*50 POINTS* 7th Grade Geometry please help

Answer:

Both 6 and 3 would be negative

Step-by-step explanation:

Both are on the -x and -y side of the graph

Answer:

There are 2 terms.

Step-by-step explanation:

1st term: m

2nd term: 2n

Answer: w=117.82 cm and L=44 cm

Step-by-step explanation:

72^2 = 5184 cm

5184/44 = about 117.82 cm

The volume of the original box is given as

V = lwh

V = 10(6)(3)

V = 180 in³

Answer:

BFA

Step-by-step explanation:

Answer:C

Step-by-step explanation:

Answer: I believe you just multiply each point by 1/2. So -10/2=-5 and -6/2=-3

So point b will be(-5,-3)

if not im not sure

Answer:same as them

Step-by-step explanation:

Answer:

B= (27,0)

A= (34,14)

Step-by-step explanation:

The point where the right angle is (34,0). B would be halfway between this and (20,0). It would be 20+34=54 then 54/2. This is 27. (since it lies on y=0, it's just y=0). The point is (27,0).

A is halfway between (34,0) and (34, 28). They have the same X point, so it would be the middle of 28 and 0. 28+0=28, then 28/2= 14. A would be (34,14).

Answer:

Step-by-step explanation:

the formula is 2(WL+HL+HW)

width=w

h=height

l=length

if we were to substitute in these given numbers the equation would become:

2(15*36+20.4*36+20.4*15)

=3160.8

hope it helps.

Answer:

2(1/2 * 3 * 4) + 4 * 2 + 3 * 2 + 5 * 2

Step-by-step explanation:

this triangular prism can be divided into 3 rectangles(S = a*b) and 2 right angle triangles((a*b)/2)

so, the surface area of the triangular prism = ( 4*2 + 3*2 + 5*2) + ((4*3)/2 + (4*3)/2) = 2(1/2 * 3 * 4) + 4 * 2 + 3 * 2 + 5 * 2

The total number of candies in the jar is 70, out of which 14 are brown. Therefore, the number of candies that are not brown is 70 - 14 = 56.

To find the probability of drawing a candy that is not brown, replacing it, and then drawing an orange candy, we can use the multiplication rule of probability. According to this rule, the probability of two independent events occurring together is the product of their individual probabilities.

So, the probability of drawing a candy that is not brown on the first draw is 56/70. After replacing the candy, there are still 70 candies in the jar, so the probability of drawing an orange candy on the second draw is 28/70.

Multiplying these probabilities, we get:

(56/70) x (28/70) = 0.16

Therefore, the probability of randomly drawing a candy that is not brown, replacing it, and then drawing an orange candy is 0.16 or 16%.

Answer: About 12.843 or 12[tex]\frac{59}{70}[/tex]

Step-by-step explanation:

    We will follow the Order of Operations to solve this question.

   Given:

[tex]\displaystyle (\frac{-3}{5})(-\frac{4}{7} )+12.5[/tex]

   Multiply:

[tex]\displaystyle (\frac{-3*-4}{5*7})+12.5[/tex]

[tex]\displaystyle (\frac{12}{35})+12.5[/tex]

   Add:

12 [tex]\frac{59}{70}[/tex]≈ 12.843

Answer:

12.8428571429

Answer:

X= 4,469

Y=4,474

Z=4,478

Step-by-step explanation:

X = 4469

Y = 4474

Z = 4478

X = 4470 - 1 = 4469   OR   4480 - 11 = 4469

Because, X is 1 space behind 4470 and 11 spaces behind 4480.

Y = 4470 + 4 = 4474   OR   4480 - 6 = 4474

Because, Y is 4 spaces ahead of 4470 and 6 spaces behind 4480.

Z = 4470 + 8 = 4478   OR   4480 - 2 = 4478

Because, Z is 8 spaces ahead of 4470 and 2 spaces behind 4480.

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Answer:-13 is to the left of -10. -10 is to the right of -13.

-13<-10

Step-by-step explanation:

-10 is to the left of -13 bc it is closer to the number 0 than -13. -10 is greater than -13.

Answer: is there a picture of the table?

Step-by-step explanation:

Donation sorting can be considered indirect service because it does not involve direct interaction with the intended beneficiaries of the donations. Instead, it involves organizing, categorizing, and preparing donated items for distribution to those in need. While donation sorting may not involve face-to-face interactions with the people being served, it is still an important aspect of the service process because it helps to ensure that donated items are distributed in an organized and efficient manner, and that they reach the people who need them the most. By volunteering in donation sorting, individuals can indirectly contribute to the betterment of their community and the well-being of those who are less fortunate.

Answer:

[tex]\large\boxed{\tt \angle ADC}[/tex]

Step-by-step explanation:

[tex]\textsf{We are asked for which angle is \underline{Adjacent} to} \ \tt \angle ADB.[/tex]

[tex]\large\underline{\textsf{What are Adjacent Angles?}}[/tex]

[tex]\textsf{Adjacent Angles are 2 angles that share a common vertex. These angles are}[/tex]

[tex]\textsf{referred to as angles next to each other. Note that it's only possible for an angle to}[/tex]

[tex]\textsf{be Adjacent with another angle if both angle share a common vertex.}[/tex]

[tex]\textsf{Consider noting as well that Adjacent Angles always have to have a common line}[/tex]

[tex]\textsf{segment. This means that one 'arm' of an angle has to be an arm of another.}[/tex]

[tex]\textsf{*Adjacent Angles don't overlap!}[/tex]

[tex]\underline{\textsf{Review of what a Vertex is;}}[/tex]

[tex]\textsf{A Vertex is an intersection point mainly created by lines, or line segments.}[/tex]

[tex]\large\underline{\textsf{Identifying the Adjacent Angle;}}[/tex]

[tex]\textsf{Our focus should be on} \ \tt \angle ADB. \ \textsf{We are trying to find the Adjacent Angle of} \ \tt \angle ADB.[/tex]

[tex]\textsf{We have 2 options to choose from, and they are;} \ \tt \angle ADC \ or \ \measuredangle BCD.[/tex]

[tex]\tt \measuredangle BDC \ \textsf{is a Right Angle, and is greater than} \ \tt \angle ADB. \ \textsf{Hence,} \ \tt \angle BDC \ \textsf{is incorrect.}[/tex]

[tex]\textsf{This leaves our final, and correct option;} \ \tt \angle ADC.[/tex]

[tex]\tt \angle ADB \ and \ \angle ADC \ \textsf{are Adjacent Angle for multiple reasons. Note that these angles}[/tex]

[tex]\textsf{are next to each other, they share the same Vertex point, and they share a common}[/tex]

[tex]\textsf{side/arm which is} \ \overrightarrow{\tt DA}.[/tex]

Answer:

Step-by-step explanation:

Answer:

P = 2(3 + 8) = 2(11) = 22

The correct answer is C.

The statement that is best supported by the information shown on the dot plots is A. The data of the two populations have different ranges.

The range of the data as shown in the dot plots of the weight of squirrels in the two populations can be found by the formula :

= Largest weight - Smallest weight

Range of population 1;

= 18 - 12

= 6 ounces

Range of population 2:

= 19 - 11

= 8 ounces

The range of the two populations is therefore different.

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Answer:

The correct answer is C. 126 units².

Step-by-step explanation:

To solve this problem, we must first realize that this figure is a trapezoid. To find the area of a trapezoid, we should use the following formula:

Area = 1/2(b1 + b2)*h

In this formula, b1 and b2 represent the two bases of the trapezoid and h represents the height.

The height of the trapezoid is 9 units, and the bases are 16 units and 12 units.

Plugging in these values, we get:

A = 1/2(16 units + 12 units)(9 units)

A = (1/2)(28 units)(9 units)

A = 14 units * 9 units

A = 126 units²

Therefore, the correct answer is C. 126 units².

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Answer:

i think its c

Step-by-step explanation:

Answer:

(4x – 5) – (-3x + 4) can be simplified by distributing the negative sign to the terms inside the parentheses:

(4x - 5) + (3x - 4)

We can then combine like terms by adding the coefficients of x and the constants:

7x - 9

Therefore, the expression that is equivalent to (4x – 5) – (-3x + 4) is 7x - 9.

Answer: 4 students

Step-by-step explanation:

Don't count the dots anything two or less, only count the dots that are > 2

Answer:

144

Step-by-step explanation:

Substitute x with 12 then times 6 by 12 then add 72 to get 144

Answer:

164 square centimeters

Step-by-step explanation:

S = 2(1/2)(5)(4) + 5(9) + 5(9) + 6(9)

= 20 + 45 + 45 + 54

= 164 square centimeters

Answer:same

Step-by-step explanation:

Answer: Angle D

Step-by-step explanation:

Based on the surface area and cost of the boxes, the company saves $11.50 by choosing to make 50 Box 2 instead of 50 Box 1.

To solve this problem, we need to calculate the surface area of each box to determine how much material is needed to make 50 of each box.

The surface area of Box 1 is:

SA1 = 2lw + 2lh + 2wh

SA1 = 2(206) + 2(204) + 2(6*4)

SA1 = 240 + 160 + 48

SA1 = 448 square inches

To convert to square feet, we divide by 144 (since there are 144 square inches in a square foot):

SA1 = 448/144

SA1 = 3.11 square feet

The cost of material for one Box 1 is:

C1 = 1.25 * SA1

C1 = 1.25 * 3.11

C1 = $3.89

The surface area of Box 2 is:

SA2 = 2lw + 2lh + 2wh

SA2 = 2(154) + 2(158) + 2(4*8)

SA2 = 120 + 240 + 64

SA2 = 424 square inches

Converting to square feet:

SA2 = 424/144

SA2 = 2.94 square feet

The cost of material for one Box 2 is:

C2 = 1.25 * SA2

C2 = 1.25 * 2.94

C2 = $3.67

To find the cost savings of making 50 Box 2 instead of 50 Box 1, we calculate the difference in cost:

Savings = (50 * C1) - (50 * C2)

Savings = (50 * 3.89) - (50 * 3.67)

Savings = $11.50

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