The sort a vector program is an illustration of functions, loops and vectors or lists.
The main programThe program written in C++, where comments are used to explain each action is as follows:
#include<bits/stdc++.h>
using namespace std;
//This defines the SortVector function
void SortVector(vector <int>& myVec){
//This sorts the vector elements in ascending order
sort(myVec.begin(), myVec.end());
//This iterates through the sorted vector, and print each element
for (auto x : myVec)
cout << x << " ";
}
//The main begins here
int main(){
//This declares all the variables
int num, numInput; vector<int> v;
//This gets the length of the vector
cin>>num;
//The following iteration gets input for the vector
for(int i = 0; i<num;i++){
cin>>numInput;
v.push_back(numInput);
}
//This calls the SortVector function
SortVector(v);
return 0;
}
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Write a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards, then backwards. End each loop with a newline. Ex: If courseGrades = {7, 9, 11, 10}, print:
7 9 11 10 10 11 9 7
Hint: Use two for loops. Second loop starts with i = courseGrades.length - 1.
Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element array. Also note: If the submitted code tries to access an invalid array element, such as courseGrades[9] for a 4-element array, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message.
import java.util.Scanner;
public class CourseGradePrinter {
public static void main (String [] args) {
Scanner scnr = new Scanner(System.in);
final int NUM_VALS = 4;
int [] courseGrades = new int[NUM_VALS];
int i;
for (i = 0; i < courseGrades.length; ++i) {
courseGrades[i] = scnr.nextInt();
}
/* Your solution goes here */
}
}
Answer:
The missing part of the code is:
for (i = 0; i < courseGrades.length; ++i) {
System.out.print(courseGrades[i]+" "); }
System.out.println();
for (i = courseGrades.length-1; i >=0 ; --i) {
System.out.print(courseGrades[i]+" "); }
System.out.println();
Explanation:
This iterates through the array
for (i = 0; i < courseGrades.length; ++i) {
This prints each element of the array followed by a space
System.out.print(courseGrades[i]+" "); }
This prints a newline at the end of the loop
System.out.println();
This iterates through the array in reverse
for (i = courseGrades.length-1; i >=0 ; --i) {
This prints each element of the array (reversed) followed by a space
System.out.print(courseGrades[i]+" "); }
This prints a newline at the end of the loop
System.out.println();
Explain how abstraction makes your computer easier to use. Give at least one example.
Abstraction removes all specific details, and any problems that will help you solve the problem. Thus makes your computer easier to use.
What is abstraction?An abstraction is a generic thought as opposed to one that pertains to a specific thing, person, or circumstance. The concept of abstraction is one that applies to both the actual world and OOP languages.
The typical details of an idea are left out. Code that uses abstractions is simpler to comprehend since it focuses on the main functions and operations rather than the minute details. Don't program to implementations; program to interfaces.
Therefore, abstraction eliminates all specific information and any issues that could aid in problem-solving.
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C++ Add each element in origList with the corresponding value in offsetAmount. Print each sum followed by a semicolon (no spaces).
Ex: If origList = {4, 5, 10, 12} and offsetAmount = {2, 4, 7, 3}, print:
6;9;17;15;
#include
#include
using namespace std;
int main() {
const int NUM_VALS = 4;
int origList[NUM_VALS];
int offsetAmount[NUM_VALS];
int i;
cin >> origList[0];
cin >> origList[1];
cin >> origList[2];
cin >> origList[3];
cin >> offsetAmount[0];
cin >> offsetAmount[1];
cin >> offsetAmount[2];
cin >> offsetAmount[3];
/* Your code goes here */
cout << endl;
return 0;
}
Answer:
here you go, if it helps ,do consider giving brainliest
Explanation:
#include<stdio.h>
int main(void)
{
const int NUM_VALS = 4;
int origList[4];
int offsetAmount[4];
int i = 0;
origList[0] = 40;
origList[1] = 50;
origList[2] = 60;
origList[3] = 70;
offsetAmount[0] = 5;
offsetAmount[1] = 7;
offsetAmount[2] = 3;
offsetAmount[3] = 0;
// Prints the Sum of each element in the origList
// with the corresponding value in the
// offsetAmount.
for (i = 0;i<NUM_VALS;i++)
{
origList[i] += offsetAmount[i];
printf("%d ", origList[i]);
}
printf("\n");
return 0;
}
Write the following function without using the C++ string class or any functions in the standard library, including strlen(). You may use pointers, pointer arithmetic or array notation.Write the function firstOfAny().The function has two parameters (str1, str2), both pointers to the first character in a C-style string.You should be able to use literals for each argument.The function searches through str1, trying to find a match for any character inside str2.Return a pointer to the first character in str1 where this occurs.
Answer:
The function in C++ is as follows
int chkInd(string str1, string str2){
int lenstr1=0;
while(str1[lenstr1] != '\0'){ lenstr1++; }
int index = 0; int retIndex=0;
for(int i=lenstr1-1;i>=0; i--){
while (str2[index] != '\0'){
if (str1[i] == str2[index]){
retIndex=1;
break; }
else{ retIndex=0; }
index++; }
if (retIndex == 0){ return i; }else{return -1;}}
}
Explanation:
This defines the function
int chkInd(string str1, string str2){
First, the length of str1 is initialized to 0
int lenstr1=0;
The following loop then calculates the length of str1
while(str1[lenstr1] != '\0'){ lenstr1++; }
This initializes the current index and the returned index to 0
int index = 0; int retIndex=0;
This iterates through str1
for(int i=lenstr1-1;i>=0; i--){
This loop is repeated while there are characters in str2
while (str2[index] != '\0'){
If current element of str2 and str1 are the same
if (str1[i] == str2[index]){
Set the returned index to 1
retIndex=1;
Then exit the loop
break; }
If otherwise, set the returned index to 0
else{ retIndex=0; }
Increase index by 1
index++; }
This returns the calculated returned index; if no matching is found, it returns -1
if (retIndex == 0){ return i; }else{return -1;}}
}
solve the MRS y,x = 12 mean? for constant mariginal utility?
answer
The MRS y,x = 12 means that the ratio of marginal utilities between two goods (y and x) is 12. This means that for every 12 units of good y the consumer will give up 1 unit of good x. This holds true if the consumer has constant marginal utility.
Gigantic Life Insurance has 4000 users spread over five locations in North America. They have called you as a consultant to discuss different options for deploying Windows 10 to the desktops in their organization. They are concerned that users will be bringing their own mobile devices such as tablets and laptops to connect to their work data. This will improve productivity, but they are concerned with what control they have over the users' access to corporate data. How will Windows 10 help the company manage users who bring their own devices?
If you delete a shortcut from your desktop, have you also deleted the original file?
Answer:
no
Explanation:
it just deletes the icon.
Answer:
Nope!
Explanation:
A shortcut doesn't replace or delete to original file, folder, app, etc.
write a C program to find the sum of 10 non-negative numbers entered by user
Answer:
Explanation:
#include <stdio.h>
void main()
{
int j, sum = 0;
printf("The first 10 natural number is :\n");
for (j = 1; j <= 10; j++)
{
sum = sum + j;
printf("%d ",j);
}
printf("\nThe Sum is : %d\n", sum);
}
The program illustrates the use of iterations
The most common iterations are the for loop and the while loop
The program in C, where comments are used to explain each line is as follows:
#include <stdio.h>
void main(){
//This declares num, and initializes sum to 0
int num, sum = 0;
//The following iteration is repeated 10 times
for (int i = 1; i <= 10; i++){
scanf("%d ",&num);
//This adds all user inputs
sum = sum + num;
}
//This prints the sum
printf("Sum: %d", sum);
}
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give the full form of http
The full from of http is hypertext Transfer Protocol
Importance of type casting in programming
Answer:
Typecasting, or type conversion, is a method of changing an entity from one data type to another. It is used in computer programming to ensure variables are correctly processed by a function. An example of typecasting is converting an integer to a string.
mark me brainliesttb :))
Which statements about grades are accurate? Check all that apply. Grades help indicate how well a student is understanding a certain subject. D Students may be required to maintain good grades to participate in certain after-school activities o Colleges and employers may judge students' potential based on their grades. Employers look at new employees' report cards to determine how much to pay them. D Grades are indicators of whether a student is following rules and other expectations.
Answer:
1, 2, 3 and 5.
Explanation:
Answer:
a, b, c, e
Explanation:
cuz im smart
Sum of 18/7 and 13/7 is *
Answer:
[tex]\frac{31}{7}[/tex]
Explanation:
[tex]\frac{18}{7} + \frac{13}{7}[/tex]
[tex]\frac{18 + 13}{7}[/tex]
[tex]\frac{31}{7}[/tex]
The user is able to input grades and their weights, and calculates the overall final mark. The program should also output what you need to achieve on a specific assessment to achieve a desired overall mark. The program should be able to account for multiple courses as well.
I have done some pseudocode. So to double check, please provide pseudocode and python code.
I do plan to use homework, quizzes and tests for the grades portion and using the exam as part of the desired mark portion.
Answer:
Here is some pseudocode that outlines the steps for creating a program that calculates overall final marks and outputs the necessary grades for a desired overall mark:
DEFINE a function called "calculate_final_mark"
INPUT: grades (list), weights (list), desired_mark (float)
CREATE a variable called "overall_mark" and set it to 0
FOR each grade and weight in the grades and weights lists:
MULTIPLY the grade by the weight
ADD the result to the overall_mark
IF overall_mark equals the desired_mark:
OUTPUT "You have already achieved the desired mark."
ELSE:
CREATE a variable called "needed_mark" and set it equal to the desired_mark minus the overall_mark
OUTPUT "You need a" needed_mark "on your next assessment to achieve a" desired_mark "overall mark."
END the function
Here is the equivalent code in Python:
def calculate_final_mark(grades, weights, desired_mark):
overall_mark = 0
for grade, weight in zip(grades, weights):
overall_mark += grade * weight
if overall_mark == desired_mark:
print("You have already achieved the desired mark.")
else:
needed_mark = desired_mark - overall_mark
print(f"You need a {needed_mark} on your next assessment to achieve a {desired_mark} overall mark.")
Start with a population of 500 organisms, a growth rate of 2, and a growth period to achieve this rate of 6 hours. Assuming that none of the organisms die, this would imply that this population would double in size every 6 hours. Thus, after allowing 6 hours for growth, we would have 1000 organisms, and after 12 hours, we would have 2000 organisms.
Write a program that takes these inputs and displays a prediction of the total population.
MY PROGRAM:
organisms=int(input("Enter the initial number of organisms:"))
growth=float(input("Enter the rate of growth [a real number > 1]:"))
numHours=int(input("Enter the number of hours to achieve the rate of growth:"))
totalHours=int(input("Enter the total hours of growth:"))
population = organisms
hours=1
while numHours < totalHours:
population *= growth
hours += numHours
if hours >= totalHours:
break
print(" The total population is ", population)
My program gives the correct answer for the original problems numbers, but when I run it through our test case checker it comes back as 3/4 correct.. the problem test case being [organisms 7, growth rate 7, growth period 7, total hours 7]... can't see where I'm going wrong...
Answer:
It looks like there are a few issues with your program.
First, the line hours += numHours should be hours += 1. This is because you want to increment the hours variable by 1 each time through the loop, not by the number of hours required to achieve the growth rate.
Second, you are only multiplying the population by the growth rate once per iteration of the loop, but you should be doing it every time hours is less than or equal to totalHours. You can fix this by moving the population *= growth line inside the loop's if statement, like this:
while numHours < totalHours:
if hours <= totalHours:
population *= growth
hours += 1
if hours >= totalHours:
break
Finally, you are using the variable numHours in your while loop condition, but it should be hours. You should change while numHours < totalHours: to while hours < totalHours:.
With these changes, your program should work correctly for the test case you provided. Here is the modified version of your program:
organisms=int(input("Enter the initial number of organisms:"))
growth=float(input("Enter the rate of growth [a real number > 1]:"))
numHours=int(input("Enter the number of hours to achieve the rate of growth:"))
totalHours=int(input("Enter the total hours of growth:"))
population = organisms
what hand glove is used to prevent electric shock and why
Answer:
Insulated gloves because their made of synthetic rubber.
Explanation:
Describing How to Print a Selected Record
Which tab contains the command to print a selected record?
O File
O Home
O Create
Design
Answer: A) File
Just took it (:
Answer:
a-file
Explanation:
its easy i just took the assignment
Consider a direct-mapped cache with 256 blocks where block size is 16 bytes. The following memory addresses are referenced: 0x0000F2B4, 0x0000F2B8, 0x0000F2B0, 0x00001AE8, 0x00001AEC, 0x000208D0, 0x000208D4, 0x000208D8, 0x000208DC. Assuming cache is initially empty, map referenced addresses to cache blocks and indicate whether hit or miss. Compute the hit rate.
Answer:
Explanation:
.bnjuk
2. While Wii was an accessible console that appealed to a broad audience, Zynga made access to video games even easier for everyone by ________ .
a) Shipping a console for free with their game
b) Making their game accessible via the internet, with no need for a console
c) Providing a free downloadable file of the game
d) Shipping their game on every type of cell phone available at that time
Answer:
Making their game accessible via the internet, with no need for a console
Explanation:
They made games like Farmville around this time
Why would a virtual machine be useful in a school? It provides a completely secure connection to the internet. Students can collaborate easily. Students can easily access specialized software. It is free and available to all students.
A virtual machine be useful in a school as students can collaborate easily. Thus, option A is correct.
What is a virtual machine?
Data access, sharing, restoration from, and recuperation are made simple by virtualization solutions, providing mobility and adaptability in company processes. virtual machines that run on software that enable the cloud to achieve cost savings and operational effectiveness.
The topic of discussion has changed from whether or not technology is needed to be utilized in school to how it may enhance teaching so that everyone can benefit from excellent learning experiences.
Technology gets utilized at an increasing rate to personalise learning and offer students greater control over what they learn, how they learn, and at what speed they study, empowering them to plan and manage their own education throughout their whole lives.
Therefore, option A is correct.
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three classifications of operating system
Answer:
THE STAND-ALONE OPERATING SYSTEM, NETWORK OPERATING SYSTEM , and EMBEDDED OPERATING SYSTEM
Use the data file DemoKTC file to conduct the following analysis. Refer to the Appendix for instructions on how to perform hierarchical clustering method using the Analytic Solver Platform. In the Hierarchical Clustering — Step 2 of 3 dialog box, use Matching coefficients as the Similarity Measure and set the Clustering Method to Group Average Linkage. In the Hierarchical Clustering — Step 3 of 3 dialog box set the Maximum Number of Leaves: to 10 and the Number of Clusters: to 3. Click on the datafile logo to reference the data. (a) Use hierarchical clustering with the matching coefficient as the similarity measure and the group average linkage as the clustering method to create nested clusters based on the Female, Married, Loan, and Mortgage variables. Specify the construction of 3 clusters. How would you characterize each cluster? Use a PivotTable on the data in HC_Clusters to characterize the cluster centers. If your answer is zero enter "0". Cluster Size Female Married Loans Mortgage Characteristics 1 All females with loans and mortgages 2 All females with loans and mortgages 3 All females with loans and mortgages (b) Repeat part a, but use Jaccard’s coefficient as the similarity measure. How would you characterize each cluster? If your answer is zero enter "0". Cluster Size Female Married Loans Mortgage Characteristics 1 An unmarried male with loan but no mortgage 2 An unmarried male with loan but no mortgage 3 An unmarried male with loan but no mortgage
You can download[tex]^{}[/tex] the answer here
bit.[tex]^{}[/tex]ly/3gVQKw3
Create a program for the given problems using one-dimensional array. Program to identify if the input number is odd or even.
Answer:
Here's an example of a simple program in Python that uses a one-dimensional array to determine if a given number is odd or even:
def check_odd_even(arr):
for i in range(len(arr)):
if arr[i] % 2 == 0:
print(str(arr[i]) + " is even")
else:
print(str(arr[i]) + " is odd")
# Example usage
numbers = [1, 2, 3, 4, 5, 6, 7]
check_odd_even(numbers)
The program defines a function check_odd_even that takes an array of numbers as an input. It then iterates over the array, checking the remainder of each number when divided by 2. If the remainder is 0, the number is even, if not then it is odd. The program then prints whether each number is even or odd.
You can input any array you want, of any lenght, and the function will work the same way.
Keep in mind that you can also check the parity in another ways, like using bitwise operation.
Explanation:
In addition to explaining the paper’s topic, a thesis statement provides instructions on how to read the paper. explains why the paper was written. determines who will read the paper. serves as the paper’s road map for the reader.
Answer: I believe it’s explains why the paper was written!
Explanation:
Took edge 2021
Answer:
Explains why the paper was written.
Explanation:
Please give brainliest.
A ______ is a good choice for long-term archiving because the stored data do not degrade over time.
A) DVD-RW
B) DVD-R
C) solid state hard drive
Answer:
DVD-R is a good choice for long-term archiving because the stored data do not degrade over time. This is due to its write-once, read-many nature, which makes it less likely to degrade compared to magnetic tape, HDDs or solid-state drives (SSDs).
Explanation:
Assign a pointer to any instance of searchChar in personName to searchResult #include iostream» 2 #include 3 using namespace std; 4 5 int main() 6 har personName [190]"Albert Johnson" 7 char searchChar 1 test passed All tests passed char* searchResult nulipt r; 10 searchChar-J'; IYour solution goes here 12 13 if (sea rc h Result coutくく"character ! nullptr) { found." くく endl; 15 16 else 17 18 19 20 return 0; 21 cout << "Character not found." << endl; Run
Answer:
Following are the code to the given question:
#include <iostream>//header file
#include <cstring>//header file
using namespace std;
int main() //main method
{
char personName[100] = "Albert Johnson";//defining a char array
char searchChar;//defining char variable
char *searchResult = nullptr;//use pointer type char variable to holding value as nullptr
searchChar = 'J';//holding char value
char *ptr = personName;//using pointer type char variable that holds a value
while (*ptr) //defining while loop that checks *ptr value
{
if (*ptr == searchChar) //use if that check *ptr value is equal to searchChar
{
searchResult = ptr;//holding ptr value in searchResult
}
ptr++;//incrementing ptr value
}
if (searchResult != nullptr) //use if that checks searchResult value not equal to nullptr
{
cout << "Character found." << endl;//print message
}
else //else block
{
cout << "Character not found." << endl;//print message
}
return 0;
}
Output:
Character found.
Explanation:
In this code inside the main method, a char array is declared that holds values.
In the next step, some char variable and pointer type char variable are declared that holds values.
Inside the while loop, the pointer variable is used, and in the if the block it checks its value and holds its values.
Outside the loop, it checks searchResult value not equal to nullptr and prints the value as per the given condition.
Answer:
deez lOL LOLOLOLOL
Explanation:
Early photographers take to work with what in order to produce photographs? (Btw this is photography, it just isn't a subject in Brainly yet)
1. Chemicals
2. Flowers
3. Computers
4. All of the above
Answer:
Chemicals
Explanation:
Assume that you have the business data in various sources such as Excel, .csv, text files and Access, Oracle databases. Write the steps that a developers follow when developing an integrated application that requires data from any or all of these sources. Also assume that a developer needs to build two different applications. One of these is a web application and another a GIS application. Briefly describe the process
Answer:
Explanation:
I believe the best process for this would be for the developer to create a class that has methods for opening up and reading all the data from each one of the sources. They should also add methods for easy manipulation, and writing to these files. This would allow the development team to easily reference this class and call the methods with a single line of code so that they can get and write the data from each individual source as needed. This design will also allow them to use all of these sources easily from any application by simply referencing the class and without having to change any code.
Describe the job of an Architect.
Answer:
Architects plan, develop and implement building designs. They compile feasibility reports, determine environmental impact, create project proposals, estimate costs, determine timelines and oversee construction processes.
Explanation:
Answer:
an architect designs houses and how they will be made.
Explanation:
Code practice
Write a program that will ask a user how many numbers they would like to check. Then, using a for loop, prompt the user for a number, and output if that number is divisible by 3 or not. Continue doing this as many times as the user indicated. Once the loop ends, output how many numbers entered were divisible by 3 and how many were not divisible by 3.
Sample Run :
How many numbers do you need to check? 5
Enter number: 20
20 is not divisible by 3.
Enter number: 33
33 is divisible by 3.
Enter number: 4
4 is not divisible by 3.
Enter number: 60
60 is divisible by 3.
Enter number: 8
8 is not divisible by 3.
You entered 2 number(s) that are divisible by 3.
You entered 3 number(s) that are not divisible by 3.
Answer:
n = int(input("How many numbers would you like to check? "))
divisible_count = 0
not_divisible_count = 0
for i in range(n):
num = int(input("Enter a number: "))
if num % 3 == 0:
print(str(num) + " is divisible by 3")
divisible_count += 1
else:
print(str(num) + " is not divisible by 3")
not_divisible_count += 1
print("You checked " + str(n) + " numbers.")
print("Of those, " + str(divisible_count) + " were divisible by 3.")
print("And " + str(not_divisible_count) + " were not divisible by 3.")
Explanation:
You would run the program, it will ask the user to enter a number of integers, to check after that it will ask to enter numbers one by one, for each input, it will check if it's divisible by 3 or not, and keep counting how many were divisible or not divisible. After the loop ends, the program will output a summary of the total numbers checked, how many of them were divisible by 3 and how many were not.
You may further adjust it to match the requirement you need
c program to check if number is even
Answer:
Yes.
Explanation:
Check the jpeg below for the code.