correct answer as an emulsifying agent in the given context.

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Answer: Smokestacks are not a method to reduce the emissions of particulate matter.

Explanation: Smokestacks are the structures that release the emissions into the atmosphere. The other options listed - scrubbers, fluidized bed combustion, fabric filters, and electrostatic precipitators are all methods to reduce particulate matter emission.

The method that is not used to reduce the emissions of particulate matter is "Smokestacks".

Smokestacks are not a method to reduce the emissions of particulate matter. Smokestacks are the exhaust pipes in industries that emit the waste products into the atmosphere. Smokestacks are installed in the factories for the removal of flue gases produced during the combustion process.

Scrubbers, Fluidized bed combustion, Fabric filters, and Electrostatic precipitator are some methods used to reduce the emissions of particulate matter. These are explained below:

Scrubbers are used to eliminate acidic gases ([tex]SO_2[/tex] and NOx) as well as particulate matter from industrial flue gas. When flue gases enter a scrubber, they are exposed to a liquid solution that contains a base. [tex]SO_2[/tex] and NOx gases are neutralized as they pass through this solution, and particulate matter is trapped.

Fluidized bed combustion: In this method, the fuel is burned in a bed of inert particles at a high temperature, resulting in less NOx emissions and the release of less particulate matter into the atmosphere.

Fabric filters are used to filter out fine particles from flue gases by trapping them in woven filter bags. The bags are cleaned regularly to keep them functional.

Electrostatic precipitators use electrical charges to remove particulate matter from flue gases. Particles are ionized by a high-voltage electric field and then collected on oppositely charged plates, resulting in clean flue gas being released into the environment.

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The correct answer is To calculate the pressure required to compress 198 L of air at 2.5 atm into a cylinder whose volume is 35 L, we can use the ideal gas law.

PV = nRT where P is the pressure, V is the volume, n is the number of moles of gas, R is the universal gas constant, and T is the temperature in Kelvin. Assuming that the temperature remains constant during compression, we can rearrange the equation to solve for the final pressure: P_final = (nRT) / V_final where V_final is the final volume of the compressed air. First, we need to calculate the initial number of moles of air: n_initial = (P_initial * V_initial) / (RT) where P_initial is the initial pressure, V_initial is the initial volume, and R is the universal gas constant. Since we know the initial volume and pressure, we can plug in the values and solve for n_initial: n_initial = (2.5 atm * 198 L) / (0.0821 L·atm/mol·K * 298 K) n_initial = 20.3 mol Next, we can use the ideal gas law again to calculate the final pressure: P_final = (n_initial * R * T) / V_final where T is the constant temperature in Kelvin. Assuming the temperature is 298 K, and the final volume is 35 L, we can plug in the values and solve for P_final: P_final = (20.3 mol * 0.0821 L·atm/mol·K * 298 K) / 35 L P_final = 3.0 atm Therefore, the pressure required to compress 198 L of air at 2.5 atm into a cylinder whose volume is 35 L is 3.0 atm.

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The volume of oxygen consumed when 458 g of CH4 is combusted at STP is 1278.14 L.

What is STP?

STP stands for Standard Temperature and Pressure, which is a standard set of conditions used in chemistry and physics experiments. The standard temperature is 0 degrees Celsius or 273.15 Kelvin, while the standard pressure is 1 atmosphere or 101.3 kilopascals (kPa). At STP, one mole of any ideal gas occupies a volume of 22.4 liters (L). These standard conditions allow scientists to compare the properties of different gases under the same conditions, making it easier to make accurate measurements and predictions.

To find the volume of oxygen consumed during the combustion of methane, we need to use the balanced chemical equation and the ideal gas law.

First, let's find the number of moles of methane used:

Molar mass of CH4 = 12.01 + 4(1.01) = 16.05 g/mol

Number of moles of CH4 = 458 g / 16.05 g/mol = 28.53 mol

According to the balanced chemical equation, one mole of CH4 reacts with two moles of O2, so we need:

28.53 mol CH4 × 2 mol O2/1 mol CH4 = 57.06 mol O2

At STP (standard temperature and pressure), one mole of any ideal gas occupies 22.4 L of volume. Therefore, the volume of oxygen consumed is:

57.06 mol O2 × 22.4 L/mol = 1278.14 L

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The solubility of a gas in a liquid is dependent on the partial pressure of the gas above the liquid, as stated in the third statement. However, the second statement is false because the solubility of a solute in a solvent typically increases as the strength of the attractive forces between the solute and solvent molecules increases, not decreases.

The statement "the weaker the attraction between the solute and solvent molecules, the greater the solubility" is false.

Solubility is a measure of how much of a solute can dissolve in a given amount of solvent at a certain temperature and pressure. The solubility of a solute depends on various factors such as the nature of the solute and solvent, temperature, pressure, and the intermolecular forces between them.

Generally, substances with similar intermolecular attractive forces tend to be soluble in one another, as stated in the first statement. Nonpolar liquids tend to be insoluble in polar liquids, as stated in the fourth statement.

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Phosphorus pentafluoride is not an ionic compound. Option A is correct.

Phosphorus pentafluoride (PF₅) is a covalent compound composed of one phosphorus atom and five fluorine atoms. It is a colorless, toxic, and reactive gas that is used in various chemical reactions and as a reagent in the synthesis of other chemical compounds.

The PF₅ molecule has a trigonal bipyramidal shape, with the phosphorus atom at the center and the five fluorine atoms arranged around it. The molecule has a dipole moment and is polar, which makes it soluble in polar solvents such as water.

An ionic compound is a type of chemical compound that is formed by the attraction of positively and negatively charged ions. In an ionic compound, one or more atoms will lose electrons to form a positively charged ions known as cations, while one or more atoms gain electrons to form negatively charged ions known as anions.

Hence, A. is the correct option.

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--The given question is incomplete, the complete question is

"Which compound name does not correspond to an ionic compound? select one: A) phosphorus pentafluoride B) silver iodide C) magnesium bromide D) molybdenum(v) chloride."--

Answer:

B, C, D, F, I

Explanation:

A covalent bond is a chemical bond between two nonmetals (their electronegativity difference must be greater than 1.5-1.6)

.

A. Ca is a metal and O is nonmetal, so the bond in CaO is ionic

B. Both H and Cl are nonmetals, so the bond in HCl is covalent

C. Both C and O are nonmetals, so the bond in CO2 is covalent

D. Both S and O are nonmetals, so the bond in SO2 is covalent

E. Na is a metal and O is nonmetal, so the bond in Na2O is ionic

F. Both P and Cl are nonmetals, so the bond in PCl3 is covalent

G. Mg is a metal and O is nonmetal, so the bond in MgO is ionic

H. Na is a metal and H is nonmetal, so the bond in NaH is ionic

I. Both C and H are nonmetals, so the bond in CH2 is covalent

A thermodynamic state function is a value that is independent of a route. As a result, functions like as pressure, volume, and temperature are determined only by the state of a system and not by the path.

A thermodynamic potential, also known as a basic function, is a quantity used to indicate a system's state. Internal energy U, enthalpy H, Helmholtz free energy F, and Gibbs free energy G are our four fundamental functions.

State functions or point functions are properties whose value does not depend on the path followed to obtain that value. Path functions, on the other hand, are those functions that do depend on the path between two places.

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The mixture's final temperature is 62.8°C.

The specific heat of water is 4.184 J/g-K due to the fact that there are 4.184 joules in a calorie. The molar heat capacity of a substance—the amount of heat required to increase the temperature of one mole of the substance by either 1oC or 1K—can also be used to characterise how easily it gains or loses heat.

Q = mcΔT

Q hot = -Q cold

where Q hot is the heat lost by the hot water, and Q cold is the heat gained by the cold water.

Using the equation above, we can write:

m hot * c water * (T final - T hot) = -m cold * c water * (T final - Tcold)

where m hot is the mass of the hot water, m cold is the mass of the cold water, c water is the specific heat capacity of water, T hot is the initial temperature of the hot water, T cold is the initial temperature of the cold water, and T final is the final temperature of the mixture.

Substituting the given values, we get:

(6.0x102 g) * (1 cal/g°C) * (T final - 90.0°C) = -(4.00x102 g) * (1 cal/g°C) * (T final - 22.0°C)

Simplifying and solving for T_final, we get:

T final = (m hot * T hot + m cold * T cold) / (m hot + m cold)

T final = [(6.0x102 g) * (90.0°C) + (4.00x102 g) * (22.0°C)] / (6.0x102 g + 4.00x102 g)

T final = (54000 + 8800) / 1000

T final = 62.8°C

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According to Graham's law of effusion, the rate of effusion of a gas is inversely proportional to the square root of its molar mass. That is:

rate of effusion ∝ 1/√M

where M is the molar mass of the gas.

Let's assume that the molar mass of CO2 is M1 and the molar mass of the product gas is M2. We can express the ratio of their effusion rates as:

M2/M1 = (rate of effusion of CO2) / (rate of effusion of the product gas)

M2/M1 = (1/1.63)^2 (since the product gas took 1.63 times as long to effuse as CO2)

M2/M1 = 0.376

We know that the molar mass of CO2 is 44 g/mol. Therefore, we can solve for the molar mass of the product gas:

M2 = M1 x 0.376

M2 = 44 g/mol x 0.376

M2 = 16.544 g/mol

So the molar mass of the product gas is approximately 16.5 g/mol.

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The volume of a gas is directly proportional to its temperature when pressure and moles remain constant. As the temperature increases, the volume of nitrogen gas also increases. Hence, the correct option is (D) i.e. 5.59 L.

To solve this problem, we can use the combined gas law:

(P1V1)/T1 = (P2V2)/T2

where P is pressure, V is volume, and T is temperature. We can assume that the pressure remains constant, as the problem states that the container is flexible.

Given:

V1 = 5.00 L

T1 = 298 K

T2 = 333 K

We need to find V2 of nitorgen.

(P1V1)/T1 = (P2V2)/T2

V2 = (P1V1T2)/(P2T1)

We can assume that the pressure remains constant, so P1 = P2. Therefore, we can simplify the equation to:

V2 = (V1T2)/(T1)

V2 = (5.00 L)(333 K)/(298 K)

V2 = 5.59 L

Therefore, the correct option is (D) 5.59 L.

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From the calculation, it is clear that the mass of the S8 that has been produced here is about 136 g.

The mole is commonly used in chemistry for stoichiometric calculations, such as determining the amount of reactants needed in a chemical reaction to produce a desired amount of product.

We know that;

Number of moles of SO2 = 91g/64g/mol

=1.42 moles

Now if 8 moles of SO2 produces 3 moles of  S8

1.42 moles of SO2 will produce 1.42 * 3/8

= 0.53 moles

Mass of the S8 = 0.53 * 256 g/mol

= 136 g

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Charles's Law-

[tex]\:\:\:\:\:\: \:\:\:\:\:\:\star\longrightarrow\sf \underline{\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}}\\[/tex]

Where:-

As per question, we are given that -

We are given the initial in °C.So, we first have to convert the temperature in Celsius to kelvin by adding 273-

[tex]\:\:\:\:\:\:\star\sf T_1[/tex] = 23+ 273 =296K

Now that we have obtained all the required values, so we can put them into the formula and solve for T₂ :-

[tex]\:\:\:\:\:\: \:\:\:\:\:\:\star\longrightarrow\sf \underline{\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}}\\[/tex]

[tex]\:\:\:\:\:\: \:\:\:\:\:\:\longrightarrow\sf \underline{\dfrac{T_2}{V_2}=\dfrac{T_1}{V_1}}\\[/tex]

[tex]\:\:\:\:\:\: \:\:\:\:\:\:\longrightarrow\sf \underline{T_2=\dfrac{T_1}{V_1} \times V_2}\\[/tex]

[tex]\:\:\:\:\:\: \:\:\:\:\:\:\longrightarrow\sf T_2=\dfrac{296}{12} \times 52\\[/tex]

[tex]\:\:\:\:\:\: \:\:\:\:\:\:\longrightarrow\sf T_2=24.66....... \times 52\\[/tex]

[tex]\:\:\:\:\:\: \:\:\:\:\:\:\longrightarrow\sf T_2=1282.66.........\:K\\[/tex]

[tex]\:\:\:\:\:\: \:\:\:\:\:\:\longrightarrow\sf T_2=(1282.67 -273)°C\\[/tex]

[tex]\:\:\:\:\:\: \:\:\:\:\:\:\longrightarrow\sf T_2=1009.66....\:°C\\[/tex]

[tex]\:\:\:\:\:\: \:\:\:\:\:\:\longrightarrow\sf \underline{T_2=1009.67\:°C}\\[/tex]

Therefore, If 12L of neon at 23 °C is allowed to expand to 52 L then the new temperature will become 1009.67°C or 1282.67K to maintain constant pressure.

The source of energy used to heat massive amounts of water to boiling temperature for steam can vary, depending on the specific context and application. However, some common sources of energy used for this purpose include: Fossil fuels, Nuclear energy, and Renewable energy.

Fossil Fuels: Coal, oil, and natural gas are commonly used as fuels to produce steam. They are burned to generate heat, which is then transferred to the water to increase its temperature.

Nuclear Energy: Nuclear power plants use the energy released by nuclear reactions to generate heat, which is then used to produce steam.

Renewable Energy: Renewable sources of energy such as solar, wind, geothermal, and hydroelectric power can also be used to produce steam. For example, solar thermal power plants use sunlight to heat a fluid, which is then used to generate steam.

The amount of energy required to heat massive amounts of water to boiling temperature for steam production depends on various factors, such as the volume of water being heated, the desired temperature, and the efficiency of the heating system.

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Methane (CH₄) plays the same role on Titan as water does on Earth, existing as gas, liquid, and solid.

On Earth, water exists as a gas (water vapor), liquid (water), and solid (ice) due to the planet's temperature and atmospheric pressure conditions. On Titan, the largest moon of Saturn, the role of water is replaced by methane. Methane exists as a gas in Titan's atmosphere, and due to the extremely low temperatures and high atmospheric pressure, it can also exist as a liquid and solid on the moon's surface.

Titan's atmosphere is primarily composed of nitrogen, with small amounts of methane, ethane, and other gases. The presence of methane and other hydrocarbons on Titan has led scientists to speculate about the possibility of life on the moon, although this has yet to be confirmed.

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Answer:7 at 25 °C

Explanation:

but when exposed to the carbon dioxide equilibrium results in a pH of approximately 5.2 because CO2 in the air dissolves in the water and forms carbonic acid.

Answer:

The pH of pure water (H20) is 7 at 25 °C,

Explanation:

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(S)-2-aminobutane could be used as a resolving agent for a racemic carboxylic acid.

To be used as a resolving agent, an amine must be able to form a diastereomeric salt with the racemic carboxylic acid. This salt can then be separated into its enantiomeric forms using conventional separation techniques. The key is to find an amine that will selectively react with one enantiomer of the carboxylic acid and not the other.

Out of the amines shown, only (S)-2-aminobutane has a chiral center and is therefore capable of forming diastereomeric salts with a racemic carboxylic acid. The other amines are achiral and would not be able to differentiate between the enantiomers of the carboxylic acid.

When an amine is used as a resolving agent for a racemic carboxylic acid, it reacts with the acid to form a diastereomeric salt. This salt can be separated into its enantiomeric forms using conventional separation techniques such as recrystallization or chromatography. The key is to find an amine that will selectively react with one enantiomer of the carboxylic acid and not the other.

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The change in mass of the anode and cathode in an electrochemical cell can be used to determine the amount of reactants that have been converted into products during the electrochemical reaction. Therefore, the concentration of the electrolyte solution may change during the course of the electrochemical reaction.

The amount of reactants consumed at the anode will be equal to the amount of products produced at the cathode. Therefore, the change in mass of the anode should be equal in magnitude but opposite in sign to the change in mass of the cathode.

For example, in a galvanic cell where zinc is oxidized at the anode and copper is reduced at the cathode, the mass of the anode will decrease as zinc atoms are converted to Zn²⁺ ions and electrons, while the mass of the cathode will increase as copper ions are reduced to copper atoms and gain electrons.

The amount of zinc consumed at the anode should be equal to the amount of copper produced at the cathode, and so the change in mass of the anode should be equal in magnitude but opposite in sign to the change in mass of the cathode.

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--The given question is incorrect, the correct question is

"How does the change in mass of the anode compare with the change in mass of the cathode? what happens to the concentration."--

The client will receive 550 ml of fluid volume over a period of 10 hours if D5W is infusing at 55 gtt/min with a drop factor of 60 gtt/ml.

To calculate the fluid volume that the client will receive in 10 hours, we need to use the following formula:

Volume (in ml) = Flow rate (in gtt/min) x Time (in min) / Drop factor (in gtt/ml)

Given that the D5W solution is infusing at a rate of 55 gtt/min and the drop factor is 60 gtt/ml, we can plug in these values to the formula:

Volume (in ml) = 55 gtt/min x 600 min / 60 gtt/ml

Simplifying the equation, we get:

Volume (in ml) = 550 ml

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Asteroids are real objects that are thought to be remnants of the solar system. Little, stony objects known as asteroids go around the Sun. Option D is correct.

Little, stony objects known as asteroids go around the Sun. They resemble planets but are smaller and frequently formed erratically. A variety of rocks make up the majority of them, although some also contain clay or metal.

Asteroids are rocky, airless leftovers from the early stages of the solar system's formation, which occurred around 4.6 billion years ago. They are also known as minor planets.

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He notices a rise in the water's temperature from 10.0°C to 18.0°C in total. The metal cube's final temperature is 69.04°C.

Q = mcT, where Q is the heat dissipated by the cube, m is its mass, c is its specific heat, and T is its change in temperature.

The formula for the energy the water gains is Q = mcT.

mcT = mcT (cube) (water)

When we solve for the cube's final temperature, we obtain:

Tcube = (m cube c cube) / (m water c water)

Tcube is equal to (18.0°C - 10.0°C) 1 kg times 4182 J/kg°C and 1 kg times 375 J/kg°C

Tcube equals 0.96 °C

Final temperature: 70 °C minus 0.96 °C equals 69.04 °C.

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In the inductive step of a proof, you need to prove the statement that If P(k) is true and then P(k+1) is true.

In the induction process, a charged object is brought near but not touched to a neutral conducting object. The presence of a charged object near a neutral conductor will force (or induce) electrons within the conductor to move.

The method can be extended to prove statements about more general well-founded structures, such as trees; this generalization, known as structural induction, is used in mathematical logic and computer science. Mathematical induction in this extended sense is closely related to recursion. Mathematical induction is an inference rule used in formal proofs, and is the foundation of most correctness proofs for computer programs.

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3020 grams of iron are produced when 27.0 moles of hematite react with 86.0 moles of carbon monoxide.

Balanced chemical equation for the reaction between hematite and carbon monoxide will be; Fe₂O₃(s) + 3CO(g) -> 2Fe(s) + 3CO₂(g)

From the balanced equation, we can see that 1 mole of Fe₂O₃ reacts with 3 moles of CO to produce 2 moles of Fe. So, to determine the amount of iron produced, we first need to determine which reactant is limiting.

We can calculate the moles of Fe₂O₃ and CO;

Moles of Fe₂O₃ = 27.0 moles

Moles of CO = 86.0 moles

To determine the limiting reactant, we need to compare the mole ratio of Fe₂O₃ to CO required by the balanced equation (1:3) to the actual mole ratio of Fe₂O₃ to CO provided.

Mole ratio of Fe₂O₃ to CO = 27.0/1 : 86.0/3 = 81 : 86 ≈ 0.94 : 1

Since the actual mole ratio of Fe₂O₃ to CO is less than the mole ratio required by the balanced equation, Fe₂O₃ is the limiting reactant.

The amount of Fe produced can be calculated using the mole ratio of Fe₂O₃ to Fe in the balanced equation.

Moles of Fe = 2/1 × moles of Fe₂O₃ = 2/1 × 27.0 moles = 54.0 moles

Finally, we can convert moles of Fe to grams of Fe using the molar mass of Fe

Grams of Fe = moles of Fe × molar mass of Fe = 54.0 moles × 55.85 g/mol = 3020 g

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The chemical equation for the reaction is as follows:CH3CH2COOH + H2O → CH3CH2COOH + H3O+

When answering a question on Brainly, as a question answering bot, it is important to always be factually accurate, professional, and friendly. Additionally, it is essential to be concise and not provide extraneous amounts of detail.

Any typos or irrelevant parts of the question should be ignored. Below is the condensed structural formula of the organic product for propanoic acid reacting with each of the following:

NaOHSodium hydroxide (NaOH) reacts with propanoic acid (CH3CH2COOH) to give sodium propanoate (CH3CH2COO-Na+). The chemical equation for the reaction is as follows:

CH3CH2COOH + NaOH → CH3CH2COO-Na+ + H2OMethanolWhen propanoic acid reacts with methanol (CH3OH) in the presence of a catalyst, such as sulfuric acid (H2SO4), methyl propanoate (CH3CH2COOCH3) is formed.

The chemical equation for the reaction is as follows:CH3CH2COOH + CH3OH → CH3CH2COOCH3 + H2OWaterWhen propanoic acid reacts with water (H2O), it undergoes hydrolysis to give propanoic acid and hydronium ions (H3O+).

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In comparison to the greater hydrogen bonding in ethanol, diethyl ether molecules are bound together by weak dispersion forces. As a result, one mole of diethyl ether takes less heat to vapourize than one mole of ethanol.

The vapour pressure of diethyl ether at these temperatures is more than 20 times that of water, indicating its volatility.

Diethyl Ether, CH3CH2OCH2CH3, is a highly flammable organic solvent that was also revealed to be one of the earliest anaesthetics. Because it boils at 34.6°C, just below the typical human body temperature, ether evaporates quickly. Since its vapour is denser than air, ether fumes tend to sink into the atmosphere.

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F-18 has a biological half-life of about 6 hours and a physical half-life of 1.83 hours, making its active half-life roughly 1.4 hours (7). Fluorine F 18 has a half-life is 109.7 minutes and decays by positron,(+) emission.

Positrons are released by this fluorine radioactive isotope. A radioactive version of glucose that's also easily absorbed by cancer cells as well as normal cells can be created using F-18. Nuclear imaging can be used to locate tumours, map brain activity, and identify other diseases.

A key source of positrons is the fluorine radioisotope fluorine-18 (18F). Its half-life was 109.771(20) minutes, and its mass is 18.0009380(6) u. 96% of the time, it decays via positron emission, and 4% by electron capture.

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Saltation is the skipping or bouncing motion of particles transported by running water. Saltation is a type of bedload transport in which small and medium-sized particles are lifted and moved downstream by the flow of water.

The particles that are involved in saltation are too large to be carried in suspension by the water, but too small to roll or slide along the streambed.

The term saltation comes from the Latin word "saltare," which means "to leap or dance." It is used to describe the movement of sediment particles that bounce and leap along the streambed. Saltation occurs when the velocity of the water is strong enough to lift particles from the streambed, but not strong enough to carry them in suspension.

In saltation, particles that are lifted from the streambed by the flow of water fall back to the bed after they lose momentum. This falling back to the bed causes the particles to bounce and leap along the bed in a zig-zag motion. Saltation can move sediment over a short distance, but it is an important process in stream erosion and sediment transport.

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Explanation:

Yes, that is correct.

When aluminum sulfate solution (Al2(SO4)3) and calcium hydroxide solution (Ca(OH)2) are mixed, a double displacement reaction occurs, resulting in the formation of solid aluminum hydroxide (Al(OH)3) and solid calcium sulfate (CaSO4). The balanced chemical equation for this reaction is:

Al2(SO4)3 + 3Ca(OH)2 → 2Al(OH)3 + 3CaSO4

The aluminum hydroxide precipitates out of the solution as a gelatinous solid, while the calcium sulfate forms a white solid. This reaction is commonly used in water treatment plants to remove impurities from drinking water, as the aluminum hydroxide acts as a coagulant that binds to particles and organic matter in the water, allowing them to be removed more easily.